what does terminal velocity mean ? please help

Answers

Answer 1

[tex] \underline{ \bf{\underline{\large{Terminal \: Velocity}}}}[/tex]

The maximum constant velocity acquired by a body while falling through a viscous medium is called it's terminal velocity. It is usually denoted by [tex] \sf V_T [/tex].It is directly proportional to the square of the radius of the body (a²) & the difference of the densities of the body and the fluid [tex] \sf (\rho - \sigma) [/tex].It is inversely proportional to the viscosity of the medium [tex] \sf (\eta) [/tex].Formula of Terminal Velocity:[tex] \boxed{ \bf{V_T = \dfrac{2}{9} \dfrac{ {a}^{2} }{ \eta} ( \rho - \sigma)g}}[/tex]
Answer 2
Terminal velocity means steady speed achieved.

Related Questions

Tyler drives 50km north. Tyler then drives back 30km south. What distance did he cover? What was his displacement?

Answers

Answer:

80 km is distance and 30km north is displacement

Explanation:

distance= 50+30=80km

displacement= 50-20=30

his displacement is 30km north

When Tyler drives 50 km north and then drives back 30 km south, we have:

1. The distance that he covers is 80 km.

2. Tylor's displacement is 20 km.  

1. The distance is a scalar that is given by the sum of the kilometers traveled by Tyler as follows:

[tex] d = d_{1} + d_{2} = 50 km + 30 km = 80 km [/tex]

Hence, the distance traveled by Tyler was 80 km.

2. The displacement is a vector that depends on the direction of travel. Takin the north direction as positive we have:

[tex] x = x_{1} + x_{2} = 50 km + (-30 km) = 20 km [/tex]

Therefore, Tyler's displacement is 20 km.

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The small piston of a hydraulic lift has an area of 15 cm². A car weighing 45,000 N is placed on the 2500 cm² large piston. How much force is required on the small piston to lift the car?​

Answers

Explanation:

I believe the answer is 12 N

What is the moment of inertia of a disc of mass 5kg and radius 10cm?

Answers

Answer:

500

Explanation:

I=1/2MR²
I=1/2(5 kg)(0.1 m)²
I=0.025 kg/m²

How could semantics be defined?
A.
as a set of rules that studies how words are broken down into morphemes
B.
as a set of rules that is concerned with understanding the meaning of words
C.
as a set of rules that dictates how vowels and consonants are pronounced
D.
as a set of rules that determines how words can be arranged into sentences

Answers

Answer:

its b >.<

Explanation:

just trust me laddies

Semantics can be defined : ( B ) As a set of rules that is concerned with understanding the meaning of words

What are semantics ?

Semantics can be defined as the message conveyed by words in a sentence and context where the sentence is placed. It is a set of rules that is concerned with the understanding of words in sentences used in a context.

Hence we can conclude that Semantics can be defined : ( B ) As a set of rules that is concerned with understanding the meaning of words.

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Is static electricity more harmful than it is helpful or vice versa

Answers

Answer:

You might even see a spark if the discharge of electrons is large enough. The good news is that static electricity can't seriously harm you. Your body is composed largely of water and water is an inefficient conductor of electricity, especially in amounts this small. Not that electricity can't hurt or kill you.

Explanation:

You might even see a spark if the discharge of electrons is large enough. The good news is that static electricity can't seriously harm you. Your body is composed largely of water and water is an inefficient conductor of electricity, especially in amounts this small. Not that electricity can't hurt or kill you.

HELP MEEEEEEE
Which choice is the smallest in mass? neutron nucleus proton electron

Answers

The answer is electron

Answer:

electron

Explanation:

Plyometrics can help a person maintain cardiorespiratory fitness. Please select the best answer from the choices provided. T F

Answers

Answer: IT IS TRUE

Explanation:

Hope this helps

Plyometrics can help a person maintain cardiorespiratory fitness T

It is TRUE that plyometrics can help a person maintain cardiorespiratory fitness

Plyometrics

Plyometrics is a type of exercise training that works with the principle of using speed and force of different movements to build muscle power.

Plyometrics include different types of exercises such as pushups, throwing, running, jumping, and kicking.

Learn more about plypmetrics:

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How many kilograms in 17,000 mg?

Answers

The answer to your question is 0.017

How much time will it take for a truck to travel 20 meters if it is traveling at 4 m/s?

Answers

Answer:

The answer is 5 s

Explanation:

The time taken can be found by using the formula

[tex]t = \frac{d}{v} \\ [/tex]

d is the distance

v is the velocity

From the question we have

[tex]t = \frac{20}{4} \\ [/tex]

We have the final answer as

5 s

Hope this helps you

the answer to this question is 5s

n
Which of the following has a crystalline appearance?
baking soda
salt
baking powder
corn starch

Answers

Salt has a crystalline appearance.

