Using the simple spinner below what is the probability of landing on either 2, 4, or 7?

Using The Simple Spinner Below What Is The Probability Of Landing On Either 2, 4, Or 7?

Answers

Answer 1

Answer:

3/10

Step-by-step explanation:

Total possibilities = 10

favourable possibilities = 3

Answer 2

Answer:

A

Step-by-step explanation:

There is a 1 out of 10 chance that it will land on 2.

There is a 1 out of 10 chance that it will land on 4.

There is a 1 out of 10 chance that it will land on 7.

[tex]\frac{1}{10}\cdot3=\frac{3}{10}[/tex] so the anwser is A.


Related Questions

Which choice correctly shows the solution(s) of the equation x2 = 1442
A)
x= √144
B)
x=V12
X=-
-V144
D)
x = 1V144

Answers

Answer:

Step-by-step explanation:

If the 2s are exponents, you need to indicate this with "^":  

x^2 = 144^2 means x² = 144²

x = ±√144² = ±144

Answer:

Step-by-step explanation:

f the 2s are exponents, you need to indicate this with "^":  

x^2 = 144^2 means x² = 144²

x = ±√144² = ±144

A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 3 large boxes and 5 small boxes has a total weight of 88 kilograms. A delivery of 12 large boxes and 2 small boxes has a total weight of 235 kilograms. How much does each type of box weigh?

Answers

Answer:

Step-by-step explanation:

We need a system of equations here. The first equation is that 3L boxes + 5s boxes (L = large and s = small) = 88 kg so

3L + 5s = 88

12L + 2s = 235 according to the other information given.

Solve the first equation for either L or s. I'll solve for L, just because:

3L = 88 - 5s and

L = [tex]\frac{88}{3}-\frac{5}{3}s[/tex] and sub that into the second equation for L:

[tex]12(\frac{88}{3}-\frac{5}{3}s)+2s=235[/tex] and if you distribute the 12 into the parenthesis you'll simplify it down a bit to

352 - 20s + 2s = 235 and combine like terms:

-18s= -117 so

s = 6.5 kg and plug that in to solve for L:

L = [tex]\frac{88}{3}-\frac{5}{3}(6.5)[/tex] and

L = 18.5 kg

Percent decrease from 20 to 11

Answers

Answer:

45 percent

Step-by-step explanation:

20-11=9

9 divided by 20= 0.45

0.45 x 100= 45%

Please Help!
Function: y=x^2+5x-7
Vertex: (___,___)
Solutions: (___,___) and (___,___)

* i thought the vertex was (-5/2,-53,4) but apparently i’m wrong since it keeps saying it* i need answers please

Answers

Answer:

Step-by-step explanation:

Write this quadratic equation in standard form.

Answers

Answer:

-[tex]x^{2} + 3x -8 = 0[/tex]

Step-by-step explanation:

[tex]x^{2} + x -8 - 2x = 0[/tex] [tex]x^{2} + 3x -8 = 0[/tex]

what percent is equal to 7/25​

Answers

28% because 25x4=100 7x4=28

Help please. I need the answer

Answers

Answer:

y=-2/3x+6

Step-by-step explanation:

Graph it

Answer:

y= -2/3 x + 6

Step-by-step explanation:

1. In the graph, you can see the points (0,6) and (6,2)

2. Since you have all the available options, you can input both points into all equations.

3. In this case, the correct answer is y= -2/3 x + 6

Write an inequality for the shaded region shown in the figure.​

Answers

Answer:

the equation of the circle is x^2 + y^2 < 36

NOT LESS OR EQUAL cause of the dotted lines

and the theory behind this is because the square root of 36 is +-6 so when the equation is less than +-6 the shade cannot go outside these point, if you know what i mean

hope that answers your question :)

1.8>4.7+w

Does anyone know what this may be ? Thank you very much .

Answers

Answer:

-2.9 > w

Step-by-step explanation:

1.8>4.7+w

Subtract 4.7 from each side

1.8-4.7>4.7-4.7+w

-2.9 > w

Answer:

w = -2.9

Step-by-step explanation:

An automobile went 84 miles on 6.5 gallons of gasoline. At this rate, how many gallons would be needed to travel 126 miles

Answers

Answer:

10 gallons

Step-by-step explanation:

84 ÷ 6.5 =12.9(The unit rate.)

