The radius of a cylinder of volume 2970cm³ is 30mm. Find the volume of a similar cylinder of radius 40mm.

Answers

Answer 1

34.3 cm3

if you use formula    

30mm 2970cm3

x-x un^3


Related Questions

can you reduce 18/35 if so what is the answer?

Answers

The fraction 1835 is already in the simplest form so it isn't possible to reduce it any further So nah u can’t do nothing to it

Answer: 0.514285714286 ≈

Step-by-step explanation: 18/35 is already in the simplest form. It can be written as 0.514286 in decimal form

plz any one here to follow me plz tellme any one ?​

Answers

I’ll follow you, but on what?



ig?
No hjjjjghk punctuating

Find the volume of the composite figure

Answers

Answer:

540m^3

Step-by-step explanation:

find volume of top + volume of bottom

bottom: l*w*h = 16*5*4 =300 m^3

top = area of side times width = area of triangle times width

area of triangle is 1/2*b*h = (6*16)/2 = 48 m^2

multiply by width = 48*5=240m^3

add top and bottom = 300+240=540m^3

What is another word for zeros?​

Answers

Answer:

nothing

Step-by-step explanation:

Zero is a number without a value so nothing could be another word for it

Another word for zeros is null

75 mm
a
60 mm
What is the length of the missing leg?

Answers

Answer:

a = 45 millimeters

Step-by-step explanation:

In order to solve this, we need to know that for right-angled triangles the following is true:

[tex]c^{2} = a^{2} + b^{2}[/tex] (where c is the hypotenuse and "a" and "b" are the legs)

From the formula above we can conlude that...

[tex]a = \sqrt{c^{2} - b^{2} }[/tex]

Now we just substitute the variable that we know and get that...

[tex]a = \sqrt{c^{2} - b^{2} }\\a = \sqrt{75^{2} - 60^{2} } \\a = \sqrt{5,625 - 3600} \\a = \sqrt{2025} \\a = 45[/tex]

Therefore a = 45millimeters.

Please help I’ll give brainliest

Answers

Answer:

- a + 18b

Step-by-step explanation:

2(a + 6b) - 3(a - 2b)

= 2a + 12b - 3a + 6b

= 2a - 3a + 12b + 6b

= - a + 18b (Ans)

Answer:

-a + 18b

Step-by-step explanation:

2(a + 6b) - 3(a - 2b)

Distribute the 2

2a + 12b - 3(a - 2b)

Distribute the 3

2a + 12b - 3a + 6b

Combine like terms

-a + 18b

Someone pls pls pls solve this!!!!!!! And pls explain how u solved it. I need this due rn ASAP!!!

Answers

35°..

can also be 145° but not in this case since the angle is less than 90°

A ride-share company has a fee that includes a fixed cost and a cost that depends on both the time spent travelling, in minutes, and the distance travelled, in kilometres. The fixed cost of a ride is $2.55 Judy's ride costs $16.75 and took eight minutes. The distance travelled was 10 km. Pat's ride cost $30.35 and took 20 minutes. The distance travelled was 18 km. Roy's ride took 10 minutes. The distance travelled was 15 km. Find the cost of Roy's ride.

Answers

Answer:

the cost of Roy's ride is $23.05

Step-by-step explanation:

According to the Question,

Let, Cost of per minute charge is 'x' & Cost Of Per Kilometre charge is y .

Given, A ride-share company has a fee of the fixed cost of a ride is $2.55 .And, The Total cost of the Ride depends on both the time spent on travelling(in minutes), and the distance travelled(in kilometres) .

⇒ Judy's ride costs $16.75 . but the actual cost after deducting the fixed charge is 16.75-2.55 = $14.20, took 8 minutes & The distance travelled was 10 km. Thus, the equation for the journey is 8x+10y=14.20 ⇒ Equ. 1

⇒ Pat's ride costs $30.35 . but the actual cost after deducting the fixed charge is 30.35-2.55 = $27.80, took 20 minutes & The distance travelled was 18 km. Thus, the equation for the journey is 20x+18y=27.80 ⇒ Equ. 2

Now, on Solving Equation 1 & 2, We get

x=0.4(Cost of per minute charge) & y=1.1(Cost Of Per Kilometre charge)

Now, Roy's ride took 10 minutes & The distance travelled was 15 km . Thus, the cost of Roy's Ride is 10x+15y ⇔ 10×0.4 + 15×1.1 ⇔ $20.5

Hence, the total cost of Roy's ride is 20.5 + 2.55(fixed cost) = $23.05

What is an equation of the line that is perpendicular to 3z +y=-5 and passes through the point (3, – 7)?
Enter your equation in the box

Answers

The answer is
y=1/3 x - 8

A partial listing of monthly startup costs for a store includes $2,750 for rent, $479 for electricity, $217 for telephone and Internet service, $9,423 for employee salaries, $250 for cleaning service, and $100 for supplies. What percent of your monthly startup cost is rent?

