Answer:
f(n) = 0.15n + 0.35Step-by-step explanation:
The sequence of the problem above is an arithmetic sequence
For an nth term in an arithmetic sequence
F(n) = a + ( n - 1)d
where a is the first term
n is the number of terms
d is the common difference
To find the equation first find the common difference
0.65 - 0.5 = 0.15 or 0.80 - 0.65 = 0.15
The first term is 0.5
Substitute the values into the above formula
That's
f(n) = 0.5 + (n - 1)0.15
f(n) = 0.5 + 0.15n - 0.15
The final answer is
f(n) = 0.15n + 0.35Hope this helps you
Answer:
The correct option is: f(n) = 0.15n + 0.35Step-by-step explanation:
Took the math test on edge
An oblique cylinder is shown.
An oblique cylinder is shown. It has a radius of 5, a height of 12, and a slant length of 13.
Which represents the volume of the cylinder, in cubic units?
120π
130π
300π
325π
Answer:
The volume in terms of Pi is 300πStep-by-step explanation:
This problem is on the mensuration of solid shapes, an oblique cylinder.
the expression for the volume of an oblique cylinder is given as
[tex]volume= \pi r^2h[/tex]
Given data
radius r= 5
height h= 12, and
slant length of 13.
Substituting the given data into the expression we can solve for the volume below
[tex]volume= \pi* 5^2*12\\\ volume= \pi*25*12\\\ volume= \pi*300\\\ volume= 300\pi[/tex]
Answer:
300
Step-by-step explanation:
Please help with this, thanks
Answer:
BDC is half of mBC = 11°
Easily you see that C is A + BDC = 23°
Since C = 23° so mDC is twice = 46°
x
Heidi bought a machine that throws tennis balls for her dog to fetch. The height of each ball thrown by the machine, in feet, is modeled by the function f(x) = –x2 + x + 2, where x represents time in seconds. How many seconds after the machine throws the ball does it hit the ground?
Answer:
2 seconds
Step-by-step explanation:
Given the equation:
[tex]f(x) = -x^2 + x + 2[/tex]
Where f(x) represents the height of each ball thrown by machine.
and x represents the time in seconds.
To find:
The number of seconds after which the machine throws the balls hits the ground = ?
Solution:
In other words, we have to find the value of [tex]x[/tex] after which the [tex]f(x) = 0[/tex]
(Because when the ball hits the ground, the height becomes 0).
Let us put [tex]f(x) = 0[/tex] and solve for [tex]x[/tex]
[tex]f(x) = -x^2 + x + 2 =0\\\Rightarrow -x^2 + x + 2 =0\\\Rightarrow x^2 - x - 2 =0\\\Rightarrow x^2 - 2x+x - 2 =0\\\Rightarrow x(x - 2)+1(x - 2) =0\\\Rightarrow (x+1)(x - 2) =0\\\Rightarrow x =-1, 2[/tex]
[tex]x=-1[/tex] sec is not a valid answer because time can not be negative.
So, the answer is after 2 seconds, the ball hits the ground.
If m2 DOC = 44º and m2 COB = 80°,
find the measure of the indicated arc in circle 0.
Find measure of arc DC.
Answer:
44°
Step-by-step explanation:
Given:
m<DOC = 44°
m<COB = 80°
Required:
Angle measure of arc DC
SOLUTION:
A central angle is said to be equal to the angle measure of the arc it intercepts or corresponds with. Therefore, angle measure of arc DC = m<DOC.
measure of arc DC = 44°
1. Determine whether the given procedure results in a binomial distribution. If not, state the reason why.
Rolling a single die 53 times, keeping track of the "fives" rolled.
A) Not binomial: there are too many trials.
B) Not binomial: there are more than two outcomes for each trial.
C) Not binomial: the trials are not independent.
D) Procedure results in a binomial distribution.
2. Determine whether the given procedure results in a binomial distribution. If not, state the reason why.
Spinning a roulette wheel 7 times, keeping track of the winning numbers.
A) Not binomial: there are more than two outcomes for each trial.
B) Procedure results in a binomial distribution.
C) Not binomial: there are too many trials.
D) Not binomial: the trials are not independent.
1. Not binomial: there are more than two outcomes for each trial.
Thus, option (B) is correct.
2. Procedure results in a binomial distribution.
Thus, option (B) is correct.
1. Not binomial: there are more than two outcomes for each trial.
In a binomial distribution, each trial can have only two outcomes (usually referred to as success and failure).
