Answer:
Explanation:
Una manifestación, protesta o marcha es la exhibición pública de la opinión de un grupo activista (económica, política o social), mediante una congregación en las calles, a menudo en un lugar o una fecha simbólicos y asociados con esa opinión.
A vehicle is moving with a velocity of 20 m/s.how far does it moves in one hrs
How many moles of carbon are in the sample?
Answer:
12.01 grams per mole
Explanation:
theres no sample or example so if theres grams of Carbon, convert it to moles using 12.01g/mol
What is the balance equation for
_AI+_Pb(NO3)2—__Pb+__Ca(NO3)2
Answer:
2 Al + 3 Pb(NO3)2 > 2 Al(NO3)3 + 3 Pb
Explanation:
A toy plane has a mass of 2.5kg and is 18 m above the ground. It is moving 4.5 m/s.
how much mechanical energy does the toy have?
A. 416J
B. 441J
C. 466J
D. 491J
Answer:
466J (c)
Explanation:
Mechanical Energy= Kinetic+Potential
Potential energy= mgh
Plug in givens
mgh=2.5*18*9.8=441J
Kinetic Energy = 1/2mv^2
Plug in givens
1/2mv^2= 1/2(2.5)(4.5)^2= 25.3125J
Mechanical energy= 441J+25.3125J=466.3125J or 466J
Can someone do a True or false for these
Answer:
all i can accurately say is that 2 and 4 are both true
True or false, In a neutral atom of an element, the number of protons always equals the number of electrons.
Answer:
true
Explanation:
As an atom with no charge have same number of proton and electrons
A 80°C la presion de vapor del benceno (C6H6) es de 1 atm. Calcula la cantidad de hexano (C6H14) que debemos añadir a 200g de benceno para que su presion de vapor sea de 700mm de Hg
Answer:
18,9g de hexano son necesarios
Explanation:
Basados en la ley de Raoult, la presión de vapor ejercida por una solución es:
P = P°*Xsolvente
Donde P es la presión de la solución deseada = 700mmHg, P° la presión de vapor de vapor del benceno = 1atm = 760mmHg y X es la fracción molar del solvente (Benceno).
Reemplazando:
700mm Hg = 760mmHg * X(Benceno)
0.9211 = X(Benceno)
La fracción molar de benceno se define como:
X = Moles benceno / Moles benceno + Moles hexano
Moles benceno -Masa molar: 78g/mol-
200g * (1mol/78g) = 2.5641 moles benceno
X = Moles benceno / Moles benceno + Moles hexano
0.9211 = 2.5641 moles benceno / 2.5641 moles benceno + Moles hexano
0.9211moles Hexano + 2.3618 = 2.5641
0.9211*Moles Hexano = 0.2023
Moles hexano = 0.2023/0.9211 = 0.2196 moles hexano.
Masa Hexano -Masa molar: 86g/mol-
0.2196 moles hexano * (86g/mol) =
18,9g de hexano son necesariosLa cantidad de hexano (C6H14) que se debe agregar a 200 g de benceno para permitir que la presión de vapor se convierta en 700 mm de Hg sería:
18.9 g
Usando la ley de Raoult, la presión de vapor que libera una solución se encuentra por:
P = P ° × X disolvente
Donde (P) denota la presión de la solución deseada
P ° denota la presión de vapor del benceno y
X denota la fracción molar del disolvente (benceno).
En el caso dado,
(P) = 700 mmHg,
P° = 1atm = 760mmHg
Fracción molar de benceno = 0,9211 (∵ 700/760)
La fracción molar de benceno (X) = Moles de benceno/Moles de benceno + Moles de hexano
Moles de benceno - Masa molar: 78g / mol - 200 g × (1 mol / 78 g)
= 2.5641 moles de benceno
X = Moles de benceno/Moles de benceno + Moles de hexano
0.9211 = 2.5641 moles Benceno/2.5641 moles Benceno + Moles de Hexano
⇒ 0,9211 × moles de Hexano + 2,3618 = 2,5641
⇒ 0.9211 × moles de Hexano = 0.2023
∵ Moles de Hexano = 0.2023/0.9211
[tex]= 0.2196 moles[/tex]
[tex]Hexane mass - Molar mass = 86g/mol - 0.2196 mole hexane[/tex] × [tex](86g/mole)[/tex]
[tex]= 18.9g[/tex]
Por tanto, 18,9 g es la respuesta correcta.
