Someone pls help me ill give out brainliest pls don’t answer if you don’t know

Answer:

(2x + y) ( x + 2y)

Step-by-step explanation:

Assuming you want to do a cartesian product, then you basically form items (x,y)  such that x is in set A, and y is in set A

More generally, A * B will consist of items of the form (x,y) such that x is in A and y is in B. However, we have B = A.

So,

A * A = {

(a,a), (a,b), (a,c)

(b,a), (b,b), (b,c)

(c,a), (c,b), (c,c)

}

I broke things up into separate rows to show that we can form a 3x3 table. Each row is a different x value from the set {a,b,c}. Each column is a different y value from the set {a,b,c}

In my opinion, this helps organize things much better than rather have it all on one single line like this

A * A = { (a,a), (a,b), (a,c), (b,a), (b,b), (b,c), (c,a), (c,b), (c,c) }

which in all honesty looks like a bit of a cluttered mess.

Answer:

Step-by-step explanation:

A={a,b,c}

A×A={a×a,a×b,a×c,b×a,b×b,b×c,c×a,c×b,c×c}

Answer:6.91239069507

Step-by-step explanation:

Answer:

Solution given

Cos[tex]\displaystyle \theta_{1}=\frac{13}{15}[/tex]

consider Pythagorean theorem

[tex]\bold{Sin²\theta+Cos²\theta=1}[/tex]

Subtracting [tex]Cos²\theta[/tex]both side

[tex]\displaystyle Sin²\theta=1-Cos²\theta[/tex]

doing square root on both side we get

[tex]Sin\theta=\sqrt{1-Cos²\theta}[/tex]

Similarly

[tex]Sin\theta_{1}=\sqrt{1-Cos²\theta_{1}}[/tex]

Substituting value of [tex]Cos\theta_{1}[/tex]

we get

[tex]Sin\theta_{1}=\sqrt{1-(\frac{-13}{15})²}[/tex]

Solving numerical

[tex]Sin\theta_{1}=\sqrt{1-(\frac{169}{225})}[/tex]

[tex]Sin\theta_{1}=\sqrt{\frac{56}{225}}[/tex]

[tex]Sin\theta_{1}=\frac{\sqrt{56}}{\sqrt{225}}[/tex]

[tex]Sin\theta_{1}=\frac{\sqrt{2*2*14}}{\sqrt{15*15}}[/tex]

[tex]Sin\theta_{1}=\frac{2\sqrt{14}}{15}[/tex]

Since

In III quadrant sin angle is negative

Answer:

Step-by-step explanation:

In the quadrant III both the sine and cosine get negative value.

Use the identity:

And consider negative value as mentioned above:

Answer:

there is always a y-intercept in all graphs.

Step-by-step explanation:

be it a line graph, quadratic graph or cubic graph. all graphs will definitely have a y-intercept. and in this case, since y=mx + c where c is the y-intercept. the y intercept of this graph is 10

Answer:

h=6

Step-by-step explanation:

9514 1404 393

Answer:

  x = 90°

Step-by-step explanation:

Half the sum of x and 120° is the angle where the chords cross, 105°. Then ...

  105° = (1/2)(x +120°)

  210° = x + 120°

  210° -120° = x = 90°

_____

Additional comment

z is the arc that finishes the circle: 360° -90° -68° -120° = 82°.

Step-by-step explanation:

Y=

[tex]y = 10 - 8x \\ put \: this \: in \: the \: second \: equation \\ 2(10 - 8x) - 4x = 40 \\ 20 - 16x - 4x = 40 \\ 20 - 20x = 40 \\ - 20 = 20x \\ x = - 1 \\ put \: the \: value \: of \: x \: in \: th \: first \: equation \\ y = 10 - 8( - 1) \\ y = 10 + 8 \\ y = 18[/tex]

Hence, x=-1 and y=18

Answer:

(- 1, 18 )

Step-by-step explanation:

Given the equations

y + 8x = 10 ( subtract 8x from both sides )

y = 10 - 8x → (1)

2y - 4x = 40 → (2)

Substitute y = 10 - 8x into (2)

2(10 - 8x) - 4x = 40 ← distribute and simplify left side

20 - 16x - 4x = 40

20 - 20x = 40 ( subtract 20 from both sides )

- 20x = 20 ( divide both sides by - 20 )

x = - 1

Substitute x = - 1 into (1) for corresponding value of y

y = 10 - 8(- 1) = 10 + 8 = 18

solution is (- 1, 18 )

Answer:

0.0347 = constant of proportionality

[tex]1 * e^{0.0347t} = 15000[/tex]

Step-by-step explanation:

Given

[tex]1*e^{0.0347t}[/tex]

Solving (a): what does 0.0347 represent?

An exponential model is represented as:

[tex]f(t) = a * e^{kt}[/tex]

Where:

[tex]k \to[/tex] constant of proportionality

So, by comparison:

[tex]k = 0.0347[/tex]

Hence:

[tex]0.0347 \to[/tex] constant of proportionality

Solving (b): Formula to calculate when balance equals 15000

To do this, we simply equate the formula to 15000.

