Answer:
40%
Step-by-step explanation:
ok so first find the og price:
100% - 20% = 80%
so 80% = 200
let the 100% be x:
x * 0.8 = 200
x= 250
100% = 250
(difference/ og price) * 100% = the percentage decrease/ increase
(250-150/250)* 100% = 40%
OR
((the final price/ og price) * 100%) - 100%
((150/250)*100%) - 100% = 40%
There was a 40% decrease from the og price to the final price of 150.
WILL GIVE BRAINLIEST IF CORRECT!
Write an equation that represents the line. Use exact numbers.
Answer:
y=0.5x-3.5
Step-by-step explanation:
(-4)-(-5)=1
3-1=2
1/2=0.5
y=0.5x-3.5
Answer:
[tex]y=-2y-7[/tex]
Step-by-step explanation:
Coordinates plotted on the equation:
[tex](1,-4)[/tex]
[tex](4,-5)[/tex]
{check the image for your reference}
Find the value of x. Round to
the nearest tenth.
17°
47
Х
X =[?]
Answer:
13.7 units
Step-by-step explanation:
Hi there!
The dotted lines and the hypotenuse of the green triangle create a new right triangle, with one of its acute angles measuring 17 degrees and its hypotenuse measuring 47 units.
Given this information and that we must solve for the side opposite the given angle, we can use the sine ratio:
[tex]sin\theta=\frac{opposite}{hypotenuse}[/tex]
Plug in known information
[tex]sin17=\frac{x}{47}\\47*sin17=x\\13.7=x[/tex]
Therefore, the value of x when rounded to the nearest tenth is 13.7 units.
I hope this helps!
I have a lot of algebra problems. Someone help me even with this one please!
Answer: Choice D
The graph will be discrete because there is no such thing as a partial person to sign up, and the booth is set up once each day for sign ups.
=========================================================
Explanation:
Let's start with the independent variable d. This acts as the variable x. It's the input. The value of d only takes on positive whole numbers (eg: d = 1, d = 2, d = 3, etc). We cannot have something like d = 2.718
So this bit of evidence shows that our function is discrete. Discrete input values (d) plug into the function to produce corresponding discrete output values (m).
Furthermore, we know that m is discrete because the number of people cannot be a fractional or decimal number. We can't have half a person for instance.
---------------
A quick way to see if a set is discrete or continuous is to ask the question: "is it possible to apply the midpoint formula for ANY two values, and have the output make sense?"
So a set like {1,2,3,4,5,...} is discrete because the midpoint of 2 and 3 is 2.5, but that value is not in the set mentioned.
In other words, discrete sets have "gaps" so to speak, while continuous ones do not.
---------------
Another useful property is that let's say that a < x < b, and x is drawn from the domain set. This reduced set will be finite if we're dealing with discrete data. Eg: The set {1,2,3,4,5,...} has the subset {2,3,4} which is finite and discrete.
In contrast, the subset of real numbers x such that [tex]2 \le x \le 4[/tex] is continuous and this subset is infinitely large (has infinitely many members) because we could have things like 2.718 or 3.14 etc
Evaluate the expression 42 +6.52 – 33 = 32,
Clara lends half her collection of formal attires to her sister, Susan. Clara then buys four more attires. If she has 12 attires now, how many attires did Clara initially?
Answer:
16
Step-by-step explanation:
Number of attires Clara has initially = x
lends half her collection of formal attires to her sister
Attires remaining after lending = Number of attires Clara has initially - attires she lent her sister
= x - 1/2x
= 1/2x
Clara then buys four more attires
= 1/2x + 4
If she has 12 attires now
12 = 1/2x + 4
12 - 4 = 1/2x
8 = 1/2x
x = 8 ÷ 1/2
= 8 × 2/1
= 16
x = 16
Number of attires Clara has initially = x = 16
What is the frequency of the graph of y = 1/3 sin(2x)?
Given:
The sine function is:
[tex]y=\dfrac{1}{3}\sin (2x)[/tex]
To find:
The frequency of the graph of given function.