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I need answers to question 1,2,3
Answer:
1. 0.125 mole
2. 42.5 g
3. 0.61 mole
Explanation:
1. Determination of the number of mole of NaOH.
Mass of NaOH = 5 g
Molar mass of NaOH = 23 + 16 + 1
= 40 g/mol
Mole of NaOH =?
Mole = mass /molar mass
Mole of NaOH = 5/40
Mole NaOH = 0.125 mole
2. Determination of the mass of NH₃.
Mole of NH₃ = 2.5 moles
Molar mass of NH₃ = 14 + (3×1)
= 14 + 3
= 17 g/mol
Mass of NH₃ =?
Mass = mole × molar mass
Mass of NH₃ = 2.5 × 17
Mass of NH₃ = 42.5 g
3. Determination of the number of mole of Ca(NO₃)₂.
Mass of Ca(NO₃)₂ = 100 g
Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (3×16)]
= 40 + 2[14 + 48]
= 40 + 2[62]
= 40 + 124
= 164 g/mol
Mole of Ca(NO₃)₂ =?
Mole = mass /molar mass
Mole of Ca(NO₃)₂ = 100 / 164
Mole of Ca(NO₃)₂ = 0.61 mole
define hydroscopy in chemistry
Answer: A hygroscopic substance is one that readily attracts water from its surroundings, through either absorption or adsorption
Explanation:
How many of each kind of atom is in one molecule of water? 1 hydrogen atom and 2 oxygen atoms 1 hydrogen atom and 1 oxygen atom 2 hydrogen atoms and 1 oxygen atom 2 hydrogen atoms and 2 oxygen atoms
Answer:
What period is the atom in?
1.
What group is the atom in?
What is the name of this atom?
What other atom would have similar
properties to the atom?
Will this atom conduct electricity well
Explanation:
How many of each kind of atom is in one molecule of water? 1 hydrogen atom and 2 oxygen atoms 1 hydrogen atom and 1 oxygen atom 2 hydrogen atoms and 1 oxygen atom 2 hydrogen
and 2 oxygen atoms
Balancing equations
1. __Na + __Oz -> __Na2O
Answer:
Balancing equations
1
[tex]4Na + O_{2} -> 2Na_{2}O[/tex]
Write a hypothesis to answer the lesson question
"How can electrolysis be used to separate a
compound into its components?"
If_____ (an electrical current, a salt, an electrode, or oxygen)?
is applied to water
containing an electrolyte, then the water will
decompose into____( water vapor, sodium gas, hydrogen gas, oxygen gas, hydrogen and oxygen gas)?
because____________?
Answer:
Electric current
Hydrogen and oxygen gas
Explanation:
Electrolysis is defined as a method of separation whereby an electric current is introduced into compounds to separate them . The electric current used here is a direct electric current (DC) and it makes the compound to be spit into its' component elements.
Now, in the case of water like it says in the question. Water is a mixture of hydrogen and oxygen gas. Thus, when electric current is passed through water which has an Electrolyte, it makes the water to decompose into its compound elements which are hydrogen and oxygen.
How does fluorine (F)differ from iodine(I)
A. Fluorine (F) has 3 more energy shells than iodine (I).
B. Fluorine (F) has 1 less energy shell than iodine (I).
C. Fluorine (F) has 1 more energy shell than iodine (I).
D. Fluorine (F) has 3 less energy shells than iodine (I).
Fluorine (F) and iodine(I) are the halogen elements that belong to group 17. They differ from each other as fluorine has 3 fewer energy shells than iodine. Thus, option D is correct.
What are halogen groups?Halogen is a nonmetallic element that belongs to group 17 and consists of six elements namely fluorine, bromine, tennessine, chlorine, astatine, and iodine.
