The system of equations can be solved using linear combination to eliminate one of the variables. 2x − y = −4 → 10x − 5y = −20 3x + 5y = 59 → 3x + 5y = 59 13x = 39 Which equation can replace 3x + 5y = 59 in the original system and still produce the same solution?

Answer:

It will still be 9.  y=9 is a horizontal line.  No matter the x value, the answer will be the same.

Step-by-step explanation:

Answer:

point C ad B located on the x axis

Step-by-step explanation:

"must be used first" is a very hard phrasing. multiplication is commutative.

and I am not sure that the problem is stated correctly.

I read here

(i×y²) to the power of 1/3.

i is the imaginary constant sqrt(-1) ?

exponents brought themselves to the power of something else multiply.

e.g.

[tex]({2}^{3})^{4} = {2}^{12} [/tex]

exponents in multimedia expressions of the same base simply add up.

e.g.

[tex] {2}^{3} \times {2}^{4} = {2}^{7} [/tex]

a negative exponent means that the expression with the same positive exponent is just at the bottom of a division.

e.g.

[tex] {2}^{ - 3} = 1 \div {2}^{3} [/tex]

and a fraction as exponent specifies a root to be taken.

e.g

[tex] {2}^{1 \div 3} = \sqrt[3]{2} [/tex]

so, I would do all the exponent multiplications to simplify the expression.

[tex] \sqrt[3]{i \times {y}^{2} } = ({i \times {y}^{2} })^{1 \div 3} = [/tex]

[tex] = ( { - 1}^{1 \div 2} \times {y}^{2} ) ^{1 \div 3} [/tex]

1/2 × 1/3 = 1/6

2 × 1/3 = 2/3

[tex] = { - 1}^{1 \div 6} \times {y}^{2 \div 3} = \sqrt[6]{ - 1} \times \sqrt[3]{ {y}^{2} } [/tex]

so, as we can see, we can move freely from multiplying the fraction exponents to converting them into root expressions and vice versa.

Answer:

The range of the following relation is(-5,2,-4)

Step-by-step explanation:

by referring to the diagram,

a = 8

Answer:

C

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos45° = [tex]\frac{\sqrt{2} }{2}[/tex] , then

cos45° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{s}{6}[/tex] = [tex]\frac{\sqrt{2} }{2}[/tex] ( cross- multiply )

2s = 6[tex]\sqrt{2}[/tex]  ( divide both sides by 2 )

s = 3[tex]\sqrt{2}[/tex] → C

Answer:

Problem 1: 25

Problem 2: 693

Step-by-step explanation:

Problem 1:

f(x) = -5n + 1

g(x) = -6n + 2

(f + g)(-2) = f(-2) + g(-2)

f(-2) = -5(-2) + 1

f(-2) = 10 + 1

f(-2) = 11

g(-2) = -6(-2) + 2

g(-2) = 12 + 2

g(-2) = 14

(f + g)(-2) = 11 + 14

(f + g)(-2) = 25

Problem 2:

f(x) = 7 + 2x

g(x) = 5x - 2

fg(7) = f(7) × g(7)

f(7) = 7 + 2(7)

f(7) = 7 + 14

f(7) = 21

g(x) = 5(7) - 2

g(x) = 35 - 2

g(x) = 33

Therefore:

fg(7) = 21 × 33

fg(7) = 693

Answer:

9 cm²

Step-by-step explanation:

the area = ½× 3√2 × 3√2 = ½×18 = 9

Answer:

Graph the system on linear equations.

Step-by-step explanation:

(-4, 4) & (-4, -6)

Answer:

x=21

Step-by-step explanation:

they are corresponding to each other

Answer:

[tex]\frac{x}{x-1}[/tex]

Step-by-step explanation:

[tex]\frac{3x^2 - 1}{x^2 - 1} - \frac{2x + 1}{x + 1}[/tex]                                          [tex][ \ x^ 2- 1 = (x-1)(x + 1) \ ][/tex]

[tex]= \frac{3x^2 - 1}{(x-1)(x + 1 )} - \frac{2x + 1}{x + 1}\\\\=\frac{(3x^2 - 1)-(2x + 1)(x-1)}{(x + 1)(x-1)}[/tex]                        [tex][\ Taking \ LCM \ ][/tex]

[tex]= \frac{(3x^2 - 1)- (2x^2 - 2x + x - 1)}{(x+1)(x-1)}\\\\=\frac{3x^2 - 1 - 2x^2 + x + 1 }{(x+1)(x-1)}\\\\=\frac{x^2 +x}{(x+1)(x-1)}\\\\=\frac{x(x+1)}{(x+1)(x-1)}\\\\=\frac{x}{x-1}[/tex]

Finding LCM :

Example :

                 [tex]\frac{1}{6} + \frac{1}{3}[/tex]

6 = 2  x   3

3 = 1   x   3

                [tex]\frac{1}{2 \times 3} + \frac{1}{ 3}[/tex] [tex]= \frac{1}{2 \times 3} + \frac{1 \times 2}{ 3 \times 2}[/tex]  

[ To make the denominators same : the second fraction is multiplied and divided by 2 ]

Similarly :

 [tex](x^2 - 1 ) = (x -1)(x+1)\\\\(x + 1) = 1 \times (x + 1)[/tex]

Same rule we applied : multiplied the numerator and denominator of the second term with ( x - 1 )

Therefore the second term becomes ,

                                       [tex]\frac{2x + 1}{x + 1} = \frac{(2x + 1)(x - 1)}{(x + 1)( x - 1)}[/tex]

Answer:

12

Step-by-step explanation:

Step-by-step explanation:

THE AMOUNT RECIEVE BY JOY IF SHE WORKED m HOURS AT PHP300 PER HOUR?

hi please mark me as brilliant

Answer: (12, 0) and (0, 8)

Step-by-step explanation:

This equation is in standard form. We can sub in a number for x to solve for y and vice versa.

