what is the answer to this?

[tex]\large\mathcal{\red{ \implies \: 2 \: \pi \: {r}^{2} \: + \: 2 \: \pi \: r \: h}}[/tex]

Option ( C ) is the correct answer.

Answer:

<ADC=90

therefore AC= 20 using Pytagoras

BAC is a right angle triangle because it belongs to the Pytagoras theorem:25,20,15 i.e 25²=15²+20²

3) I DON'T THINK PQR IS A RIGHT ANGLE TRIANGLE because it doesn't belong to the Pytagoras triple.

9514 1404 393

Answer:

  2675.08 kg/m³

Step-by-step explanation:

  [tex]\dfrac{167\text{ lb}}{\text{ft}^3}\times\dfrac{0.45359237\text{ kg}}{1\text{ lb}}\times\left(\dfrac{1\text{ ft}}{0.3048\text{ m}}\right)^3\approx\boxed{2675.08\text{ kg/m$^3$}}[/tex]

9514 1404 393

Answer:

  A, C, D, E

Step-by-step explanation:

Any relation that is different from a straight line with a defined constant slope will be a relation that is either or both of ...

__

a) degree 3, not linear

b) a linear function

c) a vertical line with undefined slope, not a function

d) a curve opening downward, not linear

e) a line with a bend in the middle, not linear

f) a linear function

Answer:

Total student= 600

Step-by-step explanation:

Let x be the number of students

[tex]x \times \frac{80}{100} = 480 \\ = 480 \times \frac{10}{8} \\ x = 600[/tex]

Brainliest please~

Answer:600

Step-by-step explanation:

by taking total number of pupils x

80/100×x=480

48000/80=600

x=600

Answer:

-9/2 < x < -3/5

Step-by-step explanation:

So first, we take the left part of the inequality to solve and ignore the right part for now, which leaves us 6x + 3 < x.

1. Subtract 3 from both sides:

6x < x - 3

2. subtract x from both sides:

5x < -3

3. divide 5 from both sides:

x < -3/5

Then, we do the same thing as part 1, but this time with x < 3x + 9.

1. Subtract 9 from both sides:

x - 9 < 3x

2. subtract x from both sides:

-9 < 2x

3. divide both sides by 2:

-9/2 < x.

Notice how we have a value that x is less than and a value that x is greater than. So now, all we have to do is to put the two inequalities together, leaving only one x in the middle. Hence, -9/2 < x < -3/5.

I hope this helped! :D

[tex]\\ \sf\longmapsto 6x + 3 < x < 3x + 9 \\ \\ \sf\longmapsto 6x - 3x < x < 9 - 3 \\ \\ \sf\longmapsto 3x < x < 6 \\ \\ \sf\longmapsto x < \frac{x}{3} < 2[/tex]

Answer: 16 bags

Step-by-step explanation:

(20) (4/5) = 16

(16) (3) / 2 = 24

Answer:

10. x is 15; y is \sqrt104. 11. \sqrt5

Step-by-step explanation:

for 10:

first we find the face on the left side; which according to the pythagorean theorem x is 144 + 81 =225 = x = 15. and y is 11^2 + y^2 = 225 = 225 - 121 = y^2 = y = the square root of 104.

for 11:

144 + y^2 = 169 = y^2 = 25 = y = 5. because the two sides are equivalent, the base is also 5 for the left part of the triangle. therefore, 5^2 + 5^2 = x^2 which means x is the square root of 5.

Answer

3.0/5

33

nickhollandmck

Ambitious

26 answers

1.7K people helped

Answer:

A: We know that the confidence interval is 0.22 ± 0.04, this equals .22 plus .04, .22 minus .44, or (.18,.26). Because of the fact that .25 is in the range of (.18,.26), there is no statistical evidence that the program is not working as intended.

B: As we established earlier, .25 is within the range of (.18,.26). This means that there is statistical evidence that the program makes the discount with a .25 probability.

C: To solve this problem, we need to use the margin of error formula. The margin of error formula is z times the square rout of p-hat times 1 minus p hat over n. From this formula we see that the me is inversely proportional to the square rout of the sample size. Because this is the case, the new me value is determined by dividing the old me value by 2 because of the fact that the proportion of p is 22%. This means that the new me is equal to .04/2, which equals .02, which means that the new margin of error is .02.

