The side of a rectangle legnth x+2 and width x-5. WHich equation describes the area A of the rectangle in terms of x?

12.

[tex]we \: know \: that \\ \frac{sum \: of \: all \: quantities}{number \: of \: quantities} = mean \\ => \frac{26 + 22 + 32 + 28 + 35 + x}{6} = 30 \\ = > \frac{143 + x}{6} = 30 \\ = > 143 + x = 30 \times 6 \\ = > 143 + x = 180 \\ = > x = 180 - 143 \\ = > x = 37 \\ [/tex]

This is the answer.

Hope it helps!!

Answer:

6in^2

Step-by-step explanation:

formula of a triangle: l x h : 2

4 x 3 = 12

12 : 2 = 6^2

Answer:

Step-by-step explanation:

is option a correct

The correct property of addition is shown in the equation is,

⇒ Identity property.

The process of combining two or more numbers is called the Addition. The 4 main properties of addition are commutative, associative, distributive, and additive identity.

Given that;

The equation is,

⇒ a + bi + 0 + 0i

Now, We know that;

Condition of identity property is,

⇒ a + 0 = a

Thus, The correct property of addition is shown in the equation is,

⇒ Identity property.

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Answer:

Step-by-step explanation:

what is it that you don't understand about how to get this?  

2(4-3x) + 5(2x-3) = 20-5x

Answer:

the answer is gonna be

6x^2+1

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\huge\textsf{Just do PEMDAS}\\\\\\\huge\textsf{Parentheses}\\\\\huge\textsf{Exponents}\\\\\huge\textsf{Multiplication}\\\\\huge\textsf{Division}\\\\\huge\textsf{Addition}\\\\\huge\textsf{Subtraction}[/tex]

[tex]\large\textsf{18 }\div\large\textsf{ 3 }\times\large\textsf{ 2 + 1}\\\\\\\large\textsf{18 }\div\large\textsf{ 3 = \bf 6}\\\\\\\large\textsf{6 }\times\large\textsf{ 2 + 1}\\\\\\\large\textsf{6 }\times\large\textsf{ 2 = \bf 12}\\\\\\\large\textsf{12 + 1}\\\\\\\large\textsf{= \bf 13}\\\\\\\boxed{\boxed{\huge\textsf{Answer: \bf 13}}}\huge\checkmark[/tex]

[tex]\huge\textsf{Or you could if your equation is: }\\\\\large\textsf{18}\div\large\textsf{3x}\mathsf{^2}\large\textsf{ + 1}[/tex]

[tex]\large\textsf{18}\div\large\textsf{3x}\mathsf{^2}\large\textsf{ + 1}\\\\\large\textsf{18}\div\large\textsf{3x}\mathsf{^2}\large\textsf{ = \bf 6x}\mathsf{\bf ^2}\\\\\large\textsf{= \bf 6x}\mathsf{\bf ^2 \ + }\large\textsf{ \bf 1}\\\\\\\\\\\boxed{\boxed{\large\textsf{Answer: \bf 6x}\mathsf{\bf ^2}\large\textsf{ \bf + 1}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

[tex]{ \bf{2x + y = 8 - - - (a)}} \\ { \bf{x + y = 4 - - - (b)}} \\ a - b : \\ x = 4 \\ 4 + y = 4 \\ y = 0 \\ { \tt{they \: intersect \: at \: (4, \: 0)}}[/tex]

Answer:

yes is correct 6/6 = 1 / 3*2=6 =1

Answer:

nonsense. what's the difference between 6/6 or 1 .

Given:

The sum of two numbers is 24 and their difference is one sixth of the sum.

To find:

The smaller number between the two numbers.

Solution:

Let x and y be the two numbers where x>y.

The sum of two numbers is 24.

[tex]x+y=24[/tex]           ...(i)

Their difference is one sixth of the sum.

[tex]x-y=\dfrac{1}{6}\times 24[/tex]

[tex]x-y=4[/tex]              ...(ii)

Adding (i) and (ii), we get

[tex]2x=28[/tex]

[tex]x=\dfrac{28}{2}[/tex]

[tex]x=14[/tex]

Putting [tex]x=14[/tex] in (i), we get

[tex]14+y=24[/tex]

[tex]y=24-14[/tex]

[tex]y=10[/tex]

The two numbers are 14 and 10.

