Use the van der Waals equation to calculate the pressure exerted by 1.475 molmol of Cl2Cl2 in a volume of 4.635 LL at a temperature of 299.0 KK .

Answers

Answer 1

Answer:

7.812atm

Explanation:

Using Van der Waals equation, which goes as follows:

Pv = nRT

Where;

P is the pressure

V is the volume (4.635L)

n is the number of moles (1.475mol)

T is the temperature (299K)

R is the universal gas constant (0.082057 L atm mol-1K-1)

Pv = nRT

P = nRT/V

P = 1.475 × 0.0821 × 299/4.635

P = 36.2081/4.635

P = 7.812atm


Related Questions

i will give the first person brainliest! please helppp

Answers

okay so the  Answer is c

A 1.00 gram sample of which of the following compounds contains the greatest mass of oxygen? And explain.

1. K2O2
2. Na2O
3. BeO

Answers

Answer:

BeO will have the greatest mass composition of oxygen

Explanation:

To solve this problem, we would find the mass composition of oxygen in each of the given sample.

To find this mass composition, let us derive the molecular mass of the given species;

  K₂O₂ = 2(39) + 2(16) = 110g/mol

  Na₂O = 2(23) + 16 = 62g/mol

   BeO = 9 + 16  = 25g/mol

Now; we know that mass of each sample is 1g;

mass composition of O in K₂O₂ = [tex]\frac{32}{110}[/tex] x  1= 0.29g

mass composition of O in Na₂O = [tex]\frac{16}{62}[/tex] x 1 = 0.26g

mass composition of O in BeO = [tex]\frac{16}{25}[/tex] x 1 = 0.64g

We can see that BeO will have the greatest mass composition of oxygen.

The mass composition of oxygen has been highest in BeO. Thus, option 3 is correct.

The molecular mass has been the mass of each element that has been present in the compound. The molecular mass of given compounds have been:

[tex]\rm K_2O_2[/tex] = 2(mass of K) + 2(mass of O)

= 2 (39) + 2 (16)

= 110 g/mol

[tex]\rm Na_2O[/tex]= 2(mass of N) + mass of O

= 2 (23) + 16

= 62 g/mol

BeO = mass of Be + mass of O  

= 9 + 16

= 23 g/mol

The mass composition of oxygen in 1 gram of the following compounds have been:

Mass composition = [tex]\rm \dfrac{Mass\;of\;Oxygen}{Molecular\;mass\;of\;compound}\;\times\;weight\;of\;sample[/tex]

[tex]\rm K_2O_2[/tex] = [tex]\rm \dfrac{32}{110}\;\times\;1\;gram[/tex]

[tex]\rm K_2O_2[/tex] = 0.29 grams

[tex]\rm Na_2O[/tex] = [tex]\rm \dfrac{16}{62}\;\times\;1\;gram[/tex]

[tex]\rm Na_2O[/tex] = 0.26 grams

BeO = [tex]\rm \dfrac{16}{23}\;\times\;1\;gram[/tex]

BeO = 0.64 grams.

The mass composition of oxygen has been highest in BeO. Thus, option 3 is correct.

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1. With the aid of a Hess cycle, determine the enthalpy of the decomposition reaction of sodium nitrate, NaNO3 to sodium nitrite, NaNO2 and oxygen, O2. [5]

Enthalpy of formation of NaNO3 = -468 kJ/mol
Enthalpy of formation of NaNO2 = -369kJ/mol

Answers

Answer:

Explanation:

2NaNO₃ = 2NaNO₂ + O₂

NaNO₃    =     NaNO₂   +    1/2 O₂

- 468 kJ           -369 kJ           0  kJ

enthalpy of decomposition reaction

= - 369 - ( - 468 ) kJ

= 99 kJ / mol .      

Question in picture!!!!!!

Answers

Answer:

6 atoms

Explanation:

Name 2 ways heat can be transferred through convention.

Answers

Answer:

Heat can travel from one place to another in three ways: Conduction, Convection and Radiation. Both conduction and convection require matter to transfer heat. If there is a temperature difference between two systems heat will always find a way to transfer from the higher to lower system.

Explanation:

Explain how Bohr's model built on the ideas of Einstein and Planck.

Answers

Explanation:

Bohr built on Nicholson's idea by adopting the requirement that the angular momentum can have only certain discrete values related to Planck's constant. However Bohr's atom has many orbits for the electrons.