Solution:
If a sine function is defined as:
[tex]y=A\sin(Bx+C)+D[/tex]
Then, the frequency of the sine function is:
[tex]f=\dfrac{B}{2\pi}[/tex]
We have,
[tex]y=\dfrac{1}{3}\sin (2x)[/tex]
Here, [tex]B=2[/tex]. So, the frequency of the given function is:
[tex]f=\dfrac{2}{2\pi}[/tex]
[tex]f=\dfrac{1}{\pi}[/tex]
Therefore, the correct option is D.
A carpet manufacturer is inspecting for flaws in the finished product. If there are too many blemishes, the carpet will have to be destroyed. He finds the number of flaws in each square yard and is interested in the average number of flaws per 10 square yards of material. If we assume the standard deviation of the number of flaws per square yard is 0.6, the sample mean, , for the 10 square yards will a standard deviation of
Answer:
10 square meters will have a standard deviation of 1.897.
Step-by-step explanation:
Standard deviation for n instances of a variable:
If the standard deviation for one instance of a variable is [tex]\sigma[/tex], for n instances of the variable, the standard deviation will be of [tex]s = \sigma\sqrt{n}[/tex]
The standard deviation of the number of flaws per square yard is 0.6
This means that [tex]\sigma = 0.6[/tex]
For the 10 square yards will a standard deviation of
[tex]n = 10[/tex], so:
[tex]s = \sigma\sqrt{n} = 0.6\sqrt{10} = 1.897[/tex]
10 square meters will have a standard deviation of 1.897.
The equation px²+px+3q=1+2x has roots 1/p and q
(a) Find the values of p and of q
Answer:
p = 2/3
q = 1/2
Step-by-step explanation:
The given equation is ,
[tex]\sf\to px^2 + px + 3q = 1 + 2x [/tex]
We can write it as ,
[tex]\sf\to px^2 + px + 3q - 1 -2x=0 [/tex]
Rearrange the terms ,
[tex]\sf\to px^2 - 2x + px + (3q -1)=0 [/tex]
This can be written as ,
[tex]\sf\to px^2 + x ( p - 2) + (3q -1) =0[/tex]
Now wrt Standard form of a quadratic equation ,
[tex]\bf \implies ax^2+bx + c = 0 [/tex]
we have ,
a = p b = p - 2 c = 3q - 1We know that product of zeroes :-
[tex]\to \sf q \times \dfrac{1}{p} = \dfrac{3q-1}{p } \\\\\sf\to 3q - 1 = q \\\\\sf\to 2q = 1 \\\\\sf\to \boxed{ q =\dfrac{1}{2}}[/tex]
Sum of roots :-
[tex]\to \sf q + \dfrac{1}{p} = \dfrac{2-p}{p} \\\\\sf\to \dfrac{ qp + 1}{p}= \dfrac{2-p}{p} \\\\\sf\to qp + 1 = 2 - p \\\\\sf\to p/2 + p = 1 \\\\\sf\to 3p/2 = 1 \\\\\sf\to \boxed{ p =\dfrac{2}{3}}[/tex]
Sales of a certain product are declining at a rate proportional to the amount of sales. If at the end of the first year the sales have declined by 22%, then how many years will have passed (since the beginning of the first year) when sales become only 31% of their original value? Express your answer as a decimal, correct to within 0.001 years.
Answer:
The answer is "6.093 years".
Step-by-step explanation:
The rate of decline in sales in [tex]22\%[/tex] per year.
The starting sales is 100 units:
Using compounding formula:
[tex]\to 100 \times (1-\frac{22}{100})^t=22\% \ of \ 100\\\\\to 100 \times (\frac{100-22}{100})^t=\frac{22}{100} \times \ 100\\\\\to (\frac{78}{100})^t=\frac{22}{100}\\\\\to 0.78^t=0.22\\\\\text{taking \log on both the sides}\\\\[/tex]
taking log on both sides
[tex]\to \log_e \ 0.78^t= \log_e\ 0.22\\\\\to t \log_e \ 0.78= \log_e\ 0.22\\\\\to t = \frac{\log_e 0.22}{\log_e 0.78}\\\\[/tex]
[tex]= \frac{-0.6575}{-0.1079}\\\\= \frac{0.6575}{0.1079}\\\\=6.093[/tex]
Find the value of x. Write it as a decimal.
