Un bloque de 3 kg en reposo se deja libre a una altura de 5 m sobre una rampa curva y sin rozamiento. Al pie de la rampa se encuentra un resorte de constante k = 400 N/m, como se muestra en la fig. El objeto desliza por la rampa y llega a chocar contra el resorte comprimiéndolo una distancia x antes de que quede en reposo momentáneamente. Determinar: a) La velocidad con la que el bloque alcanza al resorte. ____________________ b) La distancia x que el bloque comprime al resorte. __________________ c) La velocidad con la que el bloque es expulsado por el resorte. ____________________ d) La altura que alcanza sobre la parte curva. ________________ e) ¿Alcanzará la misma altura si la rampa no está libre de rozamiento? ___________________

Answers

Answer 1

Answer:

a) La velocidad del bloque cuando llega al resorte es de aproximadamente 9,9 m / s

b) La distancia a la que se comprime el resorte es de aproximadamente 0,86 m

c) La velocidad con la que el resorte expulsa el bloque es de aproximadamente 9,9 m / s

d) La altura que alcanza el bloque es de 5 metros.

e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción

Explanation:

a) Los parámetros dados del bloque son;

La masa del bloque, m = 3 kg

La altura a la que se coloca el bloque, h = 5 m

La constante de resorte, k = 400 N / m

La aceleración debida a la gravedad, g = 9,8 m / s²

La energía potencial de un cuerpo, P.E. = m · g · h

Por tanto, la energía potencial inicial del bloque, P.E. se da como sigue;

P.E. = 3 kg × 9,8 m / s² × 5 m = 147 julios

P.E. = 147 julios

La energía cinética del bloque al pie de la rampa, K.E. = 1/2 · m · v²

Dónde;

v = La velocidad del bloque cuando llega al resorte

Por lo tanto, para el bloque dado tenemos;

K.E. = 1/2 · m · v² = 1/2 × 3 kg × v²

Por el principio de conservación de la energía, tenemos;

El PE. del bloque en reposo a una altura de 5 m = La energía cinética al pie de la rampa. K.E.

∴ P.E. = K.E.

147 J = 1/2 × 3 kg × v²

v² = 147 J / (1/2 × 3 kg) = 98 m² / s²

v = √ (98 m² / s²) = 7 · √2 m / s

v = 7 · √2 m / s ≈ 9,9 m / s

b) La energía recibida por el resorte comprimido, E = 1/2 · k · x²

Dónde;

k = La constante del resorte = 400 N / m

x = La distancia a la que se comprime el resorte

Por el principio de conservación de la energía, tenemos;

La energía recibida por el resorte comprimido, E = La energía potencial inicial del resorte, P.E.

∴ E = 1/2 · k · x² = P.E.

De lo que tenemos;

E = 1/2 × 400 N / m × x² = 147 julios

x² = 147 Julios / (1/2 × 400 N / m) = 0,735 m²

x = √ (0,735 m²) = 0,7 · √ (3/2) m ≈ 0,86 m

La distancia a la que se comprime el resorte = x ≈ 0.86 m

c) La velocidad con la que el resorte expulsa el bloque se indica a continuación;

La energía en el resorte = 1/2 · k · x² = La energía cinética dada al bloque, 1/2 · m · v²

∴ 1/2 · k · x² = 1/2 · m · v²

∴ La velocidad con la que el bloque es expulsado por el resorte, v = La velocidad con la que el bloque llega al resorte = 7 · √2 m / s

La velocidad con la que el resorte expulsa el bloque, v = 7 · √2 m / s ≈ 9,9 m / s

d) La altura que alcanza el bloque también viene dada por la siguiente relación anterior;

P.E. = K.E.

∴ m · g · h = 1/2 · m · v²

v = 7 · √2 m / s

De donde tenemos h = La altura inicial del bloque en la rampa = 5 metros

e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción porque se utilizará energía para superar la fuerza de fricción

Answer 2

a) La velocidad final del bloque es aproximadamente 9.903 metros por segundo.

b) El resorte se deforma 0.858 metros.

c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.

d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).

a) Conforme a la situación de este problema, la energía cinética traslacional final ([tex]K[/tex]), en joules, es igual a la energía potencial gravitacional inicial ([tex]U[/tex]), en joules.

