What are the first two steps in solving the radical equation below?
X+3 - 7 - 15
A. Square both sides and then subtract 3 from both sides.
B. Add 7 to both sides and then square both sides.
C. Add 7 to both sides and then subtract 3 from both sides.
D. Square both sides and then add 7 to both sides.
Answers
Answer:
B
Step-by-step explanation:
add 7 to get away the 7 on the left hand side
square both side to eliminate square root
The first two steps in solving the radical equation are to Add 7 to both sides and then square both sides.
What are radical?A radical is the opposite of the power, therefore, the roots are known as the radical. It is denoted as √, ∛, etc.
In order to solve the given radical, we will go through the following steps,
[tex]\sqrt{x+3}-7=15[/tex]
1. Add 7 both the sides to eliminate -7 from both the sides,
[tex]\sqrt{x+3}-7+7=15+7\\\\\sqrt{x+3}=22[/tex]
2. Square both the sides to remove the square root,
[tex]\sqrt{x+3}=22\\\\(\sqrt{x+3})^2=22^2\\\\x+3 = 484[/tex]
Hence, the first two steps in solving the radical equation are to Add 7 to both sides and then square both sides.
Learn more about Radical:
https://brainly.com/question/1369233
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Step-by-step explanation:
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ta da!
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Step-by-step explanation:
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Step-by-step explanation:
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2
(
3
r
+
4
)
−
3
(
r
+
1
)
=
11
Answers
Hey there!
ASSUMING
2(3r + 4) - 3 (r + 1) = 11
IF SO
2(3r + 4) - 3 (r + 1) = 11
2(3r + 4) - 3 (1r + 1) = 11
DISTRIBUTE
2(3r) + 2(4) - 3(1r) - 1(1) = 11
6r + 8 - 3r - 1 = 11
COMBINE the LIKE TERMS
(6r - 3r) + (8 - 3) = 11
6r - 3r + 8 - 3 = 11
3r + 5 = 11
SUBTRACT 5 to BOTH SIDES
3r + 5 - 5 = 11 - 5
SIMPLIFY!
3r = 11 - 5
3r = 6
DIVIDE 3 to BOTH SIDES
3r/3 = 6/3
SIMPLIFY!
r = 6/3
r = 2
Therefore, the answer should be: r = 2
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
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B)3x²
C)3xy
D)3x²y
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Please help another one
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Answer:
1) [tex]x^{2}\cdot y[/tex] - It is a monomial with two variables: [tex]x[/tex], [tex]y[/tex]
2) [tex]3\cdot x^{3}+x^{3}[/tex] - It is binomial reductible to a monomial due to like terms. Number of variables: [tex]x[/tex]
3) [tex]a^{2}\cdot b^{3}\cdot c^{4}[/tex] - It is a monomial with three variables: [tex]a[/tex], [tex]b[/tex], [tex]c[/tex]
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Step-by-step explanation:
We proceed to explain the context on each case and answer appropriately:
1) [tex]x^{2}\cdot y[/tex] - It is a monomial with two variables: [tex]x[/tex], [tex]y[/tex]
2) [tex]3\cdot x^{3}+x^{3}[/tex] - It is binomial reductible to a monomial due to like terms. Number of variables: [tex]x[/tex]
3) [tex]a^{2}\cdot b^{3}\cdot c^{4}[/tex] - It is a monomial with three variables: [tex]a[/tex], [tex]b[/tex], [tex]c[/tex]
4) [tex]2\cdot x^{2}-3=n[/tex] - It is binomial equivalent to a monomial. Number of variables: [tex]x[/tex], [tex]n[/tex].
5) [tex]x^{2}-y+2\cdot x^{2} = 3[/tex] - It is trinomial reductible to a binomial due to like terms. And equivalent to a constant. Number of variables: [tex]x[/tex], [tex]y[/tex]
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А
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Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
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Step-by-step explanation:
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Answers
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Answers
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Answers
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Step-by-step explanation:
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if ∡M is 90° then you can do:
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h = 25(sin 65°)
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B cone
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Answer:
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Terms:
Constants:
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constants: 24
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