The spring in the dart gun is compressed by 0.16 m
From the question given above, the following data were obtained:
Spring constant (K) = 50 N/m
Potential Energy (PE) = 0.640 J
Compression (e) =?The compression experience by the spring can be obtained as follow:
PE = ½ke²
0.64 = ½ × 50 × e²
0.64 = 25 × e²
Divide both side by 25
e² = 0.64 / 25
Take the square root of both side
e = √(0.64 / 25)
e = 0.16 m
Therefore, the spring is compressed by 0.16 m
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How many sulfur atoms are there in 25 molecules c4h4s2?.
if acceleration due to gravity is 10m/s², what will be the potential energy of a body of mass 2 kg kept at a height of 5 meter ?
Answer:
50J
Explanation:
Ep = mgh
Here,
m = 1kg; g = 10 m/s2; h = 5m
So, Ep = 1kg*10m/s2*5m
= 50J
So, the potential energy is 50J (Ans).
A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its original linear momentum. a) Determine what fraction of the kinetic energy is lost in the collision.
The fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
The given parameters;
initial speed of the ball, = vifinal momentum of the ball, Pf = ¹/₃PiThe initial and final momentum of the ball is calculated as;
[tex]P_i = m_ivi[/tex]
[tex]P_f = m_fv_f = \frac{1}{3} m_iv_i[/tex]
The initial and final kinetic energy of the ball is calculated as;
[tex]K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i[/tex]
The change in the kinetic energy is calculated as;
[tex]\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i[/tex]
Thus, the fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
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Train car A is at rest when it is hit by train car B. The two cars, which have the same mass, stick together and move off after the collision. How does the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision?.
The value of the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision is [tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex].
According to the principle of conservation of linear momentum, the total momentum before and after collision is conversed.
[tex]m_av_a_1 + m_bv_b_1 = v(m_a + m_b)[/tex]
where;
[tex]v_a_1 \ \ and \ \ v_b_1[/tex] are the initial velocity of the cars before collisionv is the final velocity of the cars after collisionsince the train car A is at rest, [tex]v_a _1 = 0[/tex]
[tex]m_bv_b_1 = v(m_a + m_b)[/tex]
The relationship between the final velocity and initial velocity of the cars is given as;
[tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex]
Thus, the value of the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision is [tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex].
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Answer: the answer is the third option. Edge 2021
Explanation: i just answered the problem
A scientist fills a container with sea water. The container has dimensions 30 cm x 30 cm x 40 cm The density of sea water is 1020 kg/mº. Calculate the mass of the sea water in the container.
Answer:
30600kg
Explanation:
density=m/v make v subject of the formula
What is the horizontal acceleration of a ball that is launched horizontally with a velocity of 5. 6 m/s? â€""9. 8 m/s2 0 m/s2 5. 6 m/s2 9. 8 m/s2.
The horizontal acceleration of a ball that is launched horizontally is equal to: B. 0 [tex]m/s^2[/tex]
Given the following data:
Horizontal velocity = 5.6 m/sTo determine the horizontal acceleration of a ball that is launched horizontally:
Acceleration can be defined as the rate of change of velocity with respect to time. In Physics, the acceleration of an object or body is calculated by subtracting its initial velocity from the final velocity and dividing by the time.
Mathematically, acceleration is given by the formula;
[tex]Acceleration = \frac{V\; -\;U}{t}[/tex]
The projectile motion of an object launched horizontally has a constant velocity and as such its horizontal acceleration would be equal to zero meter per seconds square ([tex]0\;m/s^2[/tex]).
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At about 1 second after the beginning of the universe, one type of particle was able to start traveling freely through the universe. These particles are still with us, but they are extremely hard to detect. They are called:
The Big Bang theory allows finding the result for which particles were formed in the 1 s of the universe is:
The quark subatomic particles were the first to form due to the high amount of energy.
The Big Bang theory says that the universe is formed about 14 billion years ago, of a structure that is very high energy.
Einstein's equation establishes the relationship between energy and matter, establishing that energy can be converted into matter.
E = m c²
Where E is energy, m is mass, and c is the speed of light.
In the 1 s of the universe the energy density was so high that all subatomic particles were formed, the first being quarks.
When the universe cooled enough, the quarks combined to form protons and neutrons, from which atoms were formed.
In conclusion, using the Big Bang theory we can find the result for which particles were formed in the 1 s of the universe is:
The quark subatomic particles were the first to form due to the high amount of energy.