Answer:
68.5
Step-by-step explanation:
Arc ABE = 360 - 2x
Arc AE = 2x
half the difference between the two arcs is 43
43 = [tex]\frac{1}{2}[/tex] [360 -2x - (2x)]
the solution of the quadratic equation x square - 4 x + 4
Answer:
[tex]\rm x = 2 , 2 [/tex]
Step-by-step explanation:
A quadratic equation is given to us and we need to find the solution of the equation. The given equation is ,
[tex]\implies x^2 -4x + 4 = 0 [/tex]
Now for finding the roots of the equation , let's use the quadratic formula , or by factorising out the equation . Here I would be using the factorization method , as ,
[tex]\implies x^2 -4x + 4 = 0\\\\\implies x^2-2x-2x+4 = 0 \\\\\implies x(x-2) -2(x-2) = 0 \\\\\implies (x-2)(x-2) = 0 \\\\\implies x = 2, 2 [/tex]
Hence the Solution of the equation is 2,2.
Answer:
Step-by-step explanation:
x² - 4x +4 = 0
Factorization method:
Sum = -4
Product = 4
Factor = (-2) ; (-2) {-2 * -2 = 4 & (-2) + (-2) = -4}
x² -4x + 4 = 0
x² - 2x - 2x + (-2)*(-2) = 0
x(x - 2) - 2 (x - 2) = 0
(x - 2) (x - 2) = 0
x - 2 = 0 or x -2 = 0
x = 2 or x = 2
x = 2 , 2
write an expression for 8 less than 2 times a number
show your work
Answer:
Step-by-step explanation:
Let's call the number x. The statement "...2 times a number" if the number is x looks like this:
2x
"8 less than" that looks like this:
... - 8
Putting the whole thing together:
2x - 8
A petting zoo gives out large buckets of healthy popcorn snacks for visitors to feed to the animals. what fraction of the snack is left in the bucket after a cow eats 1/3, a goose eats 1/12, and a goat eats 2/9?
Answer:
13/36 is left
Step-by-step explanation:
cow- 1/3 = 12/36
goose- 1/12 = 3/36
goat= 2/9 = 8/36
12 + 3 + 8 = 23/36
23/36 is consumed...
13/36 is left
The fraction of the snack left in the bucket will be 13/36.
What is a fraction?The fraction is defined as the division of the whole part into an equal number of parts.
Given that:
cow- 1/3 = 12/36goose- 1/12 = 3/36goat= 2/9 = 8/36The amount consumed is:-
( 12/ 36 )+ (3 / 36 ) +( 8 / 36 ) = 23/36
So the amount left will be calculated as:-
Amount left = 1 - ( 23 / 36 )
Amount left = ( 36 - 23 ) / 36
Amount left = 13 / 36
Therefore fraction of the snack left in the bucket will be 13/36.
To know more about fractions follow
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factorise the following. x²-4
(x-2)(x+2) is factorize is given eq
Solve 4x + 11 = k for x.
O A. x= -11
O B. x=-11
O C. x = 4k - 44
D. x= k-7
Answer:
4x + 11 = k
<=> 4x = k - 11
<=>
[tex]x = \frac{k - 11}{4} [/tex]
Someone be generous & help me please I’ll return the favor
Answer:
Step-by-step explanation:
Al sumar y/o restar números decimales, siempre se debe aplicar la norma de los signos. * 1 punto FALSO VERDADERO
Answer:
La norma de los signos es para el producto de números reales, y la norma es la siguiente.
(+)*(+) = (+)
(+)*(-) = (-)
(-)*(+) = (-)
(-)*(-) = (+)
Es decir, el producto de dos números de mismo signo es siempre positivo
El producto de dos números de distinto signo es siempre negativo.
Particularmente, para la suma esta norma no funciona (pues no está definida para la suma)
Pero en casos como:
5 - (-4)
(esto sería: "la diferencia entre cinco y menos cuatro")
notar que podemos reescribir esto como:
5 + (-1)*(-4)
Ahora podemos aplicar la norma de los signos:
5 + 4 = 9
Donde aplicamos la norma de los signos,
Podemos concluir que, si bien es una regla que aplica al producto, siempre la tenemos que tener en cuenta en cualquier operación que hagamos.
