translate this into an expression: the quotient of a number, x, and 8, could you please explain it to me?​

Answers

Answer 1

Answer:

x/8

Step-by-step explanation:

First, we are given "the quotient of...". This means that we are dividing something/something else. If two numbers are given in the phrase "something and something else", the first number given will be the something, and the second number will be the something else.

The first number listed is x. Therefore, we have

x/something else.

Next, we are given "and 8", so we have x/8 as our expression


Related Questions

The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day. They would like the estimate to have a maximum error of 0.14 gallons. A previous study found that for an average family the standard deviation is 2 gallons and the mean is 16 gallons per day. If they are using a 95% level of confidence, how large of a sample is required to estimate the mean usage of water

Answers

Answer:

A sample of 784 is required to estimate the mean usage of water.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

The standard deviation is 2 gallons

This means that [tex]\sigma = 2[/tex]

They would like the estimate to have a maximum error of 0.14 gallons. How large of a sample is required to estimate the mean usage of water?

This is n for which M = 0.14. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.14 = 1.96\frac{2}{\sqrt{n}}[/tex]

[tex]0.14\sqrt{n} = 1.96*2[/tex]

[tex]\sqrt{n} = \frac{1.96*2}{0.14}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96*2}{0.14})^2[/tex]

[tex]n = 784[/tex]

A sample of 784 is required to estimate the mean usage of water.

Which one goes where?

Answers

"RS tangent to circle a..." is first statement          Reason: Given

Second Reason: "Radius perpendicular to tangent"

Second Statement: "AR is parrallel to BS"      Reason: "2 lines perpendicular..."

Suppose point (4, −9) is translated according to the rule (, ) → ( + 3, − 2). What are the coordinates of ′? Explain

Answers

Answer: I’m sorry I just need points..

Dr. Burger rides his bike to work in the mornings. Usually, he leaves his house at 8:20 and gets to the office at 9:00 riding at a rate of 15 miles an hour. On this particular morning he has overslept and leaves at 8:45. How fast does he need to ride to avoid being late

Answers

Answer:

40 mph

Step-by-step explanation:

40 mins to bike usually, which means he bikes 10 miles. He needs to bike at a minimum of 10 miles in 15 mins, which translates to 40 miles in an hour.

P.S. He is going to surely be late.

6. Find average of the following
expressions (4-2x), (-7-3x), and
(11x+6)

Answers

Answer:

2x + 1.

Step-by-step explanation:

Average = sum of the expression / number of expressions

= [(4 - 2x) + (-7 - 3x) + (11x + 6)] / 3

= (-2x - 3x + 11x + 4 - 7 + 6) / 3

= 6x + 3 / 3

= 2x + 1

Answer:

2x+1

Step-by-step explanation:

(4-2x), (-7-3x),(11x+6)

Add the three expressions

(4-2x)+ (-7-3x)+(11x+6)

Combine like terms

-2x-3x+11x+4-7+6

6x+3

Divide by the number of expressions which was 3

(6x+3)/3

2x+1

The average is 2x+1

The 8th term in the arithmetic sequence is 17, the 12th term is 25. Find the first term, and the sum of the first 20 terms.

Answers

Answer:

First term a = 3

Sum of first 20 term = 440

Step-by-step explanation:

Given:

8th term of AP = 17

12th term of AP = 25

Find:

First term a

Sum of first 20 term

Computation:

8th term of AP = 17

a + 7d = 17 ....... EQ1

12th term of AP = 25

a + 11d = 25 ...... EQ2

From EQ1 and EQ2

4d = 8

d = 2

a + 7d = 17

a + 7(2) = 17

First term a = 3

Sum of first 20 term

Sn = [n/2][2a + (n-1)d]

S20 = [20/2][(2)(3) + (20-1)2]

S20 = [10][(6) + 38]

S20 = [10][44]

S20 = 440

Sum of first 20 term = 440

PLEASE HELP WILL MARK BRAINLIEST

Answers

9514 1404 393

Answer:

  x = 10/3 = 3 1/3 ≈ 3.33

Step-by-step explanation:

Triangles ABC and ADE are similar, so corresponding sides are proportional.

  DE/DA = BC/BA

  x/(4+6) = 2/6

  x = 10(2/6) = 10/3 = 3 1/3

hope anyone help me please​

Answers

9514 1404 393

Answer:

  a) Lahulspiti: -8; Srinigar: -2; Shimla: 5; Ooty: 14; Bengahuru: 22

  b) 30

  c) 6

  d) yes; no

Step-by-step explanation:

a) The values are read from the graph.

