Trace the evaluation of the following expressions, and give their resulting values. Make sure to give a value of the appropriate type (such as including a .0 at the end of a double or quotes around a String).
4 + 1 + 9 + "." + (-3 + 10) + 11 / 3
8 + 6 * -2 + 4 + "0" + (2 + 5)
1 + 1 + "8 - 2" + (8 - 2) + 1 + 1
5 + 2 + "(1 + 1)" + 4 + 2 * 3
"1" + 2 + 3 + "4" + 5 * 6 + "7" + (8 + 9)

Answer:

hi..,.................................................

Answer:

The program in Python is as follows:

def ASCIIsum(str1,str2):

   asciisum1 = 0;    asciisum2 = 0

   for chr in str1:

       asciisum1 += (ord(chr) - 96)

   for chr in str2:

       asciisum2 += (ord(chr) - 96)

   if asciisum1 > asciisum2:

       return True

   else:

       return False

str1 = input("Enter first string: ")

str2 = input("Enter second string: ")

if ASCIIsum(str1,str2) == True:

   print(str1,"has a higher ASCII value")

else:

   print(str2,"has a higher ASCII value")

Explanation:

This defines the function

def ASCIIsum(str1,str2):

This initializes the ascii sum of both strings to 0

   asciisum1 = 0;    asciisum2 = 0

This iterates through the characters of str1 and add up the ascii values of each character

   for chr in str1:

       asciisum1 += (ord(chr) - 96)

This iterates through the characters of str2 and add up the ascii values of each character

   for chr in str2:

       asciisum2 += (ord(chr) - 96)

This returns true if the first string has a greater ascii value

   if asciisum1 > asciisum2:

       return True

This returns false if the second string has a greater ascii value

   else:

       return False

The main begins here

This gets input for first string

str1 = input("Enter first string: ")

This gets input for second string

str2 = input("Enter second string: ")

If the returned value is True

if ASCIIsum(str1,str2) == True:

Then str1 has a greater ascii value

   print(str1,"has a higher ASCII value")

If otherwise

else:

Then str2 has a greater ascii value

   print(str2,"has a higher ASCII value")

Answer: Users expect to see a certain pattern in the data

Explanation:

Confirmatory Data Analysis occurs when the evidence is being evaluated through the use of traditional statistical tools like confidence, significance, and inference.

In this case, there's an hypothesis and the aim is to determine if the hypothesis is true. In this case, we want to know if a particular pattern on the data visualization conforms to what we have.

Answer:

Here the answer is given as follows,

Explanation:

import seaborn as sns  

import pandas as pd  

df = {'country': ['US', 'US', 'US', 'US', 'UK', 'UK', 'UK'],  

  'year': [2008, 2009, 2010, 2011, 2008, 2009, 2010],  

  'Happiness': [4.64, 4.42, 3.25, 3.08, 3.66, 4.08, 4.09],  

  'Positive': [0.85, 0.7, 0.54, 0.07, 0.1, 0.92, 0.94],  

  'Negative': [0.49, 0.09, 0.12, 0.32, 0.43, 0.21, 0.31],  

  'LogGDP': [8.66, 8.23, 7.29, 8.3, 8.27, 6.38, 6.09],  

  'Support': [0.24, 0.92, 0.54, 0.55, 0.6, 0.38, 0.63],  

  'Life': [51.95, 55.54, 52.48, 53.71, 50.18, 49.12, 55.84],  

  'Freedom': [0.65, 0.44, 0.06, 0.5, 0.52, 0.79, 0.63, ],  

  'Generosity': [0.07, 0.01, 0.06, 0.28, 0.36, 0.33, 0.26],  

  'Corruption': [0.97, 0.23, 0.66, 0.12, 0.06, 0.87, 0.53]}  

dataFrame = pd.DataFrame.from_dict(df)  

explanatory_vars = ['LogGDP', 'Support', 'Life', 'Freedom', 'Generosity', 'Corruption']  

plot_vars = ['Happiness'] + explanatory_vars  

sns.pairplot(dataFrame,  

            x_vars = explanatory_vars,  

            dropna=True,  

            palette="Blues")    