Answers

Answer:

I think it is 20.8%

Step-by-step explanation:

The percentage of rent in the monthly startup cost is 20.8%

What is percentage?

A part of a whole expressed in hundredths. In percentage we equate the total with hundred and find the sum.

The formula of percentage is (Y/X)×100 = P%, where "X" is total , "Y" is the individual number of which we want to find the percentage and "P" is the percentage value.

According to the formula,

X ⇒ $2,750 + $479 + $217 + $9,423 +  $250 + $100 = $13,219

Y = $2,750

P = (Y/X)×100

2750/13219 =0.20803

0.20803×100=20.80%

Thus the percentage of the rent in the total monthly startup cost is 20.80%

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4g+1 5 − G−7 4 = 2g−5 10

Answers

The answer is g=-7 hope it helps

You have $9 and earn $0.75 for each cup of orange juice you sell. Write an equation that represents the total amount $A​ (in dollars) you have after selling $j​ cups of orange juice. $A

Answers

Answer:

I believe it's   A = 0.75j + 9

Step-by-step explanation:

If x or j is the amount of cups of OJ you sell, and you earn $0.75 per cup.

0.75x

The b = 9 which adds to the total amount of money you have

0.75x+9

A is the total money you earn after you sell j cups.

I hope this helps!

Classify the triangle by its angle and sides

Answers

Answer:

Right Triangle

Step-by-step explanation:

It has a 90 degree angle

What are the domain, range, and asymptote of h(x)=2x+4

Answers

Step-by-step explanation:

Domain = x € the real Numbers

Range = y € the real Numbers

No asymptotes

Brenya Estate produces a high quality tea branded Super by blending three types of tea coded A, B and C in the ration 1: 5:1. Originally Type A tea costs GHS 1,600 type B costs GHS 800 and type C costs GHS 1,700 per kg to produce. Brenya Tea Estate packs Super tea in packets of 825g each. Blending and packing costs are 40 per kg. Determine the production cost for a packet of Super tea,

Answers

Solution :

Cost of 1 kg super tea mixture

[tex]$=\frac{1(1600)+5(800)+1(1700)}{1+5+1}$[/tex]

[tex]$=\frac{1600+4000+1700}{7}$[/tex]

[tex]$=\frac{7300}{7}$[/tex]

= 1042.8

≈ 1043

Include of cost blending and packaging.

So, cost of 1 kg is 1043 + 40 = 1083

Cost of packaging of 825 gram super tea = [tex]$\frac{825}{1000} \times 1083$[/tex]

                                                                     = 893.47

The price of a technology stock has risen to $9.66 today. Yesterday's price was $9.59. Find the percentage increase. Round your answer to the nearest tenth of a percent.

Answers

Answer:

% increase = 100 x [(new price) - (original price)] / (original price)] = 100 (9.67 - 9.56) / 9.56

% increase ≅ 1.2% (to the nearest tenth)

Find x in circle O. Figure is not drawn to scale. HURRY PLEASE

Answers

Answer:

B. 23,5

Step-by-step explanation:

why do bank charge transaction fees ?​

Answers

Answer:

To make a profit of course

Step-by-step explanation:

it

then

yes

Possibly.

help plzzzzzzzzzzzzzzzzzzzzz

Answers

I believe it’s B but I could be wrong

Given three points A(-7, 1), B(m, 6) and P(-1, n). If the point P divides AB internally in the ratio of 3: 2, find the values of m and n.​

Answers

Answer:

m = 3 , n = 4

Step-by-step explanation:

Using Section Formula.