__

b) 22 -(-8) = 22 +8 = 30 . . . . difference between highest and lowest

__

c) -2 -(-8) = -2 +8 = 6 . . . positive difference

(Technically, the difference between L and S is L - S = (-8) -(-2) = -6.)

__

d) -2 + 5 < 5 . . . . true

  -2 + 5 < -2 . . . . false

Assuming that the sample mean carapace length is greater than 3.39 inches, what is the probability that the sample mean carapace length is more than 4.03 inches

Answers

Answer:

The answer is "".

Step-by-step explanation:

Please find the complete question in the attached file.

We select a sample size n from the confidence interval with the mean [tex]\mu[/tex]and default [tex]\sigma[/tex], then the mean take seriously given as the straight line with a z score given by the confidence interval

[tex]\mu=3.87\\\\\sigma=2.01\\\\n=110\\\\[/tex]

Using formula:

[tex]z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]  

The probability that perhaps the mean shells length of the sample is over 4.03 pounds is

[tex]P(X>4.03)=P(z>\frac{4.03-3.87}{\frac{2.01}{\sqrt{110}}})=P(z>0.8349)[/tex]

Now, we utilize z to get the likelihood, and we use the Excel function for a more exact distribution

[tex]=\textup{NORM.S.DIST(0.8349,TRUE)}\\\\P(z<0.8349)=0.7981[/tex]

the required probability: [tex]P(z>0.8349)=1-P(z<0.8349)=1-0.7981=\boldsymbol{0.2019}[/tex]

Thorazine is available in a strength of 25 mg/mL. Express this strength as a percent.

Answers

Answer:

2.5%

Step-by-step explanation:

Thorazine is available in the strength of 25mg/mL.

To find out the percentage strength,

W/V = g/mL  (weight in grams of solute/milliliters of solute.)

1mL of Thorazine contains 25mg.

Dissolve Thorazine with the 100mL solution.

Therefore, 25 x 100 = 2500mg

Which is equals to 2.5g

100mL solution contains 2.5g of Thorazine.

Percentage Strength (W/V) = 2.5 / 100 x 100 = 2.5%.

The percentage strength of Thorazine 25mg/mL has 2.5%

For -180°<θ<0 , which of the primary trigonometric functions may have positive values?

Answers

Answer:

cos theta  = adj / hyp is positive (+/+)

Step-by-step explanation:

In this open interval, the hypotenuse (radius) is always positive, whereas the adjacent side is positive and the opposite side negative.

in this interval:

sin theta = opp / hyp is neg (-/+)

cos theta  = adj / hyp is positive (+/+)

tan theta = opp / adj = (-/+) :  negative

What is the explicit formula for the sequence ? -1,0,1,2,3

Answers

Answer:

B

Step-by-step explanation:

substitute the values in the eq. Ot is also arithmetic progression.

Which statement best compares the two functions?
A) Neither function A nor function B has an x-intercept.
B) Neither function A nor function B has a y-intercept.
C) The domain and range of both functions contain only
positive numbers.
D) The domain and range of both functions contain only
positive numbers and zero

Answers

Answer:

A) Neither function A nor function B has an x-intercept.

Step-by-step explanation:

Help please, I attached the question. Is it a!?

Answers

Answer:

A

Step-by-step explanation:

Recall that for a quadratic equation of the form:

[tex]0=ax^2+bx+c[/tex]

The number of solutions it has can be determined using its discriminant:  

[tex]\Delta = b^2-4ac[/tex]

Where:

If the discriminant is positive, we have two real solutions. If the discriminant is negative, we have no real solutions. And if the discriminant is zero, we have exactly one solution.

We have the equation:

[tex]2x^2+5x-k=0[/tex]

Thus, a = 2, b = 5, and c = -k.

In order for the equation to have exactly one distinct solution, the discriminant must equal zero. Hence:

[tex]b^2-4ac=0[/tex]

Substitute:

[tex](5)^2-4(2)(-k)=0[/tex]

Solve for k. Simplify:

[tex]25+8k=0[/tex]

Solve:

[tex]\displaystyle k = -\frac{25}{8}[/tex]

Thus, our answer is indeed A.

the answer to this is A

khai niem hinh cat don gian ?

Answers

Answer:

khai niem hinh cat don gian?

