The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of RT and R1, what is R2 R2 blank is ohms

Answers

Answer 1
Answer:

[tex]R_2[/tex]  is 3 ohms

Step-by-step explanation:

In a circuit containing two resistors [tex]R_1[/tex] and [tex]R_2[/tex] connected together in parallel, the total resistance [tex]R_T[/tex] is given by;

[tex]\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}[/tex]              ---------(i)

Make [tex]R_2[/tex] subject of the formula;

=> [tex]\frac{1}{R_2} = \frac{1}{R_T} - \frac{1}{R_1}[/tex]  

=> [tex]\frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}[/tex]

=>   [tex]{R_2} = \frac{R_TR_1}{R_1 - R_T}[/tex]       ---------------(ii)

From the question,

[tex]R_1[/tex] = 6Ω

[tex]R_T[/tex] = 2Ω

Substitute these values into equation (ii) as follows;

=> [tex]{R_2} = \frac{2*6}{6 - 2}[/tex]

[tex]{R_2} = \frac{12}{4}[/tex]

[tex]R_2[/tex] = 3Ω

Therefore, the value of [tex]R_2[/tex] = 3 ohms or [tex]R_2[/tex] = 3Ω

Answer 2

Answer: is 3 ohms.

Explanation: edmentum/plato :)


Related Questions

The area of a circle is 4π ft². What is the circumference, in feet? Express your answer in terms of \piπ.

Answers

Answer:

C = 4 pi ft

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

Solving for r

4 pi = pi r^2

Dividing each side by pi

4 = r^2

Taking the square root of each side

sqrt(4) = sqrt(r^2)

2 = r

Now we can find the circumference

C = 2 * pi *r

C = 2*pi*2

C = 4 pi ft

May I please have help ?! Thanks ❤️

Answers

b is the correct answer

What is the remainder when x^3-8x^2+20x-16 is divided by x+2?

Answers

Answer:

(x - 4)(x - 2)²

Step-by-step explanation:

x³ - 8x² + 20x - 16

x³ - 4x² + 4x - 4x² + 16x - 16

x(x² - 4x + 4) - 4(x² - 4x + 4)

(x - 4)(x² - 4x + 4)

(x - 4)(x² - 2x - 2x + 4)

(x - 4)(x(x - 2) - 2(x - 2))

(x - 4)(x - 2)(x - 2)

(x - 4)(x - 2)²

(x - 4)(x - 2)²

Answer:

-96

Step-by-step explanation:

x+2=0 take 2 to the other side which will be -2

the -2 you sub it into the quotient and calculate

what's the length of each side using the Pythagorean theorem, round to the nearest hundredth if necessary. Will give brainliest ​

Answers

Answer:

X.2 y C 5

Step-by-step explanation:

the dots please

What type of graph would you use to compare the prices of Felix's books and of Tyler's books? In two or more sentences, explain your choice.

bar graph
line graph
scatter plot
histogram
box-and-whisker plot

Answers

Answer:

I think its bar graph, bar graphs are suitable for comparing values for different things.. that's all I know sorry

Step-by-step explanation:

Answer : Bar graph

A bar graph would be the best option to compare the prices of Felix’s books and Tyler’s books. This is because Bar Graphs are more often used for comparisons of general things, which includes the comparing of product prices. It clearly shows the differences, unlike the other options listed.

What is the perimeter of the parallelogram???

Answers

answer: 22

explanation: the easiest way is to separate one of the diagonals into a triangle and use the pythagorean theorem.
a^2 + b^2 = c^2
4^2 + 3^3 = c^2
16 + 9 = c^2
25 = c^2
5 = c
you now know that both of the diagonals have a length of 5.
by counting the units on the two straight, you know that their length is 6.
6 + 6 + 5 + 5 = 22

Please help I will give brainliest to whoever answer correct first

Answers

The correct answer is y=1/3x-3

What is the value of x?
45°
m
(2x-5)
n

Answers

Answer:

x = 70

Step-by-step explanation:

The two angles are same side interior angles and same side interior angles add to 180

45+ (2x-5) = 180

Combine like terms

2x +40 = 180

Subtract 40 from each side

2x+40-40 =180-40

2x =140

Divide by 2

2x/2 = 140/2

x = 70

Answer:

x=70

Step-by-step explanation:

hope it helped! :)

have a nice day

What is the approximate measure of the leg opposite of angle A???

Answers

Answer:

8.7 cm

Step-by-step explanation:

take 60 degree as reference angle

using sin rule

sin 60=opposite/hypotenuse

[tex]\frac{\sqrt{3} }{2}[/tex]=opposite/10

[tex]\frac{\sqrt{3} }{2} * 10[/tex]=opposite

[tex]\sqrt{3} *5[/tex] = opposite

[tex]5\sqrt{3}[/tex] =opposite

8.66=opposite

8.7 =opposite

Lines Line A E and Line G H are parallel in the image below. The image will be used to prove that the sum of the measures of the interior angles of Triangle C G H is 180°.