Seeing as one gallon can get you 12.9 miles;

126÷12.9=9.7

So the answers 9.7 gallons, but if you need to round, then 10 to get a whole number.

Answer:

9.75

Step-by-step explanation:

We can write a ratio to solve

84 miles          126 miles

--------------   = -------------------

6.5 gallons        x gallons

Using cross products

84 x = 6.5 * 126

84x=819

84x/84 = 819/84

x = 9.75

Simplify, write without exponents.

[tex]2*4^{2} *(128\frac{1}{4})[/tex]


[tex]_\sqrt[_]{_}[/tex]


a.) 8

b.) 20

c.) 2

d.) 64

e.) 4

f.) 16

Answers

it is helpful to you

Question two
The lengths of the sides of a triangle are in the ratio 2:3:4. The shortest side is 14cm long.
Find the lengths of the other two sides​

Answers

Answer:

14 and 21 and 28

Step-by-step explanation:

2:3:4.

The shortest side is 14

14/2 = 7

Multiply each side by 7

2*7:3*7:4*7

14 : 21 : 28

Triangle are in the ratio 2:3:4.

2x =5

x = 5/2 = 2.5 cm

3x = 3(2.5) =7.5 cm
4x =4(2.5) =10.0 cm

in a fruit punch drink,the 3 ingredients are apple juice,orange juice and cramberry juice.if 3/4 of the drink is apple juice and 1/10 is orange juice then write the ratio of cranberry juice to apple juice to orange juice in its simplest form​

Answers

Answer:

3 : 15 : 2

Step-by-step explanation:

Let cranberry juice = x,

3/4 + 1/10 + x = 1

x = 3/20

Ratio = cranberry : apple : orange

= 3/20 : 3/4 : 1/10

= 3 : 15 : 2 (Times everything with 20)

what is the value of x

Answers

Answer:

c 112⁰

Step-by-step explanation:

cuz the triangle is the same and x is on a straight line so get 180 - 68 = 112

Answer:

the angle opposite to x is 61 degree (being alternate angle)

so

x+ 61 = 180(being linear pair)

or, x = 180 - 61

so, x = 119

the answer is 119(d).

HELP URGENT !!!!!!



what happens if the lines that are being cut by the transversal are not parallel

Answers

The answer is c. Alcohol your welcome

Suppose the distributor charges the artist a $40.00 cost for distribution, and the streaming services pays $4.00 per unit. (Note: One unit = one thousand streams)

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Formula: y = 40x + 4 (Graph Attached)

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

After how many streams will you pay for the distributor charges? (Hint: this is where the line crosses the x-axis, round to the nearest thousand)

Answers

Answer:

356 streams

Step-by-step explanation:

From the graph, you will see that the line cross the x-axis at x = 8.8

Substitute into the expression y = 40x + 4

y = 40(8.8)+4

y = 352 + 4

y = 356

Hence the distributor charges will be paid for after 356 streams

PLEASE ANSWER ASAP THANK YOU!!! How much money will be in a bank account after 3 years if $9 is deposited at an interest rate of 5% compounded annually? Round to the nearest dollar.....​

Answers

Answer:

10 bucks

Step-by-step explanation:

Money=9*(1+0.05)^3

Money=9*(1.05)^3=10.41≈10

Use formula autocomplete to enter a sum function in cell B7 to calculate the total of cells in B2:B6

Answers

Excel enables the users to perform mathematics basic and advanced function with just one formula.

The formula for sum of entire row or column can be done with just entering a single formula and results are shown in seconds.

The formula for sum of few column cells is,

=SUM(B2:B6)

The spreadsheet allows the user to enter various formula and results are displayed withing seconds.

There are formulas for basic math functions and there are also formulas for advance mathematics calculations. For addition of values of many cells sum formula is used and range is assigned for reference.

The formula adds all the values of selected cells and displays the results in different cell.

Learn more at https://brainly.com/question/24365931

The hypotenuse of a right triangle measures 14 cm and one of its legs measures 1 cm. Find the measure of the other leg. If necessary, round to the nearest tenth.