Answer:

if (numCycles < 1){

        System.out.println("Too few.");

     }

     else if (numCycles > 4){

        System.out.println("Too many.");

        }    

  else{

     for(int i = 1; i <= numCycles; i++)

  {

     System.out.println(i + ": Lather and rinse.");

  }

     System.out.println("Done.");

  }

Explanation:

Answer:

Local Area Network

Explanation:

In the Information technology it is called Local Area Network.

there are ten letters in the word, so for the first position we can choose out of 10 option.

no matter wich specific option we choose, we will have 9 letters left for the 2nd letter.

and 8 for the third place.

...

when we will have used up 9 of 10 letters, there will be only one option for the last place.

the number of possible decision-paths is therefore given by this expression:

10*9*8*7*6*5*4*3*2*1

wich is 3,628,800

there are quite a few ways to rearrange 10 letters

The sorting method which commands entries in a going to head predicated on each character without regard to space as well as punctuation, therefore there are 3628800 ways.

So, as [tex]\bold{ 10\times 9 \times 8.... \times 3 \times 2 \times 1 = 362,8800}[/tex] ways, we have such a total number of ways.

Learn more:

brainly.com/question/17276660

Answer:

The right approach is Option d (Automated information systems).

Explanation:

Other choices aren't related to the given scenario. So the above is the appropriate one.

Answer:

Step Out

Explanation:

In the field of computer science, the control flow or the flow of control is defined as the order where the individual statements, [tex]\text{function calls}[/tex] or instructions of a program are [tex]\text{evaluated or executed. }[/tex]

The Step Out control flow program runs to the [tex]\text{end of the code block}[/tex] and it resumes the [tex]\text{break mode}[/tex] at the statement that it follows.

Answer:

Based on the requirements indicated in the question above, the best Local Area Network (LAN) operating system that can be used is

Windows 7 , 8.1 or Windows 10. This is because they all are configured to handle extensive LAN activity and can connect over 200 users.

Explanation:  

Generally speaking, Windows 10 packs more improvement over the previous windows.

Cheers

Answer: is this a real question but I think it would be Ip address hope this helps :)))

Explanation:

Answer:

Meta tag

Explanation:

Answer:

Following are the solution to the given question:

Explanation:

The common folder called Report has also been shared. Writing access to a shared folder was given to management group members. Mark is a member of a group of managers. We can access the files within your reporting directory, but you really should not access the Confidential.xls file. We want to add Mark Mangum to our ACL files using Deny permissions on Confidential.xls.

Answer:

A software where you can document letters, essays or anything really.

Explanation:

Answer:

Job order production

Explanation:

A job order production has the least flexibility and is best suited for mass production.

It also has an arrangement of machines that process identical products in a predefined order, with automatic movement of materials between machines.

brainleist please..

Answer -------> Transfer line <---------

please click on the picture look at the PICTURE for the correct answer.

Answer:

Denial of service attack.

Explanation:

In Cybersecurity, vulnerability can be defined as any weakness, flaw or defect found in a software application or network and are exploitable by an attacker or hacker to gain an unauthorized access or privileges to sensitive data in a computer system.

This ultimately implies that, vulnerability in a network avail attackers or any threat agent the opportunity to leverage on the flaws, errors, weaknesses or defects found in order to compromise the security of the network.

Data theft can be defined as a cyber attack which typically involves an unauthorized access to a user's data with the sole intention to use for fraudulent purposes or illegal operations. There are several methods used by cyber criminals or hackers to obtain user data and these includes DDOS attack, SQL injection, man in the middle, phishing, sniffing, DOS attack, etc.

A denial of service (DOS) attack is a form of cyber attack that involves either the exploitation of a software flaw or overwhelmingly floods a computer system in a network with traffic in order to prevent authorized users from performing legitimate activities or transactions.

