what equation do I use to find the apothem?

Answer:

ok so we know that it order 85 shirts for each of its 22 stores so we can multiply 22 by 85 which is 1870. so the company order 1870 shirts and they pay 20$ for each so we can multiply 1870 by 20 which is 37400. so top shoppe pays 37400 for the shirts.

A=37400

B=I don't know what the order was so i dont know

C= also there is nothing about the size of the shirts

D=1870

so the most important variable is probity A but there could be an argument made about the importance of D.

Your Welcome

BIFFY OUT!!!

Answer:

gotta be  answer A

Step-by-step explanation:

you can search up f(x) = square root of x

Answer:

[tex]\int\limits {\int\limits_R {7(x + y)e^{x^2 - y^2}} \, dA = \frac{1}{2}e^{42} -\frac{43}{2}[/tex]

Step-by-step explanation:

Given

[tex]x - y = 0[/tex]

[tex]x - y = 7[/tex]

[tex]x + y = 0[/tex]

[tex]x + y = 6[/tex]

Required

Evaluate [tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA[/tex]

Let:

[tex]u=x+y[/tex]

[tex]v =x - y[/tex]

Add both equations

[tex]2x = u + v[/tex]

[tex]x = \frac{u+v}{2}[/tex]

Subtract both equations

[tex]2y = u-v[/tex]

[tex]y = \frac{u-v}{2}[/tex]

So:

[tex]x = \frac{u+v}{2}[/tex]

[tex]y = \frac{u-v}{2}[/tex]

R is defined by the following boundaries:

[tex]0 \le u \le 6[/tex]  ,  [tex]0 \le v \le 7[/tex]

[tex]u=x+y[/tex]

[tex]\frac{du}{dx} = 1[/tex]

[tex]\frac{du}{dy} = 1[/tex]

[tex]v =x - y[/tex]

[tex]\frac{dv}{dx} = 1[/tex]

[tex]\frac{dv}{dy} = -1[/tex]

So, we can not set up Jacobian

[tex]j(x,y) =\left[\begin{array}{cc}{\frac{du}{dx}}&{\frac{du}{dy}}\\{\frac{dv}{dx}}&{\frac{dv}{dy}}\end{array}\right][/tex]

This gives:

[tex]j(x,y) =\left[\begin{array}{cc}{1&1\\1&-1\end{array}\right][/tex]

Calculate the determinant

[tex]det\ j = 1 * -1 - 1 * -1[/tex]

[tex]det\ j = -1-1[/tex]

[tex]det\ j = -2[/tex]

Now the integral can be evaluated:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA[/tex] becomes:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{x^2 - y^2}} \, *\frac{1}{|det\ j|} * dv\ du[/tex]

[tex]x^2 - y^2 = (x + y)(x-y)[/tex]

[tex]x^2 - y^2 = uv[/tex]

So:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *\frac{1}{|det\ j|}\, dv\ du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *|\frac{1}{-2}|\, dv\ du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *\frac{1}{2}\, dv\ du[/tex]

Remove constants

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 {\int\limits^7_0 {ue^{uv}} \, dv\ du[/tex]

Integrate v

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 \frac{1}{u} * {ue^{uv}} |\limits^7_0 du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 e^{uv} |\limits^7_0 du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{u*7} - e^{u*0}]du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{7u} - 1]du[/tex]

Integrate u

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7u} - u]|\limits^6_0[/tex]

Expand

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -(\frac{1}{7}e^{7*0} - 0)][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -\frac{1}{7}][/tex]

Open bracket

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} - 6 -\frac{1}{7}][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} -\frac{43}{7}][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{42} -\frac{43}{7}][/tex]

Expand

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{1}{2}e^{42} -\frac{43}{2}[/tex]

Answer:

2 1/6 or 13/6

Step-by-step explanation:

Equation: [tex]\frac{1}{3}[/tex] × 6[tex]\frac{1}{2}[/tex]

Distribute: (1/3) ( 6 + 1/2)

(1/3)(6) + (1/3)(1/2)

2 + 1/6

2 1/6 or 13/6

Answer:

23

Step-by-step explanation:

The absolute value of any number is just the positive version of that number. For example the absolute value of -12 is 12.

Hope this helps! :)

The type of correlation not associated with scatterplots is an indefinite correlation

Correlation or dependence is any statistical relationship, whether causal or not, between two random variables or bivariate data.

Correlation can only be between -1 and 1 but not outside these values.