[tex]If \ the \ line \ segment \ AB \ where \ A = (x _1, y_1) \ and \ B = (x_2, y_2) \ divided \ by \ P =(x , y) \ in \ the \ ratio \ a : b,\\\\Then \ the \ points \ of \ P \ \\\\x = \frac{ax_2 + bx_1}{a+b} \ and \ y = \frac{ay_2 + by_1}{a+b}[/tex]

   [tex]Here (x_1 , y_ 1 ) = ( -7 , 1 ) \ and \ (x_ 2 , y _ 2 ) = (m , 6)\\\\ratio\ a:b = 3 : 2\\\\Therefore, P (x, y) \\\\x = \frac{3m + (2\times -7)}{5} \ \ \ \ \ \ \ \ \ \ \ [ \ x = -1 \ ] \\\\-1 = \frac{3m - 14}{5}\\\\- 5 = 3m - 14\\\\-5 + 14 = 3m\\\\9 = 3m \\\\m = 3[/tex]

  [tex]y =\frac{3\times 6 + 2 \times 1}{5}\\\\n = \frac{18 + 2}{5} = \frac{20}{5} = 4[/tex]

Determine the value of a so that x1-3x3=-3 2x1+ax2-x3=-2 (i)unique solution(ii)no solution(iii)many solutions

Answers

Answer:

(i)unique solution

Explanation:

We solve for x1 thus in the first equation:

x1-3x3=-3

x1-9=-3

x1=-3+9

x1= 6

We solve for a thus in the second equation:

2x1+ax2-x3=-2

2+a2-x3=-2

a2-x3=-4

a2=-4+x3

What is the highest common factor of 65 and 56?

Answers

Highest common factor of 56&65 is 1

Question 2 of 10
A rectangle's width is 5 feet less than its length. Write a quadratic function
that expresses the rectangle's area in terms of its length.
O A. A(1) = lw
B. A(1)=12 + 51
C. All) = w(w+5)
O D. All) = 12 - 51

A rectangle's width is 5 feet less than its length. Write a quadratic function
that expresses the rectangle's area in terms of its length.
O A. A(1) = lw
B. A(1)=12 + 51
C. All) = w(w+5)
O D. All) = 12 - 51

Answers

I don’t know if you meant to post the same question twice but the answer is C

Given(a*b)*c=a*(b*c) what property does this represent

Answers

Answer:

The associative property allows us to change groupings of addition or multiplication and keep the same value. (a+b)+c = a+(b+c) and (a*b)*c = a*(b*c).

Step-by-step explanation:

in mathematics, either of two laws relating to number operations of addition and multiplication, stated symbolically: a + (b + c) = (a + b) + c, and a(bc) = (ab)c; that is, the terms or factors may be associated in any way desired.

Answer:

Associative

Step-by-step explanation:

The points A, B, C and D lie on a circle centre O.
Angle AOB = 90° angle COD= 50° and angle BCD= 1239
The line DT is a tangent to the circle at D.
Find
(a) angle OCD

Answers

A I think is the answer

The measure of angle OCD from the given figure is 58°.

Given that, the points A, B, C and D lie on a circle Centre O.

What is the circle?

A circle is a two-dimensional figure formed by a set of points that are at a constant or at a fixed distance (radius) from a fixed point (center) on the plane. The fixed point is called the origin or center of the circle and the fixed distance of the points from the origin is called the radius.

Here, OC and OB are radius of a circle, then BOC is isosceles triangle

Now, ∠BOC+∠OBC+∠OCB=180°

50°+∠OBC+∠OBC=180°

⇒ 2∠OBC=130°

⇒ ∠OBC=65°

Here, ∠OCD=∠BCD-65°

⇒ x=123-65=58°

Hence, the measure of angle OCD from the given figure is 58°.

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A trained stunt diver is diving off a platform that is 15 m high into a pool of water that is 45 cm deep. The height, h, in meters, of the stunt diver above the water, is modeled by h=-4.9t^2+12t+5, where t is the time in seconds after starting the dive.

a) How long is the stunt diver above 15 m?

b) How long is the stunt diver in the air?

Answers

Answer:

a) 0 seconds.

b) The stunt diver is in the air for 2.81 seconds.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]

[tex]\Delta = b^{2} - 4ac[/tex]

Height of the diver after t seconds:

[tex]h(t) = -4.9t^2 + 12t + 5[/tex]

a) How long is the stunt diver above 15 m?

