If both are similar ratio of sides will be same
[tex]\\ \sf\longmapsto \frac{x}{25} = \frac{7}{5} \\ \\ \sf\longmapsto 5x = 7 \times 25 \\ \\ \sf\longmapsto 5x = 175 \\ \\ \sf\longmapsto x = \frac{175}{5} \\ \\ \sf\longmapsto x = 35[/tex]
Can anyone help plz?
Answer:
just add a small amount and and square the new number
between 2.82 and 2.83 seems a bit closer
Step-by-step explanation:
x x^2
2.8 7.84
2.81 7.8961
2.82 7.9524
2.83 8.0089
2.84 8.0656
2.85 8.1225
2.86 8.1796
2.87 8.2369
NEED HELP ASAP!!!!!!!
Can someone help me out with this
We know
[tex]\boxed{\Large{\sf Circumference=\pi d}}[/tex]
[tex]\\ \Large\sf\longmapsto Circumference=\dfrac{22}{7}\times 23.4[/tex]
[tex]\\ \Large\sf\longmapsto Circumference=\dfrac{514.8}{7}[/tex]
[tex]\\ \Large\sf\longmapsto Circumference=73.5in[/tex]
Find all complex numbers z such that z^4 = -4.
Note: All solutions should be expressed in the form a+bi, where a and b are real numbers.
Prove that 1/√2 is irrational
Answer:
Step-by-step explanation:
Let's assume that it is rational , so this number can be represented as[tex]\Large \boldsymbol{}\bf \dfrac{p^{^/is \ an \ integer}}{q^{ / natural}} -irreducible \ \ fraction[/tex]
[tex]\Large \boldsymbol{}\bf \dfrac{1 ^{/ an \ integer }}{\sqrt{2}^{ / not \ \ integer } }[/tex] -Since the denominator is not a natural number then the 1/√2 is respectively an irrational number
If a wheel has a radius of 5cm
how much is one rotation of the wheel
How many rotations can the wheel do within a distance of 50km
Answer:
circumference = 2*PI*radius
circumference = 2 * PI * 5 cm
circumference = 31.4159265358979 cm
50 km = 500,000 centimeters
rotations = 500,000 / 31.4159 cm
15,915.51 rotations
Step-by-step explanation:
How many solutions does the system have?
⎪
⎪
⎨
⎪
⎪
⎧
x+y=3
5x+5y=15
Solve 4 sinx + 9 cosx=0 for 0°
4 sin(x) + 9 cos(x) = 0
4 sin(x) = -9 cos(x)
tan(x) = -9/4
x = arctan(-9/4) + nπ … … … (in radians)
or
x = arctan(-9/4) + 180n ° … … … (in degrees)
where n is any integer.
I'm guessing you're solving for x over some domain, probably 0° ≤ x < 360°. In that case, you would have two solutions for n = 1 and n = 2 of
x ≈ 113.96° and x ≈ 293.96°
Determine the quotient of .    
Find the height of the triangle by applying formulas for the area of a triangle and your knowledge about triangles.
This is a triangle. side a has a length of 6 yards. side b has a length of 10 yards. side c has a length of 14 yards. The altitude to side c has a length of X yards. what is x
Answer:
3.71 yd
Step-by-step explanation:
Heron's formula:
area = 0.25 * √((a + b + c) * (-a + b + c) * (a - b + c) * (a + b - c))
so h = 0.5 * √((a + b + c) * (-a + b + c) * (a - b + c) * (a + b - c)) / c
a = 6
b = 10
c = 14
a+b+c = 30
-a+b+c = 18
a-b+c = 10
a+b-c = 2
x = h = 0.5×sqrt(30×18×10×2)/14 = sqrt(30×18×10×2)/28 =
= sqrt(10800)/28 = sqrt(400×9×3)/28 =
= 20×3×sqrt(3)/28 = 60×sqrt(3)/28 = 15×sqrt(3)/7 =
= 3.711537 yd
Lorraine writes the equation shown. x²+4-15=0 She wants to describe the equation using the term relation and the term function. The equation represents a relation and a function a relation but not a function a function but not a relation neither a relation nor a function
Answer:
Neither a relation nor a function
Step-by-step explanation:
A relation in mathematics is a relationship between two or more set of values in an ordered pair, such as related x and y-values
An equation is a statement that gives declare the equality between two expressions
A function is a mapping rule that maps each element in the domain set to only one element in the range set
Therefore, the given equation in one variable, x, that asserts the equality of the expressions on the left and right hand side, is neither a relation nor a function
Find the area of the bolded outlined sector.
Outlined sector:
2 πr x 225/360 +2r
=2x3.14x10 x 225/360 +20
=59.25 cm
Hope this helped!
