Ty'Sean went to the bowling alley and spent $14.50. If his rental shoes cost $4.50 and he played in 5 games, what was the price per game?

Answer:

8/25.

Step-by-step explanation:

As a fraction it is 32/100 but simplified is 8/25 :)

Answer:

It can either be 17593pi/9000 rad or if youre looking for a decimal answer is it 1.95pi and rad=6.14

Step-by-step explanation:

Answer:

25 free throws on Friday.

Step-by-step explanation:

On Monday  made 20 free throws

On Friday made 25%  more free throws on Friday than Monday

On Friday made 20 free throws + 25% of Monday free throws

On Friday = Monday throws + 25% × Monday throws

On Friday       = 20 + (.25 × 20)

On Friday        = 20 + 5

On Friday         = 25

Answer:

Step-by-step explanation:

180 - (180 - 102) - (180 - 123) = 180 - 78 - 57 = 45°

Answer:

14 m actural sif 124075n

Step-by-step explanation:

Answer:

a = -x + 2

Step-by-step explanation:

First, you must distribute to get 2x + 2 and adding in the -3x it equals 2x + 2 - 3x = a

Combine the like terms to get -x + 2 = a

Since there is 2 variables then the answer will stay a = -x + 2 because x or a must be substituted in order to find the other variable

Answer:

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Step-by-step explanation:

don't know don't know don't know don't know don't know don't know don't know don't

100 francs = 50 dollars

Exchange rate = 50/100

= 1/2

= 0.50 dollars per franc (C)

Note :-

It's dollars per franc because here the dollar has more value.

______

RainbowSalt2222 ☔

Answer:

Im pretty sure it is c

Step-by-step explanation:

Answer:

Step-by-step explanation:

if 50 AED= 12 Euro

for 1 AED ? Euro

50AED/1AED= 12Euro/x

cross multiplication:

50*x=12*1

50*x=12

x=12/50

x=0.24 Euro

so for 1AED you will get 0.26 Euro

Answer:

Given 3:5 = 3+5=10,

400*3/8=150,

400*5/8=250.

1. The given equation is probably supposed to read

y'' - 2y' - 3y = 64x exp(-x)

First consider the homogeneous equation,

y'' - 2y' - 3y = 0

which has characteristic equation

r² - 2r - 3 = (r - 3) (r + 1) = 0

with roots r = 3 and r = -1. Then the characteristic solution is

[tex]y = C_1 e^{3x} + C_2 e^{-x}[/tex]

and we let y₁ = exp(3x) and y₂ = exp(-x), our fundamental solutions.

Now we use variation of parameters, which gives a particular solution of the form

[tex]y_p = u_1y_1 + u_2y_2[/tex]

where

[tex]\displaystyle u_1 = -\int \frac{64xe^{-x}y_2}{W(y_1,y_2)} \, dx[/tex]

[tex]\displaystyle u_2 = \int \frac{64xe^{-x}y_1}{W(y_1,y_2)} \, dx[/tex]

and W(y₁, y₂) is the Wronskian determinant of the two fundamental solutions. This is

[tex]W(y_1,y_2) = \begin{vmatrix}e^{3x} & e^{-x} \\ (e^{3x})' & (e^{-x})'\end{vmatrix} = \begin{vmatrix}e^{3x} & e^{-x} \\ 3e^{3x} & -e^{-x}\end{vmatrix} = -e^{2x} - 3e^{2x} = -4e^{2x}[/tex]

Then we find

[tex]\displaystyle u_1 = -\int \frac{64xe^{-x} \cdot e^{-x}}{-4e^{2x}} \, dx = 16 \int xe^{-4x} \, dx = -(4x + 1) e^{-4x}[/tex]

[tex]\displaystyle u_2 = \int \frac{64xe^{-x} \cdot e^{3x}}{-4e^{2x}} \, dx = -16 \int x \, dx = -8x^2[/tex]

so it follows that the particular solution is

[tex]y_p = -(4x+1)e^{-4x} \cdot e^{3x} - 8x^2\cdot e^{-x} = -(8x^2+4x+1)e^{-x}[/tex]

and so the general solution is

[tex]\boxed{y(x) = C_1 e^{3x} + C_2e^{-x} - (8x^2+4x+1) e^{-x}}[/tex]