Some of the ways to prevent vulnerability or cyber attacks in a network are;

1. Ensure you use a very strong password with complexity through the use of alphanumerics.

2. You should use a two-way authentication service.

3. You should use encrypting software applications or services.

Base to be converted to was not included but we would assume conversion to base 10(decimal)

Answer and Explanation:

The 3DF in base 16 is a hex number so we need to convert to its equivalent binary/base 2 form:

We therefore each digit of given hex number 3DF in base 16 to equivalent binary, 4 digits each.

3 = 0011

D = 1101

F = 1111

We then arrange the binary numbers in order

3DF base 16 = 1111011111 in base 2

We then convert to base 10 =

= 1x2^9+1x2^8+1x2^7+1x2^6+0x2^5+1x2^4+1x2^3+1x2^2+1×2^1+1×2^0

= 991 in base 10

The correct answer to this open question is the following.

Unfortunately, you did not provide any context or background about the situation of Sally and the problem with her slides. We do not know it, just you.

However, trying to be of help, we can comment on the following general terms.

When someone does not meet professional expectations, this means that this individual did not prepare her presentation, lacked technical skills, did not included proper sources, or missed the proper visual aids to make the presentation more attractive and dynamic.

What Sally can improve about her slides is the following.

She can design a better structure for the presentation to have more congruence.

Sally has to clearly establish the goal or goals for her presentation.

She has to add many visuals instead of plain text. This way she can better capture the interest of her audience.

If she can use more vivid colors instead of pale or dark ones, that would be best.

No paragraphs unless necessary. She better uses bullet points.

Take care of the tone of her voice. During her practice, she can record her vice to check how it sounds.

Incomplete question. Here's the full question:

Data-Time Inc. is a company that manages databases for a large city in Colorado. Included in these databases is information collected from the city’s homeless shelters and free clinics. Specifically, the databases contain personal information of the users of these services over the past 10 years; this includes people’s Social Security numbers and health records.

This data is highly secure and only accessible to the employees of Data-Time Inc. Employees are given a laptop when they are hired which allows them to access the database remotely. Unfortunately, one of these laptops is stolen and the security of the database is compromised.

A majority of the people whose information was compromised are homeless; therefore there is no easy way to contact them in order to alert them of the security breach. How should Data-Time Inc. manage this breach in security?

Explanation:

Since the emphasis is not on reversing the breach that has occurred, but on managing the level of security damage that could occur, it is important measures are directed towards preventing unauthorized access to sensitive information.

For example, the Media Access Control Address (MAC address) of the laptop if known could be greylisted from accessing the server that contains the sensitive information.

Answer:

Explanation:

The following code is written in Java. It creates a GetColors method that takes in the two parameter colors of either red, blue or yellow. It combines those colors and returns the mix of the two colors back to the user. A test case has been used in the main method and the output can be seen in the attached image below.

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       System.out.println(GetColors("yellow", "red"));

   }

   public static String GetColors(String color1, String color2) {

       if (color1 == "red") {

           if (color2 == "blue") {return "purple";}

           else if (color2 == "yellow") {return "orange";}

           else {return "red";}

       } else if (color1 == "blue") {

           if (color2 == "red") {return "purple";}

           else if (color2 == "yellow") {return "green";}

           else {return "blue";}

       } else if (color1 == "yellow") {

           if (color2 == "red") {return "orange";}

           else if (color2 == "blue") {return "green";}

           else {return "yellow";}

       } else {

           return "Wrong Parameters";

       }

   }

}

Answer:

---------------------------

Explanation:

Answer:

"Warm; Cool/receding" is the correct answer.

Explanation:

Thus the above is the right answer.

Answer:

it is....insert tab..B

Explanation:

insert tab includes editing options

Answer:

The given statement is "True".