Lines A E and G H are parallel. Angles A and H are congruent.

Which statement would be included in a proof of why Measure of angle C + measure of angle G + measure of angle H = 180 degrees.?
Angles F and H are congruent.
Angles A and G are congruent.
Angles A and H are congruent.
Angles E and C are congruent.

Answers

Answer:

Angles F and H are congruent.

Step-by-step explanation:

Answer:

Angles F and H are congruent.

Step-by-step explanation:

Choose ALL the adjacent angles

Answers

Answer:

d, e, g, and h.

Step-by-step explanation:

Adjacent angles sit next to each other, and don't overlap.

Mr. Williams asks to buy 1/2 of a pan of brownies that is 2/3 full what fraction of the original pan does he buy?

Answers

Mark brainliest please

Answer:

Explanation :1/3

1/2 * 2/3 = 2/6= 1/3

1/3 fraction of the original pan he bought.
Yes 1/3 is the correct answer

Please help me, the answer is v=24, but I need working out

Answers

Answer:

v=24

Step-by-step explanation:

V= 3[tex]\sqrt{10^{2} - 6^{2} }[/tex]

V= 3[tex]\sqrt{100-36}[/tex]

V= 3[tex]\sqrt{64}[/tex]

V= 3×8

V= 24

Question 6 of 9 Last week, Hayden rode his bike 5 times. Each time, he biked a 3-mile path, a 2-mile path, and a 2 1 4 2 1 4 -mile path. Which expression represents the total number of miles he biked? A. 5 × ( 3 + 2 + 2 1 4 ) 5 × ( 3 + 2 + 2 1 4 ) B. 5 + ( 3 × 2 × 2 1 4 ) 5 + ( 3 × 2 × 2 1 4 ) C. 5 × ( 3 × 2 × 2 1 4 ) 5 × ( 3 × 2 × 2 1 4 ) D. 5 + ( 3 + 2 + 2 1 4 )

Answers

Answer:

A. 5 × ( 3 + 2 + 2 1/4 )

Step-by-step explanation:

Hayden rode his bike 5 times. Each time, he biked a 3-mile path, a 2-mile path, and a 2 1/4 -mile path.

The expression represents the total number of miles he biked is calculated as:

The number of times he rode his bike × (sum of the number of miles he biked)

= 5 × ( 3 mile + 2 miles + 2 1/4 miles)

= 5 × (3 + 2 + 2 1/4)

Therefore, Option A is the correct option

BRAINILEST PLZZZZZzzzzz

Answers

Answer:

Base:3

Height:5

Area= 15

Step-by-step explanation:

Formula=BxH

3x5=15

What number is between 200 and 300.

Answers

250

250 is in-between 200 nd 300

Which statement illustrates the associative property of addition?
Select one:

a. (1+√3)² + √7= 1 + (√3+√7) ²
b.(-2+72) + 4i - 2 + (7i+ 42)
c. v 18 + 5/3 (√6 +5)
d. (51.21) + 111 – 111 + (51-21)​

Answers

I think it’s B because

quadratic formula?

2x^2-4x+2=0
A. 1
B. -4
C. 6
D. -2
E. 2

Answers

The answer is A.) One

Find the growth factor associated with the given growth rate. Growth rate = 6% *

A. 0.06
B. 1.06
C. 0.6
D. 1.6

Answers

I think it’s A or C but i would look up what’s the decimal of 6%!:)
Well I changed it in to a decimal and got 0.06 so I think the answer is A

Surface area. Math hw I need help on.

Answers

Answer:

Area of A is 30

Step-by-step explanation:

total area = 280

amount of area given= 60+60+50+50

                                   =220

area left = 280-220

              =60

Area of 1 A= 60/2

                 =30

Fill in the blank. In the triangle below, x=__. Round your answer to two decimal places.

Answers

Given:

The figure of a right triangle.

To find:

The value of x.

Solution:

In a right triangle,

[tex]\tan \theta=\dfrac{Perpendicular}{Base}[/tex]

In the given right angle triangle,

[tex]\tan 52^\circ=\dfrac{x}{35}[/tex]

[tex]1.2799\times 35=x[/tex]

[tex]44.7965=x[/tex]

Approximate the value to two decimal places.

[tex]x\approx 44.80[/tex]

Therefore, the value of x is about 44.80 units.