Answer:

B: Salt

Explanation:

I answered this correct beforehand.

what force is the total force felt by an object?

Answers

Answer:

net force

Explanation:

Net force felt by an object.

It is a push or pull and a force

Andy has been consuming a set number of calories and recently added an additional 100 calories in the form of a daily snack. Although he is not trying to lose weight, he has lost one pound per week over the last two months. He wants to increase his level of activity and exercise, and he wants to return to his weight from two months ago. Which strategy should he follow to prevent becoming underweight?

Increase his activity and exercise levels and add more calories to gradually gain weight
Increase his activity and exercise levels and eat the same number of calories to gradually gain weight
Increase his snacks to two or three per day until he reaches his target weight
Increase his calories consumed and do less activity and exercise until he reaches his target weight

Answers

Answer:

Increase his activity and exercise levels and add more calories to gradually gain weight

Explanation:

What do all elements in a column in the periodic table have in common? (2 points)

Answers

Answer:

Each column is called a group. The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements.

Explanation:

In lab you submerge 100 g of iron nails at 40 0C in 100 g of water at 20 0 C. Specific heat of iron is 0.12 cal/g∙0C. Equate the heat gained by water to the heat lost by nails and show that the final temperature of water becomes 22.1 0C.

Answers

Let T be the final temperature of water and nails (iron).

Given that the initial temperature of 100 g nails, [tex]T_{1F}=40^{\circ}C[/tex].

Specific heat of the iron, [tex]C_F=0.12 cal/g^{\circ}C[/tex].

So, the heat lost by nails [tex]= mC_F(T_{1F}-T}[/tex]

[tex]=100\times 0.12 \times (40-T)\cdots(i)[/tex]

The initial temperature of 100 g water, [tex]T_{1w}=20^{\circ}C.[/tex]

Specific heat of water, [tex]C_w=1 cal/g^{\circ}C[/tex]

So, the heat gained by water [tex]= mC_w(T-T_{1w}}[/tex]

[tex]=100\times 1 \times (T-20)\cdots(ii)[/tex]

As the exergy is conserved, so

the heat lost by the nails = the heat gained by the water

From equation (i) and (ii), we have

[tex]100\times 0.12 \times (40-T)=100(T-20)[/tex]

[tex]\Rightarrow 0.12(40-T)=T-20[/tex]

[tex]\Rightarrow 0.12\times 40 -120T=T-20[/tex]

[tex]\Rightarrow 0.12T+T=4.8+20[/tex]

[tex]\Rightarrow 1.12T=24.8[/tex]

[tex]\Rightarrow T=24.8/1.12= 22.1^{\circ}C[/tex]

Hence, the final temperature of both, iron nails as well as water, become [tex]22.1^{\circ}C[/tex].

How can the potential energy in magnets be used to create kinetic energy in an object without making contact?

Answers

Answer:  If you move a magnet quickly through a coil of copper wire, the electrons will move - this produces electricity.

Explanation:

Katie is making a strawberry milkshake in her blender. A 0.05kg strawberry is rapidly spun around the inside of the container with a speed of 11.0 m/s, held by a centripetal force of 12.0 N. What is the radius of the blender at the strawberry’s location? Round answers to two decimal places.

Answers

Answer:

The radius of the blender is approximately 0.5041[tex]\bar 6[/tex] meters

Explanation:

The given parameters are;

The mass of the strawberry, m = 0.05 kg

The speed with which the strawberry is spun, v = 11.0 m/s

The centripetal force holding the strawberry = 12.0 N

The formula for the centripetal force, [tex]F_c[/tex], is given as follows;

[tex]F_c = \dfrac{m \cdot v^2}{r}[/tex]

Where;

r = The radius of the centripetal rotation, which is the radius of the blender

[tex]\therefore r = \dfrac{m \cdot v^2}{F_c}[/tex]

Substituting the values gives;

[tex]\therefore r = \dfrac{0.05 \times 11^2}{12} = \dfrac{121}{240} \approx 0.5041 \bar 6[/tex]

The radius of the blender, r ≈ 0.5041[tex]\bar 6[/tex] meters.

What is mean by speed?​

Answers

Answer:

Speed is acceleration or a high rate of motion

Answer:

the rate at which something or someone moves or operates or is able to move or operate .

A projectile was fired from ground with 50 m/s initial velocity at 45 degree angle. How long will stay in the air? What is range? What is the maximum height the projectile?

Answers

Answer:

1. Time of flight = 7.22 s

2. Range = 255.10 m

3. Maximum height = 63.77 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 50 m/s

Angle of projection (θ) = 45°

Time of flight (T) =?