Explanation:

Answer:

Network scan

Explanation:

Cyber security can be defined as preventive practice of protecting computers, software programs, electronic devices, networks, servers and data from potential theft, attack, damage, or unauthorized access by using a body of technology, frameworks, processes and network engineers.

Some examples of cyber attacks are phishing, zero-day exploits, denial of service, man in the middle, cryptojacking, malware, SQL injection, spoofing etc.

Generally, a security assessment is carried out by network security experts on a regular basis to determine potential loopholes or vulnerabilities in the information and technology (IT) infrastructure. One of the techniques or approach used in security assessment is a network scan.

A network scan is a security assessment technique used for the automatic detection of host systems on a network. Although a network scan isn't capable of discovering or detecting all the weaknesses on a network, it avails users information about the computer systems that are active on the network and what services the computer systems offer or what ports are available on them.

Automation tools allow applications, businesses, teams or organizations to automate their processes which could be deployment, execution, testing, validation and so on. Automation tools help increase the speed at which processes are being handled with the main aim of reducing human intervention.

Linkedln automation tools are designed to help automate certain processes in Linkedln such as sending broadcast messages, connection requests, page following and other processes with less or no human or manual efforts. Some of these automation tools include;

i. Sales navigator for finding right prospects thereby helping to build and establish trusting relationships with these prospects.

ii. Crystal for providing insights and information about a specified Linkedln profile.

iii. Dripify used by managers for quick onboarding of new team members, assignment of roles and rights and even management of subscription plans.  

Answer:

Well, for me I personally use LinkedCamap to drive more LinkedIn connections, hundreds of leads, sales, and conversions automatically.  

Some other LinkedIn automation tools are;  

Hope this helps!

Answer:

Multiple devices can be connected

The social network created through digital technology is referred to as a "digital network." It provides phone, video, data, and other network services for digital switching and transmission.

In order to align the network with business demands, it has markets, data networks, and communications networks.

Digital networks' core are networking components like switches, routers, and access points. These tools are used to link networks to other networks, secure equipment like computers and servers connected to organizational networks, and analyze data being sent across networks.

Through cloud-enabled central administration, digital networks provide end-to-end network services for on-premises and cloud space. All network components are monitored, analyzed, and managed by a central server.

Therefore, The social network created through digital technology is referred to as a "digital network." It provides phone, video, data, and other network services for digital switching and transmission.

To learn more about Technology, refer to the link:

https://brainly.com/question/9171028

#SPJ2

Answer:

The Rich Text Format is a proprietary document file format with published specification developed by Microsoft Corporation from 1987 until 2008 for cross-platform document interchange with Microsoft products.

Answer:

removeDuplicates() function:-

//removeDuplicates() function removes duplicate elements form linked list.

   void removeDuplicates() {

       //declare 3 ListNode pointers ptr1,ptr2 and duplicate.

       //initially, all points to null.

       ListNode ptr1 = null, ptr2 = null, duplicate = null;

       //make ptr1 equals to head.

       ptr1 = head;

        //run while loop till ptr1 points to second last node.

       //pick elements one by one..

       while (ptr1 != null && ptr1.next != null)

       {

               // make ptr2 equals to ptr1.

               //or make ptr2 points to same node as ptr1.

           ptr2 = ptr1;

           //run second while loop to compare all elements with above selected element(ptr1->val).

           while (ptr2.next != null)

           {

              //if element pointed by ptr1 is same as element pointed by ptr2.next.

               //Then, we have found duplicate element.

               //Now , we have to remove this duplicate element.

               if (ptr1.val == ptr2.next.val)

               {

                  //make duplicate pointer points to node where ptr2.next points(duplicate node).

                       duplicate = ptr2.next;

                       //change links to remove duplicate node from linked list.

                       //make ptr2.next points to duplicate.next.

                   ptr2.next = duplicate.next;

               }

             //if element pointed by ptr1 is different from element pointed by ptr2.next.

               //then it is not duplicate element.

