Two snails climbed up a tree at a constant rate. A person measured and recorded their respective distances above the ground. • Snail A was 12.5 inches above the ground at 10 minutes and 16 inches above the ground at 24 minutes. • Snail B started at 3 inches above the ground and climbed 0.3 inch per minute. The snails continued at the same speeds. • Determine the amount of time, in minutes, it took for the two snails to be the same distance above the ground. • Include an equation to represent each snail's distance above the ground, y, in terms of x, the minutes elapsed since the measurement started. Show your work or explain your answer.

Answers

Answer 1

Answer:

140 minutes

Step-by-step explanation:

Using m = (y₂ - y₁)/(x₂ - x₁) , we find the rate at which Snail A moves which is also the gradient of the line with which it moves. Given that Snail A was 12.5 inches above the ground at 10 minutes and 16 inches above the ground at 24 minutes, x₁ = 10 min, y₁ = 12.5 inches, x₂ = 24 min and y₂ = 16 inches.

So, m = (y₂ - y₁)/(x₂ - x₁)

m = (16 - 12.5)/(24 - 10) = 3.5/14 = 0.25

Also, the equation of the line,

(y - y₁)/(x - x₁) = m

(y - 12.5)/(x - 10) = 0.25

cross-multiplying, we have

y - 12.5 = 0.25(x - 10)

expanding the bracket, we have

y - 12.5 = 0.25x - 2.5

adding 12.5 to both sides, we have

y - 12.5 + 12.5 = 0.25x - 2.5 + 12.5

y = 0.25x + 10

Since Snail B started at 3 inches above the ground and climbed 0.3 inch per minute. The snails continued at the same speeds, its distance y moved is y = 0.3t + 3

We now find the time x it takes the snails to cover the same distance by equating both expressions. So,

0.25x + 10 = 0.3x + 3

collecting like terms, we have

10 - 3 = 0.3x - 0.25x

7 = 0.05x

0.05x = 7

x = 7/0.05

x = 140 minutes


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Answers

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Step-by-step explanation:

Given

Azmyne decided to study a total of [tex]6\ \frac{1}{2}\ hours[/tex]

She spent [tex]1\ \frac{1}{4}\ hours[/tex] on Friday and  [tex]2\ \frac{2}{3}\ hours[/tex] on Saturday

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[tex]\Rightarrow 1\ \frac{1}{4}=\frac{5}{4}\ hours[/tex]

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[tex]\Rightarrow 2\ \frac{2}{3}=\frac{8}{3}\ hours[/tex]

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[tex]\Rightarrow \dfrac{13}{2}-\dfrac{5}{4}-\dfrac{8}{3}\\\\\Rightarrow \dfrac{13\times6-5\times3-8\times4}{12}=\dfrac{78-15-32}{12}\\\\\Rightarrow \dfrac{31}{12}=2\ \frac{7}{12}\ \text{hours}[/tex]

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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Answers

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Answers

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Step-by-step explanation:

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It takes 313131 employees and \$7500$7500dollar sign, 7500 to build a car, and it takes 191919 employees and \$4300$4300dollar sign, 4300 to build a motorcycle. Genghis Motors wants to spend more than \$84000$84000dollar sign, 84000 to build cars and motorbikes using at most 706706706 employees.

Answers

Complete question :

It takes 313131 employees and \$7500$7500dollar sign, 7500 to build a car, and it takes 191919 employees and \$4300$4300dollar sign, 4300 to build a motorcycle. Genghis Motors wants to spend more than \$84000$84000dollar sign, 84000 to build cars and motorbikes using at most 706706706 employees. Let CCC denote the number of cars they build and MMM the number of motorbikes they build. Write an inequality that represents the condition based on the number of employees. Write an inequality that represents the condition based on the number of dollars.

Answer:

31C + 19M ≤ 706

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Step-by-step explanation:

C = number of cars built

M = number of motorcycles built

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Cost = 31 + $7500

Cost of building a motorcycle,:

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To build, C cars :

Number of employees = 31C

7500 * C = 7500C

To build, M motorcycles :

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4300 * M = 4300M

Genghis budget :

Amount > 84000

Number of employees ≤ 706

Hence, the constraints

31C + 19M ≤ 706

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