what foxes need to eat to
stay alive​

Answer:

Both are electromagnetic waves

Explanation:

Hope this helped!!

Answer:  H

the lights travel through the mirr to create a bigger wider light.

hope this helps (:

Answer:

The power generated by the woman is 259 W

Explanation:

Given;

mass of the woman, m = 45.7 kg

initial velocity of the woman, u = 0

total height ascended by the woman, h = 2.54 m

time of the woman's motion, t = 5.0 s

final velocity of the woman, v = 2.63 m/s

acceleration due to gravity, g =  9.8 m/s²

The potential energy of the woman due to the height she ascended;

P.E = mgh

P.E = 45.7 x 9.8 x 2.54

P.E = 1137.564 J

The kinetic energy of the woman due to her final velocity;

K.E = ¹/₂mv²

K.E = ¹/₂ x 45.7 x (2.63)²

K.E = 158.051 J

The total mechanical energy of the woman at the top of the stairs;

M.E = P.E + K.E

M.E = 1137.564 J  +  158.051 J

M.E = 1295.615 J

The power generated by the woman;

Power = Energy/time

Power = 1295.615 J / 5 s

Power = 259.123 W

Power = 259 W

Answer:

7

Explanation:

The light travels a total of 4 cm to the screen, of that, 3 cm is in air and 1 cm is in the glass plate.

The total number of wavelengths of light between the source and screen is just the number of wavelengths in air plus the number in the glass.

To determine the number of wavelengths in air, divide the thickness of air (3 cm) by the wavelength of the light (6000 Angstroms), converting units as needed.

The refractive index of the glass is 1.5. That means that the velocity of propagation of the light in the glass is 2/3 of what it is in air, and so the wavelength of the light in glass is 2/3 of what it is in air. So, divide the thickness of glass (1 cm) by the wavelength of the light in glass (6000 * 2/3).

Add the two values for the final answer

Answer:

The other 30% is lost from friction.

Explanation:

       friction 30% ---> |O| <------ 70% work

A machine has an efficiency of 70%, and the remaining 30% of the input work is lost as waste energy or dissipated in the form of heat, noise, or vibration, which cannot be harnessed to do any useful work.

In any machine, the total work input is equal to the total work output plus any work that is lost or dissipated due to various factors such as friction, heat transfer, etc., so, for example, if a machine receives 100 units of energy as input, only 70 units of energy are converted into useful output work, and the remaining 30 units of energy are lost as waste energy.

Hence, the remaining 30% of the input work is lost as waste energy or dissipated in the form of heat, noise, or vibration, which cannot be harnessed to do any useful work.

Learn more about the work by machine here.

https://brainly.com/question/15365822

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Answer:

speed=distance/time

Explanation:

its distance over time like division

Answer:

a.  0.00189 kg

b. 18.552 mN

c. 1.363 kN

d. Since the molecular density is high, the force exerted by the sample is thus high.

Explanation:

(a) Find the mass of the gas. kg

Using PV = mRT/M where P = pressure on gas = atmospheric pressure = 1.013 × 10⁵ Pa, V = volume of gas = L³ where L = length of cube = 11.6 cm = 0.116 cm,m = mas of gas, R = molar gas constant = 8.314 J/mol-K, T = temperature of gas = 291 K and M = molar mass of gas = 28.9 g/mol

So, m = PVM/RT = PL³M/RT

Substituting the values of the variables into the equation, we have

m = PL³M/RT

= 1.013 × 10⁵ Pa × (0.116)³ × 28.9 g/mol/ 8.314 J/mol-K × 291 K

= 0.0457 × 10⁵ Pa g/mol/2419.374J/mol

= 1.89 × 10⁻⁵ × 10⁵ g

= 1.89 g

= 1.89 × 10⁻³kg

= 0.00189 kg

(b) Find the gravitational force exerted on it. mN

The gravitational force, F exerted on it is its weight W

So, F = W = mg where m = mass of gas = 1.89 × 10⁻³ kg and g = acceleration due to gravity = 9.8 m/s²

F = mg

= 1.89 × 10⁻³ kg × 9.8 m/s²

= 18.522 × 10⁻³ kgm/s²

= 18.552 × 10⁻³ N

= 18.552 mN

(c) Find the force it exerts on each face of the cube. kN

Since pressure, P = F/A where F = force exerted on each face and A = area of each face = L² where L = length of side of cube = 11.6 cm = 0.116 m

So, F = PA since P = atmospheric pressure = 1.013 × 10⁵ Pa,

F = PL²

= 1.013 × 10⁵ Pa (0.116 m)²

= 0.01363 × 10⁵ N

= 1.363 × 10³ N

= 1.363 kN

(d) Why does such a small sample exert such a great force

To answer this question, we need to find the density of the gas in the cube.

