This sketch of a neutral molecule is shaded red or blue wherever the electrostatic potential at the molecule's surface isn't zero. What could the chemical formula of the molecule be?

Scientists would research the impacts of marble monuments and acid rain. A chemist. Hoping this is useful.

The correct answer is :C.

Surface sediments are transported and large stones are broken up through wind, water, and ice. Years are often needed for weathering, erosion, and deposition to cause noticeable changes. Nonetheless, certain things change the Planet's surface far more quickly than others. Extreme events, earthquakes, and volcanic eruptions are a few of them.

Weathering and erosion caused by water movement change the properties of the terrain. Regional wind patterns and climate are defined by several interactions, including the role of the ocean. The unique physical and chemical properties of water have a profound effect on the planet's dynamics.

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The correct Lewis structures of the compounds that we have in the question have been shown in the images attached.

A Lewis structure is a diagram that shows the bonding between atoms in a molecule and the arrangement of electrons around the atoms. It is also known as a Lewis dot structure, Lewis dot diagram, or electron dot structure.

Lewis structures are useful in predicting the geometry of molecules and determining the polarity of molecules. They are also helpful in understanding the reactivity of molecules and how they interact with other molecules.

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Answer:

1.82 atm

Explanation:

Ideal gas law

P=nRT/V

1) solve for n which is moles

7.16 / 4 = 1.79 mole He

2)

n=1.79

R=0.0821

T=692 K

V=55.9

P=1.79 X 0.0821 X 692 / 55.9 =1.82 atm

Answer:2.5 g CuSO4⋅5H2O.

Explanation:

You're dealing with copper(II) sulfate pentahydrate,

CuSO

4

⋅

5

H

2

O

, an ionic compound that contains water of crystallization in its structure.

More specifically, you have five moles of water of crystallization for every one mole of anhydrous copper(II) sulfate. This means that you're going to have to account for the mass of this water of crystallization in your calculations.

Now, you need your target solution to have a molarity of

0.10 M

and a volume of

100. mL

. Since molarity is defined as moles of solute per liter of solution, you can say that the target solution must contain

The molecule that is drawn in a conformation that has a proton and a leaving group anti-periplanar is H₂C, Br.

The A, B, C, and D bond angles of a molecule are referred to as anti-periplanar, or antiperiplanar, in organic chemistry. The dihedral angles of the A–B and C–D bonds in this conformer are larger than +150° or less than 150°. In textbooks, the term "anti-periplanar" is frequently used to refer to a strictly anti-coplanar structure with a 180° AB CD dihedral angle. The anti-periplanar functional groups will be 180° apart from one another and in a staggered configuration in a Newman projection of the molecule.  

Conformation is an essential factor in predicting reactivity in organic molecules. The anti-periplanar conformation of a molecule is one that occurs when two atoms in a molecule are in the same plane and are separated by 180 degrees. In this case, the proton and leaving group are placed in a perpendicular plane to the atoms directly in between them. This is the most stable conformer of the molecule. A significant factor in predicting reactivity in organic molecules is conformation. In this case, the molecule H₂C, Br is drawn in a conformation that has a proton and a leaving group anti-periplanar.

Therefore, the correct option is H₂C, Br.

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a. -813.4 kJ.  enthalpy of the reaction is -813.4 kJ

One of the characteristics of a thermodynamic system is enthalpy, which is calculated by multiplying the internal energy of the system by the sum of its pressure and volume. The total enthalpy of a system cannot be directly calculated because the internal energy's components are either unknown, hard to access, or unimportant to thermodynamics.The overall reaction can be represented as: [tex]Ca(s) +\frac{ 1}{2}O_2(g) + CO2(g) \rightarrow CaCO_3(s).[/tex]

The reaction enthalpy [tex](\Delta H_{rxn})[/tex]is the result of adding the reaction's separate enthalpies.The enthalpy of each of the individual reactions is given as:

[tex]Ca(s) + \frac{1}{2}0_2(g) \rightarrow Cao(s) \Delta H_{rxn} = -635.1 kJ CaCO_3(s) \rightarrow Cao(s) + CO2(g) \Delta H_{rxn} = 178.3 kJ[/tex]

Therefore, the overall enthalpy change for the reaction is given as:

[tex]\Delta H_{rxn} = \Delta H_{rxn}(Ca(s) +\frac{ 1}{2}0_2(g) \rightarrow Cao(s)) +\Delta H_{rxn} (CaCO_3(s) \rightarrow Cao(s) + CO2(g))[/tex]

[tex]\Delta H_{rxn} = -635.1 kJ + 178.3 kJ \Delta H_{rxn} = -813.4 kJ[/tex]

Therefore,The reaction's enthalpy is -813.4 kJ.