In this case, the procedure involves rolling a single die 53 times and keeping track of the "fives" rolled.
Since the outcome can be any number from 1 to 6 on each trial, it does not meet the criteria for a binomial distribution.
Thus, option (B) is correct.
2. Procedure results in a binomial distribution.
In this case, the procedure involves spinning a roulette wheel 7 times and keeping track of the winning numbers. The outcome of each trial is either a win or a loss, which satisfies the requirement for a binomial distribution.
Thus, option (B) is correct.
Learn more about Binomial Distribution here:
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Hi people, Please if someone can give me a hand, l already have done the first part of the exercise, but l cant make Angle CAB= X^0 c) calculate the lower bound for the value of tan X^0 there is the answer 1.02 (2dp) but l have no clue how to get it thanks i used Toa (Tan = Opp/ adj) but l couldnt find it thanks
Answer:
(c) 1.02
Step-by-step explanation:
(c) The tangent is the ratio of Opposite to Adjacent. Its lowest value will be found where Opposite is lowest, and Adjacent is highest:
min tan(A) = (min BC)/(max AB) = 75/73.5 ≈ 1.020408...(42-digit repeat)
X2 + (y - 1) 2 = 4 .............................
Answer:
Step-by-step explanation:
x²+(y-1)²=4
x²+y²+1-2y=4
x²+y²-2y=3
Answer:
[tex]x=\pm \sqrt{6-2y}[/tex]
[tex]$y=\frac{1}{2} (6-x^2)$[/tex]
Step-by-step explanation:
[tex]x^2+(y-1)\cdot 2 =4[/tex]
[tex]x^2+2y-2 =4[/tex]
[tex]x^2+2y =6[/tex]
I will solve it for [tex]x[/tex]
[tex]x^2 =6-2y[/tex]
[tex]x=\pm \sqrt{6-2y}[/tex]
Solving for [tex]y[/tex]
[tex]$y=3-\frac{x^2}{2} $[/tex]
[tex]$y=\frac{1}{2} (6-x^2)$[/tex]
there was a total of 400 oranges and mangoes at a fruit stall.3/8 of these fruits were mangoes.each orange was priced at 40 cents,and each mango was priced at 60 cents.how much would mr.mead make if he sold 2/3 of the mangoes and 4/5 of the oranges?
Answer:
First find the number of Mango and oranges. 400 divided by 8 = 50. We use 8 because it is the whole part of the percentage. Since, there is 3/8 mangoes, multiply 50* 3= 150 mangoes and 50*5= 250 oranges.
2/3 of 150=100 mangoes. You would find this by dividing 150/3=50 then multiply by 2.
4/5 of 250= 200 oranges. You would find this by dividing 250/5=50 then multiply by 4.
$.40*100= $40.00 mangoes
$.60*200= $120.00 oranges
Mr. Mead would make $160.00
Step-by-step explanation:
state crunchy theorem
Answer: it says that if two different paths connect the same two points.
Step-by-step explanation:
It says that is two different paths connect the same two points, and a function holomorphic everywhere in between the two paths, then the two path integrals of the functions will be same.
i will rate you branliest
Answer:
a₃ = 9
Step-by-step explanation:
The numbers in the set are referred to as { a₁, a₂, a₃, ... }
Answer:
a3 = 9 is the answer to this questionIs math a feature of the universe or a feature of human creation?
Answer:
a feature of the universe
Step-by-step explanation:
Math is a feature of the universe because what we call math is just a way of explaining how things work.
PLLLEEEASSSSEEEE ANSWER FAST
The shape is based only on squares, semicircles, and quarter circles. Find the area of each shaded part.
Answer:
36.48 cm²
Step-by-step Explanation:
If you take a careful look at the figure given, you'd realise that the area of the shaded portion is actually created by 2 overlapping quarter circle.