So, we have:

[tex]1 * e^{0.0347t} = 15000[/tex]

Answer:

The common for the second question is 30

Answer:

39/30 Here 30 will be common in denominators

Step-by-step explanation:

6/15×2/2=12/30

3/10×3/3=9/30

3/5×6/6=18/30

= 12/30+9/30+18/30

39/30

Step-by-step explanation:

Using R, I used the following code to create a histogram:

bowling.scores <- c(87, 104, 79, 94, 117, 82, 72, 116, 105, 95, 88, 93, 109, 119, 75,  

                   103, 112, 97, 73, 85, 91, 86, 102, 99, 106, 84, 98, 83, 81, 96, 92)

data.frame(bowling.scores)

ggplot(data.frame(bowling.scores), aes(x=bowling.scores)) +  

 xlim(c(70, 120)) +

 scale_y_continuous(breaks = seq(0, 10, by=1), "Frequency") +

 geom_histogram(breaks=seq(70, 120, by=10), color="black", fill="grey60") +

 labs(title="Histogram of Bowling Scores", x="Bowling Scores", y="Frequency")

Answer:

1.) (2,1) is a solution

2.) (4,3) is NOT a solution

Step-by-step explanation:

1.) (2,1)

These are these mean (x,y)

2=x and 1=y

You want to substitute the numbers for the letters in the equation.

so.

2(2)+1=5

4+1=5

5=5, This statement is true so (2,1) is a solution.

2.) Same as above. 4=x and 3=y

4(4)-3(3)=10

16-9=10

7 Does Not Equal 10, Therefore, (4,3) is Not a solution to the equation.

Answer:

If 4 flower pots cost 4.08 dollars, then 1 flower pot costs 4.08/4 dollars.

4.08/4 = 1.02.

So the unit price is $1.02.

Let me know if this helps!

Answer:

10,596 cubic inches

Step-by-step explanation:

The shape of the prism with which the sand castle can be modelled = Square prism

The arrangement of the square prism = One on top of the other

The given height of each prism, h = 6 inches

The side length of the base of the bottom prism, s₄ = 30 inches

The side length of the base of the other prism = The side length of the base of the prism below each prism - 7 inches

Therefore;

The side length of a prism = 7 inches + The side length of the prism above it

Given that the side length of the base prism (The fourth prism), s₄ = 30 inches

The side length of the prism, directly above the base prism (The fourth prism), s₃ = (30 - 7) inches = 23 inches

The side length of the prism, directly above the third prism (The second prism), s₃ = (23 - 7) = 16 inches

The side length of the top most prism, s₁ = (16 - 7) inches = 9 inches

The volume of the sand castle, V = h × (s₄² + s₃² + s₂² + s₁²)

∴ V = 6 × (30² + 23² + 16² + 9²) = 10,596

The volume of the sand castle, V = 10,596 in.³

Heyo!

The volume of the sandcastle above is 10,596 cubic inches.

Hope this helps! If so, please lmk! Tysm and good luck guys!

Answer:

No

Step-by-step explanation:

It can still be 8x - 2

first of all you collect like terms

5x + 3x - 2

= 8x -2

Answer:

94.2 cm^3.

Step-by-step explanation:

Volume of a cone = 1/3πr^2h

The radius of the cone = 1/2 * 6 = 3

So here the volume is:

1/3 * π *  3^2 * 10

= 94.247

Answer:

2x - 19

Step-by-step explanation:

Perimeter = sum of sides

First let's simplify each side

We can simplify each side by using distributive property. Distributive property is where you multiply the number on the outside of the parenthesis by the numbers on the inside of the parenthesis.

2(x + 5)

Distribute by multiplying x and 5 by 2

2 * x = 2x and 2 * 5 = 10

2x + 10

1/2(4x + 8)

Distribute by multiplying 4x and 8 by 1/2

1/2 * 4x = 2x and 1/2 * 8 = 4

2x + 4

-3(2x + 11)

Distribute by multiplying 2x and 11 by -3

-3 * 2x = -6x

-3 * -33

-6x - 33

Finally add all the simplified expressions ( remember that they represent the side lengths of the triangle )

2x + 10 + 2x + 4 - 6x - 33

Combine like terms

2x + 2x - 6x = -2x

10 + 4 - 33 = -19

Perimeter: -2x - 19

Answer:

Perimeter = - 2x - 19

Step-by-step explanation:

[tex]Perimeter \: of \: a \: triangle \\ = Sum \: of \: the \: length \: of \: all \: sides \\ = [2(x+5)]+[-3(2x+11)]+[ \frac{1}{2} (4x+8)] \\ = [(2 \times x)+(2 \times 5)]+[(-3 \times 2x)+( - 3 \times 11)]+[ (\frac{1}{2} \times 4x) + ( \frac{1}{2} \times 8)] \\ = (2x + 10) + ( - 6x - 33) + (2x + 4) \\ = 2x + 10 - 6x - 33 + 2x + 4 \\ = 2x - 6x + 2x + 10 - 33 + 4 \\ = - 2x - 19[/tex]

So, the perimeter is - 2x - 19.

Answer:

[tex]\|a\| = 5\sqrt{13}[/tex].