[tex]U = K[/tex] (1)

Por las definiciones de las energías cinética traslacional y potencial gravitacional expandimos la ecuación anterior:

[tex]m\cdot g\cdot h = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (1)

Ahora despejamos la velocidad de esa ecuación:

[tex]v = \sqrt{2\cdot g\cdot h}[/tex]

Donde:

[tex]m[/tex] - Masa del bloque, en kilogramos.[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.[tex]h[/tex] - Altura inicial del bloque, en metros.[tex]v[/tex] - Velocidad final del bloque, en metros por segundo.

Si sabemos que [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] y [tex]h = 5\,m[/tex], entonces la velocidad final del bloque es:

[tex]v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}[/tex]

[tex]v\approx 9.903\,\frac{m}{s}[/tex]

La velocidad final del bloque es aproximadamente 9.903 metros por segundo.

b) Por el principio de conservación de la energía, la energía cinética traslacional inicial es igual a la energía potencial elástica final, cuyas fórmula es la siguiente:

[tex]\frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}[/tex] (2)

Where:

[tex]k[/tex] - Constante de resorte, en newtons por metro.[tex]x[/tex] - Deformación del resorte, en metros.

Ahora despejamos la deformación del resorte:

[tex]x = \sqrt{\frac{m}{k} }\cdot v[/tex] (3)

Si sabemos con [tex]k = 400\,\frac{N}{m}[/tex], [tex]m = 3\,kg[/tex] y [tex]v \approx 9.903\,\frac{m}{s}[/tex], entonces la deformación del resorte es:

[tex]x = \sqrt{\frac{3\,kg }{400\,\frac{N}{m} } }\cdot \left(9.903\,\frac{m}{s} \right)[/tex]

[tex]x \approx 0.858\,m[/tex]

El resorte se deforma 0.858 metros.

c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.

d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).

Invitamos cordialmente a ver este problema sobre el principio de conservación de la energía: https://brainly.com/question/16582988


Related Questions

what is noise pollution? what are the necessary measures to be taken to reduce it ?​

Answers

Answer:

Explanation:

Definition: Noise pollution is generally defined as regular exposure to elevated sound levels that may lead to adverse effects in humans or other living organisms.

Measures to be taken:

international bodies like the WHO agree that awareness of noise pollution is essential to beat this invisible enemy. For example: avoid very noisy leisure activities, opt for alternatives means of transport such as bicycles or electric vehicles over taking the car, do your housework at recommended times, insulate homes with noise-absorbing materials, etc. Educating the younger generation is also an essential aspect of environmental education.Governments can also take measures to ensure correct noise management .Close the Windows.Put on Earplugs. … Improve your Insulation. … Invest in Noise-Canceling Headphones. … Do Wall-to-Wall Carpeting. … Install a Fence. … Be Creative with the Office or House Layout. … Invest in Noise-Friendly Flooring..
I can give an example
On a movie called a quiet place, after years of noise pollution, a meteor hits earth a hence come a type of alien that is blind and hunts by sound on top of being bulletproof so the family has to lean to survive until being quiet, like using sign language or walking barefoot on sand paths.

What is one way homeostasis benefits living organisms?
it maintains balance.
It reduces air pollution.
It increases food consumption
It regulates atmospheric temperature

Answers

Answer:

it maintains balance, it keeps body temperatures , heart rate and all other bodily functions regulated to keep the organism stable when the environment is not.

Answer:

What the other guy said.

Explanation:

Yeah I'm doing this so he can have brainliest.

A cube has a volume of 583cm^3. What is the length of one side?

Answers

Answer:

shdkahfkkfrgs

Explanation:

:)

Definition of Reverse bump

Answers

Answer:As the name implies, the Bump and Run Reversal (BARR) is a reversal pattern that forms after excessive speculation drives prices up too far, too fast. Developed by Thomas Bulkowski, the pattern was introduced in the June-97 issue of Technical Analysis of Stocks and Commodities and also included in his book, the Encyclopedia of Chart Patterns.

THIS AIN'T MINE

Answer:

to collide with (something) with a moderately forceful impact; thump.

Explanation:

A 1800 kg car moving south at 17.5 m/s collide with a 2800 kg car moving north. The cars stick together and move as a unit after the collision at a velocity of 5.22 m/s to the north. Find the velocity of the 2800 kg car before the collision

Answers

Answer:

   v₀₂ = -2.67 m / s

Explanation:

Let's use the conservation of the moment, for this we define a system formed by the two cars.