Geometry, please answer question ASAP
Answer:
m<D = 170°
Step-by-step explanation:
In a pentagon, the angles add up to 540°. This means the sum of <A, <B, <C, <D, and <E add up to that, and we can write an equation:
m<A + m<B + m<C + m<D + m<E = 540°
We are already given the measures of all the angles except D, so we can substitute them in:
87° + 125° + 63° + m<D + 95° = 540°
Now, we can simplify and solve for <D:
m<D + 370° = 540°
m<D = 170°
4. Which property of similarity can be used to prove triangles DEF and GHI are similar?
Answer:
SSS
Step-by-step explanation:
We know all three sides of both triangles. The common ratio of DEF to GHI is 2/3.
Answer:
SSS
Step-by-step explanation:
Similar triangles must have congruent corresponding angles and proportional corresponding sides.
Pressure varies inversely as volume. When the pressure is 8 Pascals, the volume is 22 liters. What would the volume be if the pressure were increased to 16 pascals?
Answer:
we can use 2 formule to solve your question: One is P*V=n(mol)*R*T(KELVIN)
Step-by-step explanation:
And other is P(first)*V(first)=P(last)*V(last)
8*22=16*?
the ?=11
Geometry, please answer question ASAP
Answer:
I think the shape above has an order of 5 because it has a reflectional symmetry of 5.
I hope this helps
Another of Bhaskara's problems results in a quadratic equation Parthava was enraged and seized a certain number of arrows to slay Karna. He expended one-half of them in defending himself. Four times the square root of the number of arrows were discharged against the horses. With six more, he transfixed Shalya, the charioteer. With three more, he rent the parasol, the standard, and the bow; and with the last one he pierced the head of Karna. How many arrows did Parthava have?
Answer:
Parthava had 100 arrows.
Step-by-step explanation:
Let's define N as the number of arrows that Parthava originally has.
He uses one-half of them in defending himself, so he used N/2 arrows
Now he uses four times the square root of the number of arrows, so now he uses:
4*√N
Then he uses 6
Then he uses 3
Then he uses the last one.
If we add all these numbers of arrows that he used, we should get the initial number of arrows that he used, then:
N/2 + 4*√N + 6 + 3 + 1 = N
Now we have an equation that we can try to solve.
First, let's move all the terms to the same side:
N/2 + 4*√N + 6 + 3 + 1 - N = 0
now we can simpify it:
(N/2 - N) + 4*√N + (6 + 3 + 1) = 0
-(1/2)*N + 4*√N + 10 = 0
Now we can define a new variable x = √N
Then we have: x^2 = N
now we can replace these new variables in our equation to get:
-(1/2)*x^2 + 4*x + 10 = 0
Now we just have a quadratic equation.
Remember that for a quadratic equation of the form:
0 = a*x^2 + b*x + c
The solutions were given by:
[tex]x = \frac{-b \pm \sqrt{b^2 - 4*a*c} }{2a}[/tex]
Then in our case, the solutions will be:
[tex]x = \frac{-4 \pm \sqrt{4^2 - 4*(-1/2)*10} }{2*(-1/2)} = \frac{-4 \pm 6 }{-1} = 4 \pm 6[/tex]
So there are two solutions:
x = 4 + 6 = 10
x = 4 - 6 = -2
And remember that x = √N
Then x should be positive, then we take x = 10 as our solution here.
then we can use the equation:
x = 10 = √N
then
10^2 = √N^2 = N
10^2 = 100 = N
Parthava had 100 arrows.
Convert 5π∕6 radians to degrees. Question 1 options: A) 25° B) 150° C) 150π° D) 1080°
Step-by-step explanation:
Hi there!
Given;
= 5(π\6)
We have;
π = 180°
Keeping value of π in the question;
= 5(180°/6)
= 5*30°
= 150°
Therefore, answer is option B.
Hope it helps!
Which angles are adjacent to each other?
Angle CHG and Angle HDL
Angle AEB and Angle DEA
Angle CHG and Angle HCE
Angle JCH and Angle CHG
Please make sure it's correct because one person once tried it and got it wrong..lol.
Answer:
B
Step-by-step explanation:
Adjacent angles must have the same vertex, so if the middle letter of the three letters used to name each of the angles in a pair are not the same, the angles cannot be adjacent.
That eliminates choices A, C, and D.
Answer: B
Look in the picture first below. Each pair of angles with the same vertex marked in blue is a pair of adjacent angles. For two angles to be adjacent angles, they must be next to each other, have the same vertex, and one cannot be inside the other.
Now look in the second picture below. Each pair of angles marked in red is not a pair of adjacent angles. Some of them are not next to each other. Others have one angle inside the other.
Find the values of x and y if (-x + 5, 1) = (-y, 2x - 5y).