A day trading firm closely monitors and evaluates the performance of its traders. For each $10,000 invested, the daily returns of traders at this company can be modeled by a Normal distribution with mean = $830 and standard deviation = $1,781.
(a) What is the probability of obtaining a negative daily return, on any given day? (Use 3 decimals.)
(b) Assuming the returns on successive days are independent of each other, what is the probability of having a negative daily return for two days in a row? (Use 3 decimals.)
(c) Give the boundaries of the interval containing the middle 80% of daily returns: (use 3 decimals) ( , )
(d) As part of its incentive program, any trader who obtains a daily return in the top 2% of historical returns receives a special bonus. What daily return is needed to get this bonus? (Use 3 decimals.)

Answers

Answer:

a) 0.321 = 32.1% probability of obtaining a negative daily return, on any given day.

b) 0.103 = 10.3% probability of having a negative daily return for two days in a row.

c) (-$1449.68, $3109.68)

d) A bonus of $4,488.174 is needed.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normal distribution with mean = $830 and standard deviation = $1,781.

This means that [tex]\mu = 830, \sigma = 1781[/tex]

(a) What is the probability of obtaining a negative daily return, on any given day?

This is the p-value of Z when X = 0, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{0 - 830}{1781}[/tex]

[tex]Z = -0.466[/tex]

[tex]Z = -0.466[/tex] has a p-value 0.321.

0.321 = 32.1% probability of obtaining a negative daily return, on any given day.

(b) Assuming the returns on successive days are independent of each other, what is the probability of having a negative daily return for two days in a row?

Each day, 0.3206 probability, so:

[tex](0.321)^2 = 0.103[/tex]

0.103 = 10.3% probability of having a negative daily return for two days in a row.

(c) Give the boundaries of the interval containing the middle 80% of daily returns

Between the 50 - (80/2) = 10th percentile and the 50 + (80/2) = 90th percentile.

10th percentile:

X when Z has a p-value of 0.1, so X when Z = -1.28.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.28 = \frac{X - 830}{1781}[/tex]

[tex]X - 830 = -1.28*1781[/tex]

[tex]X = -1449.68[/tex]

90th percentile:

X when Z has a p-value of 0.9, so X when Z = 1.28.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.28 = \frac{X - 830}{1781}[/tex]

[tex]X - 830 = 1.28*1781[/tex]

[tex]X = 3109.68[/tex]

So

(-$1449.68, $3109.68)

d) As part of its incentive program, any trader who obtains a daily return in the top 2% of historical returns receives a special bonus. What daily return is needed to get this bonus?

The 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]2.054 = \frac{X - 830}{1781}[/tex]

[tex]X - 830 = 2.054*1781[/tex]

[tex]X = 4488.174 [/tex]

A bonus of $4,488.174 is needed.

ABC ~ DEF. What sequence of transformations will move ABC ~ DEF​

Answers

Answer:

D

Step-by-step explanation:

we first dilate it, making it the same size, then translate it to the right. I hope I have helped :)

As one once said Another one

Answers

Answer:

f

Step-by-step explanation:

Answer:

S = 62.9

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan S = opp side / adj side

tan S = sqrt(42)/ sqrt (11)

tan S = sqrt(42/11)

Taking the inverse tan of each side

tan ^ -1( tan S) =  tan ^-1(sqrt(42/11))

S=62.89816

Rounding to the nearest tenth

S = 62.9

Using the digits 5, 6, 7, 8, 9 and repetition is allowed how many options are there to
Create a 4 digit even number?
[2]




Create a 4 digit odd number?

Answers

Answer:

250 options to create an even number

375 options to create an odd number

fifteen more than 3 times a number is 33. What is the equation and solve

Answers

Answer:

x = 6

Step-by-step explanation:

15 more represents “+15”

3 times a number represents “3*x” which is written as “3x”

So fifteen more than 3 times a number is 33 would be written as;

3x + 15 = 33

Now solve for x using algebra;

3x = 33 - 15

3x = 18

x = 18 / 3

x = 6

Hope this helps!

