The pressure of a gas in a cylinder when it is heated to a temperature of 250k is 1.5 atm. What was the initial temperature of the gas if it’s initial pressure was 1 atm?

Answers

Answer 1

Answer:

[tex]T1=166.66K[/tex]

Explanation:

According to Gay-Lussac’s law simply states that the ratio of the initial pressure and temperature is equal to the ratio of the final pressure and temperature for a gas of a fixed provided that the mass is kept at a constant volume.

Given:

Initial pressure, P1 = 1 atm

Final pressure, P2 = 1.5 atm

Final temperature, T2 = 250 K

The law can be applied using the below formula

P1T2 = P2T1

Then,

T1 = (P1T2)/P1 = (1*250)/(1.5) = 166.66 Kelvin.

[tex]T1=166.66K[/tex]

:

Answer 2

Answer:

[tex]T_1=166.7K[/tex]

Explanation:

Hello,

In this case, by applying the Gay-Lussac's law which help us to understand the pressure-temperature gas behavior via a directly proportional relationship:

[tex]\frac{P_1}{T_1} =\frac{P_2}{T_2}[/tex]

In such a way, as we are asked to compute the initial temperature knowing the initial pressure and final both temperature and pressure, so we solve for it:

[tex]T_1=\frac{T_2P_1}{P_2}=\frac{250K*1atm}{1.5atm} \\\\T_1=166.7K[/tex]

Best regards.


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The balanced equation based on half-reactions is 2Cu + 8HNO3 + 6H+ -> 2Cu(NO3)2 + 2NO + 4H2O.

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Answers

Answer:

458.7 mmHg

Explanation:

Step 1:

Data obtained from the question. This includes:

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Explanation:

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Answers

Answer:

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Answers

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Answer:Releasing insulin to decrease blood sugar and releasing glucagon to increase blood sugar

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Homeostasis could be positive or negative. It usually involves a sensor which detects the changes in the body and passes the information to the control center, a control center which receive information from the sensor and sends signals to the effectors and the effector which acts on the information sent by the control center to effect normalcy.

In this case, when a person eats food,he gets glucose. Blood sugar most be kept at constant so the endocrine system release the hormone insulin. Insulin helps to convert glucose to glycogen, which is the form it can be stored in the liver

When the blood sugar levels is low, the brain which is the control center causes glucagon to be released . This hormone converts glycogen to glucose

Answer:

Answer:Releasing insulin to decrease blood sugar and releasing glucagon to increase blood sugar

Explanation:

The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.
C6H12O6(aq) + 6 O2(g) → 6 CO2(g) + 6 H2O(l)

Calculate the volume of dry CO2 produced at body temperature (37°C) and 0.960 atm when 24.5 g of glucose is consumed in this reaction.

Answers

Answer:

[tex]\large \boxed{\text{21.6 L}}[/tex]

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:        180.16

         C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g:      24.5

(a) Moles of C₆H₁₂O₆

[tex]\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}[/tex]

(b) Moles of CO₂

[tex]\text{Moles of CO}_{2} =\text{0.1360 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol CO}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.8159 mol CO}_{2}[/tex]

(c) Volume of CO₂

We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.960 atm

n = 0.8159 mol

T = 37  °C

(i) Convert the temperature to kelvins

T = (37 + 273.15) K= 310.15 K

(ii) Calculate the volume

[tex]\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}[/tex]

Calculate the molarity of a nitric acid solution if 38 ml of the solution is neutralized by 16 ml of 0.25 M barium hydroxide solution. The balanced equation for the reaction is

Answers

Answer:

l

Explanation:

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