Please help
It’s super quick

Answers

Answer:

1. a

Explanation:

2. c

Answer:

1 is A number two is C

28. A gas exerts pressure at 5atm at 300K. What is the pressure of the gas at 600K?
a) 1 atm b) 10 atm c).1 atm d) 100 atm

Answers

B the atm hehsjskkakajahhajajajajjajajajsjsjjsjsjsnsnnsns

What is the name of the process that is used to clean up environmental waste and how does it work?

Answers

Answer:

Environmental cleanup includes removal of heavy metals and other toxic contaminants from the environment and the process is called remediation.

Which of the following aqueous solutions has the lowest pH? Why?
a. 0.1 M HCl;
b. 0.1 M acetic acid (pKa = 4.86);
c. 0.1 M formic acid (pKa = 3.75

Answers

Answer:

HCI

Explanation:

The solution with the lowest pH is HCI with a pH value of 1. It is understood that it is more acidic because it is a strong acid.

What is the density of a glass piece that has mass of 18 g and a volume of 24 mL?

Answers

Answer:

The answer is 0.75 g/mL

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\ [/tex]

From the question we have

[tex]density = \frac{18}{24} = \frac{3}{4} \\ [/tex]

We have the final answer as

0.75 g/mL

Hope this helps you

Which are correct ???

Answers

Answer:

last one

Explanation:

endothermic reactions release energy

PLEASE HELP ME!!!!!!!!!!!!!!!!!!!
WRITE A SHORT PASSAGE ON HOW FIBRES ARE SPUN



HELPPP WILL MARK AS BRAINLIEST

Answers

Answer: Spun yarn is made by twisting staple fibers together

To make a cohesive thread Or “single”. Twisting fibers, into yarn in the process called spinning can be dated back to the upper Paleolithic. Yarn spinning was one of the first processes to be industrialized.

Explanation:

What most likely to cuase the rate of a chemical reaction to increase

Answers

Answer:

An increase on temperature.

Explanation:

Answer: adding a catalyst or increasing temperature

Explanation:


is the movement of particles from an area of higher concentration to an area of lower concentration

Answers

Answer:

The answer is Diffusion.

Answer:

Hypertonic

Explanation:

What are some foods that bacteria helps in the production of?

Answers

Answer:

yeasts, moulds, bread, beer, wine, ...

Explanation:

Two moles of acetyl chloride was mixed with two moles of dimethylamine. After the reaction is complete, what species can be found in the mixture

Answers

Answer:

See explanation

Explanation:

The reaction is shown in the image attached. This reaction occurs by a carbocation (ionic) mechanism.

The lone pair on the nitrogen atom attacks the carbocation leading to the formation of the product as shown in the image attached.

Since the reaction occurs in a 1:1 ratio, two moles of reactants yields two moles of product.

What mass is contributed by Br-79?

Answers

Answer:

Calculate the mass of BR -79? Bromine has 2 naturally occurring isotopes (Br-79 and Br-81) and has an atomic mass of 79.904 amu

Explanation:

if i get this wrong srry

What is the oxidation number of P in PF6−?

Answers

Answer:

P = +5

Hope it helps!

What is the Atomic number of 12

Answers

Answer:

atomic number of 12 is MG

Explanation:

Magnesium

Salt is water solution is made salt or water

Answers

Answer:

Both

Explanation:

because salt water comes from water mixing with salt

Which of the following conclusions about the two intermolecular forces is correct? X represents London dispersion forces, and Y represents ion-dipole forces. X represents dipole-dipole forces, and Y represents ion-dipole forces. X represents hydrogen bonding, and Y represents dipole-dipole forces. X represents London dispersion forces, and Y represents dipole-dipole forces.

Answers

Answer:

X represents London dispersion forces, and Y represents dipole-dipole forces.

Explanation:

How much heat would be required to convert 5.31 mol of a pure substance from a liquid at 40.0°C to a gas at 113.0°C?

Answers

Answer:

Q = 7.7 KJ

Explanation:

The complete question carries the following data:

Specific Heat Capacity of Liquid State = C(l) = 1.45 J/mol.°C

Specific Heat Capacity of Gaseous State = C(g) = 0.65 J/mol.°C

Boiling Temperature = Tb = 88.5°C

Heat of Vaporization = ΔH(vap) = 1.23 KJ/mol

Now, first we calculate the heat required (Q₁) to raise he temperature to boiling point:

Q₁ = n*C(l)*ΔT₁

where,

n = no. of moles = 5.31 mol

ΔT₁ = Temperature difference from 40°C to Tb = 88.5°C - 40°C = 48.5°C

Therefore,

Q₁ = (5.31 mol)(1.45 J/mol.°C)(48.5°C)

Q₁ = 373.4 J = 0.37 KJ

Now, we calculate the heat required (Q₂) to change its phase:

Q₂ = nΔH(vap)

Q₂ = (5.31 mol)(1.23 KJ/mol)

Q₂ = 6.53 KJ

Now, we calculate the heat required (Q₃) to raise he temperature to boiling point:

Q₃ = n*C(g)*ΔT₃

where,

n = no. of moles = 5.31 mol

ΔT₃ = Temperature difference from Tb to 113°C = 113°C - 88.5°C = 24.5°C

Therefore,

Q₃ = (5.31 mol)(0.65 J/mol.°C)(24.5°C)

Q₃ = 84.5 J = 0.08 KJ

So, the total heat required to convert 5.31 mol of this pure substance from a liquid at 40°C to a gas at 113°C is:

Q = Q₁ + Q₂ + Q₃

Q = 0.37 KJ + 6.53 KJ + 0.08 KJ

Q = 7.7 KJ

The total heat required to convert the pure substance from liquid to gas at the given temperature is 814 J.

The given parameters;

molar heat capacity of liquid, C(l) = 1.45 J/mol.⁰Cmolar heat capacity of gas, C(g) = 0.65 J/mol.⁰C

The total heat required to convert the pure substance from liquid to gas at the given temperature is calculated as follows;

[tex]Q = nc_l \Delta \theta + nc_g \Delta \theta \\\\ \Delta \theta = (113 - 40) = 73^0 C \\\\Q = (5.31 \ mol \times 1.45 \frac{J}{mol .\ ^0C} \times 73\ ^0C) + (5.31 \ mol \times 0.65 \frac{J}{mol .\ ^0C} \times 73 \ ^0C)\\\\Q = 814 \ J[/tex]

Thus, the total heat required to convert the pure substance from liquid to gas at the given temperature is 814 J.

"Your question is not complete, it seems to be missing the following information;"

How much heat would be required to convert 5.31 mol of a pure substance from a liquid at 40.0°C to a gas at 113.0°C? (molar heat capacity of liquid, C(l) is 1.45 J/mol.⁰C and molar heat capacity of gas, C(g) is 0.65 J/mol.⁰C).

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PLEASE HELP IM TIMED

Which of the following is not an oxidation-reduction reaction?
Upper X e upper F subscript 6 (s) right arrow upper X e upper F subscript 4 (s) plus upper F subscript 2 (g).
2 upper C s (s) plus upper I subscript 2 (g) right arrow 2 upper C s upper I (s).
2 upper H subscript 2 upper S upper O subscript 4 (a q) plus 2 upper B a (upper O upper H) subscript 2 (a q) right arrow 2 upper B a upper S upper O subscript 4 upper H subscript 2 upper O (l).
Upper Z n (s) lus 2 upper A g upper N upper O subscript 3 (a q) right arrow upper Z n (upper N upper O subscript 3) subscript 2 (a q) plus upper A g (s).

Answers

Answer: choice 2

Explanation:

Calculate the number of moles of solute in 431.9 L of 0.722 M sodium cyanide.

Answers

Answer:

[tex]312 \ mol \ solute[/tex]

General Formulas and Concepts:

Chemistry

Molarity = moles of solute / liters of solution

Explanation:

Step 1: Define variables

M = 0.722

L = 431.9

m = x

Step 2: Solve for x

Substitute:                   [tex]0.722 \ M=\frac{x \ mol}{431.9 \ L}[/tex]Isolate x:                      [tex]311.832=x \ mol[/tex]Rewrite:                       [tex]x=311.832 \ mol[/tex]

Step 3: Check

Our smallest sig figs is 3. Follow sig figs rules.

[tex]311.832 \ mol \approx 312 \ mol \ solute[/tex]

The critical resolved shear stress for a metal is 35 MPa. Determine the maximum possible yield strength (in MPa) for a single crystal of this metal that is pulled in tension.

Answers

Answer:

The maximum possible yield strength for a single crystal is 70 MPa.

Explanation:

To find the maximum possible yield strength for a single crystal we need to use the following equation:

[tex]\sigma_{y} = \frac{\tau_{CRSS}}{m_{max}}[/tex]

Where:

[tex]m_{max}[/tex] is the maximum value for Schmid factor

[tex]\tau_{CRSS}[/tex] is the critical resolved shear stress = 35 MPa

[tex] \sigma_{y}[/tex] is the yield strength =?    