Hence the type of correlation not associated with scatterplots is an indefinite correlation

Learn more on correlation here: https://brainly.com/question/26172866

Answer:

A = -7.5   B = -17.5

Step-by-step explanation:

A + B = -25

A = B + 10

Plug the second equation into the first equation:

B + 10 + B = -25

2B = -35

B = -17.5

Plug that value into the first equation:

A - 17.5 = -25

A = -7.5

Answer:

24

Step-by-step explanation:

4/5 of 30 = 4/5×30 = 24

___

Answer:

4/5 of 30 = 24

Step-by-step explanation:

4/5 x 30

4/1 x 6 = 24

Answer:

The probability to get the vowel is 1/4.

Step-by-step explanation:

The number of elements in sample space, n(S) = 20

The number of elements in event, n (E) = 5

The probability to get the vowel is

[tex]P(E) =\frac{n(E)}{n(S)}\\\\P(E)=\frac{5}{20}\\\\P(E) = \frac{1}{4}[/tex]

Answer:

43 hours

Step-by-step explanation:

[tex]\frac{y}{1} :\frac{408}{9.5}[/tex]

y × 9.5 = 408 × 1

9.5y = 408

9.5y ÷ 9.5 = 408 ÷ 9.5

[tex]y=42\frac{18}{19}[/tex]

43 hours

Answer:

£72000

Step-by-step explanation:

According to the Question,

Thus, 5 ⇒ 9000 People

So, 4 ⇒ 7200 People(Men)

      1 ⇒ 1800 People(Women)

Thus, The amount of money made from tickets sold to men is 7200 total Men x £10 Per Ticket Cost ⇒ £72000.

Answer:

I think 2 points

Step-by-step explanation:

I may be wrong bc I suck at algebra. literally who is gonna use algebra ever?

Answer: two points hope it helps

Given:

In a right angle triangle, the measures of two legs are 5 ft and 5.6 ft. The measure of the hypotenuse is x.

To find:

The value of x.

Solution:

Pythagoras theorem: In a right angle triangle,

[tex](Hypotenuse)^2=(Base)^2+(Perpendicular)^2[/tex]

Using Pythagoras theorem, we get

[tex](x)^2=(5)^2+(5.6)^2[/tex]

[tex]x^2=25+31.36[/tex]

[tex]x^2=56.36[/tex]

Taking square root on both sides, we get

[tex]x=\sqrt{56.36}[/tex]

[tex]x=7.50733[/tex]

[tex]x\approx 7.5[/tex]

The measure of missing side is 7.5 ft. Therefore, the correct option is D.

Answer: (I am not a maths moderator)

x=4

Step-by-step explanation:

Multiply the exponents

(2x-4)^12=(4^2)^6 (exponents multiply so)

(2x-4)^12=4^12

4^12 = 16777216

(2x-4)^12= 16777216

Take the 1/12 exponent for both sides

that will remove the ^12 exponent from the left side and will take the 12th root for the right.

2x-4=4

add 4 to both sides

2x=8

divide both sides by 2

x=4

Step-by-step explanation:

6/20

3/10 (simplified)

do you want the percentage?

Answer:

[tex]\frac{3}{10}[/tex]

Step-by-step explanation:

The multiplies of 3 from 1-20 are:

3, 6, 9, 12, 15, 18

Since there are [tex]20-1+1=20[/tex] numbers from 1-20 inclusive, the probability that a ball is a multiple of 3 is [tex]\frac{6}{20}=\boxed{\frac{3}{10}}[/tex]

Step-by-step explanation:

First, given that we must use point slope form, we can define that as

y - y₁ = m (x-x₁), with m being the slope .

To find the slope, we can use the equation

[tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex]. Two points on the graph are (0, 1) and (1, 3). For these points, when calculating the slope, 0 and 1 represent x₁ and y₁ respectively, while 1 and 3 represent x₂ and y₂ respectively Using this formula, we can plug our points in to get

[tex]\frac{3-1}{1-0} = 2/1 = 2[/tex]

as our slope. Therefore, our equation is

y - y₁ = 2 (x-x₁).