They are diatomic and have 7 valence electrons in the outer shell, which makes them highly reactive and electronegative. The shielding effect is less in F than I due to the closer placement and attraction of the valence electron to the nucleus.
Fluorine differs from iodine as it has a smaller size with fewer energy shells than iodine. Iodine has five energy shells, whereas fluorine has two energy shells that make the difference of three shells between them.
Therefore, F and I differ from each other.
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PLEASE HELP ASAP!!!!!!!!
Answer:
ouch......it's kinda a practical question..
Answer: ?
Explanation: what was the answer?
(Please Help)
1.What is the most common isotope for element X
2.Calculate the average atomic mass or element X
Answer:
1. Isotope 2 occurs most commonly
2. 39.02amu
Explanation:
1. Isotope 2 has a relative abundance of 78.68% i.e. 78.68 out of 100, hence, it is the isotope that occurs most commonly.
2. Isotope 1 = 9.67%, mass no: 38
Isotope 2 = 78.68%, mass no: 39
Isotope 3 = 11.34%, mass no: 40
Isotope 4 = 0.31%, mass no: 41
To find the average atomic mass of element X, we multiply each isotopes' relative abundance by its mass no and find the sum as follows:
We convert each percentage to decimal abundance:
Isotope 1 = 9.67% = 0.0967
Isotope 2 = 78.68% = 0.7868
Isotope 3 = 11.34% = 0.1134
Isotope 4 = 0.31% = 0.0031
(0.0967 × 38) + (0.7868 × 39) + (0.1134 × 40) + (0.0031 × 41)
3.6746 + 30.6852 + 4.536 + 0.1271
Average atomic mass = 39.02amu
PLEASE HELP
Which of the following correctly orders the types of radiation from the LONGEST wavelength to the SHORTEST wavelength?
A. Green Visible Light, Red Visible Light, Blue Visible Light, Ultraviolet
B. Microwave, Orange Visible Light, Ultraviolet, Violet Visible Light
C. Red Visible Light, Infrared, Microwaves, Radio waves
D. Microwave, Blue Visible Light, Ultraviolet, Gamma
Answer:
D. Microwave, Blue Visible Light, Ultraviolet, Gamma
Explanation:
colors longest to shortest are
red green blue violet
longest wavelength to shortest:
radio waves, microwaves, infrared, optical, ultraviolet, X-rays, and gamma-rays.
What volume is occupied by 0.109 molmol of helium gas at a pressure of 0.98 atmatm and a temperature of 307 K
Answer:
2.8 L
Explanation:
From the question given above, the following data were obtained:
Number of mole (n) = 0.109 mole
Pressure (P) = 0.98 atm
Temperature (T) = 307 K
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) =?
The volume of the helium gas can be obtained by using the ideal gas equation as follow:
PV = nRT
0.98 × V = 0.109 × 0.0821 × 307
0.98 × V = 2.7473123
Divide both side by 0.98
V = 2.7473123 / 0.98
V = 2.8 L
Thus, the volume of the helium gas is 2.8 L.
Cuál o cuáles de las siguientes características son correctas para la mayoría de los compuestos del carbono?
I) Los compuestos del carbono son solubles en disolventes no polares como el hexano, benceno, éter, etc.
II) Los compuestos del carbono generalmente presentan puntos de fusión y de ebullición bajos
III) La gran mayoría de los compuestos del carbono son combustibles, sean estos, gaseosos, líquidos o sólidos
IV) El enlace covalente es característico de los compuestos del carbono
Todas son correctas
II
I y IV
I, III y IV
Answer:
Todas son correctas
Explanation:
I) Los compuestos del carbono son solubles en disolventes no polares como el hexano, benceno, éter, etc. VERDADERO. La mayoría de los compuestos de carbono son apolares, y basados en la regla: Similar disuelve similar, podemos presumir que la mayoría de compuestos de carbono se disuelven en solventes no polares.