D: We know using the new me that the new CI is .22 ± .02. This also equals .22 plus .02, .22 minus .02, or (.2,.24) Because .25 is not within the range of (.2,.24), there is not statistical evidence that the program is working as intended.  

Step-by-step explanation:

Your welcome

TyrantMC

Answer:

Answer

3.0/5

33

nickhollandmck

Ambitious

26 answers

1.7K people helped

Answer:

A: We know that the confidence interval is 0.22 ± 0.04, this equals .22 plus .04, .22 minus .44, or (.18,.26). Because of the fact that .25 is in the range of (.18,.26), there is no statistical evidence that the program is not working as intended.

B: As we established earlier, .25 is within the range of (.18,.26). This means that there is statistical evidence that the program makes the discount with a .25 probability.

C: To solve this problem, we need to use the margin of error formula. The margin of error formula is z times the square rout of p-hat times 1 minus p hat over n. From this formula we see that the me is inversely proportional to the square rout of the sample size. Because this is the case, the new me value is determined by dividing the old me value by 2 because of the fact that the proportion of p is 22%. This means that the new me is equal to .04/2, which equals .02, which means that the new margin of error is .02.

D: We know using the new me that the new CI is .22 ± .02. This also equals .22 plus .02, .22 minus .02, or (.2,.24) Because .25 is not within the range of (.2,.24), there is not statistical evidence that the program is working as intended.  

Answer:

2.7*10³=2700

note if power positive you add '0s' to the back eg 10³=1000 if the power is negative e.g10^-3 add to the front and a decimal e.g 0.001

[tex]\\ \sf \longmapsto 2.7\times 10^3[/tex]

[tex]\\ \sf \longmapsto 27\times 10^{-1}\times 10^3[/tex]

[tex]\\ \sf \longmapsto 27\times 10^{-1+3}[/tex]

[tex]\\ \sf \longmapsto 27\times 10^2[/tex]

[tex]\\ \sf \longmapsto 27\time 100[/tex]

[tex]\\ \sf \longmapsto 2700[/tex]

Let the original price = x

From X to get the new price you multiply by 1 + the percent of the increase which is 25%

1,25X = 2.00

Divide both sides by 1.25:

X = 1.60

The original price was B. 1.60

Answer:

x=1.60

Step-by-step explanation:

Let x be the original price

We increase by 25%

x+ .25x = new price

1.25x = 200

Divide each side by 1.25

x = 2.00/1.25

x=1.60

Answer:

32 ounces

Step-by-step explanation:

Answer:

Hours of labor needed  = 8 hour

Step-by-step explanation:

Given:

Amount total charged = $715

Listed amount = $315

Hourly rate for labor = $50

Find:

Hours of labor needed

Computation:

Total amount of labour = Amount total charged - Listed amount

Total amount of labour = 715 - 315

Total amount of labour = $400

Hours of labor needed  = Total amount of labour / Hourly rate for labor

Hours of labor needed  = 400 / 50

Hours of labor needed  = 8 hour

the sequence is arithmetic because it's incrementing by a constant ratio of -4

The sequence 11,7,3,... is arithmetic because there is a constant increase of (-4)

Must click thanks and mark brainliest

Answer:

I think it is segment...........

Answer:

14

Step-by-step explanation:

Answer:

The first line:

y₁ = (2/3)*x + 6

Has the larger y-intercept, by 5 units.

Step-by-step explanation:

Here we need to find the equation for each line.

First, some theory.

A linear relationship can be written as:

y = a*x + b

where a is the slope and y is the y-intercept.

We know that if the line passes through the points (x₁, y₁) and (x₂, y₂), then we can write the slope as:

a = (y₂ - y₁)/(x₂ -x₁)

And, if a line is:

y = a*x + b

a perpendicular line to that one must have a slope equal to:

-(1/a).

Now we can answer this question.

We know that the first line, let's call it y₁, passes through the points (3, 8) and (-3, 4), then its slope will be:

a = (8 - 4)/(3 - (-3)) = 4/6 = 2/3

then the line is something like:

y₁ = (2/3)*x + b

to find the value of b, we can use the fact that we know that the line passes through the point (3, 8)

this means that when x = 3, we must have y₁ = 8

replacing these in the above equation, we get:

8 = (2/3)*3 + b

8 = 2 + b

8 - 2 = b = 6

then the equation for this line is:

y₁ = (2/3)*x + 6

Now let's find the equation for the other line, that we will call y₂.