Answer:
x = 8, y = 3
Step-by-step explanation:
Equating corresponding x and y coordinates , then
- y = - x + 5 ( multiply through by - 1 )
y = x - 5 → (1)
2x - 5y = 1 → (2)
Substitute y = x - 5 into (2)
2x - 5(x - 5) = 1 ← distribute and simplify left side
2x - 5x + 25 = 1
- 3x + 25 = 1 ( subtract 25 from both sides )
- 3x = - 24 ( divide both sides by - 3 )
x = 8
Substitute x = 8 into (1) for corresponding value of y
y = 8 - 5 = 3
please answer this question!!
Answer:
a
Step-by-step explanation:
all angles of an equilaterall triangle are equal therefore 180÷3 = 60
9) Three times a number added to 12 gives -6. Find the number.
Answer:
The number is -6.
Step-by-step explanation:
Variable x = a number
Set up an equation:
3x + 12 = -6
Isolate variable x:
3x = -18
x = -6
Check your work:
3(-6) + 12 = -6
-18 + 12 = -6
-6 = -6
Correct!
Answer:
3x +12=-6
3x=-6-12
3x=-18
x=-18/3
x=-6
traders fix the price of cosmetic items 30% above the cost price when he sold an item at 25% discount there was a loss of Rs 15 find the cost price and marked price of the item
Cost price is Rs600 and marked price is Rs780.
Must click thanks and mark brainliest
The temperature on a mountain peak was 7 degreesFahrenheit (F) at 6:00 p.m. By 8:00 p.m., thetemperature had dropped to 0F. If the temperaturecontinued to drop at about the same rate, which isthebestestimate of the temperature at 11:00 p.m
A -20 / B. -14 / C -10 / D -9 /
Given:
The temperature on a mountain peak was 7°F at 6:00 p.m.
By 8:00 p.m., the temperature had dropped to 0°F.
To find:
The temperature at 11:00 p.m. if the temperature continued to drop at about the same rate.
Solution:
Time between 6:00 p.m. to 8:00 p.m. is 2 hours.
Change in temperature in 2 hours is -7°F.
Change in temperature in 1 hours is [tex]-\dfrac{7}{2}^\circ[/tex]F.
Time between 8:00 p.m. to 11:00 p.m. is 3 hours.
Change in temperature in 3 hours is [tex]3\times \dfrac{-7}{2}^\circ[/tex]F, i.e., [tex]-\dfrac{21}{2}^\circ[/tex]F.
Now, the temperature at 11:00 p.m is:
[tex]0-\dfrac{21}{2}=-10.5[/tex]
Therefore, the temperature at 11:00 p.m. is -10.5°F.
Note: All options are incorrect.
To paint a wooden cube, Pinocchio needs 4 grams of paint. When it is dry, he cut the cube into 8 smaller pieces of smaller size. How much paint additional paint does Pinocchio need to paint the unpainted surfaces of the smaller cubes
Answer:
9 grams of paint
Step-by-step explanation:
6×8=48
48÷4= 12
48-12=36
36÷4=9
first multiply 6 by 8 because a cube has six faces and you cut that cube eight times
second after you cut that you will have 48 faces and for every six faces there are 4 grams of paint so you divide 48 by 4 and you get 12 this means that 12 of the faces are painted
next you subtract 12 from 48 and you get 36 this means that 36 faces are not painted
lastly you divide 36 by 4 and you will get 9 grams of paint
Uma maneira de realizar a operação 9972 - 9 de forma rápida e correta é calculando 1 000 * 994, que é igual a 994 000. A igualdade que justifica esse fato está expressa em:
a) (a + b)² = a² + b² + 2ab
//
b) a² - b² = (a + b)(a - b)
//
c) a² - b² = (a - b)²
//
d) (a - b)² = a² - 2ab + b²
//
e) a² - b² = 1 000(a + b)
Answer:
a)
Step-by-step explanation:
(cos^2x-sin^2x)-sin4x+sin^22x=0
Answer:
x=22.5
Step-by-step explanation:
(there's a correction in the question since the I did this one before, so I know)
(cos²x-sin²x)²-sin4x+sin²2x=0
or, cos²2x-sin4x+sin²2x=0
or, 1-sin4x=0
or, sin4x=1
or, 4x=90
or, x=22.5
Rob cuts a circular hole out of a rectangular piece of paper. The paper measures 20 centimeters by 30 centimeters. The hole is 10 centimeters in diameter. How much of the piece of paper, in square centimeters, is left over after the hole is cut out?
Answer:
521.25
Step-by-step explanation:
the circle is 78.75 in area and the square is 600 so 600- 78.75 = 521.25
Plz help similarity theorems
Answer:
b is the answer bro and try first then ask questions
Decide !!!!!!!!!!!!!!!!!!
Make note of the coefficients in the first and fourth equations. They've been conveniently picked so that subtracting one equation from the other eliminates every variable but t. We have
(3r + 2s + t + 2u + 3v) - (3r + 2s + 3t + 2u + 3v) = 7 - 17
-2t = -10
t = 5