Hi there!
[tex]\large\boxed{p(x) = 7x + 7x^2 + \frac{7}{2}x^3 + \frac{7}{6}x^4}[/tex]
Recall a Taylor series centered at x = 0:
[tex]p(x) = f(0) + f'(0)(x) + \frac{f''(0)}{2}x^{2} + \frac{f'''(0)}{3!}x^{3} + ...+ \frac{f^n}{n!}x^n[/tex]
Begin by finding the derivatives and evaluate at x = 0:
f(0) = 7(0)e⁰ = 0
f'(x) = 7eˣ + 7xeˣ f'(0) = 7e⁰ + 7(0)e⁰ = 7
f''(x) = 7eˣ + 7eˣ + 7xeˣ f''(0) = 7(1) + 7(1) + 0 = 14
f'''(x) = 7eˣ + 7eˣ + 7eˣ + 7xeˣ f'''(0) = 21
f⁴(x) = 7eˣ + 7eˣ + 7eˣ + 7eˣ + 7xeˣ f⁴(0) = 28
Now that we calculated 4 non-zero terms, we can write the Taylor series:
[tex]p(x) = 0 + 7x + \frac{14}{2}x^2 + \frac{21}{3!}x^3 + \frac{28}{4!}x^4[/tex]
Simplify:
[tex]p(x) = 7x + 7x^2 + \frac{7}{2}x^3 + \frac{7}{6}x^4[/tex]
The length of a rectangle is 12 m and its diagonal is 15 m. find
the breadth and area of the rectangle.
Answer:
108 square metres
Step-by-step explanation:
A=√d square - l square
here
A = area
d= diagonal
l= length
what type of number cannot be written as a fraction p/q, where p and q are intergers and q is not equal to zero
Answer:
irrational numbers
Step-by-step explanation:
An irrational number is a number that cannot be expressed as a fraction p/q for any integers p and q.
Hi there!
»»————- ★ ————-««
I believe your answer is:
Irrational Number
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
The definition that is given in the question was the definition of a irrational number.A number that cannot be written as a fraction with two integers is called a irrational number. Some examples of irrational numbers are non-terminating decimals that do not repeat and non-perfect squares. A number that CAN be written as a fraction with two integers is called a rational number.⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
im stuck on this question!!!!
Answer:
reflected across the y axis: (5,2)
reflected across the x axis: (-2,5)
Answer:
Answer: (5,2) when reflected off the y-axis. (-5,-2) when reflected off the x-axis
please help me i begging.
Answer:
The two equivalent expressions are 6(x − y) and 6x − 6y.
Step-by-step explanation:
The awnser for this question
The radius of a sphere is increasing at a rate of 2 mm/s. How fast is the volume increasing (in mm3/s) when the diameter is 60 mm?
Answer:
22608 mm³/s
Step-by-step explanation:
Applying chain rule,
dV/dt = (dV/dr)(dr/dt)............... Equation 1
Where dV/dr = rate at which the volume is increasing
But,
V = 4πr³/3
Therefore,
dV/dr = 4πr²............... Equation 2
Substitute equation 2 into equation 1
dV/dt = 4πr²(dr/dt).............. Equation 3
From the question,
Given: dr/dt = 2 mm/s, r = 60/2 = 30 mm
Consatant: π = 3.14
Substitute these values into equation 3
dV/dt = 4×3.14×30²×2
dV/dt = 22608 mm³/s
Two functions, A and B, are described as follows: Function A y = 9x + 4 Function B The rate of change is 3 and the y-intercept is 4. How much more is the rate of change of function A than the rate of change of function B?
2
3
6
9
Answer:
[tex]{ \tt{rate \: of \: change \: in \: A = 9}}[/tex]
Rate of change in function A is two times than that in function B
You are dealt one card from a 52-card deck.
a) Find the odds in favor of getting a red king.
b) Find the odds against getting a red king.
Answer:
(a)So, there are 2 kings in red- one of hearts and the other of diamonds. Therefore, the probability of selecting a red king from a deck of cards= 2/52 or 1/26.
(b) There are 6 red face cards in a 52-card deck (so 46 other cards). PROBABILITIES compare the number of favorable outcomes to the total number of possible outcomes: The PROBABILITY of getting a red face card is 6/52 = 3/26.
The odds in favor of getting a red king will be 1/26. And the odds against getting a red king will be 25/26.
What is probability?Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.
You are dealt one card from a 52-card deck.