Answers

Answer:

b=14 cm

Step-by-step explanation:

Use pythagorean equation

A^2+b^2=c^2

1^2+b^2=14^2

1+b^2=196

b^2=195

b=13.964

Find the midpoint of the line segment defined by the points: (5, 4) and (−2, 1) (2.5, 1.5) (3.5, 2.5) (1.5, 2.5) (3.5, 1.5)

Answers

Answer:

[tex]\boxed {\boxed {\sf (1.5 , 2.5)}}[/tex]

Step-by-step explanation:

The midpoint is the point that bisects a line segment or divides it into 2 equal halves. The formula is essentially finding the average of the 2 points.

[tex](\frac {x_1+x_2}{2}, \frac {y_1+ y_2}{2})[/tex]

In this formula, (x₁, y₁) and (x₂, y₂) are the 2 endpoints of the line segment. For this problem, these are (5,4 ) and (-2, 1).

x₁= 5 y₁= 4 x₂= -2 y₂= 1

Substitute these values into the formula.

[tex]( \frac {5+ -2}{2}, \frac {4+1}{2})[/tex]

Solve the numerators.

5+ -2 = 5-2 = 3 4+1 = 5

[tex]( \frac {3}{2}, \frac{5}{2})[/tex]

Convert the fractions to decimals.

[tex](1.5, 2.5)[/tex]

The midpoint of the line segment is (1.5 , 2.5)

Help im stuck! xoxo thanks! <3

Answers

Answer:

3. 60° is the correct answer.

4. 8

Step-by-step explanation:

3. sum of all the sides of a quadrilateral is 360°

hence,

2h+2h+h+h=360°

6h=360°

h=360°/6

h=60°

4. Sum of interior angle of a polygon with n sides is 1080. N=8 (octagon)

Hope this helps you. Have a nice day.^_^

Answer:

3)60°

4)8 sides

Step-by-step explanation:

3) 2h+2h+h+h=360°

    6h=360°

    6h/6=360°/6

     h=60°

4)(n-2)180=1080°

  n-2=1080°/180

   n-2=6

    n=8

What would be the equation for this word problem?

Jack drove y miles in 20 mins. If he continues at the same rate how many miles can he drive in the next 15 mins?

Answers

9514 1404 393

Answer:

  d/15 = y/20

Step-by-step explanation:

At a given rate, distance is proportional to time. The distance d that Jack can drive in 15 minutes will be ...

 d/15 = y/20 . . . . the equation

  d = (3/4)y . . . . . the solution (multiply the above equation by 15, reduce)

[tex]\int\limits^a_b {(1-x^{2} )^{3/2} } \, dx[/tex]

Answers

First integrate the indefinite integral,

[tex]\int(1-x^2)^{3/2}dx[/tex]

Let [tex]x=\sin(u)[/tex] which will make [tex]dx=\cos(u)du[/tex].

Then

[tex](1-x^2)^{3/2}=(1-\sin^2(u))^{3/2}=\cos^3(u)[/tex] which makes [tex]u=\arcsin(x)[/tex] and our integral is reshaped,

[tex]\int\cos^4(u)du[/tex]

Use reduction formula,

[tex]\int\cos^m(u)du=\frac{1}{m}\sin(u)\cos^{m-1}(u)+\frac{m-1}{m}\int\cos^{m-2}(u)du[/tex]

to get,

[tex]\int\cos^4(u)du=\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{4}\int\cos^2(u)du[/tex]

Notice that,

[tex]\cos^2(u)=\frac{1}{2}(\cos(2u)+1)[/tex]

Then integrate the obtained sum,

[tex]\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int\cos(2u)du+\frac{3}{8}\int1du[/tex]

Now introduce [tex]s=2u\implies ds=2du[/tex] and substitute and integrate to get,

[tex]\frac{3\sin(s)}{16}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\int1du[/tex]

[tex]\frac{3\sin(s)}{16}+\frac{3u}{4}+\frac{1}{4}\sin(u)\cos^3(u)+C[/tex]

Substitute 2u back for s,

[tex]\frac{3u}{8}+\frac{1}{4}\sin(u)\cos^3(u)+\frac{3}{8}\sin(u)\cos(u)+C[/tex]

Substitute [tex]\sin^{-1}[/tex] for u and simplify with [tex]\cos(\arcsin(x))=\sqrt{1-x^2}[/tex] to get the result,

[tex]\boxed{\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C}[/tex]

Let [tex]F(x)=\frac{1}{8}(x\sqrt{1-x^2}(5-2x^2)+3\arcsin(x))+C[/tex]