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complete question:Calculate delta Hrxn for Ca(s) + 1/202(g) + CO2(g) => CaCO3(s) given the following set of reactions:  Ca(s) + 1/202(g) => Cao(s) delta Hrxn = -635.1 kJ CaCO3(s) => Cao(s) + CO2(g) delta Hrxn = 178.3 kJ  a. -813.4 kJ  

b. -456.8 kJ

c. 813.4 kJ

d 456.8 kJ

e. None of these is within 5% of the correct answer.

Answer:

M2= 0,1 M

Explanation:

M1=0,15 M

V1= 100 mL =0,1 L

M2= ?

V2= 150 mL = 0,15 L

M1V1= M2V2

(0,15 mol/L) (0,1 L) = M2 (0,15 L)

0,015 mol / 0,15 L = M2

M2= 0,1 M

Answer:

6. The light being reflected off changes the color shown

7. The bottom, the sugar looses its positive charge

Explanation:

Answer:

Explanation:

40/ 180.2 x (-16 / 1 mole glucose)=-3.6 KJ

Answer:

0.2237 grams of NaOH

Explanation:

To calculate the grams of NaOH dissolved in 23.46 mL of a 0.238 M solution of NaOH, we can use the formula:

mass = molarity x volume x molar mass

where mass is the mass of NaOH dissolved in grams, molarity is the concentration of NaOH in moles per liter, volume is the volume of the solution in liters, and molar mass is the molar mass of NaOH in grams per mole.

First, we need to convert the volume of the solution from milliliters to liters:

volume = 23.46 mL / 1000 mL/L

volume = 0.02346 L

The molar mass of NaOH is 40.00 g/mol.

Now we can plug in the values and solve for mass:

mass = 0.238 M x 0.02346 L x 40.00 g/mol

mass = 0.2237 g

Therefore, there are 0.2237 grams of NaOH dissolved in 23.46 mL of a 0.238 M solution of NaOH.

When the pressure is 0.72 atm, the temperature in Kelvin is 156 K.

To determine the Kelvin temperature when the pressure is 0.72 atm, you will need to use the trendline equation given in Fig 6.2. First, find the equation of the trendline by using the graph's two points, (300 K, 1 atm) and (500 K, 2 atm).

The equation for the trendline is:

y = mx + b

Where y is pressure, x is the temperature in Kelvin, m is the slope, and b is the y-intercept. We can find the slope of the trendline by using the two points provided in the graph:

Slope (m) = (y2 - y1) / (x2 - x1)

Slope = (2 atm - 1 atm) / (500 K - 300 K)

Slope = 0.005 atm/K

The equation for the trendline can now be written: y = 0.005x + b. To find the y-intercept, b, we can use one of the two points: Solving for b:

1 atm = 0.005(300 K) + bb = 1.5 atm

Now we can use the equation for the trendline to find the temperature (x) at which the pressure (y) equals 0.72 atm:

0.72 atm = 0.005x + 1.5 atm

0.72 atm - 1.5 atm = 0.005x

-0.78 atm = 0.005xx

= -0.78 atm / 0.005x

= 156K

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The volume of the 0.10 molL⁻¹ NaCl solution which contains 0.1 mole of sodium chloride, NaCl is 1 L

Molarity of a solution is defined by the following formula:

Molarity = mole / volume

Cross multiply

Molarity × volume = Mole

Divide both sides by molarity

Volume = mole / molarity

With the above formula, we can obtain the volume of the solution. Details below:

Volume = mole / molarity

Volume of solution = 0.1 / 0.1

Volume of solution = 1 L

Thus, we can conclude that the volume of the solution is 1 L

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Complete question:

0.10 molL⁻¹ NaCl solution contains 1.0 mole of NaCl​. What is the volume of the solution?

The mass (in kilograms) of Cryolite, Na₃AlF₆ produced, given that 10.3 Kg of Al₂O₃, 55.4 Kg of NaOH, and 55.4 Kg of HF react completely is 42.4 Kg

The mass of Na₃AlF₆ produced from the reaction can be obtained as follow:

Al₂O₃(s) + 6NaOH(l) + 12HF(g) ⟶ 2Na₃AlF₆ + 9H₂O(g

From the balanced equation above,

0.102 Kg of Al₂O₃ reacted to produce 0.420 Kg of Na₃AlF₆

Therefore,

10.3 Kg of Al₂O₃ will react to produce = (10.3 × 0.420) / 0.102 = 42.4 Kg of Na₃AlF₆

Thus, from the above calculation, it is evident that the mass of Na₃AlF₆ produced is 42.4 Kg

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The bonds would be arranged in order of decreasing polarity as follows: H-F Bond (most polar) > O-H Bond and C-H Bond (tied) > C-C Bond (least polar).