Total events = 52
The odds in favor of getting a red king will be
Favorable events = 2
Then the probability will be
P = 2/52
P = 1/26
The odds against getting a red king will be
q = 1 – P
q = 1 – 1/26
q = 25/26
More about the probability link is given below.
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Question 8 of 9
Use a calculator to find the correlation coefficient of the data set.
у
2
15
6
13
7
8
12
X
15
13
9
8
5
A. -0.909
B. 0.909
C. 0.953
D. -0.953
Actual data table :
X __ y
2 15
6 13
7 9
8 8
12 5
Answer:
0.953
Step-by-step explanation:
The question isnt well formatted :
The actual data:
X __ y
2 15
6 13
7 9
8 8
12 5
Using a correlation Coefficient calculator, the correlation Coefficient obtained by fitting the data is 0.953 which depicts a strong linear correlation between the x and y variable. This shows that the value of y increases with a corresponding increase in x values and vice versa.
sin4x - cosx
---------------- = f(x) f^1(π/4) what is the derivative?
tanx
I think you are asked to find the value of the first derivative of f(x) at π/4. Given
[tex]f(x) = \dfrac{\sin(4x)-\cos(x)}{\tan(x)}[/tex]
use the quotient to differentiate and you get
[tex]f'(x) = \dfrac{\tan(x)(4\cos(4x)+\sin(x))-(\sin(4x)-\cos(x))\sec^2(x)}{\tan^2(x)}[/tex]
Then at x = π/4, you have
tan(π/4) = 1
cos(4•π/4) = cos(π) = -1
sin(π/4) = 1/√2
sin(4•π/4) = sin(π) = 0
cos(π/4) = 1/√2
sec(π/4) = √2
==> f ' (π/4) = (1•(-4 + 1/√2) - (0 - 1/√2)•(√2)²) / 1² = -4 + 1/√2 + √2
To find the equation of a line, we need the slope of the line and a point on the line. Since we are requested to find the equation of the tangent line at the point (36, 6), we know that (36, 6) is a point on the line. So we just need to find its slope. The slope of a tangent line to f(x) at x
Answer:
[tex]m = \frac{1}{12}[/tex]
Step-by-step explanation:
Given
[tex](x,y) = (36,6)[/tex]
[tex]f(x) = \sqrt x[/tex] ----- the equation of the curve
Required
The slope of f(x)
The slope (m) is calculated using:
[tex]m = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h}[/tex]
[tex](x,y) = (36,6)[/tex] implies that:
[tex]a = 36; f(a) = 6[/tex]
So, we have:
[tex]m = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h}[/tex]
[tex]m = \lim_{h \to 0} \frac{f(36 + h) - 6}{h}[/tex]
If [tex]f(x) = \sqrt x[/tex]; then:
[tex]f(36 + h) = \sqrt{36 + h}[/tex]
So, we have:
[tex]m = \lim_{h \to 0} \frac{\sqrt{36 + h} - 6}{h}[/tex]
Multiply by: [tex]\sqrt{36 + h} + 6[/tex]
[tex]m = \lim_{h \to 0} \frac{(\sqrt{36 + h} - 6)(\sqrt{36 + h} + 6)}{h(\sqrt{36 + h} + 6)}[/tex]
Expand the numerator
[tex]m = \lim_{h \to 0} \frac{36 + h - 36}{h(\sqrt{36 + h} + 6)}[/tex]
Collect like terms
[tex]m = \lim_{h \to 0} \frac{36 - 36+ h }{h(\sqrt{36 + h} + 6)}[/tex]
[tex]m = \lim_{h \to 0} \frac{h }{h(\sqrt{36 + h} + 6)}[/tex]
Cancel out h
[tex]m = \lim_{h \to 0} \frac{1}{\sqrt{36 + h} + 6}[/tex]
[tex]h \to 0[/tex] implies that we substitute 0 for h;
So, we have:
[tex]m = \frac{1}{\sqrt{36 + 0} + 6}[/tex]
[tex]m = \frac{1}{\sqrt{36} + 6}[/tex]
[tex]m = \frac{1}{6 + 6}[/tex]
[tex]m = \frac{1}{12}[/tex]
Hence, the slope is 1/12
The figure shows trapezoid ABCD on a coordinate plane.
Which of the following represents the area of this figure, rounded to the nearest square unit?
99
121
198
231
Answer:
121 unit^2.
Step-by-step explanation:
The area = height/2 * ( sum of the opposite parallel lines)
= h/2(BC + AD
h = BF = 14 - 3 = 11 units.
BC = 13 - 5 = 8 units.
AD = 16 - 2 = 14 units.