The area of the shaded portion = Area of Square - Area of Unshaded part
Area of square = s² = 8² = 64 cm²
Area of the Unshaded portion = 2(Area of Square - Area of Quarter Circle)
= 2(s² - ¼*πr²)
Where, radius (r) = s = 8 cm, take π as 3.14
Area of unshaded part = 2(8² - ¼*3.14*8²)
= 2(64 - ¼*3.14*64)
= 2(64 - 1*3.14*16)
= 2(64 - 50.24)
= 2(13.76)
Area of unshaded part = 27.52 cm²
Area of shaded part = Area of Square - Area of Unshaded part
Area of shaded part = 64 - 27.52 = 36.48 cm²
Identify the sample space in the following tree diagram
A.) H, T
B.) TTT, TTH, THT, THH, HTT, HTH, HHT, HHH
C.) HHH, THH, TTH, TTT
D.) HT, TH, TT, HT
There are 2 sides per coin, and 3 flips, so 2^3 = 8 total items in the sample space
HHHHHTHTHTHHHTTTHTTTHTTTTracing each branch from left to right will help form the 8 different outcomes. For instance, if you go along the upper most path of the upper tree, then you'll get HHH meaning you got 3 heads in a row. The next branch down would be HHT, and so on.
what is 38.4 cm + 38.4 cm ???
Answer:
76.8 cm
Step-by-step explanation:
Answer:
76.8 cm
Step-by-step explanation:
38.4 cm + 38.4 cm = 76.8 cm
Foram prescritos 500mg de dipirona para uma criança com febre.Na unidade tem disponivel ampola de 1g/2ml.Quantos g vão ser administrados no paciente
De acordo com a disponibilidade da unidade, há apenas a seguinte dosagem: 1g/2mL - ou seja, uma grama de dipirona a cada 2mL
O enunciado está meio mal formulado, pois é dito que foram prescritos 500mg de dipirona e é essa quantidade de farmaco que a criança tem que tomar. Deseja-se saber quantos mL deverao ser administrados.
Fazendo a classica regra de 3, podemos chegar no volume desejado:
(atentar que 500mg = 0,5g)
g mL
1 --------- 2
0,5 --------- X
1 . X = 0,5 . 2
X = 1mLTransform the Cartesian (rectangular) equation to a polar equation: x = -9. The selected answer is incorrect.
Answer:
Solution : Option C
Step-by-step explanation:
We have the equations r² = x² + y², x = r cos(θ), and y = r sin(θ) that can be used to solve this problem. In this case we only need the second two equations ( x = r cos(θ), and y = r sin(θ) ) as we don't need to apply the concept of circles etc here.
Given : x = - 9,
( Substitute r cos(θ) for x )
r cos(θ) = - 9,
r = - 9 / cos(θ)
( Remember that sec is the reciprocal of cos(θ). Substitute sec for 1 / cos(θ) )
r = - 9 sec(θ)
Therefore the third option is the correct solution.
This test statistic leads to a decision to...
reject the null
accept the null
fail to reject the null
As such, the final conclusion is that...
There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 88.9.
There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 88.9.
The sample data support the claim that the population mean is not equal to 88.9.
There is not sufficient sample evidence to support the claim that the population mean is not equal to 88.9.
Answer:
There is not sufficient sample evidence to support the claim that the population mean is not equal to 88.9.
Step-by-step explanation:
We are given the following hypothesis below;
Let [tex]\mu[/tex] = population mean.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 88.9 {means that the population mean is equal to 88.9}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu\neq[/tex] 88.9 {means that the population mean is different from 88.9}
The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;
T.S. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean = 81.3
s = sample standard deviation = 13.4
n = sample size = 7
So, the test statistics = [tex]\frac{81.3-88.9}{\frac{13.4}{\sqrt{7} } }[/tex] ~ [tex]t_6[/tex]
= -1.501
The value of t-test statistics is -1.501.
Also, the P-value of the test statistics is given by;
P-value = P([tex]t_6[/tex] < -1.501) = 0.094
Since the P-value of our test statistics is more than the level of significance as 0.094 > 0.01, so we have insufficient evidence to reject our null hypothesis as the test statistics will not fall in the rejection region.
Therefore, we conclude that the population mean is equal to 88.9.
Nine students took the SAT. Their scores are listed below. Later on, they read a book on test preparation and retook the SAT. Their new scores are listed below. Test the claim that the book had no effect on their scores.Use α=0.05. Assume that the distribution is normally distributed. Student 1 2 3 4 5 6 7 8 9 Scores before reading book 72 0 86 0 850 88 0 86 0 710 85 0 1200 95 0 Scores after reading book 74 0 86 0 840 92 0 89 0 720 84 0 1240 97 0 Nine students took the SAT. Their scores are listed below. Later on, they read a book on test preparation and retook the SAT. Their new scores are listed below. Test the claim that the book had no effect on their scores. Use α = 0.05. Assume that the distribution is normally distributed. Student 1 2 3 4 5 6 7 8 9 Scores before reading book 72 0 86 0 850 88 0 86 0 710 85 0 1200 95 0 Scores after reading book 74 0 86 0 840 92 0 89 0 720 84 0 1240 97 0
Answer:
t= 0.4933
t ≥ t ( 0.025 ,8 ) = 2.306
Since the calculated value of t= 0.4933 is less than t ( 0.025 ,8 ) = 2.306 therefore we accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the book had no effect on their scores.