II) Los compuestos del carbono generalmente presentan puntos de fusión y de ebullición bajos. VERDADERO. Al ser sustancias apolares, sus fuerzas electrostáticas son bajas. De la misma manera, como su masa atómica es pequeña, las fuerzas de Van der Waals son despreciables haciendo que sus puntos de fusión y ebullición sean bajos respecto a sustancias de estrucutra similar.
III) La gran mayoría de los compuestos del carbono son combustibles, sean estos, gaseosos, líquidos o sólidos. VERDADERO. Los gases (Como el gas natural) son combustibles usados para cocina. Los líquidos (Como la gasolina) son combustibles y bastante inflamables. Los sólidos (Como la madera) se usan como combustibles para hacer asados o son el combustible en incendios forestales.
IV) El enlace covalente es característico de los compuestos del carbono. VERDADERO. La polaridad del carbono es neutral haciendo que la mayoría de los enlaces que forma sean covalentes.
Todas son correctas
Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride?
CSF + XeF6 → CsXeF7
Answer: A mass of 84.46 g of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride.
Explanation:
Given: Mass of cesium xenon heptafluoride = 73.1 g
The molar mass of cesium xenon heptafluoride is 131.3 g/mol. So, moles of [tex]CsXeF_{7}[/tex] is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{73.1 g}{131.3 g/mol}\\= 0.556 mol[/tex]
According to the given equation, 1 mole of CsF yields 1 mole of [tex]CsXeF_{7}[/tex].
Hence, moles of CsF reacting will also be equal to 0.556 mol. As molar mass of CsF is 151.9 g/mol so its mass is calculated as follows.
[tex]Moles = \frac{mass}{molarmass}\\0.556 mol = \frac{mass}{151.9 g/mol}\\mass = 84.46 g[/tex]
Thus, we can conclude that a mass of 84.46 g of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride.
PLS HELP!!
Compare and contrast an electrolytic cell with a voltaic cell. Provide one example where both are present in daily life.
Answer:
See explanation
Explanation:
An electrolytic cell functions by a non spontaneous chemical process. Energy is supplied in the form of electricity through a battery to drive the electrochemical process.
A voltaic cell functions by a spontaneous chemical process. Energy or work can be derived from a voltaic cell.
When iron is rusting, a natural voltaic cell is set and the iron is converted to hydrated iron III hydroxide. The set up used for the extraction of sodium metal from brine functions on the basis of electrolysis.
Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride?
CSF + XeF6 → CsXeF7
Answer:
27.9 g
Explanation:
CsF + XeF₆ → CsXeF₇
First we convert 73.1 g of cesium xenon heptafluoride (CsXeF₇) into moles, using its molar mass:
Molar mass of CsXeF₇ = 397.193 g/mol73.1 g CsXeF₇ ÷ 397.193 g/mol = 0.184 mol CsXeF₇As 1 mol of cesium fluoride (CsF) produces 1 mol of CsXeF₇, in order to produce 0.184 moles of CsXeF₇ we would need 0.184 moles of CsF.
Now we convert 0.184 moles of CsF to moles, using the molar mass of CsF:
Molar mass of CsF = 151.9 g/mol0.184 mol * 151.9 g/mol = 27.9 gIf 46.3 grams of acetylene are required to run a carbide lamp for 8 hours, how many moles of water are required
Answer:
1.78 mol
Explanation:
Step 1: Write the balanced equation
CaC₂ + H₂O ⇒ C₂H₂ + CaO
Step 2: Calculate the moles corresponding to 46.3 g of C₂H₂
The molar mass of C₂H₂ is 26.04 g/mol.
46.3 g × 1 mol/26.04 g = 1.78 mol
Step 3: Calculate the moles of H₂O required to form 1.78 moles of C₂H₂.
The molar ratio of H₂O to C₂H₂ is 1:1. The moles of H₂O required are 1/1 × 1.78 mol = 1.78 mol.
The table shows four reactions.
Reactions
Reaction Equation
1 C3H8 + 5O₂ → 3CO₂ + 4H₂O
2 C₂H4 + H₂ → C₂H6
3 AgNO3 + NaCl - AgCl + NaNO3
4 2Fe + O₂ → 2Feo
Which of the above reactions is an example of combustion of an organic substance?
a) 1
b) 2
c) 3
d) 4
Answer:its B
Explanation:
i have done this before! and i got 100 so i hope you got all the other questions right!