Range (R) =?

Maximum height (H) =?

1. Determination of the time of flight

Initial velocity (u) = 50 m/s

Angle of projection (θ) = 45°

Acceleration due to gravity (g) = 9.8 m/s²

Time of flight (T) =?

T = 2uSine θ /g

T = 2 × 50 Sine 45 / 9.8

T = 100 × 0.7071 /9.8

T = 7.22 s

2. Determination of the range.

Initial velocity (u) = 50 m/s

Angle of projection (θ) = 45°

Acceleration due to gravity (g) = 9.8 m/s²

Range (R) =?

R = u²Sine 2θ /g

R = 50² × Sine (2×45) /9.8

R = 2500 × Sine 90 /9.8

R = 2500 × 1 / 9.8

R = 255.10 m

3. Determination of the maximum height.

Initial velocity (u) = 50 m/s

Angle of projection (θ) = 45°

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (H) =

H = u²Sine²θ /2g

H = 50² × (Sine 45)² / 2 × 9.8

H = 2500 × (0.7071)² / 19.6

H = 63.77 m

Answer:

Time spent in the air is 7.22 sThe range of the projectile is 255.1 mThe maximum height of the projectile is 63.77 m

Explanation:

Given;

initial velocity of projection, u = 50 m/s

angle of projection, θ = 45°

Time spent in the air is the time of flight, given as;

[tex]T = \frac{2usin \theta}{g}\\\\T = \frac{2(50)sin (45)}{9.8}\\\\T = 7.22 \ s[/tex]

The range of the projectile is given by;

[tex]R = \frac{u^2sin(2\theta)}{g}\\\\R = \frac{u^2sin(2*45)}{g}\\\\ R = \frac{u^2sin(90)}{g}\\\\ R = \frac{u^2(1)}{g}\\\\R=R_{max} = \frac{u^2}{g} =\frac{50^2}{9.8} = 255.1 \ m[/tex]

The maximum height of the projectile is given by;

[tex]H = \frac{u^2sin^2\theta}{2g}\\\\H = \frac{(50)^2sin^2(45)}{2*9.8}\\\\H = 63.77 \ m[/tex]

A car's horn produces a constant frequency of 350 Hz as it passes by Suzy. What is the best estimate of the
frequency Suzy hears after the car passes her?
330 Hz
350 Hz
360 Hz
700 Hz

Answers

Answer:

330 Hz

Explanation:

edg2020

The best estimate of the frequency Suzy hears after the car passes her is govern by doppler effect and it is 330 Hz.

What is frequency?

Frequency is the number of occurrences of a repeating event per unit of time.

What is Doppler EFFECT?

The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source.

According to the Doppler Effect, the frequency observed by an observer decreases for source going away.

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A 6.00 kg box is pulled to the left across a frictionless surface by a force of 20.0 N directed at 45o above the horizontal. The box does not move vertically. 20.0 N 45.0o 6.00 kg a) Resolve the 20.0 N vector into its horizontal and vertical components, using the trigonometric functions. b) Determine the magnitude of the normal force (will it be equal to the weight?). c) Determine the magnitude and direction of the acceleration.

Answers

I’m bored wanna talk

Circle the letter of each factor that determines whether a molecule
is polar or nonpolar.

a. the number of atoms in the molecule
b. the type of atoms in the molecule
c. the number of bonds in the molecule
d. the shape of the molecule

Answers

I believe the answer is C
Hope this helps you

Radio stations broadcast signals on two different frequency bands. These are called

Answers

Answer:

AM(amplitude modulation) and FM(frequency modulation)

Explanation:

A radio frequency band is a small adjacent section of the radio spectrum frequencies, whereby channels are usually used or set aside to be used.

They are usually of two different bands called AM which is known as amplitude modulation and FM which is known as frequency modulation

A giant treasure chest is sitting in the sand, when two rival groups of pirates (the sharks and the squids) come upon it at the same time from opposite directions. Both groups run forward and each pirate grabs a side. On the shark’s side, they have one pirate pulling with 20N, one with 30N, one with 50N, and one with 10N. On the squid’s side, they have one pirate pulling with 10N, one with 25N, one with 30N, and one with 40N.

Which team is able to pull harder?

What is the net force experienced by the chest?

If the chest weighs 100 kg, how fast is it accelerating?

Answers

Answer: if you search this up there is a video saying the answer

Explanation:

1. A ball rolls off of a table with a speed of 3.2 m/s. The table is 1.6 m high.
a) When does the ball hit the ground? (time)
b) How far away from the base of the table does the ball travel?
c) With what vertical speed does the ball hit the floor?