Consider the north direction as positive and the subscript 1 will be used for car 1 and the subscript 2 for the second car

Initial instant. Before the crash

          p₀ = -m₁ v₀₁ + m₂ v₀₂

Final moment. Right after the crash

          p_f = (m₁ + m₂) v

           p₀ = p_f

           -m₁ [tex]v_{o1}[/tex] + m₂ v_{o2} = (m₁ + m2) v_{f}

         v₀₂ = [tex]\frac{(m_1 +m_2) v }{m_2}[/tex]+  [tex]\frac{m_1 v_{o1} }{m_{1} }[/tex]

 

let's calculate

          v₀₂ = [tex]\frac{(1800 +2800) 5.22 + 1800 (-17.5)}{2800}[/tex]

          v₀₂ = -2.67 m / s

the negative sign indicates that the carriage moves in the opposite direction of the temperies

can anyone help me with differentiate between radio waves and x rays . Please Tomorrow is my exams This is A Imporrant question according to teacher..And all he taught was There definition​

Answers

search it or use answers, really helps!!

Answer:

The only difference between the two is that the frequency of X-rays is very much higher than radio waves. If, on the other hand, the radio waves or X-rays are propagating through a medium other than the vacuum, their speed will generally be less than c and will depend upon the specific properties of the medium.

what do fluorine, sodium, and aluminum have in common

Answers

Both are isoelectronic with Ne; i.e., their outside shells are filled with eight electrons and all have the same number of electrons (that is the isoelectronic part).

A spring is pulled to 10 cm and held in place with a force of 500 N. What is the spring constant of the spring in N/cm?

Answers

Answer:

K=50N/cm

Explanation:

Force can be calculated using below expresion;

F=ke

where f = force,

k =spring constant,

e = extension

force = 500 N

e= 10 cm =

Then substitute, the given values

500=10 × k

k=500/10

K=50N/cm

Waves are observed passing under a dock. Wave crests are 8.0 meters apart. The time for a complete wave to pass by is 4.0 seconds. The markings on the post submerged in water indicate that the water level fluctuates from a trough at 6.0 meters to a crest at 9.0 meters. Calculate the velocity of the wave.

Answers

Answer:

  2 m/s

Explanation:

The crest of the wave moves 8 meters in 4 seconds, so its speed is ...

  (8 m)/(4 s) = 2 m/s

Answer:

2 m/s is the answer .

Explanation:

#CarryOnLearning

How many electrons per second flow through a wire with a 12pA current?

Answers

Hence total 1.25x10^19 electrons are flowing through a wire if 2A current is flowing for 1 sec.

A person drives for 1.00 h at 10.0 km/h and 2.00 h at 20.0 km/h. What is their average speed, in SI units?

A.
4.63 m/s
B.
16.7 km/h
C.
10.3 mph
D.
16.7 m/s

Answers

i believe it is b if i’m correct

Which statement is true of an electromagnetic wave?
A. The wave needs particles in matter as a medium.
B. The wave travels through electric and magnetic fields.
C. The wave is caused by vibrating particles of matter.
D. The wave carries mechanical energy.

Answers

Answer:

C

Explanation:

Electromagnetic waves are produced by the vibration of charged particles.

The true statement of an electromagnetic wave is option c. The wave is caused by vibrating particles of matter.

What is an electromagnetic wave?

It is the wave that should be developed that leads to the vibration that lies between the electric field and a magnetic field.

Here EM waves should be composed for oscillating magnetic and electric fields.

Hence, the option c is correct.

Learn more about wave here: https://brainly.com/question/19053849

If the sun were to burn out, it would take humans just over 8 minutes to realize because light from the sun takes just over 8
minutes to reach earth. Tommy was 3 years old when his dad showed him a particular star that was estimated to be 18 light years
away from earth. If the star burned out immediately after Tommy was showed it, how old would Tommy be before he realized the
star was gone?
A)
21 years old
B)
18 years old
9 years old
D)
6 years old

Answers

the answer is (a. 21

Answer:the answer it’s A) I just took the test on USATestPrep

Explanation:

3. A fighter jet covers a distance of 895m while accelerating from 22m/s to 35m/s. How long (in
seconds) did this take to happen?

