Tyler drives 50km north. Tyler then drives back 30km south. What distance did he cover? What was his displacement?
Answers
Answer:
80 km is distance and 30km north is displacement
Explanation:
distance= 50+30=80km
displacement= 50-20=30
his displacement is 30km north
When Tyler drives 50 km north and then drives back 30 km south, we have:
1. The distance that he covers is 80 km.
2. Tylor's displacement is 20 km.
1. The distance is a scalar that is given by the sum of the kilometers traveled by Tyler as follows:
[tex] d = d_{1} + d_{2} = 50 km + 30 km = 80 km [/tex]
Hence, the distance traveled by Tyler was 80 km.
2. The displacement is a vector that depends on the direction of travel. Takin the north direction as positive we have:
[tex] x = x_{1} + x_{2} = 50 km + (-30 km) = 20 km [/tex]
Therefore, Tyler's displacement is 20 km.
You can find more about displacement and distance here: https://brainly.com/question/4307551?referrer=searchResults
I hope it helps you!
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PLZ EXPLAIN THE EQUATION AND I WILL GIVE BRAINLIST You are out and about in the country and your father sees a rock that he really wants in the yard. Now you must get the very heavy rock into the back of a truck. The truck bed is 3 feet off the ground. Your father pulls out a 5-foot plank and begins to set up a ramp. At the same time, you (who know about mechanical advantage!) have found a plank that is 8 feet long, and you show it to your father. Which plank will give you the most mechanical advantage? Calculate the MA for each plank
Answers
Answer:
The 8 foot long plank
Explanation: hope this helps :)
You are twice as likely to become good friends with the person who is in the dorm room next to you than the person two doors down. This is due to:
A. Proximity.
B. Common Interests.
C. Shared Values.
D. Social Background
Answers
Since the person is closer, you get to see them more often
A motorist, traveling east on an open highway, sets his cruise control at 90.0 km/h. How far will he travel in 0.75 hours?
Answers
Answer:
The answer is 67.5 kmExplanation:
The distance covered by an object given it's velocity and time taken can be found by using the formula
distance = velocity × time
From the question we have
distance = 90 × 0.75
We have the final answer as
67.5 kmHope this helps you
Answer: 67.5 km
Explanation:
Distance is the velocity and time.
90 x 0.75 = total distance
The distance is represented as 67.5 km/h.
Hope this helps!
Write an equation of the line in slope-intercept form.
Please explain.
Answers
Answer:
y = [tex]-\frac{1}{4}[/tex]x + 3
Explanation:
The equation of a straight line is given as:
y = mx + c
y and x are the coordinates
m is the slope
c is the y -intercept
The y-intercept = 3;
Slope = [tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]
x₁ = 0
x₂ = 4
y₁ = 3
y₂ = 2
Slope = [tex]\frac{2-3}{4 -0 }[/tex] = [tex]-\frac{1}{4}[/tex]
y = mx + c
y = [tex]-\frac{1}{4}[/tex]x + 3
The mass of the sun is 1.9891030 kg and the mass of the Earth is 5.9721024kg. If the Earth’s acceleration toward the sun is 0.0059 m/s/s, what is the sun’s acceleration toward the Earth?
Answers
Answer:
this is the answer according to my calculations
Explanation:
0.001.9
On the moon, the gravity is 1/6 that of Earth. While on the moon, Buzz Aldrin carried on his back a support system that would weigh over 1760 N on Earth. a) What did the backpack weigh on the moon? b) What was its mass on the moon? please show the work
Answers
Answer:
a) 293.[tex]\bar 3[/tex] N
b) Approximately 179.41 kg
Explanation:
The given parameters are;
The gravity (gravitational acceleration) on the moon = 1/6 × The gravity on Earth
The weight of the support system Buzz Aldrin carries = 1760 N
a) Given that the weight of the support system on Earth = Mass of the support system, m × Gravity, g (Acceleration due to gravity) = m·g
The weight of the support system on Earth = m·g
We have;
The gravity on the moon = 1/6 × g
∴ The weight of the support system on the moon = Mass of the support system, m × 1/6 × g = m·g/6
∴ The weight on the of the support system on the moon = m·g/6 = 1/6 × m·g = 1/6 × m·g = 1/6 × The weight of the support system on Earth
The weight on the of the support system on the moon = 1/6 × 1760 N = 880/3 N = 293.[tex]\bar 3[/tex] N
b) The mass, m, of the support system on the moon = The mass, m, of the support system on Earth
The mass, m, of the support system on Earth = Weight of the support system/(Gravity(acceleration due to gravity))
∴ The mass, m, of the support system on Earth = 1760/9.81 ≈ 179.41 kg
∴ The mass, m, of the support system on the moon ≈ 179.41 kg.
Explain a principal of moments of a force
Answers
The principle of moments states that when a body is balanced the total clockwise moment about a point equals the total anticlockwise moment about the same point.Equation.Moment=Force F×perpendicular distance from the pivot do.
A skydiver jumps from a plane and falls for 5 seconds before reaching his terminal velocity. During this 5 seconds interval, describe his acceleration before reaching terminal velocity?
Answers
Answer:
His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m
Explanation:
The terminal velocity is the maximum steady velocity attained by a body falling freely with increasing velocity from rest in a fluid, such as air or water
The net force, F acting on the body falling through the fluid is given as follows;
F = Weight force, W, from gravity - Drag force, D, from the fluid
F = W - D
Given that F = Mass, m × Acceleration, a, we have;
F = m × a
The acceleration, a = F/m = (W - D)/m
His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m.
Unit 2 kinetic energy mastery test
Answers
Answer: kinetic energy is Energy of motion.
Explanation:
Calculate the density of a rock that has a mass of 32 grams and a volume of
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Answers
Answer:
85.2ml
Explanation:
Which of the following is true regarding mixtures? a. One substance not combined with any other substances. b. Two or more substances physically mixed and can be separated. c. Two or more substances that are impossible to separate d. One substance that forms a compound alone.
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Answer:
aerga
dggzsd
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An object with a mass of 15 kg accelerates 10.0 m/s2 when an unknown force is applied to it. What is the
amount of the force
Answers
Answer:
f=mass × acceleration
=15×10
=150