We know that this line is perpendicular to:

y = (1/3)*x - 2

The slope of that line is:

a = (1/3)

then the slope of a line perpendicular to that one will be:

slope = -(1/a) = -(1/1/3) = -3

slope = -3

then we have:

y₂ = -3*x + b

to find the value of b, we can use the fact that our line passes through the point (2, -5)

This means that when  x = 2, we must have y₂ = -5

then:

-5 = -3*2 + b

-5 = -6 + b

-5 + 6 = b = 1

b = 1

then this equation is:

y₂ = -3*x + 1

Now we know both equations:

y₁ = (2/3)*x + 6

y₂ = -3*x + 1

Which equation does have the larger y-intercept?

We can see that the first line has an y-intercept of 6, and the second line has an y-intercept of 1, then the first line has the larger y-intercept, and is larger by 5 units.

Answer:

The total value of quarters that Samantha took is $3.75

Step-by-step explanation:

Timothy has 72 coins.

He has:

Q quarters

D dimes

N nickels

8 pennies.

Then:

Q + D + N + 8 = 72

Samantha takes:

3 dimes

2 nickels

Leaves him with one penny, then she takes 7 pennies.

all of the quarters, so she took Q quarters.

So now Timothy has 45 coins.

And for each particular type of coin, Thimothy now has:

D - 3 dimes

0 quarters

1 penny

N - 2 nickels

And we know that he has 45 coins, then:

(N - 2) + 1 + ( D - 3) = 45

Which we can rewrite as:

N + D + 1 - 2 - 3 = 45

N + D - 4 = 45

N + D = 45 + 4 = 49

So we have two equations:

Q + D + N + 8 = 72

N + D = 49

Now we can replace the second equation into the first one:

(N + D) = 49

then:

Q + D + N + 8 = 72

Q + (D + N) + 8 = 72

Q + 49 + 8 = 72

Now we can solve this for Q

Q = 72 - 49 - 8 = 15

So Samantha took 15 quarters.

Each quarter has a value of $0.25

Then Samantha took:

15*$0.25 = $3.75

The total value of quarters that Samantha took is $3.75

Answer:

90

Step-by-step explanation:

We know that area of ∆BCD = half of the area of rectangle BEFD, since any triangle drawn from taking a side and base and a point on the opposite side as the 3rd vertex has the half area of the rectangle

so, area of ∆BCD = 15×12/2 = 90 (since two legs of the right triangle are 15 and 12)

since area ∆BCD is half the area rectangle BEFD and sum of the area of ∆BEC and ∆CFD will be the rest of the area of rectangle BEFD, which is 90

Answer:

Step-by-step explanation:

I discounted the 2-m ramp. If we are supposed to be looking for the length of time the ride is above 38 m from the ground, that translates to 36 m from the very bottom of the circle that is the Ferris wheel (where the wheel would meet the "ground"). I first found the circumference of the circle:

C = 48(3.1415) so

C = 150.792 m

I enclosed this circle (the Ferris wheel is a circle) in a square and then split the square in 4 parts. Each square has a quarter of the circle in it. If you divide the circumference by 4, that means that the arc length of each quarter circle is a length of 37.698 m. But that doesn't put us 36 m above the ground, that only puts us 24 m above the ground (remember the diameter of the circle is 48, so half of that is 24, the side length of each of the 4 squares). What that means to us (so far, and we are not at the answer yet) is that when the height off the ground is 24 m, a car that starts at the bottom of the ride has traveled 37.698 m around the circle. Traveling in an arc around the outside of the circle is NOT the same thing as a height off the ground. Going around a circle takes longer because of the curve. In other words, if the car has traveled 37.698 m around the outside of the circle, it is NOT 37.698 m above the ground...it's only 24 m above the ground. Hence, the reason I enclosed the circle in a square so we have both the circle's curve {arc length} and height above the ground {side of the square}). As the car travels farther along the outside of the circle it gets higher off the ground. If one quarter of the circle is 24 m above the ground, we need to figure out how much farther around the circle we need to go so we are 36 m above the ground. The height difference is 36 - 24 = 12m. we need now to find how long the arc length of the circle is that translates to another 12 m (the difference between the 24 we found and the 36 total). Using right triangle trig I found that arc length to be 12.566. The total arc length on the circle that translates to 36 m above the ground is 50.26437 m.