Quadratic equation with [tex]a < 0[/tex], so the parabola is concave down, and it will be above 15m between the two roots that we found for [tex]h(t) = 15[/tex]. So

[tex]h(t) = -4.9t^2 + 12t + 5[/tex]

[tex]15 = -4.9t^2 + 12t + 5[/tex]

[tex]-4.9t^2 + 12t - 10 = 0[/tex]

Quadratic equation with [tex]a = -4.9, b = 12, c = -10[/tex]. Then

[tex]\Delta = 12^{2} - 4(-4.9)(-10) = -52[/tex]

Negative [tex]\Delta[/tex], which means that the stunt diver is never above 15m, so 0 seconds.

b) How long is the stunt diver in the air?

We have to find how long it takes for the diver to hit the ground, that is, t for which [tex]h(t) = 0[/tex]. So

[tex]h(t) = -4.9t^2 + 12t + 5[/tex]

[tex]0 = -4.9t^2 + 12t + 5[/tex]

[tex]-4.9t^2 + 12t + 5 = 0[/tex]

Quadratic equation with [tex]a = -4.9, b = 12, c = 5[/tex]. Then

[tex]\Delta = 12^{2} - 4(-4.9)(5) = 242[/tex]

[tex]x_{1} = \frac{-12 + \sqrt{242}}{2*(-4.9)} = -0.36[/tex]

[tex]x_{2} = \frac{-12 - \sqrt{242}}{2*(4.9)} = 2.81[/tex]

Time is a positive measure, so we take 2.81.

The stunt diver is in the air for 2.81 seconds.

Can someone explain to me how this is wrong at all? I did the math like 10 times and somehow its wrong...? please lmk what the actual answer is because apparently im just incompetent

Also giving Brainliest

Answers

Answer:

total= 98

Step-by-step explanation:

so the way to do this is to find the total surface area of the white bench and then subtract the interfacing portion for the support, and then total surface area of support and also subract the area of the interface with the white as well as the ground

bench top area

area of long side *number of sides + area of end *number of ends

(9*2)*4+(2*2)*2= 72+8=80

interface area is area of long side of red portion

5*2=10

support area is same as bench top for rationale

(5*2)*4+(2*2)=40+8=44

total surface area = area of white + area of red - 2* interface area - bottom of red that interfaces with the ground

total = 80+48-2*10-(5*2)

total = 128-20-10

total= 98

Water is being drained at a constant rate from a tank.
It contains 1000 gallons of water.
After 10 minutes there are 940 gallons of water remaining in the tank.
How much water remained in the tank after 5 minutes?
20 minutes?
30 minutes?
27 minutes?
X minutes?
What is the rate of flow of the water from the tank?
Organize your work to help you answer the questions,

Answers

Answer:

Step-by-step explanation:

1000 gallons - 940 = 60 then divide by the time which gets us 60/10=6

Now we can use this answer to help find out the amount remaining in the tank.

5 minutes = 5x6=30; 1000-30= 970 gallons

20 minutes= 20x6=120; 1000-120= 880 gallons

30 minutes=30x6=180; 1000-180= 820 gallons

27 minutes=27x6=162; 1000-162= 838 gallons

X minutes = 1000-6x

Rate of flow is 6 gallons per minute.

Hope this helps!

Jen's class 10 girls and 15 boys. The ratio of girls to boys in Ed's class is the same as the ratio of girls to boys in Jen's class. There are 24 boys in Ed's class. How many girls are in Ed's class?

Answers

Answer:

16

Step-by-step explanation:

Jen's class: 10 girls, 15 boys

ratio of girls to boys = 10:15 = 2:3 = 2x:3x

Ed's class

number of boys = 24

ratio of girls to boys = 2x:3x

3x = 24

x = 8

2x = 2(8) = 16

Answer: 16

Answer:

16

Step-by-step explanation:

If Albert owns x model airplanes and Maxim owns x + 13 model airplanes, then Albert and Maxim own___ model airplanes together. Albert owns ___ less model airplanes than Maxim.

Answers

Answer:

2x + 13

13

Step-by-step explanation:

Albert and Maxim own

x + (x + 13) = 2x + 13 model airplanes together

Albert owns

(x + 13) - x = 13 less model airplanes than Maxim.

Answer:

They own 2x+13 model airplanes together

Albert owns 13 less model airplanes than Maxim

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