X=6 so the answer is six

E. The ratio of monthly income to savings of a family is 7:2. If the savings is Rs. 500, find the monthly income and expenditure.​

Answers

Step-by-step explanation:

Since the ratio of monthly income to savings of the family is 7:2, we assume that the income be 7t and savings be 2t

Now, we are given that the savings is =Rs 500

So, According to our assumption, 2t=500

⇒t=250

Hence, the income of the family is =7×250=Rs 1750

And the expenditure is =Income−Savings

=Rs 1750−Rs 500

=Rs 1250

By selling a radio for $8400 a dealer gained 12% .how much money did she gain​

Answers

Answer:

Amount gained = $900

Step-by-step explanation:

Let the cost price be = x

Given selling price = 8400

And profit% = 12%

Profit = selling price - cost price

        = 8400 - x

[tex]Profit \ \% = \frac{profit}{cost \ price} \times 100\\\\12\% = \frac{8400 - x}{x} \times 100\\\\\ 12 \times \frac{1}{100} = \frac{8400 - x}{x}\\\\\frac{12 \ x}{100} = 8400 - x \\\\\frac{12x}{100} + x = 8400\\\\12x + 100x = 8400 \times 100\\\\112x = 8400 \times 100\\\\x = \frac{8400 \times 100}{112} = 7500[/tex]

Therefore , cost price of the radio $7500

The amount she gained = 8400 - 7500 = $ 900

What is the value of x?



Enter your answer in the box.

units

Answers

Answer:

25

Step-by-step explanation:

40/24 = x/15

x = 15•40/24

x = 25

Answer:

25

Step-by-step explanation:

just use the facts that both triangles are similar

At which root does the graph of f(x) = (x + 4)^6(x + 7)^5 cross the x-axis?
O -7
O -4
O 4
Ο 7

Answers

Answer:

Step-by-step explanation:

to cross the x-axis you need to solve f(x)=0

x(x+4)(x+7)*5=0 which means you will have x=0  ,x+4=0 or x+7=0

so the final answer is

x=0 or x=-4 or x=-7

(x²-9)(√x-2)=0 ??????????

Answers

sfddssdfa63434daasfdfddfsa

An isosceles trapezoid has a consecutive-sides of length: 10,6,10 and 14. Find the measure of each angle if the trapezoid.

Answers

Answer:

Angle A = Angle D = 69° 30'

Angle B = Angle C = 110° 30'

Step-by-step explanation:

     B ___ C

    /              \

  /                  \

A ________ D

AB and CD are 10

BC is 6

AD is 14

If we divide the trapezoid, we can imagine a line.

     B_ F_C

    /      |      \

  /        |         \

A ___E____ D

AE = ED = 7 (14/2)

BF = FC = 3

So now, we draw another line from B or C to AE or ED

     B_ F_ C

    /      |     | \

  /        |     |    \

A ___E_ G_ D

EG = GD = 3.5 (7/2)

There is a right triangle now, GCD

GD is 3.5 and CD is 10. To determine angle D, we can apply trigonometric function:

CD is H, and GD is A

cos D = A/H

cos D = 3.5/10 → 0.35

angle D = 69° 30'

By theory, we know that angle D and angle A, are the same so:

Angle D = Angle A = 69° 30'

Angle B = Angle C

We also make a cuadrilateral, which is EFCD.

Angle D is 69° 30', Angle E is 90°, Angle F is also 90°

Sum of angles in cuadrilateral is 360°

360° - 69° 30' - 90° - 90° = Angle C = Angle B

Angle C = Angle B = 110° 30'

Let's confirm the angles in the trapezoid:

69° 30' + 110° 30' + 69° 30' + 110° 30' = 360°

A + B + C + D

Write the standard form of the equation of the circle with center (−7,10) that passes through the point (−7,7)

Answers

Answer:

(x+7)^2+(y-10)^2=9

Step-by-step explanation:

The distance between the two points is sqrt((-7+7)^2+(10-7)^2)=3 which is in turn the radius of the circle

Simplify to the extent possible: (
logx16)(log2 x)

Answers

Use the change-of-base property for logarithms to write

log(16) log₂(x) = (ln(16) / ln(x)) (ln(x) / ln(2)) = ln(16)/ln(2) = log₂(16)

Then since 2⁴ = 16, we hvae

log₂(16) = log₂(2⁴) = 4 log₂(2) = 4

If $6^x = 5,$ find $6^{3x+2}$.