Por lo podemos concluir que la respuesta correcta es verdadero.
I really need help, pls help. :)
Which properties justify the steps taken to solve the system?
{2x−4y=−63x+2y=−1
Drag and drop the answers into the boxes to match each step.
Answer:
Step-by-step explanation:
1). 6x - 12y = -18
6x + 4y = -2
Multiplication property of equality.
2). -16y = -16
Substitution property of equality.
3). y = 1
Division property of equality.
4). 2x - 4(1) = -6
Substitution property of equality.
5). 2x - 4 = -6
Simplify.
6). 2x = -2
Addition property of equality
7). x = -1
Division property of equality
Find the measure of each numbered angle for each figure
Answer:
Angle 1 is 58. Angle 2 is 32.
Step-by-step explanation:
The measure of Angle ACB is 90 because C is on the circle and A and B connect to form a diameter of the circle. So, Angle 1 and Angle 2 add up to 90 (total degrees in triangle - 90). Now you can add the expressions the question gave for Angle 1 and Angle 2, and you get 7x + 6. So you have the equation 7x + 6 = 90. Solve the equation and you get x = 12. Now you can plug in that value for x into the expressions for Angles 1 and 2 to find their measures.
hello! I'm having a bit of trouble trying to solve this, could anyone help explain it to me?
[tex]\displaystyle\ 60^2 =36(36+x)\\\\1296+36x=3600\\\\36x=2304\\\\\boxed{x=64}[/tex]
Step By Step Explanation:
[tex] {60}^{2} = 36(36 + x)[/tex]Step 1Calculate 60 to the power of 2 and get 3600.
[tex]3600 = 36(36 + x)[/tex]Step 2Use the distributive property to multiply 36 by 36 + ×.
[tex]3600 = 1296 + 36 \times [/tex]Step 3Swap sides so the all variable terms are on the left hand side.
[tex]1296 + 36 \times = 3600[/tex]Step 4Subtract 1296 from both sides.
[tex]36 \times = 3600 - 1296[/tex]Step 5Subtract 1296 from 3600 to get 2304.
[tex]36 x = 2304[/tex]Step 6Divide both side by 36.
[tex] \times = \frac{2304}{36} [/tex]Step 7Divide 2304 by 36 to get 64
My Answer is
[tex]\color{GREEN} \times = 64[/tex]Simple percent question!!!!
My question says that line segment DC is 50% longer than line segment BD, and BD is 40 ft. Does that mean DC is 60 ft or 80? Please explain, brainliest to whoever explains it properly and quickly
Answer:
60ft
Step-by-step explanation:
DC is 50% longer than BD (given)
BD is 40ft (given)
DC is 50% longer than BD this means that DC= BD+50% of BD
40ft +50/100 * 40
=40ft +20ft
=60ft
Another way to solve this could be DC is 150%of BD as BD =40ft=100% of it's length.
So, 150/100 *40
=60ft
Hope this helps.
Please mark me as brainliest.
3 miles. 128 yards. Converted to feet
Someone tell me where everyone is going right please !!
For the 1st picture,
[tex]2(3x - 1) \geqslant 4x - 6[/tex]
[tex]6x - 2 \geqslant 4x - 6[/tex]
[tex] - 2 \geqslant - 2x - 6[/tex]
[tex]4 \geqslant - 2x[/tex]
[tex]x \geqslant - 2[/tex]
This means x has to be greater than -2 so -1 is the answer.
For the 2nd picture the answer is -10.
For the 3rd picture, the answer is the first three options.
For the 4th picture, the answer is the 3rd option.
again again again again again again again hello or merhaba dude
merhaba = hello
answers are at the photos
GOOD LUCK:D
greetings from Turkey (≧▽≦)
The equation of line r is y = 1/2 * x + 1 line runs parallel to line r and passes through (2, 5) what would be the equation of line 8 ?help please
Answer:
x - 2y + 8 = 0
Step-by-step explanation:
that is the procedure above
One packet of biscuits requires 2 15/16 and 1 7/8 cups of sugar. Estimated total quantity of both ingredients used in 10 such packets of biscuits will be?
