Translate the problem into a mathematical sentence, using was your variable
name. Do not use spaces in your answer.
Lisa bought 15 CDs in December. Of those, 3 were jazz, the rest were world
music. How many world music discs did she buy?
HELPPP

Hi there!

2|x - 1| + 5 < 13

Begin by subtracting 5 from both sides:

2|x - 1| < 8

Divide both sides by 2:

|x - 1| < 4

Find both the positive and negative solutions:

x - 1 < 4

x < 5

-(x - 1) < 4

-x + 1 < 4

-x < 3

x > -3

[tex]Hello[/tex] [tex]There![/tex]

Let's solve your inequality step-by-step.

[tex]2(|x-1|)+5<13[/tex]

Step 1:

You must add -5 both sides.

[tex]2(|x-1|)+5+-5<13+-5[/tex]

[tex]2(|x-1|)<8[/tex]

Step 2:

You must divide both sides by 2.

[tex]\frac{2(|x-1|)}{2}[/tex] [tex] \leq \frac{8}{2}[/tex]

[tex]|x-1|<4[/tex]

Step 3:

Solve the Absolute Value.

[tex]|x-1|<4[/tex]

We know that x−1<4 and x−1>−4.

[tex]x-1<4[/tex] Condition 1.

[tex]x-1+1<4+1[/tex] (Add 1 to both sides)

[tex]x<5[/tex]

[tex]x-1>-4[/tex] (Condition 2)

[tex]x-1+1>-4+1[/tex] (Add 1 to both sides)

[tex]x>-3[/tex]

[tex]ANSWER![/tex]

[tex]x<5[/tex] [tex]and[/tex] [tex]x>-3[/tex]

Hopefully, this helps you!!

[tex]AnimeVines[/tex]

Answer:

The quadratic formula: (-b+-sqrtb^2-4ac)/2a

Plugging in the values of a=1, b=9, and c=10, the roots of the equation are: -7.7 and -1.3.

So, the first option is correct.

Let me know if this helps!

Answer:

1) I know that if the two integers have the same sign: Add their absolute values and give the answer the same sign as the two original integers. Also, I know that If the two integers have different signs: Subtract the lesser absolute value from the greater absolute value.

2) To find the sum of a positive and a negative integer, take the absolute value of each integer and then subtract these values. The result takes the sign of the integer with the larger absolute value. The sum of any integer and its opposite is equal to zero.

3) First, draw a number line. Then, find the location of the first integer on the number line. Next, if the second integer is positive, move that many units to the right from the location of the first integer. If the second integer is negative, move that many units to the left from the location of the first integer.

4) 205 dollars

5) The fish’s location relative to the surface of the ocean is -85

6) Honestly, I'm not so sure about this now, but I believe yes.

Step-by-step explanation:

there are a lot of resources, here on this app, that i used to help answer your question. If I helped, it would be nice if you rated this brainliest, give 5 stars, and the 50 points :)

1) I know that if the two integers have the same sign: Add their absolute values and give the answer the same sign as the two original integers. Also, I know that If the two integers have different signs: Subtract the lesser absolute value from the greater absolute value.

2) To find the sum of a positive and a negative integer, take the absolute value of each integer and then subtract these values. The result takes the sign of the integer with the larger absolute value. The sum of any integer and its opposite is equal to zero.

3) First, draw a number line. Then, find the location of the first integer on the number line. Next, if the second integer is positive, move that many units to the right from the location of the first integer. If the second integer is negative, move that many units to the left from the location of the first integer.

4) $205

5) The fish’s location relative to the surface of the ocean is -85 or -25 if the fish is 25 feet deeper from surface of ocean

6) Yes if both the temperatures are in Degree Fahrenheit

please click thanks and mark brainliest if you like :)

Answer:

B

Step-by-step explanation:

Hypotenuse=sqrt(Side^2+side^2)=sqrt(14^2+14^2)=14*sqrt(2)

Answer:  

B  

Step-by-step explanation:  

Hypotenuse=sqrt(Side^2+side^2)=sqrt(14^2+14^2)=14*sqrt(2)

Answer:

When you multiply radical expressions you multiply the numbers under the radical symbols.3–√×7–√=21−−√

When you add radical expression you CANNOT add the numbers under the radical symbols.