The projectile motion of an object can be modeled using s(t) = gt2 + v0t + s0, where g is the acceleration due to gravity, t is the time in seconds since launch, s(t) is the height after t seconds, v0 is the initial velocity, and s0 is the initial height. The acceleration due to gravity is –4.9 m/s2. A rocket is launched from the ground at an initial velocity of 39.2 meters per second. Which equation can be used to model the height of the rocket after t seconds? s(t) = –4.9t2 + 39.2 s(t) = –4.9t2 + 39.2t s(t) = –4.9t2 + 39.2t + 39.2 s(t) = –4.9t2 + 39.2t – 39.2

Answers

Answer:

s(t) = -4.9t² + 39.2t

Step-by-step explanation:

Given the projectile motion of an object can be modeled using s(t) = gt2 + v0t + s0, where g is the acceleration due to gravity, t is the time in seconds since launch, s(t) is the height after t seconds, v0 is the initial velocity, and s0 is the initial height. The acceleration due to gravity is –4.9 m/s²

Given

g = -4.9m/s²

v0 = 39.2m/s

s0 = 0m (the initial height)

On substituting into the formula;

s(t) = gt² + v0t + s0

s(t) = -4.9t² + 39.2t + 0

s(t) = -4.9t² + 39.2t

This gives the equation that models the height

Answer:

b

Step-by-step explanation:

edge 2020

Help pls pls pls pls

Answers

Answer:

C

Step-by-step explanation:

Answer:

option c is correct

Step-by-step explanation:

y = 2x +5

5 = 2*0 +5

5 = 0 +5

5=5

y = 2x +5

9 = 2*2 + 5

=9 = 4 +5

9=9

y = 2x +5

13 = 2*4 +5

13 = 8 + 5

13 = 13

therefore option c is correct because it satisfies all the elements of x and y of the given function when we substitute the values.

B
20°
?
A
4.
С
( I need an answer )

Answers

Answer:

10.9899097

Step-by-step explanation:

Trigonometry.

Tan = opposite/adjacent

Adjacent = Opposite / Tan(20)

The cost of a computer processor is directly proportional to its speed.
A 4GHz processor costs £400.

Find the cost of a 6GHz processor

Answers

Answer:

Step-by-step explanation:

If cost is directly proportional to speed, then the equation for this is

£ = ks, where k is the constant of proportionality. We need to solve for this first.

400 = k4 so

100 = k. Now we will use that k value in the next equation to find the cost of a 6GHz processor:

£ = (100)(6) so

£ = 600

aasaaaaaaaaaaaaaaaaaaaa

Answers

Answer:

mjmdsfkjdsfjdfdjkfhdkfdkfdjhkjhfk

Step-by-step explanation:

dfjdbfjfshdgdsjhdh

Answer:

aasaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

hee haw i beat u i put more a's in my answer

Which of the following expressions is equivalent to the one shown below? (4^3)5 A. 49 B. 42 C. 48 O D. 415​

Answers

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{(4^3)(5)}[/tex]

[tex]\mathsf{4^3}[/tex]

[tex]\mathsf{= 4 \times 4\times 4}[/tex]

[tex]\mathsf{= 16 \times 4}[/tex]

[tex]\mathsf{= \bf 64}[/tex]

[tex]\mathsf{64(5)}[/tex]

[tex]\mathsf{= \bf 320}[/tex]

[tex]\boxed{\boxed{\huge\textsf{Answer: \bf 320}\huge\textsf{ (NONE of the ABOVE)}}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

the person below isn't giving the right answer choice did you ever get the answer for this question please comment me the answer cuz they clearly don't see the answer choice

which is the correct classification square root of 32?

Answers

Answer:

5.65

Step-by-step explanation:

But if you need to round it would be 6.

Hope this helps!

Good Luck!

PLEASE HELP QUICK
graph and show work and i will give 30 points

Answers

The equation is
4x-2y=-2
4x=2y-2
4x+2=2y
2x+1=y

Solve using the quadratic formula
2x^2+x+67=0

Answers

Answer:

[tex]\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Multiple RootsStandard Form: ax² + bx + c = 0Quadratic Formula: [tex]\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]

Algebra II

Imaginary Root i = √-1

Step-by-step explanation:

Step 1: Define

Identify

2x² + x + 67 = 0

a = 2

b = 1

c = 67

Step 2: Solve for x

Substitute in variables [Quadratic Formula]:                                                  [tex]\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2(1)}[/tex]Multiply:                                                                                                             [tex]\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2}[/tex][√Radical] Evaluate exponents:                                                                       [tex]\displaystyle x=\frac{-1 \pm \sqrt{1-4(2)(67)}}{2}[/tex][√Radical] Multiply:                                                                                           [tex]\displaystyle x=\frac{-1 \pm \sqrt{1-536}}{2}[/tex][√Radical] Subtract:                                                                                          [tex]\displaystyle x=\frac{-1 \pm \sqrt{-535}}{2}[/tex][√Radical] Simplify:                                                                                           [tex]\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}[/tex]
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