Let's sub in 0 for x.

[tex]2x+3y=24\\2(0)+3y=24\\3y=24\\\frac{3y}{3} =\frac{24}{3} \\y=8[/tex]

When x is 0 y is 8 giving us the coordinate (0, 8).

Now lets sub in 0 for y

[tex]2x+3(0)=24\\2x=24\\\frac{2x}{2} =\frac{24}{2} \\x=12[/tex]

When y is 0 x is 12 giving us the coordinate (12, 0)

Step-by-step explanation:

Begin by solving for y

3y = -2x + 24 divide by 3

y =-(2/3)x + 24

Choose x so that it is divisible by 3

Let x = 6 which 3 can divide into evenly

y = -(2/3)*6 + 24 3 into 6 is 2 so you are left with

y = - 2 * 2 + 24

y = - 4 +24

y = 20

By a similar mthed, let x = 15

y = -2/3 x + 24

y = -2/3 * 15 +24

y = -2 * 5 + 24

y = -10 + 24

y = 14

So your two solutions are

(6,20)

(15,14)

From the graph it seems to be around the area of 10%.

So,

18,000 * 0.10 = $1,800

Answer:

y = square root x2 - 5

Step-by-step explanation:

y=[tex]\sqrt{x} -5[/tex]

(the top option)

[tex]SI=\frac{P*R*T}{100}[/tex]

[tex]SI=\frac{8000*15*5}{100}[/tex]

     [tex]=Rs. 6,000[/tex]

Amount = [tex]8,000+6,000=Rs. 14,000[/tex]

Interest = [tex]Rs. 6,000[/tex] Amount = [tex]Rs. 14,000[/tex]

[tex]SI=\frac{P*R*T}{100}[/tex]

[tex]SI=\frac{6000*12*3}{100}[/tex]

     [tex]= Rs.2160[/tex]

Amount = [tex]6,000+2,160=Rs.8,160[/tex]

Interest = [tex]Rs. 21,600[/tex]  Amount = [tex]Rs.8160[/tex]

Gain: 6,000 - 2,160

Gain = Rs. 3,840

hope this helps......

Answer:

480,700 sets (first choice)

Step-by-step explanation:

If all 25 questions are different,

When order of selection counts:

P(25,7)

= 25!/(25-7)!

= 15511210043330985984000000/6402373705728000

= 2422728000

When order of selection does not count count:

C(25,7)

=25!/(7!*(25-7)!)

=15511210043330985984000000/(6402373705728000*5040)

= 480,700

Hope this helps, have a nice day.

Answer:

3

Step-by-step explanation:

the y-intercept is the point (or rather just the y coordinate of that point), where the function crosses the y-axis (that means x=0).

it is possibly visible, that this is at y=3.

Answer:

$34,341

Step-by-step explanation:

Given :

Job Salary Percent of Employees Entry 23,264 60% 47,480 38% 117,027 2%

To obtain the best value for the mean salary ; we obtain the weighted average ;

Σ(salary * weight factor) / Σ weight

[(23264 * 0.60) + (47480 * 0.38) + (117027 * 0.02)] ÷ (0.60 + 0.38 + 0.02)

= 34341.34 / 1

Average salary = 34341.34

= $34,341 ( nearest dollar)

Answer:

y=-2x+3

Step-by-step explanation:

for one, you can see that the y-intercept is at 3, so for y=m*x+b, b is 3

next, you can count to get the slope. it moves 2 units down and one unit to the left, so for slope, which is rise over run, you are -2/1= -2

so y = -2x + 3

Answer:

y=1x-4

Wait sorry I did it wrong the first time lol.

In standard Form, it should be 4x-4y=16

Step-by-step explanation:

yes yes hand me brain

Answer:

Option B:10 glasses of lemon juice and 5 glasses of water

Answer:

integers are { 3 , 4 , 5 }

Step-by-step explanation:

- 1 < 2x - 5 ≤ 5

- 1 + 5 < 2x - 5 + 5 ≤ 5 + 5                           [ adding by 5 ]

4 < 2x + 0 ≤ 10

4 < 2x ≤ 10

2 < x ≤ 5                                                     { divide by 2 ]

Therefore, integers are { 3 , 4 , 5 }

Answer:

stars: triangles

3  : 1

Step-by-step explanation:

There are 3 starts and 1 triangle

stars: triangles

3  : 1

Answer:

3:1

Step-by-step explanation:

3 Stars and 1 Triangle

Answer:

Measure Of Angle K is 82*

Step-by-step explanation:

According To Question, We Have Given

A Quadrilateral JKLM, We Know Sum Of All The Angles Of Quadrilateral Is 360* .

Thus

∠JKL=90*

∠KLM= 180* - 110* = 70* ( Find Diagram In Attachment )

∠MJK=118* (Alternative Opposite Angle)

Now We Have To Find The Value Of ∠LKJ.

∠K = 360* - (∠MJK+∠KLM+JKL)

∠K = 360* - (118* + 70* + 90*)

∠K = 360* - 278*

∠K = 82*

(Diagram, Please Find In Attachment)