Step-by-step explanation:
We state our null and alternative hypotheses as
H0: ud= 0 Ha: ud≠0
The significance level is set at ∝= 0.05
The test statistic under H0 is
t= d`/ sd/√n
which has t distribution with n-1 degrees of freedom
The critical region is t ≥ t ( 0.025 ,8 ) = 2.306
Computations
Student Scores before Scores after Difference d²
reading book ( after minus before)
1 720 740 20 400
2 860 860 0 0
3 850 840 -10 100
4 880 920 40 1600
5 860 890 30 900
6 710 720 10 100
7 850 840 -10 100
8 1200 1240 40 1600
9 950 970 20 40
∑ 6930 8020 140 4840
d`= ∑d/n= 140/9= 15.566
sd²= 1/8( 4840- 140²/9) = 1/8 (4840 - 2177.778) = 2662.22/8= 332.775
sd= 18.2422
t= 3/ 18.2422/ √9
t= 0.4933
Since the calculated value of t= 0.4933 is less than t ( 0.025 ,8 ) = 2.306 therefore we accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the book had no effect on their scores.
If cot Theta = Two-thirds, what is the value of csc Theta? StartFraction StartRoot 13 EndRoot Over 3 EndFraction Three-halves StartFraction StartRoot 13 EndRoot Over 2 EndFraction Eleven-thirds
Answer:
csctheta= [tex]\frac{\sqrt{13} }{3}[/tex]
Step-by-step explanation:
answer is provided on top
The value of the [tex]\rm cosec \theta = \frac{\sqrt{13} }{3}[/tex]. Cosec is found as the ratio of the hypotenuse and the perpendicular.
What is trigonometry?The field of mathematics is concerned with the relationships between triangles' sides and angles, as well as the related functions of any angle
The given data in the problem is;
[tex]\rm cot \theta = \frac{2}{3}[/tex]
The [tex]cot \theta[/tex] is found as;
[tex]\rm cot \theta = \frac{B}{P} \\\\ \rm cot \theta = \frac{2}{3} \\\\ B=2 \\\\ P=3 \\\\[/tex]
From the phythogorous theorem;
[tex]\rm H=\sqrt{P^2+B^2} \\\\ \rm H=\sqrt{2^2+3^2} \\\\ H=\sqrt{13} \\\\[/tex]
The value of the cosec is found as;
[tex]\rm cosec \theta = \frac{H}{P} \\\ \rm cosec \theta = \frac{\sqrt{13} }{3}[/tex]
Hence the value of the [tex]\rm cosec \theta = \frac{\sqrt{13} }{3}[/tex].
To learn more about the trigonometry refer to the link;
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Kathleen ordered a box of different colored light bulbs to use for stage lighting at the concert. Of the 60 bulbs in the box, 20% were red, 30% were orange, 30% were green, and 20% were blue. Of the blue ones, approximately 10% were damaged. What is the closest estimate for the number of blue bulbs that were damaged?
Answer:
1 bulb
Step-by-step explanation:
First find the number of blue bulbs
60 * 20 %
60 * .2
12 blue bulbs
10 % of the blue were damaged
12 * 10%
12 * .10
1.2
Rounding to the nearest whole number
1 bulb
help please I need help :(
A = 1 and 8
B = 2 and 4
C = 2 and 7
I’m pretty sure this is right? I’m still learning too :p
=======================================================
Explanations:
For the sake of simplicity, imagine that lines m and n are parallel. They don't necessarily need to be in order to answer this problem, but it might help with the terminology better.
When we use the term "interior" we basically mean the region between or inside the parallel lines. So "exterior" is everything but that, which is composed of two separate regions that don't overlap. Exterior angles shown in this diagram are
angle 1, angle 5, angle 4, angle 8
The "alternate" refers to the idea that we're on alternate sides of the transversal cutting line. One pair of alternate exterior angles is angle 1 and angle 8. We have angle 1 below the transversal while angle 8 is on the opposite side and above the transversal. For similar reasoning, angles 5 and 4 are alternate exterior angles as well.