               //So, move ptr2 = ptr2.next.

               else

               {

                   ptr2 = ptr2.next;

               }

           }

           //move ptr1 = ptr1.next, after check duplicate elements for first node.

           //Now, we check duplicacy for second node and so on.

           //so, move ptr1  by one node.

           ptr1 = ptr1.next;

       }

   }

Explanation:

Complete Code:-

//Create Linked List Class.

class LinkedList {

       //Create head pointer.

       static ListNode head;

       //define structure of ListNode.

       //it has int val(data) and pointer to ListNode i.e, next.

   static class ListNode {

       int val;

       ListNode next;

       //constructor to  create and initialize a node.

       ListNode(int d) {

               val = d;

           next = null;

       }

   }

//removeDuplicates() function removes duplicate elements form linked list.

   void removeDuplicates() {

       //declare 3 ListNode pointers ptr1,ptr2 and duplicate.

       //initially, all points to null.

       ListNode ptr1 = null, ptr2 = null, duplicate = null;

       //make ptr1 equals to head.

       ptr1 = head;

       //run while loop till ptr1 points to second last node.

       //pick elements one by one..

       while (ptr1 != null && ptr1.next != null)

       {

               // make ptr2 equals to ptr1.

               //or make ptr2 points to same node as ptr1.

           ptr2 = ptr1;

           //run second while loop to compare all elements with above selected element(ptr1->val).

           while (ptr2.next != null)

           {

              //if element pointed by ptr1 is same as element pointed by ptr2.next.

               //Then, we have found duplicate element.

               //Now , we have to remove this duplicate element.

               if (ptr1.val == ptr2.next.val)

               {

                  //make duplicate pointer points to node where ptr2.next points(duplicate node).

                       duplicate = ptr2.next;

                       //change links to remove duplicate node from linked list.

                       //make ptr2.next points to duplicate.next.

                   ptr2.next = duplicate.next;

               }

             //if element pointed by ptr1 is different from element pointed by ptr2.next.

               //then it is not duplicate element.

               //So, move ptr2 = ptr2.next.

               else

               {

                   ptr2 = ptr2.next;

               }

           }

           //move ptr1 = ptr1.next, after check duplicate elements for first node.

           //Now, we check duplicacy for second node and so on.

           //so, move ptr1  by one node.

           ptr1 = ptr1.next;

       }

   }

   //display() function prints linked list.

   void display(ListNode node)

   {

       //run while loop till last node.

       while (node != null)

       {

               //print node value of current node.

           System.out.print(node.val + " ");

           //move node pointer by one node.

           node = node.next;

       }

   }

   public static void main(String[] args) {

       //Create object of Linked List class.

       LinkedList list = new LinkedList();

       //first we create nodes and connect them to form a linked list.

       //Create Linked List 1-> 2-> 3-> 2-> 4-> 2-> 5-> 2.

       //Create a Node having node data = 1 and assign head pointer to it.

       //As head is listNode of static type. so, we call head pointer using class Name instead of object name.

       LinkedList.head = new ListNode(1);

       //Create a Node having node data = 2 and assign head.next to it.

       LinkedList.head.next = new ListNode(2);

       LinkedList.head.next.next = new ListNode(3);

       LinkedList.head.next.next.next = new ListNode(2);

       LinkedList.head.next.next.next.next = new ListNode(4);

       LinkedList.head.next.next.next.next.next = new ListNode(2);

       LinkedList.head.next.next.next.next.next.next = new ListNode(5);

       LinkedList.head.next.next.next.next.next.next.next = new ListNode(2);

       //display linked list before Removing duplicates.

       System.out.println("Linked List before removing duplicates : ");

       list.display(head);

       //call removeDuplicates() function to remove duplicates from linked list.

       list.removeDuplicates();

       System.out.println("")

       //display linked list after Removing duplicates.

       System.out.println("Linked List after removing duplicates :  ");

       list.display(head);

   }

}

Output:-