Answers

Answer:

31.404 seconds

Explanation:

To answer this equation, SUVAT is your best option utilizing and rearranging the known values to solve for the unknown.

here we have the values for

s=895

u=22

v=35

t= the unknown value

in this instant the equation s=0.5 x (u+v)t is the best equation to use

so we sub in the known values

895=0.5 x (22+35)t

rearrange to solve for t

895=28.5t

895/28.5=t

t=31.404 seconds (rounded to 3 decimal places)

If you are at the top of a hill on a roller coaster at rest and you are able to complete a loop with a radius of 30 m,

a) find the minimum speed to complete the loop (hint: this is a circular motion problem)

b) find the minimum height of the hill to complete the loop

Answers

Answer:

Explanation:

People are wild about amusement parks. Each day, we flock by the millions to the nearest park, paying a sizable hunk of money to wait in long lines for a short 60-second ride on our favorite roller coaster. The thought prompts one to consider what is it about a roller coaster ride that provides such widespread excitement among so many of us and such dreadful fear in the rest? Is our excitement about coasters due to their high speeds? Absolutely not! In fact, it would be foolish to spend so much time and money to ride a selection of roller coasters if it were for reasons of speed. It is more than likely that most of us sustain higher speeds on our ride along the interstate highway on the way to the amusement park than we do once we enter the park. The thrill of roller coasters is not due to their speed, but rather due to their accelerations and to the feelings of weightlessness and weightiness that they produce. Roller coasters thrill us because of their ability to accelerate us downward one moment and upwards the next; leftwards one moment and rightwards the next. Roller coasters are about acceleration; that's what makes them thrilling. And in this part of Lesson 2, we will focus on the centripetal acceleration experienced by riders within the circular-shaped sections of a roller coaster track. These sections include the clothoid loops (that we will approximate as a circle), the sharp 180-degree banked turns, and the small dips and hills found along otherwise straight sections of the track.

Which wave has a greater frequency?

Answers

The wave diagramed in blue.

Answer:

The wave diagramed in blue.

Explanation:

The reason for this is because frequency is explained as the number of times something has occurred in a certain period of time.

Here, we are talking about wavelength, so the frequency is the number of times the wave can oscillate in this time length.

Say we make dots on the middle of each downward slope. How long does it take to get to each dot compared to the other diagram? The answer is the one with the least amount of time. The wave diagramed in blue.

1. When is the object in motion?​

Answers

Answer:

An object is in motion when its distantance from another object is changing

Answer:

when an object is moving..

Explanation:

mark me as brainlist

what is the rate of acceleration of a 2,000-kilogram truck if a force of 4,300 N is used to make it start moving forward

Answers

The acceleration is 2.1m/s².
m=2000kg
F=4200N
a=4200/2000=2.1m/s²

who was the chairman of drafting committe​

Answers

Dr. Babasaheb Ambedkar, chairman of the Drafting Committee, presenting the final draft of the Indian Constitution to Dr. Rajendra Prasad on 25 November 1949. Constituent Assembly of India.
Dr. B. R. Ambedkar was the chairman of constitution drafting committee of Constituent Assembly. He single handedly struggled for the upliftment of the Dalits and downtrodden low castes, giving them social equality, self respect and political empowerment.

Using a box covered with graph paper allows you to simulate which aspect of a car crash?

Answers

Answer:

a computer modeling

Explanation:

Could somebody pls help me out with this?

1) You serve a Volleyball with a mass of 1.6kg. the ball leaves your hand with a speed of 25m/s. the ball has________energy. Calculate it.

2) Askateboard is sitting at the top of a hill that is 26m high. the skateboard weighs 2 N. the skateboard has _____energy. Calculate it.​

Answers

1) kinetic
2) potential

Which organelle captures sunlight and helps in food synthesis?
Chloroplast
Mitochondrion
Nucleus
Ribosome




Answers

Answer: Chloroplast

Explanation: Chloroplasts work to convert the Sun's light energy into sugars that cells can use. It's like a solar panel that converts energy from sunlight into electric power.

Chloroplast

Explanation: Conducts photosynthesis and creates sugars for the plant

A roller coaster has a loop in which the centripetal acceleration equals 9.8m/s2 . Of the tangential speed of the roller coaster cars is 15-7 m/s

Answers

Answer:

25.152m

Explanation:

Compete question;

A roller coaster has a loop in which the centripetal acceleration equals 9.8m/s² . If the tangential speed of the roller coaster cars is 15.7 m/s, find its radius.

centripetal acceleration a = v²/r

v is the tangential speed

r is the radius

Given

v = 15.7m/s

a = 9.8m/s²

9.8 =  15.7²/r

9.8r = 15.7²

r = 15.7²/9.8

r = 246.49/9.8

r = 25.152m

Hence the radius of the coaster is 25.152m

A ball of mass 12 kg is released from a height of 2.5 m
find the gravitational potential energy of the ball at point A
and when it reach the ground.
then deduce the kinetic energy of the ball once it reach the ground
(use g=10 N/kg) * 5

Answers

Answer:

300 J

Explanation:

From conservation of energy;

Gravitational potential energy at top = Kinetic Energy at bottom

mgh = ½mv²

We are given;

Mass; m = 12 kg.