3–√+7–√≠10−−√

Step-by-step explanation:

Answer:

200m

Step-by-step explanation:

Width=60m

Length=4000cm=40m

[PERIMETER OF RECTANGLE= 2(l+b)]

2(40+60)

2×100

200cm

Answer:

C) 81 degrees

Step-by-step explanation:

all quadrilateral's sum of interiror angles is 360 degrees

right angles are 90 degrees

call measure of angle C =y

360=90+90+99+y

180=99+y

y= 81

Answer:

I think this will help you

Answer:

2nd option

Step-by-step explanation:

Given f(x) then f(x + a) is a horizontal translation of f(x)

• If a > 0 then a shift left of a units

• If a < 0 then a shift right of a units

Here g(x) = (x - 1)²

The base graph f(x) has been shifted right 1 unit

Answer:

B

Step-by-step explanation:

Constant of proportionality can be calculated by two point slope formula, slope=(y2-y1)/(x2-x1)=(64-40)/(40-25)=24/15=8/5=1.6

Answer:

Parallel: AC and DB, BA and CD

Perpendicular: AC and CD, DB and CD, DB and BA, BA and AC

Neither: None

Step-by-step explanation:

Step 1: Find Slopes

Let's first find the slopes of each side of the rectangle, as that will helps us determine which sides are parallel, perpendicular, or neither.

Recall that the formula for finding the slope between two points is [tex]\frac{y_2 - y_1}{x_2-x_1}[/tex] where [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] are the coordinates of the two points. To avoid confusion, I will be taking the first point I list as [tex](x_1,y_1)[/tex] and the second point as [tex](x_2,y_2)[/tex].

Slope of [tex]BA[/tex]:

[tex]\frac{-7-(-3)}{-1-(-4)}\\=\frac{-7+3}{-1+4} \\= -\frac{4}{3}[/tex]

Slope of [tex]AC[/tex]:

[tex]\frac{-4-(-7)}{3-(-1)} \\=\frac{-4+7}{3+1} \\=\frac{3}{4}[/tex]

Slope of [tex]CD[/tex]:

[tex]\frac{0-(-4)}{0-3} \\=\frac{4}{-3} \\=-\frac{4}{3}[/tex]

Slope of [tex]DB[/tex]:

[tex]\frac{-3-0}{-4-0} \\=\frac{-3}{-4} \\=\frac{3}{4}[/tex]

Step 2: Determine which sides are parallel, perpendicular, or neither

Now that we found the slopes of the sides, we can determine which sides are parallel, perpendicular, or neither.

Recall that parallel lines have the same slope. [tex]\bf AC[/tex] and [tex]\bf DB[/tex], along with [tex]\bf BA[/tex]and [tex]\bf CD[/tex], have the same slope, so they are parallel. No other pair of sides has the same slope, so these are our only parallel pairs.

For two lines to be perpendicular, the product of their slopes must be [tex]-1[/tex]. [tex]\bf AC[/tex] and [tex]\bf CD[/tex], [tex]\bf DB[/tex] and [tex]\bf CD[/tex], [tex]\bf DB[/tex] and [tex]\bf BA[/tex], and [tex]\bf BA[/tex] and [tex]\bf AC[/tex] [tex]\bf[/tex]meet that criteria, so they are perpendicular. No other pair of sides meets the criteria, so these are our only perpendicular pairs. Hope this helps!

Answer:

DEF = 105

Step-by-step explanation:

The sum of the angles of a triangle is 180

28+47+DEF = 180

Combine like terms

DEF+75=180

Subtract 75 from each side

DEF +75-75 =180-75

DEF = 105

Answer: D

Step-by-step explanation: The answer is D because firstly we know that all right triangles add up to 180 degrees.

Using this knowledge we know 2 sides out of the 3. Therefore 47+28+x=180. Then we would add the first 2 numbers then minus 180 to get 105 as your last angle.

Answer:

cd a gimem ?

Step-by-step explanation:

Answer:

D) 20°

Step-by-step explanation:

Using the triangle sum theorem, you know that every triangle's interior angles add up to 180°. Therefore the bottom triangle's missing angle can be found by giving it the variable x.

57° + 30° + x = 180°

Simplify: 87° + x =180°

x=93°

By the vertical angles theorem, the vertical angle directly across this angle is congruent to this one. Meaning that the top triangle's angle are 67°, 93°, and unknown, which we can assign y. We can use the same method from above here.

67° + 93° + y = 180°

Simplify: 160° + y = 180°

y=20°

Answer:

(C). 26°

Step-by-step explanation:

Answer:

D. y = -5x + 6

Step-by-step explanation:

If we replace the values of x in the expressions we can find y. By replacing the values of x we see that the only option that has the correct values of y is the option D.

Answer:

57.2

Step-by-step explanation:

This is a right triangle so we can use trig ratios.

We are asked to find a side when we know a angle adjacent to that side. And we are given a side opposite of that angle. We can use Tangent to find the side length.

[tex] \tan(40) = \frac{48}{x} [/tex]

Take the reciprocal of both sides.

[tex] \frac{1}{ \tan( 40) ) } = \frac{x}{ 48} [/tex]

Multiply both sides by 48.