Area = (11/2)(8 + 14)
= 5.5 * 22
= 121 unit^2.
Answer:
121
Step-by-step explanation:
What is the sum of 4th squared number and the 2nd cube number
Answer:
mark me as brinalist if answers are correct
I need help with this.
Answer:
A and b Are in quadrant 2. F and D are in quadrant 1. F is in quadrant 3 and C is in quadrant 4
Step-by-step explanation:
each quadrant is in the boxes and the question is asking what is each coordinate is in what quadrant
If a student walked 2 feet straight to the chalk board in 2 seconds and
then walked 2 feet back to his or her original position at his or her desk at
the same speed, what was the student's displacement at 2 seconds
compared to 0 seconds?
O 6 feet
O O feet
O2 feet
O 4 feet
Answer:
2 feet
Step-by-step explanation:
Displacement at 0 seconds is 0 feet.
Displacement at 2 seconds is 2 feet because it took them 2 seconds to walk 2 feet.
The speed (S) an object falls varies directly with time. If the speed is 49.0m/s after 5 seconds, then what is the speed after 3 seconds
9514 1404 393
Answer:
29.4 m/s
Step-by-step explanation:
Speed is proportional to time, so we have ...
speed / time = s/3 = 49/5
s = 3/5(49) = 29.4
The speed of the object is 29.4 m/s after 3 seconds.
Find the volume of the cone. Round to the nearest hundredth.
Answer:
Step-by-step explanation:
volume of cone=1/3 πr²h
=1/3×π×5²×11
=275/3 ×3.14
≈287.33 in³
Solve the equation −96=3(8x)^(5/3).
Answer:
x= - 1
Step-by-step explanation:
Help please!!!!! I’m using Plato
Answer:
[tex]\frac{y^{6} }{ x^{2} }[/tex]
Step-by-step explanation:
[tex]y^{6} x^{-2}[/tex]
Answer and Step-by-step explanation:
When there is a set of values within parenthesis, and an exponents on the values and on the parenthesis, you multiply the outer exponent with the inner exponent.
When a value has a negative exponent, the value that has the negative exponent will become a fraction and go to the denominator of the fraction (or go immediately to the denominator), or if it is already a fraction, goes to the denominator. If the value that has the negative exponent is in the denominator, the value will go to the numerator. In both instances, the negative exponent will then change to positive.
First, we need to simplify the expression inside the parenthesis.
[tex]y^{\frac{3}{2} } x^{-\frac{1}{2} } --> \frac{y^{\frac{3}{2} } }{x^{\frac{1}{2}} }[/tex]
Now we multiply the 4 to the exponents.
[tex]\frac{y^{\frac{3}{2} *\frac{x4}{1} } }{x^{\frac{1}{2}}*\frac{4}{1} } = \frac{y^{\frac{12}{2}} }{x^{\frac{4}{2}}} = \frac{y^6}{x^2}[/tex]
[tex]\frac{y^6}{x^2}[/tex] is the answer.
#teamtrees #PAW (Plant And Water)
Can someone help me with this an my other work please?
What is the scale factor from ALMN to AOPQ?
M
P
3
3
3
3
2
4
N
0
4
A. 4
(
B. 0
c
C. 3
D. 1
Answer:
D
Step-by-step explanation:
There 2 ways to interpret this problem.
From the info given:
These two triangles are congruent by SSS and congruent triangles have congruent or equal side lengths so the answer have to be 1.
If the triangles are similar, the side lengths form a proportion of that
[tex] \frac{3}{3} = \frac{3}{3} [/tex]
So the ratio or scale factor is 1.
The scale factor in the figure is 1.
What is a scale factor?A scale factor in math is the ratio between corresponding measurements of an object and a representation of that object.
Given that two triangles, LMN and OPQ, we need to find the scale factor,
We can see triangles are congruent, and we know that
Two triangles are congruent, by the SSS congruence criterion, if they are similar and the scale factor happens to be 1,
Hence, the scale factor in the figure is 1.
Learn more about scale factors, click;
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solve the inequality 4t^2 ≤ 9t-2 please show steps and interval notation. thank you!
Answer: [tex]t\in [\dfrac{1}{4},2][/tex]
Step-by-step explanation:
Given
Inequality is [tex]4t^2\leq9t-2[/tex]
Taking variables one side
[tex]\Rightarrow 4t^2-9t+2\leq0\\\Rightarrow 4t^2-8t-t+2\leq0\\\Rightarrow 4t(t-2)-1(t-2)\leq0\\\Rightarrow (4t-1)(t-2)\leq0[/tex]
Using wavy curve method
[tex]t\in [\dfrac{1}{4},2][/tex]
Simplify. v80
A. 16v5
B. 5v4
C. 4v5
D. 20v4
Hi!
