To the nearest tenth of a second, the ball is in the air for s.

Answers:

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Explanation:

The domain is the set of allowed x input values, aka the set of all allowed x coordinates of the points. We see that [tex]-4 < x \le 3[/tex]. It might help to draw vertical lines through the endpoints until you reach the x axis. Note the open hole at x = -4 to indicate we do not include this as part of the domain (hence the lack of "or equal to" for the first inequality sign).

The interval [tex]-4 < x \le 3[/tex] then can be condensed into the shorthand form (-4, 3] which is the domain in interval notation.

It says: x is between -4 and 3. It can't equal -4 but it can equal 3.

So the use of parenthesis versus square brackets tells the reader which endpoint is included or not.

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The range describes all possible y outputs. We see that y = 5 is the largest it gets and y = -5 is the lower bound. It might help to draw horizontal lines through the endpoints until you reach the y axis. The open hole means -5 is not part of the range.

The range as a compound inequality is [tex]-5 < y \le 5[/tex]. This condenses into the shorthand of (-5, 5] which is the range in interval notation.

Verbally, the range is the set of y values such that y is between -5 and 5. It can't equal -5 but it can equal 5.

Answer:

Hello,

Step-by-step explanation:

Domain(f)= ]-4;3]={x€R | -4<x≤3}

Rang(f)=]-5;5]={y€R | -5< y ≤5}

Step-by-step explanation:

hope this helps to u......

Use main properties of powers

(a^m)^n=a^{m\cdot n};(am)n=am⋅n;

\dfrac{1}{a^n}=a^{-n}an1=a−n

to simplify given equation.

1.

4^x=(2^2)^x=2^{2x}.4x=(22)x=22x.

2.

\left(\dfrac{1}{8}\right)^{x+5}=\left(\dfrac{1}{2^3}\right)^{x+5}=(2^{-3})^{x+5}=2^{-3x-15}.(81)x+5=(231)x+5=(2−3)x+5=2−3x−15.

3. Then the equation is

2^{2x}=2^{-3x-15}.22x=2−3x−15.

The bases are the same, so equate the powers:

2x=-3x-15,

2x+3x=-15,

5x=-15,

x=-3.

Answer: for x=-3.

Answer:  [tex](x-3)^2 + (y-2)^2 = 16[/tex]

Explanation:

The center of this circle is point A(3,2). These coordinates are the (h,k) values.

The radius is r = 4

Plug those three items into the template [tex](x-h)^2 + (y-k)^2 = r^2[/tex] to arrive at the final answer shown above.

Step-by-step explanation:

[tex]15)2n \\ 16)1 \times {10}^{7} \\ 17) {m}^{5} \\ 18)xy \\ 19)5 {n}^{2} - 6 \\ = - 6 \\ 20)9 {a}^{ 3} + 1 \\ = \frac{d}{da} (9a {}^{ 3} + 1) \\ 21) {x}^{3} . {y}^{3} \\ = (x.y) {}^{3} \\ = {x}^{3} {y}^{3} \\ 22)c {}^{4} .d {}^{6} \\ = {c}^{4} {d}^{6} \\ 23)3e + {e}^{2} \\ = e(e + 3) \\ \\ \\ hope \: it \: is \: help \: to \: you[/tex]

15 2 times n

16 10 race to the power 7

17 m race to the power 5

18 x times y

19 6 subtracted from 5 times n race to the power 2

20 1 added to 9 times a race to the power 3

21 x race to the power 3 times y race to the power 2

22 c race to the power 4 times d race to the power 6

23 3 times e added to 2 times e race to the power 2

Must click thanks and mark brainliest

Answer:

the correct answer is C

Step-by-step explanation:

first step you change the x and y powers to the square root(showing in the pic).

second the number outside of the parenthesis times the numbers inside the parenthesis and then you just figure it out how it works...

Answer:

10

Step-by-step explanation:

2000/ 2x = 10

Multiply each side by 2x

2000/ 2x = 10 *2x

2000 = 20x

Divide by 20

2000/20 = 20x/20

100 = x

Take the square root of each side

sqrt(100) = sqrt(x)

10 = sqrt(x)

Answer:

Domain is all real numbers, and range is all numbers greater than or equal to -2.  If thee was anything you didn't understand let me know.  