[tex] x = \frac{1}{ \tan(40) } \times 48[/tex]

[tex]x = 57.2[/tex]

Answer:

Let the two equal angles be x . Hence the third angle is 3x . But the sum of the interior angles of a triangle always adds up to 180∘ . ∴x=1805=36∘

Answer:

Angle 1 = 36°

Angle 2 = 36°

Angle 3 = 108°

Step-by-step explanation:

Sum of all angles in any triangle is 180°

angle 1 = angle 2 = X

angle 3 = 3×X

angle 1 + angle 2 + angle 3 = 180°

X + X + 3×X = 5×X = 180°

X = 180° / 5 = 36°

Angle 1 = 36°

Angle 2 = 36°

Angle 3 = 108°

Answer:

lol Step-by-step explanation:

Answer:

the answer is 5

Step-by-step explanation:

11 substract 6 is equal to 5

Answer:

5/2

Step-by-step explanation:

tan&= 2/5(p/b)

here,

p=2,b=5

cot&=b/p

=5/2

Answer:

solving for x

Step-by-step explanation:

4 or -6

Answer:

x = 4

Step-by-step explanation:

Those absolute value signs are a trick, well at least for this problem. Solve it how you usually would. However, if +2 was -2 or +/-2, then you would need to pay attention. Basically, those signs make the whole equation incased positive no matter what.

[tex]\large\textsf{Hey there!}[/tex]

[tex]\large\textsf{\# 1.}[/tex]

[tex]\large\textsf{4x} \times\large\textsf{3x}[/tex]

[tex]\large\text{COMBINE the LIKE TERMS}[/tex]

[tex]\large\textsf{4x}\times\large\textsf{3x = \bf 12x}\mathsf{\bf ^2}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: \bf 12x}\bf ^2}}\huge\checkmark[/tex]

[tex]\large\text{\# 2.}[/tex]

[tex]\mathsf{\dfrac{2}{3}+\dfrac{1}{4}}[/tex]

[tex]\mathsf{= \dfrac{2\times4+1\times3}{3\times4}}[/tex]

[tex]\mathsf{2 \times 4 = \bf 8}[/tex]

[tex]\mathsf{1 \times 3 = \bf 3}[/tex]

[tex]\mathsf{3\times 4 = \bf 12}[/tex]

[tex]\mathsf{= \dfrac{8 + 3}{12}}[/tex]

[tex]\mathsf{8 + 3 = \bf 11}[/tex]

[tex]\mathsf{= \dfrac{11}{12}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf \dfrac{11}{12}}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

[tex]x=10[/tex]

Step-by-step explanation:

A secant is a line segment that intersects a circle in two places. One property of a secant is the product of the lengths ratio. This ratio can be described as the following, let ([tex]inside[/tex]) refer to the part of the secant that is inside the circle, and ([tex]outside[/tex]) refer to the part that is outside of it. ([tex]total[/tex]) will refer to the entirety of the secant or ([tex]inside+outside[/tex]). The numbers (1) and (2) will be used as subscripts to indicate that there are two different secants.

[tex](outside_1)(total_2)=(outside_2)(total_2)[/tex]

Substitute,

[tex](outside_1)(total_2)=(outside_2)(total_2)[/tex]

[tex](outside_1)(inside_1+outisde_1)=(outside_2)(inside_2+outside_2)[/tex]

[tex](6)(6+x+5)=(7)(7+x+1)[/tex]

Simplify,

[tex](6)(6+x+5)=(7)(7+x+1)[/tex]

[tex]6(x+11)=7(x+8)[/tex]

[tex]6x+66=7x+56[/tex]

Inverse operations,

[tex]6x+66=7x+56[/tex]

[tex]66=x+56[/tex]

[tex]10=x[/tex]

Answer: a

Step-by-step explanation:

Answer:

here ,

question no. L the question is incomplete.

rest all are solved hope this helped u ☺️

Answer: I can’t help with that because there should be a graph

Step-by-step explanation:

Answer:

[tex]\angle m + \angle t + \angle n = 180[/tex]

Step-by-step explanation:

Required

Show that:

[tex]\angle m + \angle t + \angle n = 180^o[/tex]

To make the proof easier, I've added a screenshot of the triangle.

We make use of alternate angles to complete the proof.

In the attached triangle, the two angles beside [tex]\angle m[/tex] are alternate to [tex]\angle t[/tex] and [tex]\angle n[/tex]

i.e.

[tex]\angle 1 = \angle t[/tex]

[tex]\angle 2 = \angle n[/tex]

Using angle on a straight line theorem, we have:

[tex]\angle 1 + \angle m + \angle 2 = 180[/tex]

Substitute values for (1) and (2)

[tex]\angle t + \angle m + \angle n = 180[/tex]

Rewrite as:

[tex]\angle m + \angle t + \angle n = 180[/tex] -- proved

Answer:

Is this suppose to be math question??

Answer:

hard work will define who wins