In order to arrange the bonds in order of decreasing polarity, we can look at the electronegativity difference between the two atoms of each bond. Electronegativity differences will determine whether the bond is polar, nonpolar, or ionic.

In general, the polarity of a bond is determined by the electronegativity difference between the atoms in the bond. The greater the difference in electronegativity, the more polar the bond is likely to be.

The following is a list of the bonds in order of decreasing polarity, based on the information provided in the table:

The table shows the following:

H-F Bond: Electronegativity difference = 1.9

C-H Bond: Electronegativity difference = 0.4

C-C Bond: Electronegativity difference = 0

HF is the least polar bond since the difference in electronegativity between hydrogen and fluorine is smaller than the differences between the other atoms in the list.

Therefore, the bonds would be arranged in order of decreasing polarity as follows: H-F Bond (most polar) > and C-H Bond (tied) > C-C Bond (least polar).

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The complete questions is:

Based on the information in the table, which of the following arranges the bonds in order of decreasing polarity

The table shows the following:

H-F Bond: Electronegativity difference = 1.9

C-H Bond: Electronegativity difference = 0.4

C-C Bond: Electronegativity difference = 0

0.100 mole sample of ethane contains approximately 1.204 x [tex]10^{24}[/tex] carbon atoms and 3.612 x [tex]10^{24}[/tex] hydrogen atoms.

What are the atoms?

In one molecule of ethane (C2H6), there are 2 carbon atoms and 6 hydrogen atoms.

To determine how many atoms are present in a 0.100 mole sample of ethane, we can use Avogadro's number, which relates the number of particles (in this case, molecules) to the amount of substance in moles. Avogadro's number is approximately 6.02 x [tex]10^{23}[/tex] particles per mole.

So, a 0.100 mole sample of ethane would contain:

Simplifying this expression, we get:

Therefore, a 0.100 mole sample of ethane contains approximately 1.204 x [tex]10^{24}[/tex] carbon atoms and 3.612 x [tex]10^{24}[/tex] hydrogen atoms.

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Taking into account the definition of dilution, if chemist must dilute 93.1 mL of 7.79 of uM aqueous mercury (I) chloride solution until the concentration falls to 3.00 uM, the final volume is 0.24175 L.

Dilution is a procedure by which the concentration of a solution is lowered, usually with the addition of a diluent.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

In this case, you know:

Replacing in the definition of dilution:

7.79 uM× 93.1 mL= 3 uM× Vf

Solving:

(7.79 uM× 93.1 mL)÷ 3 uM= Vf

241.75 mL= 0.24175 L = Vf (being 1000 mL= 1 L)

In summary, the final volume is 0.24175 L.

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Answer: To balance the given chemical equation, we can start by counting the number of atoms on both sides of the equation. We have 3 carbon atoms and 8 hydrogen atoms on the left side, and 3 carbon atoms, 6 X atoms, and 1 hydrogen atom on the right side.

C3H8(g) + X2(g) → C3H2X6(g) + HX(g)

To balance the equation, we can add a coefficient of 3 in front of HX on the product side:

C3H8(g) + X2(g) → C3H2X6(g) + 3HX(g)

Now, we have the same number of H atoms on both sides (8 H atoms on each side), and the equation is balanced.

To estimate the heat of reaction, we can use the bond energy values to calculate the energy required to break the bonds in the reactants and the energy released by forming the bonds in the products. We can then subtract the energy required to break the bonds from the energy released by forming the bonds to obtain an estimate of the heat of reaction.

Breaking bonds in the reactants:

3 C-H bonds × 414 kJ/mol = 1242 kJ/mol

1 X-X bond × 243 kJ/mol = 243 kJ/mol

Forming bonds in the products:

6 C-X bonds × 339 kJ/mol = 2034 kJ/mol

1 C-H bond × 414 kJ/mol = 414 kJ/mol

3 H-X bonds × 431 kJ/mol = 1293 kJ/mol

Estimated heat of reaction:

Energy released - energy required

(2034 kJ/mol + 414 kJ/mol + 1293 kJ/mol) - (1242 kJ/mol + 243 kJ/mol) = 2756 kJ/mol

Therefore, the estimated heat of reaction for the given chemical equation is 2756 kJ/mol. Note that this is only an estimate and actual experimental values may differ due to factors such as reaction conditions and the presence of catalysts.