---------------------------------
Notice how each line crosses to form an X shape, producing 4 angles that share the same common vertex point. For instance, angles 1, 5, 6 and 2 are all around the same point.
Angle 1 and angle 3 are corresponding angles because they
a) are to the left of each parallel line (m and n)b) both below the transversal lineSo in short, they are both in the same corner of each four corner angle configuration. They are both in the bottom left corner. This is the full list of all corresponding angle pairs
angle 1 and angle 3angle 2 and angle 4angle 5 and angle 7angle 6 and angle 8---------------------------------
As stated in the first section above, the interior region is between the parallel lines. Alternate interior angles alternate being above and below the transversal line.
So this applies to angle 2 and angle 7. It also works for angle 3 and angle 6.
Maria operates a taco truck in her neighborhood. She has created a graph based on her business performance in the previous year. The price she currently sells tacos for is $2.30. Which two statements correctly interpret this graph? Revenue and Cost Functions 1)Maria’s business is incurring losses. 2)Maria’s costs are rising over time. 3)Maria is running a profitable business. 4)Maria’s total revenue exceeds her total profit. 5)Maria’s total profit exceeds her total revenue.
Answer:
3)Maria is running a profitable business.
4)Maria’s total revenue exceeds her total profit.
Step-by-step explanation:
The graph shows variation of revenue and cost with respect to price of product and not with respect to time .
The price of the product is 2.30 . From this graph , we see that at this price revenue exceeds total cost . So maria is running a profitable business .
Total profit can not exceed total revenue as
Total revenue - total cost = total profit .
So total profit will always be less than total revenue .
Try to get to every number from 1 to 10 using four 4's and any number of arithmetic operations (+, −, ×, ÷). You may also you parentheses. Examples to get 0: 0=4+4−(4+4); 0=44−44; 0=4×4−4×4
Answer:
0=4×4−4×4
Step-by-step explanation:
Answer:
[tex]\boxed{\mathrm{view \: explanation}}[/tex]
Step-by-step explanation:
1 = 4 ÷ 4
2 = (4 + 4) ÷ 4
3 = (4 + 4 + 4) ÷ 4
4 = 4 + 4 - 4
5 = (4 × 4 + 4) ÷ 4
6 = (4 + 4) - (4 ÷ 4) - (4 ÷ 4)
7 = (4 + 4) - (4 ÷ 4)
8 = 4 + 4
9 = (4 + 4) + (4 ÷ 4)
10 = (4 + 4) + (4 ÷ 4) + (4 ÷ 4)
Use a t-test to test the claim about the population mean at the given level of significance using the given sample statistics. Assume the population is normally distributed.
Claim: μ ≥8 300, α = 0.10
Sample statistics: x = 8000, s = 440, n = 24
A. What are the null and alternative hypotheses?
B. What is the value of the standardized test statistic?
C. What is the p-value?
D. Decide whether to reject or fail to reject the null hypothesis.
Answer:
A
The null hypothesis is [tex]H_o : \mu \ge 8300[/tex]
The alternative hypothesis is [tex]H_a : \mu < 8300[/tex]
B
[tex]t = -3.34[/tex]
C
[tex]p-value = P(t< -3.34) = 0.00041889[/tex]
D
reject the null hypothesis
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = 8300[/tex]
The sample mean is [tex]\ = x = 8000[/tex]
The standard deviation is [tex]s = 440[/tex]
The sample size is [tex]n = 24[/tex]
The level of significance is [tex]\alpha = 0.01[/tex]
The null hypothesis is [tex]H_o : \mu \ge 8300[/tex]
The alternative hypothesis is [tex]H_a : \mu < 8300[/tex]
The test statistic is mathematically evaluated as
[tex]t = \frac{\= x - \mu }{ \frac{s}{\sqrt{n} } }[/tex]
=> [tex]t = \frac{8000- 8300 }{ \frac{440}{\sqrt{24} } }[/tex]
=> [tex]t = -3.34[/tex]
The p-value is obtained from the z -table ( reference calculator dot net ) , the value is
[tex]p-value = P(t< -3.34) = 0.00041889[/tex]
Looking at the values of [tex]p-value and \ \alpha[/tex] we see that [tex]p-value < \alpha[/tex] Hence we reject the null hypothesis
A mass of 5 kg stretches a spring 10 cm. The mass is acted on by an external force of 10sin( t ) N(newtons) and moves in a medium that imparts a viscous force of 2 N
when the speed of the mass is 4 cm/s. If the mass is set in motion from its equilibrium position with an initial velocity of 3 cm/s, formulate the initial value problem describing the motion of the mass.