Apply definite integral evaluation from b to a, [tex]F(x)\Big|_b^a[/tex],

[tex]F(x)\Big|_b^a=F(a)-F(b)=\boxed{\frac{1}{8}(a\sqrt{1-a^2}(5-2a^2)+3\arcsin(a))-\frac{1}{8}(b\sqrt{1-b^2}(5-2b^2)+3\arcsin(b))}[/tex]

Hope this helps :)

Answer:[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(a) + 2a(1 - a^2)^\Big{\frac{3}{2}} + 3a\sqrt{1 - a^2}}{8} - \frac{3arcsin(b) + 2b(1 - b^2)^\Big{\frac{3}{2}} + 3b\sqrt{1 - b^2}}{8}[/tex]General Formulas and Concepts:

Pre-Calculus

Trigonometric Identities

Calculus

Differentiation

DerivativesDerivative Notation

Integration

IntegralsDefinite/Indefinite IntegralsIntegration Constant C

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                    [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

U-Substitution

Trigonometric Substitution

Reduction Formula:                                                                                               [tex]\displaystyle \int {cos^n(x)} \, dx = \frac{n - 1}{n}\int {cos^{n - 2}(x)} \, dx + \frac{cos^{n - 1}(x)sin(x)}{n}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx[/tex]

Step 2: Integrate Pt. 1

Identify variables for u-substitution (trigonometric substitution).

Set u:                                                                                                             [tex]\displaystyle x = sin(u)[/tex][u] Differentiate [Trigonometric Differentiation]:                                         [tex]\displaystyle dx = cos(u) \ du[/tex]Rewrite u:                                                                                                       [tex]\displaystyle u = arcsin(x)[/tex]

Step 3: Integrate Pt. 2

[Integral] Trigonometric Substitution:                                                           [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos(u)[1 - sin^2(u)]^\Big{\frac{3}{2}} \, du[/tex][Integrand] Rewrite:                                                                                       [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos(u)[cos^2(u)]^\Big{\frac{3}{2}} \, du[/tex][Integrand] Simplify:                                                                                       [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \int\limits^a_b {cos^4(u)} \, du[/tex][Integral] Reduction Formula:                                                                       [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{4 - 1}{4}\int \limits^a_b {cos^{4 - 2}(x)} \, dx + \frac{cos^{4 - 1}(u)sin(u)}{4} \bigg| \limits^a_b[/tex][Integral] Simplify:                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4}\int\limits^a_b {cos^2(u)} \, du[/tex][Integral] Reduction Formula:                                                                          [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg|\limits^a_b + \frac{3}{4} \bigg[ \frac{2 - 1}{2}\int\limits^a_b {cos^{2 - 2}(u)} \, du + \frac{cos^{2 - 1}(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex][Integral] Simplify:                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4} \bigg[ \frac{1}{2}\int\limits^a_b {} \, du + \frac{cos(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex][Integral] Reverse Power Rule:                                                                     [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3}{4} \bigg[ \frac{1}{2}(u) \bigg| \limits^a_b + \frac{cos(u)sin(u)}{2} \bigg| \limits^a_b \bigg][/tex]Simplify:                                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(u)sin(u)}{4} \bigg| \limits^a_b + \frac{3cos(u)sin(u)}{8} \bigg| \limits^a_b + \frac{3}{8}(u) \bigg| \limits^a_b[/tex]Back-Substitute:                                                                                               [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{cos^3(arcsin(x))sin(arcsin(x))}{4} \bigg| \limits^a_b + \frac{3cos(arcsin(x))sin(arcsin(x))}{8} \bigg| \limits^a_b + \frac{3}{8}(arcsin(x)) \bigg| \limits^a_b[/tex]Simplify:                                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(x)}{8} \bigg| \limits^a_b + \frac{x(1 - x^2)^\Big{\frac{3}{2}}}{4} \bigg| \limits^a_b + \frac{3x\sqrt{1 - x^2}}{8} \bigg| \limits^a_b[/tex]Rewrite:                                                                                                         [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(x) + 2x(1 - x^2)^\Big{\frac{3}{2}} + 3x\sqrt{1 - x^2}}{8} \bigg| \limits^a_b[/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:              [tex]\displaystyle \int\limits^a_b {(1 - x^2)^\Big{\frac{3}{2}}} \, dx = \frac{3arcsin(a) + 2a(1 - a^2)^\Big{\frac{3}{2}} + 3a\sqrt{1 - a^2}}{8} - \frac{3arcsin(b) + 2b(1 - b^2)^\Big{\frac{3}{2}} + 3b\sqrt{1 - b^2}}{8}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

Solve the equation Axb by using the LU factorization given for A. Also solve Axb by ordinary row reduction. A ​, b Let Lyb and Uxy. Solve for x and y. nothing nothing Row reduce the augmented matrix and use it to find x. The reduced echelon form of is nothing​, yielding x nothing.