Answers

If 6ˣ = 5, then

(6ˣ)³ = 6³ˣ = 5³ = 125,

and

6³ˣ⁺² = 6³ˣ × 6² = 125 × 6² = 125 × 36 = 4500

Find the probability that the spinner will land on gray and then purple

Answers

Answer:

true the question is true and wait for others my could be wrong also

Other Questions
If any parts manufactured by Brown Machine Inc. should prove defective within one year from the date it is delivered new to the purchaser, the product will be ____________ immediately.Select one:A. revisedB. replaced CorrectC. preparedD. consumed A baseball fan wanted to know if there is a difference between the number of games played in a World Series when the American League won the series versus when the National League won the series. From 1922 to 2012, the population standard deviation of games won by the American League was 1.14, and the population standard deviation of games won by the National League was 1.11. Of 19 randomly selected World Series games won by the American League, the mean number of games won was 5.76. The mean number of 17 randomly selected games won by the National League was 5.42. Required:Conduct a hypothesis test use the 10% significance level. For many years, no one could communicate with people who had been born without hearing. These deaf people were not able to use a spoken language. But, beginning in the 1700s, the deaf were taught a special language. Using this language, they could share thoughts and ideas with others. The language they used was a language without sound. It was a sign language. How did this sign language work? The deaf were taught to make certain movements using their hands, faces, and bodies. These movements stood for things and ideas. People might move their forefingers across their lips. Thismeant, You are not telling the truth. They might tap their chins with three fingers. This meant my uncle. The deaf were also taught to use a finger alphabet. They used their fingers to make the letters of the alphabet. In this way, they spelled out words. Some deaf people could spell out words at a speed of 130 words per minute. Sign language and finger spelling are not used as much as they once were. Today, the deaf are taught to understand others by watching their lips. They are also taught how to speak.46. In the 1700s, the deaf were taught ____.A. to speak B. sign language C. to watch others D. move their fingers across their lips47. A tap on the chin with three fingers means____.A. hello. B. come on. C. I have a toothache. D. my uncle.48. How did sign language help the deaf? A. It helped them learn to read.B. The deaf could understand body movements made by normal people.C. It helped them communicate with other people. D. It helped them spell out words.49. Why are sign language and finger spelling not used as much as they used to?A. Because there are other ways to help the deaf communicate.B. Because it is difficult to use a finger alphabet.C. Because the speed of 130 words per minute is too difficult for most deaf people.D. Because sign language and finger spelling have no sound.50. What is the main idea of the passage youve read?A. How the deaf people communicate. B. Learning to spell.C. Teaching the deaf to speak. D. A comparison of sign language and finger spelling person's human rights should be violated.Based on these excerpts, on what principles would Gandhi and Mandela most likely agree? Select all that apply.Children must have the right to an education.Society must engage in capitalism to fulfill its destiny.Government must serve to better the lives of a society's citizens.A government foreign to its people should not decide Innocence or guilt.Colonial rule has not benefited the country that has been colonized.People have an inherent human right to justice.Can be more than one answer Personality disorders (like antisocial personality disorder or borderline personality disorder) are characterized by Group of answer choices Inflexible and enduring behavioral patterns that impair social functioning Persistent anxiety or depression An elevated level of autonomic nervous system arousal Hallucinations or delusions Which expressions are equivalent to -f-5(2f-3) 3. Based on your research and the summary in the report, write a paragraph thatdescribes how government responses to disasters relate to the rise of cooperativefederalism. Be sure your response also includes information about the overlappingresponsibilities and relationships between FEMA and GOHSEP. (10 points) Do you know this for social studies Write any three importance of Measurement. Stay Safe,Stay Healthy and Stay Happy Please answer me this question fast, PLEASE Read the question and answer it there were 13 original states. there are now 50 . what fraction of the states are the original states Select all that apply.Which conditions relate to the research of van Helmont?plant mass related only to soilconclusions partly correctdemonstrated plant food from soilconducted around 1400 AD.plant mass related to H 20 A basket contains 11/12 pound of strawberries. One serving strawberries is 1/4 pound. How many servings of strawberries are in the basket? NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!!! The product of two positive integer numbers is 70 and the sum of the same two numbers is 17. Find thenumbers. The angle of elevation to the top of theschool is 37 from where you are standing11.2 m from the wall of the school. Findthe height of the school. a shipping boox has the dimentsions what is the volume of the box in cubic yards Two cards are drawn without replacement from a standard deck of 5252 playing cards. What is the probability of choosing a red card for the second card drawn, if the first card, drawn without replacement, was a club Find the Area of the figure below, composed of a rectangle and one semicircle, with another semicircle removed. Round to the nearest tenths place.I need help, please The area around a charged object that can exert a force on other charged objects is an electric ___ the radius of a circle is 17m. find its area in terms of pi