A)Find the solution of the initial value problem in the above problem.
B)Plot the graph of the steady state solution
C)If the given external force is replaced by a force of 2 cos(ωt) of frequency ω , find the value of ω for which the amplitude of the forced response is maximum.
Answer:
A) C1 = 0.00187 m = 0.187 cm, C2 = 0.0062 m = 0.62 cm
B) A sample of how the graph looks like is attached below ( periodic sine wave )
C) w = [tex]\sqrt[4]{3}[/tex] is when the amplitude of the forced response is maximum
Step-by-step explanation:
Given data :
mass = 5kg
length of spring = 10 cm = 0.1 m
f(t) = 10sin(t) N
viscous force = 2 N
speed of mass = 4 cm/s = 0.04 m/s
initial velocity = 3 cm/s = 0.03 m/s
Formulating initial value problem
y = viscous force / speed = 2 N / 0.04 m/s = 50 N sec/m
spring constant = mg/ Length of spring = (5 * 9.8) / 0.1 = 490 N/m
f(t) = 10sin(t/2) N
using the initial conditions of u(0) = 0 m and u"(0) = 0.03 m/s to express the equation of motion
the equation of motion = 5u" + 50u' + 490u = 10sin(t/2)
A) finding the solution of the initial value
attached below is the solution and
B) attached is a periodic sine wave replica of how the grapgh of the steady state solution looks like
C attached below
find the domain of the graphed function.
Tia uses 3/4 cup of pumpkin to make 1 1/4 pounds of dog treats. How much pumpkin does Tia use to make 1 pound of treats?
Answer:
4/5 cups to make 1 pound of dog treats
Step-by-step explanation:
3/4 cups : 1 1/4 pounds
x cups : 1 pound
Cross multiply
3/4 * 1 = 1 1/4 * x
x = 3/4 / 1 1/4
= 3/4 / 5/4
= 3/4 * 4/5
= 3/5 cups
Andria wrote the following statements: Statement 1: If parallel lines have a transversal, then corresponding angles are congruent. Statement 2: A line has an infinite number of points extending in opposite directions. Which geometry term does each statement represent? (4 points) Statement 1: definition; Statement 2: theorem Statement 1: postulate; Statement 2: definition Statement 1: postulate; Statement 2: theorem Statement 1: theorem; Statement 2: postulate
Answer: Statement 1: postulate; Statement 2: definition
Step-by-step explanation:
A postulate is assumed to be a fact and used to derive conclusions about any argument .A definition is a brief explanatory statement of a term.A theorem is a statement that can be proved to be true by using given, definitions, postulates or prior proved theorems .Here, Statement 1:If parallel lines have a transversal, then corresponding angles are congruent.
which is a fact, and hence it is postulate.
Statement 2: A line has an infinite number of points extending in opposite directions.
which is an explanatory statement of a 'line', hence it is 'definition.
So the correct option is Statement 1: postulate; Statement 2: definition
Answer:statement 1 and statement 2 postulate
Step-by-step explanation:
Find f(x) and g(x) so the function can be expressed as y = f(g(x)). y= [tex]\frac{2}{x^2}[/tex]+3
Answer:
One possible answer is:
f(x) = (2/x) + 3 and g(x) = x².
Step-by-step explanation:
Explanation:
We are to write this equation as y = f(g(x)). This means we want it to be a composite of functions; in f(x), we take the value of g(x) and use in place of x.
If we let g(x) = x², this means everywhere we see an x in f(x), we will replace it with x². To make our equation y = 2/x² + 3, working backward we would substitute x for x²; this would give us f(x) = 2/x + 3.
Find (fºg)(2) and (f+g)(2) when f(x)= 1/x and g(x) = 4x +9
[tex](f\circ g)(2)=\dfrac{1}{4\cdot2+9}=\dfrac{1}{17}\\\\(f+g)(2)=\dfrac{1}{2}+4\cdot2+9=\dfrac{1}{2}+17=\dfrac{1}{2}+\dfrac{34}{2}=\dfrac{35}{2}[/tex]