The net ionic equation for the given reaction is: 1 Cr3+(aq) + 3OH-(aq) → Cr(OH)3(s)

2. The formula for the precipitate formed in this reaction is Cr(OH)3.

3. The sum of all coefficients in the net ionic equation is 4.

Consider the reaction between aqueous solutions of potassium hydroxide and chromium (III) chloride. The balanced chemical equation for the given reaction is:KOH(aq) + CrCl3(aq) → KCl(aq) + Cr(OH)3(s)1) Spectator ionsThe ions that do not take part in the reaction are known as spectator ions.

These ions are present on both sides of the equation without undergoing any chemical changes.The ionic equation for the given reaction is:3K+(aq) + 3OH-(aq) + Cr3+(aq) + 3Cl-(aq) → 3K+(aq) + 3Cl-(aq) + Cr(OH)3(s)The spectator ions are K+ and Cl-.2)

PrecipitateThe precipitate is formed when the two reactants are combined together, and it can be identified from the ionic equation. In this reaction, the precipitate is formed when KOH is added to the aqueous solution of chromium(III) chloride.The formula for the precipitate formed in this reaction is Cr(OH)3.3) Sum of all coefficientsThe net ionic equation represents the actual chemical change occurring in the reaction.

The spectator ions are removed, and only the ions that participate in the reaction are shown. The net ionic equation for the given reaction is:Cr3+(aq) + 3OH-(aq) → Cr(OH)3(s)The sum of all coefficients in the net ionic equation is 4.

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To form each of the monochlorination products shown, you will need to draw curved arrows that demonstrate the propagation steps. The first step is when a chlorine radical combines with the double bond to form a chlorine radical cation, which then donates an electron to the double bond.

This results in the formation of two radical chlorides, one on each carbon atom. These radicals then combine with two hydrogen atoms to form the monochlorination product, completing the reaction.The curved arrows for this process should be drawn as follows:

An arrow pointing from the chlorine radical to the double bond, representing the attack of the radical all arrows have been drawn, the monochlorination product has been formed. The mechanism of propagation steps to form each monochlorination product is shown in the following reaction:To represent this reaction, you can draw a curved arrow to show the movement of electrons from the bond to the chlorine. The arrow should start from the carbon-carbon double bond and point towards the chlorine.

Then, another curved arrow can be drawn to represent the formation of the C-Cl bond. The arrow should start from the chlorine and point towards the carbon with the unpaired electron.This process can be repeated to form the second monochlorination product. The following diagram shows the mechanism of the propagation steps:Here, you can see that the curved arrows are used to represent the movement of electrons during the reaction. The arrows point towards the atom that is gaining the electrons.

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The correct electron configuration for Tc (technetium) is [Kr] 5s² 4d⁵. Therefore, the correct answer is: [kr]5s²4d⁵.

Technetium (Tc) is a radioactive chemical substance with the atomic number 43 and symbol Tc. It is a silvery-gray metal that belongs to the transition metals group on the periodic table. Technetium is the first element to be artificially produced, and all of its isotopes are radioactive, with no stable isotopes. It is a highly toxic and dangerous element, and therefore has no significant commercial applications. Technetium has many nuclear and medical applications due to its radioactivity, and is used in medical imaging, cancer treatment, and scientific research.

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Answer:

C

Explanation:

edg 2023

The volume ratios from the equation 2H2 + O2 → 2H2O are:

The coefficients in a balanced chemical equation give the ratio of moles of reactants and products. From the equation 2H2 + O2 → 2H2O, we can see that:

Therefore, the following volume ratios are valid:

What are the reactants?

The reactants are the substances that participate in a chemical reaction and are consumed to form new products. In the equation 2H2 + O2 → 2H2O, the reactants are hydrogen gas (H2) and oxygen gas (O2). These reactants undergo a chemical reaction to form water (H2O) as the product.

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Answer:

The compound has 187.5 g. of Carbon

Explanation:

If the 100% of the compound is 250 gr, then you can calculate the 75% of it by multiplying:

Amount of Carbon = (75%) 250 g.

75%= 0.75

250  (0.75)

= 187.5 g.

Explanation: the resistance that one surface or object encounters when moving over another.

or

the action of one surface or object rubbing against another.