Answers

Answer:

Explanation:

for vertical displacement h = 1.6 , let time taken be t , initial vertical velocity = 0

h = ut + 1/2 g t²

= 1/2 g t²

1.6 = .5 x 9.8 x t²

t² = .3265

t = .57 s

b )

velocity in horizontal direction = 3.2 m /s

horizontal displacement

= 3.2 x .57 = 1.82 m

c )

for vertical movement

v = u + gt

= 0 + 9.8 x .57

= 5.58 m /s

Is it okay to keep an albino gecko

Answers

Answer:

Yes

Explanation:

How many times more gravitational potential energy would the same lander have on top of a 350-m hill on Earth? It would have times more gravitational potential energy

Answers

Answer:

6

Explanation:

Just did it.

The gravitational potential energy would the same lander have on top of a 350-m hill on Earth is 6.

What is gravitational potential energy?

If an object is lifted, work is done against gravitational force. The object gains energy.

The equation for calculating gravitational potential energy is

GPE =mgh

where, GPE is the gravitational potential energy, m is the mass, h is the change in height and g is the acceleration due to gravity.

The heavier the particle and the higher it is over the ground, the more gravitational potential energy it holds. Gravitational potential energy increments as weight and level increments.

Given is the height of hill h = 350m.

Thus, the same lander will have the the potential energy 6 times more.

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If it takes a planet 2.8 × 108 s to orbit a star with a mass of 6.2 × 1030 kg, what is the average distance between the planet and the star?

Answers

Answer:

9.36*10^11 m

Explanation

Orbital velocity  v=√{(G*M)/R},

G = gravitational constant =6.67*10^-11 m³ kg⁻¹ s⁻²,

M = mass of the star

R =distance from the planet to the star.

v=ωR, with ω as the angular velocity and R the radius

ωR=√{(G*M)/R},

ω=2π/T,

T = orbital period of the planet

To get R we write the formula by making R the subject of the equation

(2π/T)*R=√{(G*M)/R}

{(2π/T)*R}²=[√{(G*M)/R}]²,

(4π²/T²)*R²=(G*M)/R,

(4π²/T²)*R³=G*M,

R³=(G*M*T²)/4π²,

R=∛{(G*M*T²)/4π²},

Substitute values

R=9.36*10^11 m

Which statements correctly describe the properties of air? Select three options. Air has mass but no weight. Air pressure is created by the weight of the atmosphere pushing on Earth’s surface. Pressure is a measure of how tightly molecules are packed. Denser air is heavier than less dense air. Air is less dense at higher altitudes.

Answers

Answer:

Air pressure is created by the weight of the atmosphere pushing on Earth’s surface.

Denser air is heavier than less dense air.

Air is less dense at higher altitudes.

Explanation:

Based on the properties of air, the correct options from the given statements are:

Denser air is heavier than less dense airAir is less dense at higher altitudes.Air pressure is created by the weight of the atmosphere pushing on Earth’s surface

What is air?

Air is a mixture of gases in the atmosphere which consists of nitrigen, oxygen, carbon dioxide and noble gas as well as other trace partickes like water vapor.

Some properties of air include:

air is a mixture of gases Air has mass and weight.Air pressure is created by the weight of the atmosphere pushing on Earth’s surfaceDenser air is heavier than less dense airAir is less dense at higher altitudes.

Therefore, the correct options from the given statements are:

Denser air is heavier than less dense airAir is less dense at higher altitudes.Air pressure is created by the weight of the atmosphere pushing on Earth’s surface

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A box hangs by a rope from the ceiling. The box weighs 25 N. If the rope breaks find the acceleration of the box.

Answers

Answer:

9.81m/s^2

Explanation:

Given

Weight of box= 25N

When the rope breaks the box will obey the Newton first law, and Accelerates due to free fall, hence the acceleration will be g=9.81m/s^2

so W=F = mg

where.

F=W =is the force pulling objects toward the Earth.

m=  the mass of the object.

g= is the acceleration due to gravity; this number is a constant for all masses of matter.

What is the mass of a man who accelerates 4 m/s2 under the action of a 300 N net force?

Answers

Answer:

F = m*a

therefore m = F / a

m = 100 / 5 = 20 kg?

hope this helped you

Explanation:

The required mass of man, undergoing the acceleration is of 75 kg.

Given data:

The magnitude of acceleration of man is, a = 4 m/s².

The magnitude of action force on the man is, F = 300 N.

Here we can apply the Newton's second law of motion, which says that the applied force causes the acceleration of any object. Where the applied force is equal to the mass of object and the magnitude of acceleration of object.

Therefore,

F = ma

Solving as,

300 = m × 4

m = 300/4

m = 75 kg

Thus, we can conclude that the mass of man, undergoing the acceleration is of 75 kg.

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