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A guitar string has a fundamental frequency f. The tension in the string is increased by 1.70%. Ignoring the very small stretch of the string. How does the fundamental frequency change?
The characteristics of the speed of the waves in strings and the resonance allows to find the change in the fundamental frequency when changing the tension is:
The change in fundamental frequency is: f = 1.08 f₀
The speed of the chord wave is given by the relationship between the tension and the density of the medium.
[tex]v= \sqrt{\frac{T}{\mu } }[/tex]
Where v is the velocity of the wave, T the tension of the string and μ the density
In a rope held at the ends, a process of standing waves occurs, two at the point where it is attached we have a node and a anti-node in the center.
2L = n λ
Where L is the length of the chord and call the wavelength
Wave speeds are related to wavelength and frequency.
v = λ f
We substitute.
[tex]\sqrt{\frac{T}{\mu } } = \frac{2L}{n} \ \ f[/tex]
For the fundamental frequency n = 1
f₀ = [tex]f_o = \sqrt{\frac{T}{\mu } } \ \ \frac{1}{2L}[/tex]
They indicate that the tension increases 1.70%
T = T₀ + 0.17 T₀
T = 1.17 T₀
We substitute.
[tex]f = \sqrt{1.17 } \ \sqrt{\frac{T_o}{\mu } } \ \ \frac{1}{2L}[/tex]
f = ra1.17 f₀
f = 1.08 f₀
In conclusion, using the characteristics of the velocity of the waves in strings and the resonance we can find the change in the fundamental frequency when changing the tension is:
The change in fundamental frequency is: f = 1.08 f₀Learn more about string resonance here: brainly.com/question/16010929
The Kentucky Derby is one of the most exciting horse races run every year. In 1973, the horse Secretariat set a record that still stands. This 500-kg horse ran the 2000-m track in 120 s. What was Secretariat’s average kinetic energy? (1 kJ = 1000 J)
Need answers with explanaitions please
A. 4.2 kJ
B. 8.3 kJ
C. 69.0 kJ
D. 139.0 kJ
Answer:
C.69 kJ
Explanation:
kinetic energy
[tex] = 1 \div 2mv {}^{2} [/tex]
The magnitude of vector A is 2.5 m and is directed towards east. The magnitude and direction of A /2 will be
The magnitude and direction of half of the given vector A is 1.25 m east.
The given parameters;
magnitude of vector A = 2.5 m eastA vector can be described with both magnitude and direction. The magnitude of the vector is the scalar or numeric representation of the vector.
When the scalar representation has direction, we term the quantity a vector quantity.
The magnitude of half of the given vector is calculated as follows;
[tex]\frac{A}{2} = \frac{2.5 \ m}{2} = 1.25 \ m\ east[/tex]
Thus, the magnitude and direction of half of the given vector A is 1.25 m east.
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a girl runs once around a circular track with a radius of 100m at speed of 10m/s.
calculate her displacement
Answer:
0 m
Explanation:
Displacement is the shortest distance from one ppont to another. Here, the girl returns to the same spot after running. Hence, displacement is 0 m.
A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws
the book at a speed of 7.2 m/s. His chair moves backward. The man has a mass of 70 kg and
the chair has a mass of 9.2 kg. What is the speed of the man and the chair after the book is
thrown?
The speed of the man and the chair after the book is thrown is 0.2 m/s.
The given parameters:
mass of the book, m₁ = 2.1 kgspeed of the book, u₁ = 7.2 m/smass of the man, M = 70 kgmass of the book, m = 9.2 kgThe total mass of the man and the book is calculated as follows;
m₂ = 70 kg + 9.2 kg
m₂ = 79.2 kg
The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;
[tex]m_1 u_1 = m_2u_2\\\\u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{2.1 \times 7.2}{79.2} \\\\u_2 = 0.2 \ m/s[/tex]
Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.
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What is thermal energy.
Explanation:
thermal energy refers to the energy contained within a system that is responsible for its temperature. Heat the flow of thermal energy
Best definition of an electromagnetic wave?
A) an electromagnetic wave is a longitudinal wave with electricity
B) an electromagnetic wave is a mechanical wave
C) an electromagnetic wave is a transversal wave that has electrical and magnetic properties
Answer:
Longitudinal and mechanical waves require a medium to support their transmission:
C) is the correct answer
You push a 24.7 kg toy wagon at a speed of 9.7. What is the momentum of the wagon?
Answer:
Momentum = 239.59 kg·m/s
Explanation:
Mass x Velocity = Momentum
Explain why position is a dependent variable in a position versus time graph.