Going back to the beginning of the problem, the circumference of the circle is 150.792, and it makes one complete revolution in 5 minutes. That means that a car will travel 30.1584 m in 1 minute. Since this is the case, we can use proportions to solve for how long it takes to get 36 m above the ground:

[tex]\frac{m}{min}:\frac{30.1584m}{1min}=\frac{50.26437m}{xmin}[/tex] and cross multiply:

30.1584x = 50.26437 so

x = 1.6667 minutes, the time it takes to reach a height of 36 m. BUT this is not what the question is asking. The question is asking how long it's HIGHER than that 36 m. Let's think.

The car starts at the bottom of the ride, gets to a height of 36 m, keeps going around the circle to its max height of 48 m, then eventually comes back down and keeps going til it's back on the ground. That means that there is a portion at the top of the wheel that is above 36 m. If it goes 50.2647 m around the circle til it's at 36 m, then when it passes the max height and drops back to 36 m, it's 50.2647 m around the other side of the circle. We just found that to travel that 50.2647 m, it took the car 1.6667 minutes. We travel this distance twice (once meeting the height going up and then again coming down) so that takes up 3.3334 minutes.

5 minutes - 3.3334 minutes leaves us off 36 m above the ground for 1.6664213 minutes.

Answer:

Jocelyn will have eaten 620 (which is way too much) by the end of day 32.

Step-by-step explanation:

First find out all the numbers that have to be added.

5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35

Then, Add.

5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35

= 620

Jocelyn ate 620 gummy worms by the end of the 32nd day.

Thank YOu! Please mark me brainliest!

Answer:

656

Step-by-step explanation:

i took the test

Answer:

11

4m-28 = 16

4m = 44

m=11

Step-by-step explanation:

Bags of limes = 4

Total limes in each bag = m

Total limes = 4m

ATQ

4m - 7(4)= 16

4m = 16+28

4m = 44

m = 44/4

m = 11

Value of m = 11

Must click thanks and mark brainliest

Answer:

that would be -11

Step-by-step explanation:

it is asking for the absolute value of -7-4 however absolute value is always positive once you solve that you have a negative symbol on the outside that turns ur answer negative

Answer:

- 3

Step-by-step explanation:

- | -7+4|

Determine inside the absolute value first

-7+4 = -3

Replace inside the absolute value

- |-3|

The absolute value means take the non negative value

|-3| =3

- 3

Answer:

This is already listed in increasing order:

Given order .

We have to arrange it in increasing means lowest to highest

[tex]\\ \sf\longmapsto 780<807<870[/tex]

The listing will be

[tex]\\ \sf\longmapsto 780;807;870[/tex]

Answer:

the amount will 26.7 ......hope this may help you

Answer:

x=4

Step-by-step explanation:

First find the slope

m = ( y2-y1)/(x2-x1)

   = ( -6-5)/(4-4)

  = -11/0

This means the slope is undefined

Then means it is a vertical line

Vertical lines are in the form

x = constant

The constant in this case is the x value of the points

x=4

Answer:

25/72

Step-by-step explanation:

P( blue) = blue / total = 4/12 = 1/3

P ( blue, blue) = 1/3 * 1/3 = 1/9

P ( red) = red / total = 5/12

P ( red, red) = 5/12 * 5/12 = 25/144

P ( green) = green /total = 3/12 =1/4

P ( green , green) = 1/4 * 1/4 = 1/16

Add these together to get

P( same colour twice) = 1/9+ 25/144 + 1/16

                                      =16/144 + 25/144 + 9/144

                                      =50/144

                                     =25/72

Increased height:-

[tex]\\ \sf\longmapsto 23\times 15\%[/tex]

[tex]\\ \sf\longmapsto 23\times \dfrac{15}{100}[/tex]

[tex]\\ \sf\longmapsto \dfrac{345}{100}[/tex]

[tex]\\ \sf\longmapsto 3.45[/tex]

Now current height:-

[tex]\\ \sf\longmapsto 23+3.45=26.45ft[/tex]