√80 = √(16 • 5) = √(4² • 5) = 4√5
B
13 ft.
5 ft.
A
C
12 ft.
Find the value of Cos (B) =
Answer: the answer is 12/13
vention 1 of 10
These box plots show daily low temperatures for a sample of days in two
different towns
TWINA
M
41
41
Town 1
1620
MI
D
10
152025 M3540
Degrees (0)
Which statement is the most appropriate comparison of the centers?
O A. The median temperature for both towns is 20"
B. The mean for town A, 30", is greater than the mean for town 8,25"
C. The median temperature for both towns is 30'
D. The median for town A, 30', is greater than the median for town B,
25
PREVIOUS
9 M
The average of 6,10,x,20 and 30 is 18. what is the value of x
Answer:
24
Step-by-step explanation:
18 times 5 is 90 so that means that the given numbers have to add up to 90 (including x)
so,
6+10+20+30=66
90-66=24
I hope this helps!
Answer:
[tex]x = 24[/tex]
Step-by-step explanation:
[tex]6 + 10 + x + 20 + 30 = 18[/tex]
There are 5 numbers that we must add to average out to get 18 so let set this equation up
[tex] \frac{6 + 10 + x + 20 + 30}{5} = 18[/tex]
[tex]6 + 10 + x + 20 + 30 = 90[/tex]
[tex]x = 24[/tex]
A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with two hoses. Let X denote the number of hoses being used on the self-service island at a particular time, and let Y denote the number of hoses on the full-service island in use at that time. The joint pmf of X and Y appears in the accompanying tabulation.
p(x, y) y
0 1 2
x 0 0.10 0.03 0.01
1 0 08 0.20 0.06
2 0.05 0.14 0.33
(a) Given that X = 1, determine the conditional pmf of Y�i.e., pY|X(0|1), pY|X(1|1), pY|X(2|1).
(b) Given that two hoses are in use at the self-service island, what is the conditional pmf of the number of hoses in use on the full-service island?
(c) Use the result of part (b) to calculate the conditional probability P(Y ? 1 | X = 2).
(d) Given that two hoses are in use at the full-service island, what is the conditional pmf of the number in use at the self-service island?
Answer:
(a): The conditional pmf of Y when X = 1
[tex]p_{Y|X}(0|1) = 0.2353[/tex]
[tex]p_{Y|X}(1|1) = 0.5882[/tex]
[tex]p_{Y|X}(2|1) = 0.1765[/tex]
(b): The conditional pmf of Y when X = 2
[tex]p_{Y|X}(0|2) = 0.0962[/tex]
[tex]p_{Y|X}(1|2) = 0.2692[/tex]
[tex]p_{Y|X}(2|2) = 0.6346[/tex]
(c): From (b) calculate P(Y<=1 | X =2)
[tex]P(Y\le1 | X =2) = 0.3654[/tex]
(d): The conditional pmf of X when Y = 2
[tex]p_{X|Y}(0|2) = 0.025[/tex]
[tex]p_{X|Y}(1|2) = 0.150[/tex]
[tex]p_{X|Y}(2|2) = 0.825[/tex]
Step-by-step explanation:
Given
The above table
Solving (a): The conditional pmf of Y when X = 1
This implies that we calculate
[tex]p_{Y|X}(0|1), p_{Y|X}(1|1), p_{Y|X}(2|1)[/tex]
So, we have:
[tex]p_{Y|X}(0|1) = \frac{p(y = 0\ n\ x = 1)}{p(x = 1)}[/tex]
Reading the data from the given table, the equation becomes
[tex]p_{Y|X}(0|1) = \frac{0.08}{0.08+0.20+0.06}[/tex]
[tex]p_{Y|X}(0|1) = \frac{0.08}{0.34}[/tex]
[tex]p_{Y|X}(0|1) = 0.2353[/tex]
Using the format of the above formula for the rest, we have:
[tex]p_{Y|X}(1|1) = \frac{0.20}{0.34}[/tex]
[tex]p_{Y|X}(1|1) = 0.5882[/tex]
[tex]p_{Y|X}(2|1) = \frac{0.06}{0.34}[/tex]
[tex]p_{Y|X}(2|1) = 0.1765[/tex]
Solving (b): The conditional pmf of Y when X = 2
This implies that we calculate
[tex]p_{Y|X}(0|2), p_{Y|X}(1|2), p_{Y|X}(2|2)[/tex]
So, we have:
[tex]p_{Y|X}(0|2) = \frac{p(y = 0\ n\ x = 2)}{p(x = 2)}[/tex]
Reading the data from the given table, the equation becomes