Height; h = 2.5 m

g = 10 m/s²

Thus;

mgh = 12 × 2.5 × 10 = 300 J

Since mgh = Kinetic Energy at bottom.

Thus; kinetic energy of the ball once it reach the ground = 300 J

Temperature and Thermal Energy
Quiz
Active
2
6
7
8
10
TIME REMAINING
47:44
What happens when the thermal energy of a substance increases?
The motion of the particles in the substance increases, and the temperature of the substance decreases.
The motion of the particles in the substance decreases, and the temperature of the substance increases.
O Both the motion of the particles in the substance and the temperature of the substance decrease.
Both the motion of the particles in the substance and the temperature of the substance increase.

Answers

Answer:

the temperature increas

NEED HELP ASAP
thanks+BRAINLIST a only for correct answers
Thank you!

1.which type of image is right side up but left and right are reversed
A.real
B.virtual

2.Real images are:
A.always inverted
B.magnified or diminished
C.can be obtained on screen
D.all the above

Answers

Answer:

see below

Explanation:

1) B, virtual because the when you stand in front of a mirror, the image formed is virtual and Image is laterally inverted

2) D because, when using converging lens , real image is formed, it is inverted and it can also be magnified or diminished when the object is placed at different focal length.

real image can be captured on the screen because light rays meet at the image position

when using converging lens, the image formed if it is virtual is upright.

hope this helps

Please help me with this

Answers

Answer:

The most correct option for the magnitude of the velocity of the ship relative to the port is;

33 km/h

Explanation:

The given parameters of the cargo ship are;

The speed of the cargo ship = 25 km/h

The direction of the cargo ship, θ₁ = 20° North of East

The speed of the current = 10 km/h

The direction of the current, θ₂ = 15° North of East relative to the port

Therefore the direction of the ship relative to the port, 'θ', is given as the sum of θ₁ and θ₂ as follows;

θ = θ₁ + θ₂ = 20° + 15° = 35°

The component of the velocities relative to the port are given as follows;

The velocity of the ship, v₁ = 25·cos(35°)·i + 25·sin(35°)·j

The velocity of the current , v₂ = 10·cos(15°)·i + 10·sin(15°)·j

The velocity of the ship relative to the port, v = (25·cos(35°) + 10·cos(15°))·i + (25·sin(35°) + 10·sin(15°))·j

∴ v ≈ 30.14·i + 16.93·j

The magnitude of 'v' is [tex]\left | v \right |[/tex] = √(30.14² + 16.93²) ≈ 34.6

Therefore, the magnitude of the velocity of the ship relative to the port, [tex]\left | v \right |[/tex] ≈ 34.6 km/h.

Therefore, the closest correct option for the velocity of the ship relative to the port is 33 km/h

Answer:

The correct option for the magnitude of the velocity of the ship relative to the port is...

(33 km/h)

What happens to waves near the shore?

Answers

Answer As a wave travels across the open ocean, it gains speed. When a wave reaches a shallow coastline, the wave begins to slow down due to the friction caused by the approaching shallow bottom. ... Think of it like driving a car at high speed and then slamming on the breaks. Everything is going to fly to the front.:Waves at the Shoreline: As a wave approaches the shore it slows down from drag on the bottom when water depth is less than half the wavelength (L/2). The waves get closer together and taller. ... Eventually the bottom of the wave slows drastically and the wave topples over as a breaker. hope this helps have a nice night❤️❤️❤️

Explanation:

AP physics Will give brainliest to correct answer.

Answers

Answer:

the 4th one

Explanation:

The answer is the 4th one

Why would a person who weighs 100 lbs. on Earth weigh significantly more on Ju-piter?


a. Jupiter has more gravitational force than Earth

b. Jupiter is farther away from the sun

c. Jupiter has no atmosphere

Answers

Answer:

Is a

Explanation:

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