Therefore, the smaller number between the two numbers is 10.

Answer:

Step-by-step explanation:

To solve this, we can use polynomial long division.

Seeing the picture, we first divide x (the variable to the largest degree in x+1) from 2x³. We divide from 2x³ because that is the variable with the largest degree in the polynomial. That is equal to 2x², so we put that on top and subtract (x+1) * (2x²) from the polynomial. Then, we repeat the process, but with x² instead of 2x³, and again with -6x as the variable with the largest degree.

average =65%

average = (60+70)/(100+100)*100

= 130/200*100

= 65%

Answer:

56.25metres

Step-by-step explanation:

Given the height of the ball h meters, above the ground after t seconds modeled by the function h(t) = -5t^2 + 15t + 45, at maximum height, the velocity is zero, hence;

dh/dt = 0

Since dh/dt = -10t + 15

-10t+ 15 = 0

-10t = -15

t = 15/10

t = 3/2

t = 1.5secs

Substitute t = 1.5 into the expression given

h(1.5) =  -5(1.5)^2 + 15(1.5) + 45

h(1.5) = -5(2.25)+22.5+45

h(1.5) = -11.25+67.5

h(1.5) = 56.25

Hence the maximum height is 56.25metres

Answer:

67

Step-by-step explanation:

log(3t+9)-log21 = 1

Applying, the law of logarithm,

log(3t+9)/21 = 1

converting the log into index

(3t+9)/21 = 10

solving for t

3t+9 = 21×10

3t+9 = 210

3t = 210-9

3t = 201

t = 201/3

t = 67

Answer:

64

Step-by-step explanation:

-1.5 = (X - 82)12

-18 = X-82

X = 64

Answer: x = -2

Step-by-step explanation:

[tex]x=4+(4x-4)\frac{1}{2} \\x=4+\frac{4x}{2}-\frac{4}{2}\\x=4+2x-2\\x=2+2x\\x-2x=2\\-x=2\\x=-2[/tex]

Answer:

5x+8x+17-9+2y

13x+8+2y

Answer:

13x+8+2y

Step-by-step explanation:

5x+8x=13x

17–9=8

2y=2y

Answer: hello some part of your question is missing

Let v=〈−2,5〉 in R^2,and let y=〈0,3,−2〉 in R^3.

Find a unit vector u in R^2 such that u is perpendicular to v. How many such vectors are there?

answer:

One(1) unit vector ( < 5/√29,  2 /√29 >  ) perpendicular to 〈−2,5〉

Step-by-step explanation:

let  

u = < x , y > ∈/R^2  be perpendicular to  v = < -2, 5 > ------ ( 1 )

hence :

-2x + 5y = 0

-2x = -5y

x = 5/2 y

back to equation 1

u = < 5/2y, y >

∴ || u || = y/2 √29

∧

u   = < 5 /2 y * 2 / y√29 ,  y*2 / y√29 >

    = < 5/√29,  2 /√29 >  ( unit vector perpendicular to < -2, 5 > )

Answer:

it may be 0.75 i am not sure

Answer:

answer will be 0.75

[tex]{\color{red}{\huge{\underbrace{\overbrace{\mathfrak{\:\:\:\:\:\:\:꧁"Answer"꧂\:\:\: }}}}}}[/tex]

Because ∆XZW and WYZ is the same height and

Because ∆XZW and WYZ is the same height and the are of ∆WXZ to the the WYZ

[tex]so \:( \frac{1}{2}xw \times h)( \frac{1}{2} w)=7:2[/tex]

Because xy=21

[tex]so \: WY=2 \frac{1}{2}(7 + 2x2) \\ = 21 \frac{1}{2}p \times 2 \\ =\small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: WY=\frac{14}{3}\:\:\:\: }}}}[/tex]

The length of the line segment WY is [tex]\frac{14}{3}[/tex] unit.

The area of a triangle is defined as the total region that is enclosed by the three sides of any particular triangle.

Area of triangle = (1/2)base × height

According to the given question.

The ratio of the area of triangle WXZ to the area of triangle WYZ is 7:2.

Since, the height WZ for both the triangles WXZ and WYZ is same.