Step-by-step explanation:

The domain is what x values work, or it may be better to say the horizontal axis.  is there any number you cannot use?  if you cannot tell, this is a parabola, like x^2.  Is there any number you cannot plug into x^2.  The answer is no, the domain for all parabolic functions is all real numbers.

The range you really want to look at visually here.  Range is y values you can get, or values on the vertical axis.  I would also compare it to x^2 again.  You should know you can make it as high as you want, here is the same.  but at -2, there is no point below that.  so the range is -2 and up

The other options are just specific numbers.  you can disprove those by choosing a number not on their lists.  For the domain literally any other number.  For range any number not on the list greater than -2

A sample space is the space of all the possible outcomes in this event.

Let's define each outcome as:

(first marble, second marble)

Where the first marble can be green or red.

The second marble can be blue or yellow.

Then the possible outcomes are:

(green, yellow)

(green, blue)

(red, yellow)

(red, blue)

So we have four different outcomes, which means that the sample space has 4 elements.

Notice that the number of marbles of each color does not affect this, these numbers only affect the probability of each one of these possible outcomes.

If you want to learn more, you can read:

https://brainly.com/question/24329720

Answer:

area of base = pi x radius^2 = (ill use 3.14 as pi)

3.14 x 7^2 = 153.86 in^2

height = 12

circunference of base = 2 x pi x radius or pi x diameter (diameter = 2 x radius) = 3.14 x 14 = 43.96 in

surface area = perimeter of base x height (lateral area) + 2 x area of base

= 43.96 x 12 = 527.52 + 2(153.86) = 835.24

hope that answers your question

(be careful, i generally use 3.14 as pi, but if your question says to use other forms as pi, then just replace pi as what the question asks, ive given you the formulas on how to calculate area and circumf., so i hope it should be easier...)

Answer:

916.11 ft³

Step-by-step explanation:

(9×6)×7.83/2×13/3

= 211.41×13/3

= 916.11 ft³

Answered by GAUTHMATH

Answer:

916.11 ft³

Step-by-step explanation:

9514 1404 393

Answer:

  after 89 years

Step-by-step explanation:

For principal p, interest rate r, and number of years t, the two account balances are ...

  a = p·e^(rt) . . . . continuous compounding

  a = p(1+r)^t . . . . annual compounding

Using the given values, we have

  3000·e^(0.07t) . . . . . compounded continuously

  20000·1.05^t . . . . . . compounded annually

We want to find t so these are equal.

  3000·e^(0.07t) = 20000·1.05^t

  0.15e^(0.07t) = 1.05^t . . . . divide by 20,000

  ln(0.15) +0.07t = t·ln(1.05) . . . . take natural logarithms

  ln(0.15) = t·(ln(1.05) -0.07) . . . . subtract 0.07t

  t = ln(0.15)/(ln(1.05) -0.07) ≈ -1.8971/-0.02121 . . . . . divide by the coefficient of t

  t ≈ 89.4 ≈ 89

The two accounts will have the same balance after 89 years.

Answer:

Hello,

Step-by-step explanation:

[tex]\dfrac{x^{\frac{5}{6}} }{x^{\frac{1}{6}} } \\\\=x^{\frac{5}{6} -\frac{1}{6} }\\\\=x^{\frac{4}{6} }\\\\=x^{\frac{2}{3} }\\\\=\sqrt[3]{x^2}[/tex]

Hi there!

Look the picture for your answer.

Hope it helps!

Answer:

Step-by-step explanation:

[tex]\frac{\sqrt{x}+1 }{x-\sqrt{x}+1 }=\frac{\sqrt{x}+1}{(x+1)-\sqrt{x}}\\\\=\frac{(\sqrt{x}+1)([x+1]+\sqrt{x})}{([x+1]-\sqrt{x})+([x+1)+\sqrt{x}])}\\\\=\frac{\sqrt{x}*x+\sqrt{x}*1+\sqrt{x}*\sqrt{x}+1*x+1*1+1*\sqrt{x}}{(x+1)^{2}-(\sqrt{x})^{2}}\\\\\\=\frac{x\sqrt{x}+\sqrt{x}+x+1+x+\sqrt{x}}{x^{2}+2x+1-x}\\\\=\frac{x\sqrt{x}+2\sqrt{x}+2x+1}{x^{2}+x+1}\\\\[/tex]

Answer:

The Polynominal is not shown. So how can i answer???