[tex]p_{Y|X}(0|2) = \frac{0.05}{0.05+0.14+0.33}[/tex]
[tex]p_{Y|X}(0|2) = \frac{0.05}{0.52}[/tex]
[tex]p_{Y|X}(0|2) = 0.0962[/tex]
Using the format of the above formula for the rest, we have:
[tex]p_{Y|X}(1|2) = \frac{0.14}{0.52}[/tex]
[tex]p_{Y|X}(1|2) = 0.2692[/tex]
[tex]p_{Y|X}(2|2) = \frac{0.33}{0.52}[/tex]
[tex]p_{Y|X}(2|2) = 0.6346[/tex]
Solving (c): From (b) calculate P(Y<=1 | X =2)
To do this, where Y = 0 or 1
So, we have:
[tex]P(Y\le1 | X =2) = P_{Y|X}(0|2) + P_{Y|X}(1|2)[/tex]
[tex]P(Y\le1 | X =2) = 0.0962 + 0.2692[/tex]
[tex]P(Y\le1 | X =2) = 0.3654[/tex]
Solving (d): The conditional pmf of X when Y = 2
This implies that we calculate
[tex]p_{X|Y}(0|2), p_{X|Y}(1|2), p_{X|Y}(2|2)[/tex]
So, we have:
[tex]p_{X|Y}(0|2) = \frac{p(x = 0\ n\ y = 2)}{p(y = 2)}[/tex]
Reading the data from the given table, the equation becomes
[tex]p_{X|Y}(0|2) = \frac{0.01}{0.01+0.06+0.33}[/tex]
[tex]p_{X|Y}(0|2) = \frac{0.01}{0.40}[/tex]
[tex]p_{X|Y}(0|2) = 0.025[/tex]
Using the format of the above formula for the rest, we have:
[tex]p_{X|Y}(1|2) = \frac{0.06}{0.40}[/tex]
[tex]p_{X|Y}(1|2) = 0.150[/tex]
[tex]p_{X|Y}(2|2) = \frac{0.33}{0.40}[/tex]
[tex]p_{X|Y}(2|2) = 0.825[/tex]
How to find the surface area of a cuboid
Answer:
To find the surface area of a cuboid we can also label the length, width and the height of the prism and use the formula SA=2LW+2LH+2HW to find the area of a cuboid
Answer:
202 cm²
Step-by-step explanation:
The opposite faces of a cuboid are congruent , then
SA = top/bottom + front/ back + sides , that is
SA = 2(9 × 4) + 2(9 × 5) + 2(4 × 5)
= 2(36) + 2(45) + 2(20)
= 72 + 90 + 40
= 202 cm²
What type of line is PQ⎯⎯⎯⎯⎯⎯⎯⎯?
Answer:
median
Step-by-step explanation:
Q is at the midpoint of RS and so PQ is a median
A median is a segment from a vertex to the midpoint of the opposite side.
We want to define what type of line is PQ (the line that passes through points P and Q) by looking at the given image, one can easily see that the line PQ is a median, now let's explain why.
First, let's analyze the image:
In the image, we can see that P is one vertex of the triangle, and Q is the midpoint of the segment RS (you can see that RQ = 4 and QS = 4) , where R and S are the other two vertexes of the triangle.
Particularly, we can define a median of a triangle as the line that passes through the midpoint of one side of the triangle and by the vertex that does not belong to that side.
With that definition, we can see that PQ is a median because Q is the midpoint of one side of the triangle and P is the vertex that does not belong to that side.
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The sum of an a.p is 340. the first term is 7 and the common difference is 6. Cal the number of terms in the sequence.
anyone?
Common difference: 6
First term: 7
Second term: 13
Third term: 19
Fourth term: 25
Fifth term: 31
I hope this is correct and helps!
Answer to the following question is as follows;
Number of term in AP (N) = 10
Step-by-step explanation:
Given:
Sum of arithmetic progression (Sn) = 340
First term of AP (a) = 7
Common difference of AP (d) = 6
Find;
Number of term in AP (N)
Computation:
Sn = [n/2][2a + (n-1)d]
340 = [n/2][2(7) + (n-1)6]
340 = [n/2][14 + 6n - 6]
680 = n[6n + 8]
6n² + 8n - 680
Using Quadratic Formula
n = 10
Number of term in AP (N) = 10
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