Let, WZ = h

Therefore, the ratio of the area of the triangles is given by  

 [tex]\frac{\frac{1}{2}WX(h) }{\frac{1}{2}(WY)(h) } =\frac{7}{2}[/tex]

⇒ [tex]\frac{WX}{WY} =\frac{7}{2}[/tex]

⇒ [tex]WX = \frac{7}{2} WY..(i)[/tex]

Since, in the given figure

[tex]XY = WY + WX[/tex]

⇒ [tex]21 = WY + \frac{7}{2} WY[/tex]   (from i)

⇒ [tex]21 = \frac{9}{2}WY[/tex]

⇒ [tex]WY = \frac{14}{3}[/tex]

Hence, the length of the line segment WY is [tex]\frac{14}{3}[/tex] unit.

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Answer:

[tex]10\sqrt{3}[/tex]

Step-by-step explanation:

One is given the following expression:

[tex]\sqrt{30}*\sqrt{10}[/tex]

One property of multiplying square roots is that one can multiply the numbers under the radical by each other, and then put the radical on top of the result. The following is an example of this general format of this property:

[tex]\sqrt{a}*\sqrt{b}=\sqrt{ab}[/tex]

Apply this to the real problem:

[tex]\sqrt{30}*\sqrt{10}=\sqrt{30*10}[/tex]

Simplify,

[tex]\sqrt{30*10}=\sqrt{300}[/tex]

Rewrite as (300) as the product of two numbers, such that one number is a perfect square:

[tex]\sqrt{300}=\sqrt{3*10^2}[/tex]

Simplify, take a term out of the radical:

[tex]\sqrt{3*10^2}=10\sqrt{3}[/tex]

Step-by-step explanation:

x=4x+11

11=4x-x

11=3x

x=11/3

x=37

Answer:

c = 1/4

-1-1 = -2

-3-5 = -8  

Step-by-step explanation:

Answer:

2 ( Option A )

Step-by-step explanation:

The given integral to us is ,

[tex]\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx [/tex]

Here 5 is a constant so it can come out . So that,

[tex]\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx [/tex]

Now we can write √x as ,

[tex]\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx [/tex]

Simplify ,

[tex]\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx [/tex]

By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,

[tex]\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg) [/tex]

On simplifying we will get ,

[tex]\longrightarrow \underline{\underline{ I = 2 }}[/tex]

[tex]\displaystyle\ a(n)=-3(2)^ {n-1}\Longrightarrow a(10)=-3(2)^{10-1}=2^9\cdot -3=\boxed{-1536}[/tex]

Answer:

Try to do it yourself, since you have a test tomorrow

Good luck

Step-by-step explanation:

5: 4605

13 (8+5):

[tex] \frac{4605}{5} \times 13 = [/tex]

=Your answer

Answer:

10

Step-by-step explanation:

Apply difference of squares.

[tex](x + y)(x - y) = {x}^{2} - {y}^{2} [/tex]

[tex](2 + 6i)(2 - 6i) = {2}^{2} - {6i}^{2} [/tex]

[tex] = 4 + 6[/tex]

[tex] = 10[/tex]

Answer:

22

Step-by-step explanation:

You add up the value of each X and you get a final answer of 22. Have a great day!

Answer:

b.

b.

Step-by-step explanation:

scientific notation should have one positive in front of the decimal point, then any number (>=1) of positions after the decimal point, followed by the multiplication with the property power of 10.

the only number not following that rule is b (2 positions in front of the decimal point).

4x - 2y = 6

2x - y = 3

are the same line, as we can multiply the second equation by 2 and get exactly equation 1.

so, both lines have the same slope and the same y-intercept. therefore, they have infinitely many solutions.

Answer:

Step-by-step explanation:

Acres of corn harvested : time taken = 8 3/4 : 5/6

How much corn can she collect in a hour. ?

Let

x = Acres of corn harvested

Acres of corn harvested : time taken = x : 1

8 3/4 : 5/6 = x : 1

35/4 : 5/6 = x : 1

35/4 ÷ 5/6 = x/1

35/4 × 6/5 = x/1

35*6/4*5 = x/1

210/20 = x/1

210 * 1 = 20 * x

210 = 20x

x = 210/20

= 10 1/2 acres

x = Acres of corn harvested = 10 1/2 acres