The table shows four reactions. The reaction That is an example of combustion of an organic substance is C₂H₄ + H₂ → C₂H₆. The correct option is b) 2.
What are combustion reactions?Combustion reactions are those reactions in which the reactant reacts with oxygen and produces heat and light. An example is the burning of wood, it happens in the presence of oxygen.
Organic compounds are those compounds that are made by carbons. They are made by carbon-carbon or carbon-hydrogen bonds. They are naturally present in nature.
C₂H₄ + H₂ → C₂H₆
The equation above shows the reaction between methane and hydrogen, which is forming ethane in the presence of oxygen.
Thus, the correct option is b) 2. C₂H₄ + H₂ → C₂H₆.
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The partial pressure of carbon dioxide in air varies with the seasons. Would you expect the partial pressure in the Northern Hemisphere to be higher in the summer or winter
Answer:
It will be higher in the summer.
Explanation:
Usually, the winter season is more harsh a weather on leaves than summer because it is wet season and thus has less sunlight and this means there will be less photosynthesis reactions and therefore it means the partial pressure will be lesser here unlike in the summer when it is a more warm and dry weather with sunlight where photosynthesis reactions will be more favorable to occur.
Thus, CO2 which is a great component of photosynthesis is used more in the summer and as such the partial pressure in the summer will be higher.
the sum of two numbers is 54 one exceed the other by 14 find the number
Answer:
x=34
y=20
Explanation:
let the first number be 'x'
let the second number be 'y'
Equation 1:-
x + y = 54
Equation 2:-
x = y + 14 (Since one exceeds the other by 14)
Substituting Equation 2 in Equation 1:-
(y + 14) + y = 54
=> y + 14 + y = 54
=> 2y + 14 = 54
=> 2y = 54 - 14
=> 2y = 40
=> y = 40/2
=> y = 20
Now in Equation 1:-
x + y = 54
Substituting y=20,
x + 20 = 54
x = 54 - 20
x = 34
if slowing down is the response to seeing a blinking yellow light is it conditioned or unconditioned?
Answer:
Conditioned
Explanation:
Naturally, you do not slow down when you see a yellow light. That response is learned, therefore it is a conditioned response.
Ginger wanted to see how long it would take to get to Brownsville from Houston. If it is 570 kilometers (km) to Brownsville, how long would it take her if she could only drive an average speed of 60 km/hour
Answer:
9.5 hours/ 9 hours 30 mins
Explanation:
Distance = speed × time so
Time = Distance ÷ speed
= 570 ÷ 60
= 9.5 hours
an experiment was carried out and H2SO4 was collected resulting in a 92.0% yield. What mass of H2SO4 was collected from the experiment?
Answer:
The mass of H2SO4 collected is 92.0g assuming the theoretical yield of H2SO4 is 100g
Explanation:
Assuming the theoretical yield of the sulfuric acid, H2SO4, is 100g.
To solve this question we must use the equation of percent yield:
Percent yield = Actual yield / Theoretical yield * 100
Where percent yield = 92.0%, actual yield is the mass of H2SO4 produced and theoretical yield is 100g, the mass we are assuming
Replacing:
92.0% = Actual yield / 100g * 100
92.0g = Actual Yield
The mass of H2SO4 collected is 92.0g assuming the theoretical yield of H2SO4 is 100gCan someone help me with this one :")
Answer:
i think is probably A
Explanation:
because at constant temperature, the product of the pressure and volume of a given mass of and ideal gass in a closed system is always constant
Answer:
I believe the answer is A or D
Explanation:
I hope this helps you out!
A student is asked to separate two liquids. Liquid A boils at 100°C
and liquid B boils at 65 °C. The student sets up a fractional distillation
experiment, and after a few minutes a clear liquid is collected from the
condenser. Explain which of the two liquids will be collected first.
Answer:
liquid B
Explanation:
because B has a lower bp it needs less time and energy to turn into vapour and is collected into the condenser first