Answer:
Explanation:
The position depends on the time. The longer the time, the further the distance.
Where could light travel the easiest and fastest?
A) through air
B) through empty space
C) through liquid hydrogen
Explanation:
Light travels fastest through air
Answer:
try through air
Explanation:
Help me out with this physics please!!!
Answer: It was on between 7 and 7.30 and also between 8 and 8.30 (when the line on the graph goes up only). So it was on for an hour or 60 minutes
State the general purpose of an experiment, using the terms dependent and independent variable
Answer:
Image result for State the general purpose of an experiment, using the terms dependent and independent variable
You can think of independent and dependent variables in terms of cause and effect: an independent variable is the variable you think is the cause, while a dependent variable is the effect. In an experiment, you manipulate the independent variable and measure the outcome in the dependent variable
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Compare the amplitude of these waves.
Answer:
a smooth
b less smooth
c faster
d faster than fast c
e to fast for fast
Explanation:
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm. A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
We have that for the Question, it can be said that the amount by which the length of the stack decreases is
[tex]dl'=3.621*10^{-4}m[/tex]
From the question we are told
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.
A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
Generally the equation for copper cylinder is mathematically given as
[tex]dl=\frac{Flo}{yA}[/tex]
[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=1.19064778*10^-^4[/tex]
Generally the equation for brass cylinder is mathematically given as
[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=2.43*10^{-4}[/tex]
Therefore Total change in length
[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]
[tex]dl'=3.621*10^{-4}m[/tex]
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You find a rock that is about 20 grams large. This rock contains about 10 grams of Uranium-235 and 10 grams of the element it decays into (Thorium-231). The half life of Uranium-235 is 700 million years. How old is this rock?
The age of the given rock is 700 million years.
The given parameters;
original mass of the rock, = 20 gmass of the rock remaining after decay, = 10 ghalf life of Uranium, [tex]t_{1/2}[/tex] = 700 yearsage of the rock ----------------------------- mass remaining
0 [tex](t_0)[/tex] ------------------------------------------- 20 g
1 half life ([tex]1 \ t_{1/2}[/tex] ) ------------------------------ 10 g
Age of the rock [tex]= t_{1/2} - t_0 = 700 \ - 0 = 700 \ million \ years[/tex]
Thus, the age of the given rock is 700 million years.
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The mass of a basketball is three times greater than the mass of a softball. Compare the momentums of a softball and a basketball if they both are moving at the same velocity.
Answer:
The momentum of the basketball is three times that of the softball. Momentum equals mass times velocity. Therefore, if the basketball and softball are moving at the same velocity, and the basketball has three times the mass of the softball, the basketball has three times the momentum of the softball.
Explanation:
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Which type of solid is dry ice (solid carbon dioxide)? ionic atomic molecular none of the above.
Answer: molecular solid
Explanation:
What is occurring in the umbra?
A. a total solar eclipse
B. a total lunar eclipse
C. a partial lunar eclipse
D. a partial solar eclipse
Answer:
A. a total solar eclipse
Explanation:
During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth
Plz help ⭐..................
Answer:
where in the world is the image????..
Question 1 of 11
The book has a mass of 2.5 kg.
What net force must act on the book to make it accelerate to the left at a rate
of 7.0 m/s2? (Hint: Use F = ma.)
O A. F = 17.5 N right
OB. F = 2.8 N right
O C. F = 2.8 N left
O D. F = 17.5 N left
Answer:
D. F= 17.5 N left
Explanation:
I just took the quiz and got it correct!
State one advantage and disadvantage of friction
Answer:
Advantage: Helps us to walk without slipping.Helps machines workDisadvantage:
We slip on a wet floor.Causes the smoothness of tires and smoothness of shoes soul.5. How are electromagnetic waves similar to ocean waves?.
Answer:
Electromagnetic waves have crests and troughs similar to those of ocean waves. The distance between crests is the wavelength. The shortest wavelengths are just fractions of the size of an atom, while the longest wavelengths scientists currently study can be larger than the diameter of our planet!
Explanation:
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Explain why the 4th state of matter would and would NOT make an acceptable force field.
The 4th state of matter would make an acceptable force field.
The 4th state of matter which is plasma would make an acceptable force field because this fourth state of matter is present in ionized form which has two charges on it i.e. cation which is a positive charge and anion which is a negative charge.
We know that charges attract as well repel other objects if they are strong enough. Positive charge repel positive charge but attract negative charge so we can conclude that 4th state of matter would make an acceptable force field.
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