[tex]\|b\| = 3\sqrt{29}[/tex].

Step-by-step explanation:

Let [tex]m[/tex],[tex]n[/tex], and [tex]k[/tex] be scalars such that:

[tex]\displaystyle a = m\, (2\, \vec{i} + 3\, \vec{j}) = m\, \begin{bmatrix}2 \\ 3\end{bmatrix}[/tex].

[tex]\displaystyle b = n\, (2\, \vec{i} + 5\, \vec{j}) = n\, \begin{bmatrix}2 \\ 5\end{bmatrix}[/tex].

[tex]\displaystyle (a + b) = k\, (8\, \vec{i} + 15\, \vec{j}) = k\, \begin{bmatrix}8 \\ 15\end{bmatrix}[/tex].

The question states that [tex]\| a + b \| = 34[/tex]. In other words:

[tex]k\, \sqrt{8^{2} + 15^{2}} = 34[/tex].

[tex]k^{2} \, (8^{2} + 15^{2}) = 34^{2}[/tex].

[tex]289\, k^{2} = 34^{2}[/tex].

Make use of the fact that [tex]289 = 17^{2}[/tex] whereas [tex]34 = 2 \times 17[/tex].

[tex]\begin{aligned}17^{2}\, k^{2} &= 34^{2}\\ &= (2 \times 17)^{2} \\ &= 2^{2} \times 17^{2} \end{aligned}[/tex].

[tex]k^{2} = 2^{2}[/tex].

The question also states that the scalar multiple here is positive. Hence, [tex]k = 2[/tex].

Therefore:

[tex]\begin{aligned} (a + b) &= k\, (8\, \vec{i} + 15\, \vec{j}) \\ &= 2\, (8\, \vec{i} + 15\, \vec{j}) \\ &= 16\, \vec{i} + 30\, \vec{j}\\ &= \begin{bmatrix}16 \\ 30 \end{bmatrix}\end{aligned}[/tex].

[tex](a + b)[/tex] could also be expressed in terms of [tex]m[/tex] and [tex]n[/tex]:

[tex]\begin{aligned} a + b &= m\, (2\, \vec{i} + 3\, \vec{j}) + n\, (2\, \vec{i} + 5\, \vec{j}) \\ &= (2\, m + 2\, n) \, \vec{i} + (3\, m + 5\, n) \, \vec{j} \end{aligned}[/tex].

[tex]\begin{aligned} a + b &= m\, \begin{bmatrix}2\\ 3 \end{bmatrix} + n\, \begin{bmatrix} 2\\ 5 \end{bmatrix} \\ &= \begin{bmatrix}2\, m + 2\, n \\ 3\, m + 5\, n\end{bmatrix}\end{aligned}[/tex].

Equate the two expressions and solve for [tex]m[/tex] and [tex]n[/tex]:

[tex]\begin{cases}2\, m + 2\, n = 16 \\ 3\, m + 5\, n = 30\end{cases}[/tex].

[tex]\begin{cases}m = 5 \\ n = 3\end{cases}[/tex].

Hence:

[tex]\begin{aligned} \| a \| &= \| m\, (2\, \vec{i} + 3\, \vec{j})\| \\ &= m\, \| (2\, \vec{i} + 3\, \vec{j}) \| \\ &= 5\, \sqrt{2^{2} + 3^{2}} = 5 \sqrt{13}\end{aligned}[/tex].

[tex]\begin{aligned} \| b \| &= \| n\, (2\, \vec{i} + 5\, \vec{j})\| \\ &= n\, \| (2\, \vec{i} + 5\, \vec{j}) \| \\ &= 3\, \sqrt{2^{2} + 5^{2}} = 3 \sqrt{29}\end{aligned}[/tex].

Answer:

Yes, it is a polynomial, and the degree is 5

Step-by-step explanation:

A polynomial is a combination of terms separated using + or − signs and normally have exponents. So, this equation is a polynomial. The degree is just the highest exponential value, which is 5 because -5y is being raised to the 5th power

Answer:

Divide 278 by 4 and the remainder value is the amount of leftover brownies.

278 ÷ 4 = 69, remainder of 2

Therefore, he had 2 brownies left.

Answer:

dddddd=666=7777

Step-by-step explanation:

Answer:

x is 7

EF is 10

FG is 12

Step-by-step explanation:

[tex]EF + FG = EG \\ (4x - 18) + (3x - 9) = 22 \\ 7x - 27 = 22 \\ 7x = 49 \\ x = 7[/tex]

then substitute:

[tex]EF = 4x - 18 \\ EF = 4(7) - 18 \\EF = 28 - 18 \\ EF = 10[/tex]

[tex]FG = 3x - 9 \\ FG = 3(7) - 9 \\FG = 21 - 9 \\ FG = 12[/tex]

First question:

BC + BA = CA

BC = CA - BA

BC = 36 - 9

BC = 27

Answer:

20 miles

Step-by-step explanation:

She ran 20miles, at the same point she passed her friend

here's the answer to your question

Answer:

5555+2929

= 8484

its an irrational no.

thanks

Answer:

1

Step-by-step explanation:

1