Answers

Answer: Hello your question is poorly written attached below is the complete question

answer:

[tex]y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right][/tex]

[tex]x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right][/tex]

Step-by-step explanation:

[tex]y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right][/tex]

[tex]x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right][/tex]

attached below is the detailed solution using LU factorization

According to government data, the probability than an adult never had the flu is 19%. You randomly select 70 adults and ask if he or she ever had the flu. Decide whether you can use the normal distribution to approximate the binomial distribution, If so, find the mean and standard deviation, If not, explain why. Round to the nearest hundredth when necessary.

Answers

Answer:

Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.

The mean is 13.3 and the standard deviation is 3.28.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex], if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex].

The probability than an adult never had the flu is 19%.

This means that [tex]p = 0.19[/tex]

You randomly select 70 adults and ask if he or she ever had the flu.

This means that [tex]n = 70[/tex]

Decide whether you can use the normal distribution to approximate the binomial distribution

[tex]np = 70*0.19 = 13.3 \geq 10[/tex]

[tex]n(1-p) = 70*0.81 = 56.7 \geq 10[/tex]

Since [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal distribution can be used to approximate the binomial distribution.

Mean:

[tex]\mu = E(X) = np = 70*0.19 = 13.3[/tex]

Standard deviation:

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{70*0.19*0.81} = 3.28[/tex]

The mean is 13.3 and the standard deviation is 3.28.

.........................................................

Answers

Answer:

..............................what this

lim(x-0) (sinx-1/x-1)

Answers

9514 1404 393

Answer:

as written: the limit does not existsin(x-1)/(x-1) has a limit of sin(1) ≈ 0.841 at x=0

Step-by-step explanation:

The expression written is interpreted according to the order of operations as ...

  sin(x) -(1/x) -1

As x approaches 0 from the left, this approaches +∞. As x approaches 0 from the right, this approaches -∞. These values are different, so the limit does not exist.

__

Maybe you intend ...

  sin(x -1)/(x -1)

This can be evaluated directly at x=0 to give sin(-1)/-1 = sin(1). The argument is interpreted to be radians, so sin(1) ≈ 0.84147098...

The limit is about 0.841 at x=0.

A plane traveled 4425 miles with the wind in 7.5 hours and 3675 miles against the wind in the same amount of time. Find the speed of the plane in still air and the speed of the wind.

Answers

Answer:

540 and 50 respectively

Step-by-step explanation:

Let the speed of plane in still air be x and the speed of wind be y.

ATQ, (x+y)*7.5=4425 and (x-y)*7.5=3675. Solving it, we get x=540 and y=50

The sum of two positive integers is 19 and the product is 48

Answers

Answer:

16 and 3

Step-by-step explanation:

Let x and y represent the positive integers. We know that

[tex]x + y = 19[/tex]

[tex]xy = 48[/tex]

Isolate the top equation for the x variable.

[tex]x = 19 - y[/tex]

Substitute into the second equation.

[tex](19 - y)y = 48[/tex]

[tex]19y - {y}^{2} = 48[/tex]

[tex] - {y}^{2} + 19y = 48[/tex]

[tex] - {y}^{2} + 19y - 48[/tex]

[tex](y - 16)(y - 3)[/tex]

So our values are

16 and 3.

What are the zeros of this function?

Answers

Answer:

The zeros of this function would be: x = 4 and x = 6, assuming that option got caught off while you were taking a picture.

Step-by-step explanation:

When they're asking for the zeros of this type of function, where is forms this kind of U-shape or also known as a quadratic equation, they're asking what the x-value is when y = 0, or when the line of the function touches the x-axis. Notice that it happens when x = 4 and when x = 6.

In short, it's asking what the x-value is of the points of the function when it intersects the x-axis. Hopefully my explanation wasn't too confusing. Good luck on the rest of the quiz!

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