Step-by-step explanation:

Thank You! Hope it helps! Please Mark me brainliest!

Answer:

B

Ive had this before

Answer:

RS, RT, ST

Step-by-step explanation:

We require the third angle in the triangle

∠ T = 180° - (92 + 71)° = 180° - 163° = 17°

The shortest side is opposite the smallest angle

∠ T = 17° → opposite side RS

The longest side is opposite the largest angle

∠ R = 92° → opposite side ST

Then sides from shortest to longest is

RS, RT, ST

Answer:

[tex]\sqrt{-16} +8[/tex]

[tex]=4i+8[/tex]

OAmalOHopeO

Because all the angles are congruent (the same), this is an equilateral triangle. All equilateral triangles have congruent angles and congruent sides, so all sides has to be 14.

Answer:

The answer is "C" f(x)= x+ 4 and g(x)= x^3 - 1

Step-by-step explanation:

all you have to do is replace the x in "G" with the "F" function

F(x) = x+4  and  G(x) = x^3-1

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Explanation:

Let's try choice A to see if it works or not

G(x) = (x+4)^3

G( F(x) ) = ( F(x)+4 ) ^3 .... replace every x with F(x)

G( F(x) ) = ( x-1+4 ) ^3 .... plug in F(x) = x-1

G( F(x) ) = (x+3)^3

This isn't the same as (x+4)^3 - 1. You can confirm this with a graph or a table of values. We cross choice A off the list.

------------

Let's try choice B

G(x) = x+4

G( F(x) ) = F(x)+4

G( F(x) ) = x^3-1 + 4

G( F(x) ) = x^3 + 3

Similar to choice A, this isn't the same as (x+4)^3-1. We can cross this off the list as well.

--------------

Now choice C

G(x) = x^3 - 1

G( F(x) ) = ( F(x) )^3 - 1

G( F(x) ) = (x+4)^3 - 1

We found the final answer.

Answer:

x = 12

Step-by-step explanation:

The sum of the two smaller angles is 140

80+5x = 140

Subtract 80 from each side

80+5x-80 =140-80

5x = 60

Divide each side by 5

5x/5 = 60/5

x = 12

Answer:

C. 12 for $6.00

Step-by-step explanation:

Answer:

C. 12 for $6.00

Step-by-step explanation:

better than $13.00 for 24. as that'd be $6.50 for 12..

Answer:

I don't know ask to your teacher

The combined radical is: [tex]- 26\sqrt{3}[/tex]

The radical is given as:

[tex]- 12\sqrt{12} - 2\sqrt{3}[/tex]

We start by expressing 12 as 4 * 3

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 12\sqrt{4* 3} - 2\sqrt{3}[/tex]

Split the radical

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 12\sqrt{4}* \sqrt{3} - 2\sqrt{3}[/tex]

Take square root of 4

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 12*2* \sqrt{3} - 2\sqrt{3}[/tex]

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 24* \sqrt{3} - 2\sqrt{3}[/tex]

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 24\sqrt{3} - 2\sqrt{3}[/tex]

Combine like terms

[tex]- 12\sqrt{12} - 2\sqrt{3} = - 26\sqrt{3}[/tex]

Hence, the combined radical is: [tex]- 26\sqrt{3}[/tex]

Read more about surd radicals at:

https://brainly.com/question/14923091

7(5 + t) - 4(t + 4) =

= 35 + 7t - 4t - 16 =

= 7t - 4t + 35 - 16 = 3t + 19

Answer:

x = 1, x = 2

Step-by-step explanation:

Given

3x(x - 2) = x² - 4 ← distribute parenthesis on left side

3x² - 6x = x² - 4 ( subtract x² - 4 from both sides )

2x² - 6x + 4 = 0 ( divide through by 2

x² - 3x + 2 = 0 ← in standard form

Consider the factors of the constant term (+ 2) which sum to give the coefficient of the x- term (- 3)

The factors are - 1 and - 2 , since

- 1 × - 2 = + 2 and - 1 - 2 = - 3 , then

(x - 1)(x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 2 = 0 ⇒ x = 2