So density of gas,ρ = m/V where m = mass of gas = 1.89 g and V = volume of gas = L³ and L = length of side of cube = 11.6 cm

ρ = m/V = m/L³ = 1.89 g/(11.6 cm)³ = 1.89 g/1560.896 cm³ = 0.00121 g/cm³

We now find the number of moles of gas in a cm³ by dividing its density by its molar mass.

So n = ρ/M = 0.00121 g/cm³ ÷ 28.9 g/mol = 23687.67 mol/cm³

Since there are 6.022 × 10²³/mol, we find the number of molecules in a cm³ which is n × 6.022 × 10²³/mol = 23687.67 mol/cm³ × 6.022 × 10²³/mol

= 143731.1 × 10²³ molecules/cm³

= 1.437311 × 10²⁸ molecules/cm³

≅ 1.44 × 10²⁸ molecules/cm³

Since the molecular density is high, the force exerted by the sample is thus high.

Answer:

0.5

Explanation:

In this picture,

Answer: A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to fuse together

Explanation:

Answer:

[tex]\underline{\textsf{\textbf{Answer -}}}[/tex]

No & Yes - the case depends actually.

You can't make the velocity zero and expect to stay in space. you will need to constantly fire the engine to hold youself in position (this is possible, until you run out of fuel).

Yes, it is possible to fire the engine and lift off earth into space, and then fire in the opposite direction to earths movement until you are still, relative to the sun. But if you now turn the engine off, the suns gravity will pull you down and directly into the sun.

its the earths forward motion that prevents it falling into the sun

Answer:

No & Yes - the case depends actually.

You can't make the velocity zero and expect to stay in space. you will need to constantly fire the engine to hold youself in position (this is possible, until you run out of fuel).

Yes, it is possible to fire the engine and lift off earth into space, and then fire in the opposite direction to earths movement until you are still, relative to the sun. But if you now turn the engine off, the suns gravity will pull you down and directly into the sun.

its the earths forward motion that prevents it falling into the sun

Answer:

13.1

Explanation:

thats what i put in for acellus and its right

Answer:

B. The same on the moon.

Explanation:

The density of an object is the ratio of the mass contained by the object to the volume occupied by that mass.

[tex]Density = \frac{Mass}{Volume}[/tex]

When the object is taken from the earth to anywhere in the universe, its mass remains constant. The dimensions of the object and hence its volume also remains constant anywhere in the universe.

Therefore, the density of the object will also remain the same as it depends upon the mass and the volume of the object.

So, the correct option is:

B. The same on the moon.

Answer:

roasting,

broiling,

pan-broiling,

pan-frying,

grilling.

Explanation:

good luck

Answer:

Explanation:

1. Stir frying

2. Pan frying

3. Grilling /BBQ

4. Baking/roasting

Answer:

so you have a question

Explanation:

either way,you have a nice day

Answer:

[tex]\boxed {\boxed {\sf 100,000 \ Joules}}[/tex]

Explanation:

Kinetic energy is energy due to motion. The formula is half the product of mass and velocity squared.

[tex]E_k= \frac{1}{2} mv^2[/tex]

The mass of the roller coaster car is 2000 kilograms and the car is moving 10 meters per second.

Substitute these values into the formula.

[tex]E_k= \frac{1}{2} (2000 \ kg ) \times (10 \ m/s)^2[/tex]

Solve the exponent.

[tex]E_k= \frac{1}{2} (2000 \ kg ) \times (100 \ m^2/s^2)[/tex]

Multiply the first two numbers together.

[tex]E_k= 1000 \ kg \times (100 \ m^2/s^2)[/tex]

Multiply again.

[tex]E_k= 100,000 \ kg*m^2/s^2[/tex]

[tex]E_k= 100,000 \ J[/tex]

The roller coaster car has 100,000 Joules of kinetic energy.

Answer:

11.34 i think

Explanation:

Answer:

6.15 s

Explanation:

From the question,

Applying the law of conservation of momentum

Momentum of the Heavier skater = Momentum of the lighter skater.

Mv = mV................. Equation 1

Where M = mass of the heavier skater, m = mass of the lighter skater, v = Velocity of heavier skater, V = velocity of the lighter skater.

But,

v = r/t........................ Equation 2

V = r/t'................ Equation 3

Where r = radius of the circular rink, t = time taken for the heavier skater to reach the edge, t' = time taken for the lighter skater to reach the edge.