2. I'll again assume there's typo in the equation, and that it should read

y''' - 6y'' + 11y' - 6y = 2x exp(-x)

Again, we consider the homogeneous equation,

y''' - 6y'' + 11y' - 6y = 0

and observe that the characteristic polynomial,

r³ - 6r² + 11r - 6

has coefficients that sum to 1 - 6 + 11 - 6 = 0, which immediately tells us that r = 1 is a root. Polynomial division and subsequent factoring yields

r³ - 6r² + 11r - 6 = (r - 1) (r² - 5r + 6) = (r - 1) (r - 2) (r - 3)

and from this we see the characteristic solution is

[tex]y_c = C_1 e^x + C_2 e^{2x} + C_3 e^{3x}[/tex]

For the particular solution, I'll use undetermined coefficients. We look for a solution of the form

[tex]y_p = (ax+b)e^{-x}[/tex]

whose first three derivatives are

[tex]{y_p}' = ae^{-x} - (ax+b)e^{-x} = (-ax+a-b)e^{-x}[/tex]

[tex]{y_p}'' = -ae^{-x} - (-ax+a-b)e^{-x} = (ax-2a+b)e^{-x}[/tex]

[tex]{y_p}''' = ae^{-x} - (ax-2a+b)e^{-x} = (-ax+3a-b)e^{-x}[/tex]

Substituting these into the equation gives

[tex](-ax+3a-b)e^{-x} - 6(ax-2a+b)e^{-x} + 11(-ax+a-b)e^{-x} - 6(ax+b)e^{-x} = 2xe^{-x}[/tex]

[tex](-ax+3a-b) - 6(ax-2a+b) + 11(-ax+a-b) - 6(ax+b) = 2x[/tex]

[tex]-24ax+26a-24b = 2x[/tex]

It follows that -24a = 2 and 26a - 24b = 0, so that a = -1/12 = -12/144 and b = -13/144, so the particular solution is

[tex]y_p = -\dfrac{12x+13}{144}e^{-x}[/tex]

and the general solution is

[tex]\boxed{y = C_1 e^x + C_2 e^{2x} + C_3 e^{3x} - \dfrac{12x+13}{144} e^{-x}}[/tex]

Answer: 12√6

Step-by-step explanation:

Given the expression;

2√3 * 3√√8

= (2*3) * (√3*√8)

= 6 * (√24)

= 6 * √4*6

= 6 * (2√6)

= (6*2)√6

= 12√6

Therefore, the simplified form of the expression is 12√6.

Answer:

42.20

Step-by-step explanation:

132 ×0.32

=42.24

rounded off it give 42.20

Answer: $37.15

Step-by-step explanation:

$31.958

Step-by-step explanation:

I'm not sure guys if that's right answer

Answer:

Here

Step-by-step explanation:

It is B Because if you do (8 times 3)5 it equals 1200

The definition of the set E gives you a natural choice for the limits in the integral:

[tex]\displaystyle \iiint_E y \, dV = \int_0^6 \int_0^x \int_{x-y}^{x+y} y \, dz \, dy \, dx[/tex]

Computing the integral, we get

[tex]\displaystyle \iiint_E y \, dV = \int_0^6 \int_0^x y ((x+y)-(x-y)) \, dy \, dx = 2 \int_0^6 \int_0^x y^2 \, dy \, dx[/tex]

[tex]\displaystyle \iiint_E y \, dV = 2 \int_0^6 \frac13 (x^3 - 0^3) \, dx = \frac23 \int_0^6 x^3 \, dx[/tex]

[tex]\displaystyle \iiint_E y \, dV = \frac23 \cdot \frac14 (6^4 - 0^4) = \boxed{216}[/tex]

The evaluation of the triple integral ∭E y dV, where E = {(x, y, z) | 0 ≤ x ≤ 3, 0 ≤ y ≤ x, x − y ≤ z ≤ x + y} is 216

Triple integral integrates the integrand over three dimensions.