The Schmid factor is given by:

[tex]m = cos(\phi)cos(\lambda)[/tex]

And its maximum value is obtained when λ = 45° and Φ = 45°, so:

[tex] m = cos(45)cos(45) = 0.5 [/tex]

Finally, the maximum possible yield strength is:

[tex]\sigma_{y} = \frac{\tau_{CRSS}}{m_{max}} = \frac{35 MPa}{0.5} = 70 MPa[/tex]

Therefore, the maximum possible yield strength for a single crystal is 70 MPa.

I hope it helps you!                                                                                  

Write the net ionic equation for the acid-base reaction
PH3(aq) + HCl(aq) - PH4Cl(aq)

Answers

Explanation:

i dont understand dont you already have the equation?

The net ionic equation for the acid-base reaction PH[tex]_3[/tex](aq) + HCl(aq) [tex]\rightarrow[/tex] PH[tex]_4[/tex]Cl(aq) is PH[tex]_3[/tex](aq) + H⁺ (aq) [tex]\rightarrow[/tex] PH[tex]_4[/tex]⁺ .

What is net ionic equation?

Chemical reaction equations can be written in a variety of ways. Unbalanced chemical equations, which identify the species involved, balanced chemical equations, which identify the number and type of species, molecular equations, that also express compounds as molecules rather than component ions, and net ionic equations, which only address the species which contribute to a reaction, are some of the most popular.

A chemical equation for just a process known as the net ionic equation only includes the species that are really involved in the reaction.

PH[tex]_3[/tex](aq) + HCl(aq) [tex]\rightarrow[/tex] PH[tex]_4[/tex]Cl(aq)

PH[tex]_3[/tex](aq) + H⁺ (aq)  + Cl⁻ (aq) [tex]\rightarrow[/tex] PH[tex]_4[/tex]⁺ (aq)  + Cl⁻ (aq)

PH[tex]_3[/tex](aq) + H⁺ (aq) [tex]\rightarrow[/tex] PH[tex]_4[/tex]

Therefore,  the net ionic equation for the acid-base reaction is PH[tex]_3[/tex](aq) + H⁺ (aq) [tex]\rightarrow[/tex] PH[tex]_4[/tex]⁺ .

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When is a chemical equation considered balanced

Answers

Answer:

If each side of the equation has the same number of atoms of a given element, that element is balanced. If all elements are balanced, the equation is balanced.

Explanation:

Solubility
Mixtures and Solutions
Acellus
If 1.23 g of chlorine gas dissolves in
0.95 L of water at 15.6 psi, at what
pressure (in psi) would you be able
to dissolve 1.89 g in the same
amount of water?

Answers

The pressure : 23.48 psi

Further eplanation

Henry's Law stated that the solubility of a gas is proportional to its partial pressure  

Can be formulated  

S = kH. P.  

S = gas solubility, mol / L  

kH = Henry constant, mol / L.atm  

P = partial gas pressure  

1.23 g Cl₂

MW Cl₂ = 71 g/mol

mol of 1.23 g Cl₂ :

[tex]\tt mol=\dfrac{1.23}{71}=0.017[/tex]

Solubility O₂ : 0.017 mol/0.95 L =0.01789 mol/L

Henry's constant for O₂ :

P = 15.6 psi= 1.061517 atm

[tex]\tt S=kH.P\\\\kH=\dfrac{0.01789}{1,061517}=0.0169[/tex]

1.89 g Cl₂

[tex]\tt \dfrac{1.89}{71}=0.026[/tex]

[tex]\tt S=0.026:0.95=0.027\\\\P=\dfrac{S}{kH}=\dfrac{0.027}{0.0169}=1.598~atm=23,48~psi[/tex]

Answer:24.0

Explanation:

How does Newton’s second law apply to the golf tee balanced on the hoop? How does Newton’s second law apply to the golf tee when the hoop is pulled away?

please answer asap

Answers

Answer:

The law applies and it tells us that the object has constant velocity.

Explanation:

Using the second law of motion the momentum remains constant. Therefore, the velocity of the object is constant.

There are total three laws of newtons, first law of newtons, second law of newton and third law of newton. Therefore, when a golf club is subjected to an imbalanced force, its velocity changes, which is according to newton’s second law.

What is newton's second law?

According to Newton's Second Law of Motion, acceleration (gaining speed) occurs when a force acts on a mass (object). Riding a bicycle is a great example of this rule of motion in action. The mass is represented by your bicycle. The force is generated by your leg muscles pulling on the pedals of your bicycle.

The ball remains balanced on the tee due to the balanced forces of gravity downhill and upward. Force equals mass multiplied by acceleration (f=ma). When a golf club is subjected to an imbalanced force, its velocity changes.

Therefore, when a golf club is subjected to an imbalanced force, its velocity changes, which is according to newton’s second law.

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