Substitute equation 2 and equation 3 into equation 1

M(r/t) = m(r/t')............. Equation 4

Given: M = 65 kg, m = 40 kg, r = 50/2 = 25 m, t = 10 s.

Substitute into equation 4 and solve for t'

65(25/10) = 40(25/t')

162.5 = 1000/t'

t' = 1000/162.5

t' = 6.15 seconds

Answer:

Explanation:

My name is Jeff

Answer:

[tex]1.302\ \text{kg/s}[/tex]

Explanation:

[tex]\rho[/tex] = Density of water = [tex]1\ \text{kg/L}[/tex]

[tex]dV[/tex] = Change in volume = [tex]220\times 0.355\ \text{L}[/tex]

[tex]dt[/tex] = Time elapsed = 1 minute = 60 seconds

Mass flow rate is given by

[tex]\dot{m}=\rho\dfrac{dV}{dt}\\ =1\times \dfrac{220\times 0.355}{60}\\ =1.302\ \text{kg/s}[/tex]

The mass flow rate is [tex]1.302\ \text{kg/s}[/tex].

Answer:

Explanation:

Do you mean the solvent? If this is off the mark, let me know in a comment.

The solvent is something that the solute is (usually) soluble in.

Answer:

The correct response will be "13.755 kN".

Explanation:

According to the question,

The given values are:

a = 300 mm

i.e.,

  = 0.3 cm

b = 200 mm

i.e.,

  = 0.2 dm

Internal pressure,

[tex]P_{in}=100[/tex]

Now,

The area of the elliptical shape window will be:

⇒  [tex]A = \pi ab[/tex]

On substituting the values, we get

⇒      [tex]=3.14\times 0.300\times 0.200[/tex]

⇒      [tex]=0.1885 \ m^2[/tex]

By using the table,

At 10 km, the atmospheric pressure will be

⇒  [tex]p_o=27.03 \ kPa[/tex]

Now,

The outward force will be:

⇒  [tex]F_{net}=p_{in}A-p_{0}A[/tex]

⇒          [tex]=(p_{in}-p_{0})A[/tex]

⇒          [tex]=(100-27.03)\times (0.1885)[/tex]

⇒          [tex]=13.755 \ kN[/tex]

Answer:

hydrogen and helium

Explanation:

i got it 100 percent. Hope this Helps!

When charged objects touch, you can assume that the charges move between the objects, so that the total amount of charge doesn't change but it splits equally between the two objects.

-- like two water tanks standing next to each other, with a different amount of water in each one.  When you connect a pipe between their bottoms, some water flows across until the LEVEL of water is the same in both tanks.

-- like one hard full balloon and one soft mooshy balloon.  When you connect them together, some air flows from the hard balloon into the soft balloon, until the pressure of air is the same in both balloons.  

The total amount of charge on your two objects is (+6.0 μC  -  2.0 μC).  That's +4.0 μC  .

When they touch, charges move around until the charge is the same on both objects . . . +2 μC.

Answer:

0.238 m/min

Explanation:

The volume of water in the trough V =Ah' where A = area of cross-section = area of isosceles trapezoid = 1/2(a + b)h where a = length of bottom of isosceles trapezoid = 40 cm = 0.4 m, b =  length of top of isosceles trapezoid = 100 cm = 1 m and h = height of isosceles trapezoid = 60 cm = 0.6 m. So,

A = 1/2(a + b)h = 1/2(0.4 m + 1 m)0.6 m = (1.4 m)0.3 m = 0.42 m² and h' = height of water level in trough = H - h" where H = length of trough = 10 m and h" = depth of water level in trough = 10 cm = 0.1 m

So, V = Ah'

V = A(H - h") = A(10 - h")

Now, the rate of change of volume of the trough with respect to time dV/dt = d[A(10 - h")]/dt

dV/dt = -Adh"/dt

dh"/dt = -dV/dt/A

Since dV/dt = 0.1 m³/min, substituting the other variables into the equation, we have

dh"/dt = -dV/dt/A

dh"/dt = -0.1 m³/min/0.42 m²

dh"/dt = -0.238 m/min

This is the rate at which the depth is decreasing

Since the height h' = 10 - h"

dh'/dt = d(10 - h")/dt

= -dh"/dt

= -(-0.238 m/min)

= 0.238 m/min

So the water level is increasing at a rate of 0.238 m/min

Answer:

Mars

Explanation:

In the 1960s, humans set out to discover what the red planet has to teach us. Now, NASA is hoping to land the first humans on Mars by the 2030s. Mars has captivated humans since we first set eyes on it as a star-like object in the night sky.

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