Answer: a force that resists the motion of one object against another

The formal charge on the Z atom in the [ZO2]-1 ion is +1.

The Lewis dot structure for the [ZO2]-1 molecular ion is:

          O

          |

    Z === O

          |

          O-

1.   Determine the total number of valence electrons in the ion by adding the valence electrons of each atom and the charge of the ion.

2.  Connect the Z atom to each O atom with a single bond, which uses up 2 electrons.

3.  Add the remaining electrons in pairs as lone pairs to each atom until all valence electrons are used up.

4.  Draw the Lewis dot structure.

O

|

Z === O

|

O-

5.  Calculate the formal charge on the Z atom using the formula:

Formal charge = valence electrons - (number of lone pair electrons + 1/2 x number of bonding electrons)

Formal charge = 4 - (2 + 1/2 x 2) = 4 - 3 = +1

Therefore, the formal charge on the Z atom in the [ZO2]-1 ion is +1.

What is valence electron?

A valence electron is an electron in the outer shell associated with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed.

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The first two statements are false, whereas the last statement, which says that pressure and volume of a gas are inversely related, is true.

Statement 1: This claim was incorrect because, according to the ideal gas law, PV=nRT, pressure (P) and volume (V) are inversely proportional to each other at a constant temperature (T) and amount of gas (n). This means that as pressure increases, volume decreases. This relationship is known as Boyle's law. Therefore, the statement that pressure has no effect on volume of a gas is false.

Statement 2: This claim was incorrect because, pressure and volume of a gas are inversely related according to Boyle's law, which states that at a constant temperature, the pressure of a gas is inversely proportional to its volume. This means that if the pressure of a gas increases, its volume will decrease, and if the pressure decreases, the volume will increase, as long as the temperature remains constant.

Statement 3: This claim was correct because, According to Boyle's law, the pressure and volume of a gas are inversely proportional to each other, which means that when the pressure of a gas increases, its volume will decrease and vice versa, as long as the temperature and the number of particles in the gas are kept constant. This relationship is expressed mathematically as P₁V₁ = P₂V₂, where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.

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Strong bases like sodium ethoxide (NaOEt) or sodium hydroxide (NaOH) are used to treat 2-bromooctane, which then goes through an elimination process (also known as dehydrohalogenation) to produce various alkenes.

Ethene, propene, butene, and pentene are the first four alkenes.

Alkenes are a group of unsaturated hydrocarbons (i.e., molecules with solely carbon and hydrogen) that include at least one double bond from carbon to carbon. Olefins is a different name for alkenes. Due to the double bond, alkenes are more reactive than alkanes.

Both the hydrocarbons alkene and alkyne are unsaturated.

Whereas two Carbon atoms in Alkyne are joined by a triple bond, two Carbon atoms in Alkene only have a double bond.

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The hydronium ion concentration, [H+] of a solution with a pH of 6.82 is 1.51 × 10-⁷ M.

The hydrogen or hydronium ion concentration of a solution can be calculated from the pH using the following formula;

pH = - log {H+}

[H+] = 10−pH

by exponentiating both sides with base 10, we can "undo" the common logarithm.

{H+} = 10-⁶.⁸²

{H+} = 0.000000151356

[H+] = 1.51 × 10-⁷ M

Therefore, the hydronium ion concentration with a pH of 6.82 is 1.51 × 10-⁷ M.

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Answer: Cleavage

Explanation:

When a mineral breaks along a weekly bonded plane it is called cleavage

Answer:

Ca is a reducing agent and O is the oxidizing agent.

Explanation:

calcium is the reducing agent as it reduces oxygen while it oxidize itself and oxygen is an oxidising agent because it oxidized others and reduces itself. in this equation oxygen is reducing and Calcium is oxidising. and as it is stated in the definition that oxidizing agent is the agent which oxidises others and reduces itself and it is also stated that reducing agent reduces others and oxidize itself. so based on this statement calcium is reducing agent and O is a oxidizing agent.

Answer:

Using C2H4 + 3 O2 -> 2 CO2 + 2 H2O. If 20 moles of fuel are combusted in the above equation, how many moles of O2 are consumed?

Explanation:

According to the balanced chemical equation:

1 mole of C2H4 reacts with 3 moles of O2

Therefore, for 20 moles of C2H4 combusted, we would need:

20 moles C2H4 × (3 moles O2 / 1 mole C2H4) = 60 moles O2

So, 60 moles of O2 are consumed in the combustion of 20 moles of C2H4.