Answer:
Hey Mate! Here's your answer.
Step-by-step explanation:
One packet of biscuits requires 2½ cups of flour = \frac{5}{2}25
One packet of biscuits requires 1 \times \frac{2}{3}1×32
One packet of biscuits requires 1 \times \frac{2}{3}1×32cups of sugar. = \frac{5}{3}35
Total ingradiants for one packet of biscuits =
Total ingradiants for one packet of biscuits =( \frac{5}{2} + \frac{5}{3} ) = \frac{15 + 10}{6} = \frac{25}{6}(25+35)=615+10=625
Then, total quantity of both ingredients used in 10 such packets of biscuits =
Then, total quantity of both ingredients used in 10 such packets of biscuits =10 \times ( \frac{25}{6} ) = 5 \times ( \frac{25}{3} ) = \frac{125}{3} = 41 \times \frac{2}{3}10×(625)=5×(325)=3125=41×32
Hope it helped you!
Mrs. Nygaard needs 12 hours to grade all of her students’ projects. She made a chart to show how much time she could spend grading the projects during the week. Project Grading Day Hours Grading Monday 1 and three-fourths Tuesday 1 and one-half Wednesday 1 and one-fifth Thursday 2 Friday 1 and one-fourth How many hours will Mrs. Nygaard need to work over the weekend to finish grading the projects? 1 and three-fifths hours 4 and StartFraction 3 over 10 EndFraction hours 6 and one-half hours 19 and StartFraction 7 over 10 EndFraction hours
Answer:
B
Step-by-step explanation:
Option B is correct, 4 and 3/10 hours will Mrs. Nygaard need to work over the weekend to finish grading the projects.
What is Fraction?A fraction represents a part of a whole.
To find the total amount of time Mrs. Nygaard has available during the week to grade projects, we need to add up the hours for each day:
1 and three-fourths + 1 and one-half + 1 and one-fifth + 2 + 1 and one-fourth = 7 and five-tenths hours
This means that Mrs. Nygaard has 7.5 hours during the week to grade projects.
If she needs 12 hours to grade all the projects, then she will need to work for an additional:
12 - 7.5 = 4.5 hours over the weekend to finish grading the projects.
Therefore, 4 and 3/10 hours required to Mrs. Nygaard need to work over the weekend to finish grading the projects.
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For every quarter in his pocket, John also has 5 pennies in his pocket. If the total of the coins in John’s pocket is $ 5.40, how many quarters does John have in his pocket.
If a student receives a score of 80, how many questions did this student answer ... (5). Let x = the first number, and y = the second number ... If John only has 25 coins in his pocket, how many of the coins are quarters?
Question 4 of 10
Which describes the graph of y=-(x - 3)^2 + 2?
O A. Vertex at (-3,2)
O B. Vertex at (3,-2)
C. Vertex at (3,2)
O D. Vertex at (-3,-2)
Answer:Vertex at (3, -2)
Step-by-step explanation:
helpppppppppppppppp//////////////////////////////////////////
Answer:
m(x)
Step-by-step explanation:
please help guys !!!
Answer:
[tex] \frac{1}{4} \: \: \: \frac{1}{3} \: \: \: \frac{1}{2} \: \: \: \frac{7}{12} \: \: \: \frac{3}{4} [/tex]
Step-by-step explanation:
To arrange in ascending order, first make the denominators of all the fractions the same.
LCM of 2, 3, 4 and 12 is 12.
Now,
[tex] \frac{1}{3} = \frac{4}{12} [/tex]
[tex] \frac{3}{4} = \frac{9}{12} [/tex]
[tex] \frac{1}{4} = \frac{3}{12} [/tex]
[tex] \frac{7}{12} \: \: will \: be \: \: \frac{7}{12} [/tex]
[tex] \frac{1}{2} = \frac{6}{12} [/tex]
Arranging these in ascending order:
[tex] \frac{3}{12} \: \: \: \frac{4}{12} \: \: \: \frac{6}{12} \: \: \: \frac{7}{12} \: \: \: \frac{9}{12} [/tex]