For our first point, (0,1), we can simply plug 0 in for x₁ and 1 in for y₁ to get

y - 1 = 2(x-0) as one equation

Next, for (1,3) we can plug 1 for x₁ and 3 for y₁ to get

y - 3 = 2 (x-1) as our other equation

Answer:

The sum of money deposited is approximately $22,021.74

Step-by-step explanation:

The given interest and amounts of the deposit are outlined as follows;

The simple interest per annum, R = 0.325%

The number of years the money is deposited, T = 4 years

The total amount received (Interest + Initial deposit), A = $50,650

We have;

I = P × R × T

Where;

P = The principal (initial amount deposited)

R = The (annual) interest rate = 0.325%

T = The time = 4 years

Therefore;

The total amount received, A = P + I

P + I = P + P × R × T = P × (1 + R × T)

∴ A = P + I = P × (1 + R × T)

P = A/(1 + R × T)

Plugging in the values, gives;

P = 50,650/(1 + 0.325 × 4) = 506,500/23 ≈ 22,021.74

The sum of money deposited, P = $22,021.74

Answer:

25

Step-by-step explanation:

Moving it down does not change the length.

Answer:

8r6s3 – 13r5s4 + r4s5 – 5r3s6 it is D

Step-by-step explanation:

The value of the difference of the polynomials is,

⇒ 8r⁶s³ - 13r⁵s⁴ + r⁴s⁵ - 5r³s⁶

Subtraction in mathematics means that is taking something away from a group or number of objects. When you subtract, what is left in the group becomes less.

Given that;

The expression is,

⇒ (8r⁶s³ – 9r⁵s⁴ + 3r⁴s⁵) – (2r⁴s⁵ – 5r³s⁶ – 4r⁵s⁴)

Now, We can find the difference as;

⇒ (8r⁶s³ – 9r⁵s⁴ + 3r⁴s⁵) – (2r⁴s⁵ – 5r³s⁶ – 4r⁵s⁴)

⇒ (8r⁶s³ – 9r⁵s⁴ – 4r⁵s⁴ + 3r⁴s⁵ – 2r⁴s⁵ – 5r³s⁶

⇒ 8r⁶s³ - 13r⁵s⁴ + r⁴s⁵ - 5r³s⁶

Thus, The value of the difference of the polynomials is,

⇒ 8r⁶s³ - 13r⁵s⁴ + r⁴s⁵ - 5r³s⁶

Learn more about the subtraction visit:

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Answer:

The area of a playground is 20 square yards. The length of the playground is 5 times longer than its width. Find the length and width of the playground.

length = 1 yd, width = 20 yd

length = 2 yd, width = 10 yd

length = 10 yd, width = 2 yd

length = 20 yd, width = 1 y

Answer:

Total cost of 6 bags of popcorn and 3 drinks: [tex]\$39.75[/tex]

Total cost of [tex]p[/tex] bags of popcorn and [tex]d[/tex] drinks: [tex]4.75p+3.75d[/tex]

Step-by-step explanation:

Information given:

Therefore, the total cost of 6 bags of popcorn and 3 drinks must be [tex]6\cdot 4.75+3\cdot 3.75=\boxed{\$39.75}[/tex]

The cost of [tex]p[/tex] bags of popcorn and [tex]d[/tex] drinks is then [tex]\boxed{4.75p+3.75d}[/tex]

We know that :

⊕  Sum of the interior angles in a Pentagon should be equal to 540°

⇒  x° + (2x)° + (2x)° + 90° + 90° = 540°

⇒  (5x)° = 540° - 180°

⇒  (5x)° = 360°

[tex]\sf{\implies x^{\circ} = \dfrac{360^{\circ}}{5}}[/tex]

⇒ x° = 72°

Answer:

B. Evidence

Step-by-step explanation:

Reference: like when your drawing something and you want to make sure that you draw the hair the same way some other person did.

Cite: That’s when you give the credits to someone or something 90% sure

Hope this helps :)

Answer:

5v is an equivalent expression for 6v + -1 ?

Answer:

5v is equivalent expression for 6v + -1

Answer:

SA= 882cm^2

Step-by-step explanation:

SA=2( width*length + hight*length + hight*width )

SA=2( 9*20+ 9*20+ 9*9)

SA= 2*441

SA=882cm^2

Answer:

[tex]let \: total \: distance \: be \: x \\ 30\% \: of \: x = 9 \\ \frac{30}{100} \times x = 9 \\ 30x = 900 \\ x = 30 \\ total \: distance = 30 \: miles[/tex]

The total distance Mira plan to run is 30 miles.

Percentage is a way of expressing a number as a fraction of 100. It is often denoted using the symbol ‘%’. For example, 25% is the same as 25/100 or 0.25. Percentages are used to express how large or small one quantity is relative to another quantity.

Given that, Mira has run 9 miles.

Let the total distance be x miles.

Distance is 30% of the total distance she plans to run

Here, 30% of x =9

30/100 ×x=9

30x=900

x=900/30

x=30

Therefore, the total distance Mira plan to run is 30 miles.

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