Given that:

E = {(x, y, z) | 0 ≤ x ≤ 3, 0 ≤ y ≤ x, x − y ≤ z ≤ x + y}

Evaluating the integral:

[tex]I = \int \int \int _E y \: dV[/tex]

[tex]I = \mathlarger{\int_0^6 (\int_0^x (\int_{x-y}^{x+y} y\: dz)dy)dx}\\\\I = \int_0^6 (\int_0^x [yz]_{z=(x-y)}^{z=(x+y)}dy)dx\\\\I = \int_0^6 (\int_0^x y( (x+y) - (x-y)) \: dy)dx\\\\ I = \int_0^6 (\int_0^x y(2y) \: dy)dx\\\\I =2 \int_0^6 \left [\dfrac{y^3}{3}\right ]_{y=0}^{y=x} dx\\\\I = 2 \int_0^6 (x^3/3) dx\\\\I = \dfrac{2}{3} \left[\dfrac{x^4}{4} \right]_{x=0}^{x=6} = \dfrac{2}{3} \times \dfrac{6^4}{4} =216[/tex]

Thus, the evaluation of the triple integral ∭E y dV, where E = {(x, y, z) | 0 ≤ x ≤ 3, 0 ≤ y ≤ x, x − y ≤ z ≤ x + y} is 216

Learn more about triple integral here:

https://brainly.com/question/17206296

Answer:

15 years old

Step-by-step explanation:

You would have to create a equation. 2x+3=33, 2x=30, x=15.

Answer:

6.7 in bcoz 4-3.2=0.8 and 7.5-0.8=6.7

Answer:

x = 6

Step-by-step explanation:

This problem can be solved by setting up ratios. The ratio of lengths is 4: 3.2, so we can say that the same ratio should apply to the widths. Thus we get the equation, [tex]\frac{4}{7.5} = \frac{3.2}{x}[/tex], and we get x = 6.

9514 1404 393

Answer:

  D. choosing first second-, and third-place winners in a cooking contest​

Step-by-step explanation:

Permutations are involved when order matters. The order of people surveyed, sundae flavors, and flowers are irrelevant. The order of first-second-third is entirely relevant.

Cooking contest winners involve permutations.

Answer:

58 2/3 fps

Step-by-step explanation:

To convert a speed value from miles per hour to feet per second, multiply it by 5280, then divide by 3600.

40 * 5280 = 211200

211200 / 3600 = 58.6666..... [58 2/3]

Answer:

15:8=15/8

Step-by-step explanation:

45:24=45/24

15/8=15:8

Answer:

9x² - 12x + 4

Step-by-step explanation:

(3x - 2)² = (3x - 2)(3x - 2)

Each term in the second factor is multiplied by each term in the first factor , that is

3x(3x - 2) - 2(3x - 2) ← distribute both parenthesis

= 9x² - 6x - 6x + 4 ← collect like terms

= 9x² - 12x + 4

Answer:

slope = - [tex]\frac{6}{5}[/tex]

Step-by-step explanation:

Calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (2, 7 ) and (x₂, y₂ ) = (7, 1 )

m = [tex]\frac{1-7}{7-2}[/tex] = [tex]\frac{-6}{5}[/tex] = - [tex]\frac{6}{5}[/tex]

Hello there! :)

To find the slope of the line when we are given 2 points, we use the following formula:

m=[tex]\frac{y2-y1}{x2-x1}[/tex]

m=[tex]\frac{1-7}{7-2} \\\frac{-6}{5}[/tex]

So the slope is -6/5. Hope this helps!

~Just a cheerful gal

#CarryOnLearning

[tex]MysteriousNature :)[/tex]

Answer:

65 cows

Step-by-step explanation:

Inverse rule of three

[tex]45-------13\\x -------- 9[/tex]

[tex]x=\frac{(45)(13)}{9}=585/9=65[/tex]

Hope this helps

Answer:

5

Step-by-step explanation:

50÷5=10-5=5

wished it helped.

Answer:

Step-by-step explanation: 50 million

Answer:

the scale is balanced both times as shown below.

No scale is shown

Step-by-step explanation: