what is the answer to (x+1)(3x+2)

Step-by-step explanation:

We have given an equation −2x − 13 = 8x + 7

We need to find the operations that is used to find the value of x. It can be done by the following ways.

Subtract 8x on both the sides of the equation

−2x − 13 -8x= 8x + 7 -8x

-10x-13 = 7

Add 13 on both the sides of the equation,

-10x-13+13 = 7+13

-10x=21

Divide by -10 on both sides

[tex]x=\dfrac{-20}{10}\\\\x=-2[/tex]

Hence, the correct option is "Subtract 8x, then add 13, lastly divide by −10"

Answer:

The linear distance between the two points is the square root of the sum of the squared values of the x-axis distance and the y-axis distance. To carry on the example: the distance between (3,2) and (7,8) is sqrt (52), or approximately 7.21 units.

Step-by-step explanation:

Answer:

Step-by-step explanation:

distance formula and pythagorean formula

Answer:

None of the answers seem to be correct.

Step-by-step explanation:

The given equation is of the form y = mx + b where m is the slope and b is the y-intercept.

Here, m = -14

Two parallel lines have the same slope. So, the slope of the new line will be -14.

To calculate the y-intercept substitute x=4 and y=4 in the equation.

4 = (-14)(4) + b

Solving for b, we get b = 60.

So, the new equation will be y = -14x + 60

The equation of the line parallel to the given line is y =-14x+60, none of the given options is correct.

The equation of the straight line is given by y = mx +c , Where m is the slope of the line and c is the y-intercept.

The equation of the line is y = -14x -3

The slope of the line parallel to this will be the same as the given line.

m = -14 for both the lines

The line equation parallel to the given line is

y = -14x +c

The line passes through the points (4,4)

4 = -14 * 4 + c

c = 60

y = -14x +60

Therefore, the equation of the line parallel to the given line is y =-14x+60.

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Answer:

Option (B)

Step-by-step explanation:

From the picture attached,

F1 and F2 are the focii of the hyperbola.

Point P(x, y) is x units distant from F1 and y units distant from the other focus F2.

By the definition of a hyperbola,

"Difference between the distances of a point from the focii is always constant and equals to the measure of transverse axis."

Difference in the distances of point P from focii F1 and F2 = (x - y) units

This distance is equal to the length of the transverse axis = (x - y) units

Therefore, Option (B) will be the answer.

Answer:

x-y

Step-by-step explanation:

Answer:

True

Step-by-step explanation:

Answer:

true as positive are bigger than negetive

Step-by-step explanation:

Answer:

70%

Step-by-step explanation:

So 5600/8000 is the fraction and 80 = 1% so 5600/80 will be your answer

Answer:

associative property

The solution is,  property is shown in the matrix addition below is

associative property.

Here, we have,

The property shown in the given matrix addition is associative property.

Let's define associative property first,

The Associative Property of Addition for Matrices states :

Let A , B and C be m×n matrices .

Then, (A+B)+C=A+(B+C) .

Associative Law of Addition of Matrix:

Matrix addition is associative. This says that, if A, B and C are Three matrices of the same order such that the matrices B + C, A + (B + C), A + B, (A + B) + C are defined then A + (B + C) = (A + B) + C.

Since P and Q are of the same order and pij = qij then, P = Q.

Here, from the given information,

we get, A , B and C be 4×1 matrices,

and,  (A+B)+C=A+(B+C)

So, The solution is,  property is shown in the matrix addition below is

associative property.

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Answer:

Its 14

Step-by-step explanation:

8+6=14

Answer:

The answer is 16

08

+ 06

----------

16

Hope it helps ;)

Please mark as brainliest

Answer:

3

3+3=6

3+3+5=11

13

13-3=10

10-3=7

15

15-7=8

8-5=3

32+43=75

75-40(highest ten)=35

76+15=91

91-70=21

Answer:

The answer is

Step-by-step explanation:

To find an equation of the line using a point and the slope we use the formula

y - y1 = m(x - x1)

where

m is the slope

(x1 , y1) is the point

From the question

slope = -3/2

Point = (4,8)

So the equation of the line is

[tex]y - 8 = - \frac{3}{2} (x - 4)[/tex]

Multiply through by 2

2y - 16 = -3( x - 4)

2y - 16 = - 3x + 12

3x + 2y = 16 + 12

We have the final answer as

Hope this helps you

Answer:A

Step-by-step explanation:

The phrase can be described broadly as adjusted gross income (AGI) minus allowable tax deductions.

"Adjusted gross income, or AGI, is your gross income minus certain adjustments. The IRS uses this number as a basis for calculating your taxable income. AGI can also determine which deductions and credits you may qualify for."

Since, Taxable income is the portion of your gross income used to calculate how much tax you owe in a given tax year.

It can be described broadly as adjusted gross income (AGI) minus allowable itemized or standard deductions.

Taxable income includes wages, salaries, bonuses, and tips, as well as investment income and various types of unearned income.

Hence, the phrase can be described broadly as adjusted gross income (AGI) minus allowable tax deductions.

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[tex]\displaystyle f(x)=\sin(3x)\\\\\\f'(x)=\lim_{h\to0}\dfrac{\sin(3(x+h))-\sin(3x)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{\sin(3x+3h)-\sin(3x)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{2\cos\left(\dfrac{3x+3h+3x}{2}\right)\sin\left(\dfrac{3x+3h-3x}{2}\right)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{2\cos\left(\dfrac{6x+3h}{2}\right)\sin\left(\dfrac{3h}{2}\right)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{2\cos\left(\dfrac{6x+3h}{2}\right)\sin\left(\dfrac{3h}{2}\right)}{\dfrac{3h}{2}}\cdot\dfrac{3}{2}[/tex]

[tex]\displaystyle f'(x)=\lim_{h\to0}2\cos\left(\dfrac{6x+3h}{2}\right)\cdot\dfrac{3}{2}\\\\f'(x)=\lim_{h\to0}3\cos\left(\dfrac{6x+3h}{2}\right)\\\\f'(x)=3\cos\left(\dfrac{6x+3\cdot 0}{2}\right)\\\\f'(x)=3\cos\left(\dfrac{6x}{2}\right)\\\\f'(x)=3\cos(3x)[/tex]

The derivative of sin 3x using first principles is; 3cos(3x)

We want to find the derivative of sin 3x using first principles.

Step 1;

f'(x) = [tex]\lim_{h \to \ 0} \frac{(sin3(x + h)) - sin(3x)}{h}[/tex]

Step 2; Expand the bracket to get;

f'(x) = [tex]\lim_{h \to \ 0} \frac{(sin(3x + 3h)) - sin(3x)}{h}[/tex]

Step 3: According to trigonometric identities, we know that;

sin A - sin B = [tex]2cos\frac{A + B}{2} sin\frac{A - B}{2}[/tex]

Applying that to the answer in step 2 gives;

f'(x) = [tex]\lim_{h \to \ 0} \frac{2(cos\frac{(3x + 3h + 3x)}{2}) sin\frac{(3x + 3h - 3x)}{2})}{h}[/tex]

Step 4; Simplify the brackets to obtain;

f'(x) = [tex]\lim_{h \to \ 0} \frac{2(cos\frac{(6x + 3h)}{2}) sin\frac{(3h)}{2})}{h}[/tex]

Step 5; Rewrite the denominator to get;

f'(x) = [tex]\lim_{h \to \ 0} \frac{2(cos\frac{(6x + 3h)}{2}) sin\frac{(3h)}{2})}{\frac{3h}{2}*\frac{2}{3}}[/tex]

Step 6; Input the limit of 0 for h to get;

f'(x) = [tex]\frac{2(cos\frac{(6x)}{2}) sin\frac{(0)}{2})}{\frac{0}{2}*\frac{2}{3}}[/tex]

⇒ f'(x) = [tex]\frac{2(cos3x)}{2/3} \frac{ 0}{{0}}[/tex]

0/0 = 1. Thus;

f'(x) = 3cos(3x)

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3√3 is not equivalent to 9³/₄

3√3 is equivalent to   [tex]9^\frac34[/tex]

step-by-step:

[tex]9^\frac34=(3^2)^\frac34=3^{2\cdot\frac34}=3^{\frac32}=3^{1+\frac12}=3^1\cdot3^\frac12=3\cdot\sqrt3=3\sqrt3[/tex]

The simplest form of the number [tex]9^\frac{3}{4}[/tex]   is  [tex]3 \ \sqrt[]{3}[/tex].

It is given that the  [tex]9^\frac{3}{4}[/tex]

It is required to find the simplest value of [tex]9^\frac{3}{4}[/tex]

It is defined as the number if we multiply the number by itself we get the original number it is a non-negative number.

We have:

= [tex]9^\frac{3}{4}[/tex]

We can write the above number as below:

[tex]= (3^2)^\frac{3}{4}[/tex]

By the property of powers:

[tex]\rm (x^a)^b= x^a^\times ^b[/tex] , we get:

[tex]3^2^\times^\frac{3}{4} \\\\\\3^\frac{3}{2} \\\\\sqrt{3^3} \\\\\sqrt{3}\times \sqrt{3}\times\sqrt{3}\\\\3\sqrt{3}[/tex]

Thus, the simplest form of the number [tex]9^\frac{3}{4}[/tex]   is  [tex]3 \ \sqrt[]{3}[/tex].

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Answer:

1/5

Step-by-step explanation:

1/5

2/3+3/3+4/3

=2/5*3/6

= 1/5

I'm not sure.

Answer:

The answer should be 0.022

Find the value of xy².

xy²

★ Substituting the values of x and y ,we get :

⇒ -12 × ( -3 )²

⇒ -12 × 9

⇒ -108

Answer:

itself and numbers divisible by 7

Answer:

  40

Step-by-step explanation:

Any solution x will mod 23 will also have x+23n as a solution, for some integer n. Since 900/23 = 39 3/23, we know there are 39 or 40 three-digit integers of this form.

As it happens, 100 is the smallest 3-digit solution. So, there are 40 three-digit numbers that are of the form 100 +23n, hence 40 solutions to the equation.

_____

The equation reduces, mod 23, to ...

  10x = 11

Its solutions are x = 23n +8.

Answer: You are correct, it is the second option.

Step-by-step explanation:

Volume of a cylinder formula is: pi*r^2*h. The diameter is 6 and the radius is half the diameter so we get r=3. The height is 10 inches, so h=10. pi(3)^2(10) is the volume of the vase.

Volume of a sphere (marbles) formula is: 4/3*pi*r^3

The marbles have a diameter of 3 so 3/2=1.5. r=1.5.

The volume of the marbles is 8(4/3*pi*1.5^3).

Then you subtract the volume of the marbles from the volume of the vase to find the volume of the water in the vase.

pi(3)^2(10) - 8(4/3pi(1.5)^3)

Hope this helps. :)

Answer:

You are absolutely correct, second option is the correct answer.

Step-by-step explanation:

Diameter of vase = 6 inches

Therefore, radius r = 3 inches

Diameter of marbles = 3 inches

Radius of marbles = 1. 5 inches

Height of water h = 10 inches

Volume of water in the vase = Volume of vase - 8 times the volume of one marble

[tex] = \pi r^2h - 8\times \frac{4}{3} \pi r^3 \\\\

= \pi (3\: in) ^2(10\: in) - 8( \frac{4}{3} \pi (1.5\: in) ^3) \\\\[/tex]

Answer:

8.

Step-by-step explanation:

[tex]\sqrt{57} =\sqrt{3 * 19}[/tex]

Since this cannot be further simplified, we will calculate the square root of 57 with our calculators.

We find that the square root of 57 is 7.549834435, and since the tenths place is a 5, we will round up to the next whole number. So, the point on the number line that best represents the square root of 57 is 8.

Hope this helps!

Answer:

8

Step-by-step explanation:

The there smallest consecutive odd numbers are 1,3 and 5

Therefore the smallest possible perimeter of such triangle = 8

Answer:

C, at 0/25, 1/20, 2/15, 3/10,...

Answer:

C

Step-by-step explanation:

Answer:

what's the fraction though?

Complete Question

A genetic experiment with peas resulted in one sample of offspring that consisted of 432 green peas and 164 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?

Answer:

The  95%  confidence interval is  [tex]0.2392 < p < 0.3108[/tex]

No, the confidence interval includes​ 0.25, so the true percentage could easily equal​ 25%

Step-by-step explanation:

From the question we are told that

  The total sample size is  [tex]n = 432 + 164 =596[/tex]

   The  number of  offspring that is yellow peas is [tex]y = 432[/tex]

   The  number of  offspring that is green peas   is [tex]g = 164[/tex]

The sample proportion for offspring that are yellow peas is mathematically evaluated as

        [tex]\r p = \frac{ 164 }{596}[/tex]

        [tex]\r p = 0.275[/tex]

Given the the  confidence level is  95% then the level of significance is mathematically represented as

       [tex]\alpha = (100 - 95)\%[/tex]

      [tex]\alpha = 5\% = 0.0 5[/tex]

The  critical value of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table is  

      [tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]

Generally the margin of error is mathematically evaluated as

        [tex]E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r p (1- \r p )}{n} }[/tex]

=>      [tex]E = 1.96 * \sqrt{\frac{0.275 (1- 0.275 )}{596} }[/tex]

=>      [tex]E = 0.0358[/tex]

The  95%  confidence interval is mathematically represented as

      [tex]\r p - E < p < \r p + E[/tex]

=>   [tex]0.275 - 0.0358 < p < 0.275 + 0.0358[/tex]

=>   [tex]0.2392 < p < 0.3108[/tex]

Answer: 0.29 or 29%

Step-by-step explanation:

Given :

Probability that the athletes are football players : P(football ) = 0.28

Probability that the athletes are basketball players : P(basketball) = 0.25

Probability that the athletes play both football and basketball: P( both football and basketball ) = 0.24

Now, using formula

P(either  football or basketball)= P(football )+ P(basketball+ P( both football and basketball )

⇒P(either  football or basketball)= 0.28+0.25-0.24 = 0.29

Hence, the probability that they are either a football player or a basketball player = 0.29 .

Answer:

(4,2) is the answer on AP EX

The coordinate of the image of point A is (-4,-2)

Transformation is the process of changing the graph to a new graph by Rotation, Reflection, Translation, and Dilation.

The coordinate of A is (4,-2)

When it is reflected across y axis, the coordinate (x,y) changes to ----> (-x,y)

So, the coordinates of A (4,-2) changes to (-4,-2)

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Answer:

a21 = -61

Step-by-step explanation:

[tex]a_{n}=a_{1}+(n-1)d[/tex]

[tex]-19=a_{1}+(7-1)d[/tex]

[tex]-28=a_{1}+(10-1)d[/tex] (subtract to eliminate a₁)

9 = -3d

d = -3

-19 = a₁ + (6)(-3)

-1 = a

a21 = -1 + (21 - 1)(-3)

= -61

Answer:

-61 (Answer D)

Step-by-step explanation:

The general formula for an arithmetic sequence with common difference d and first term a(1) is

a(n) = a(1) + d(n - 1)

Therefore, a(7) = -19 = a(1) + d(7 - 1), or a(7) = a(1) + d(6) = -19

and a(10) = a(1) + d(10 - 1) = -28, or a(1) + d(10 - 1) = -28

Solving the first equation a(1) + d(6) = -19 for a(1) yields a(1) = -19 - 6d.  We substitute this result for a(1) in the second equation:

-19 - 6d + 9d = -28.  Grouping like terms together, we get:

3d = -9, and so d = -3.

Going back to an earlier result:  a(1) = -19 - 6d.

Here, a(1) = -19 - 6(-3), or a(1) = -1.

Then the formula specifically for this case is a(n) = -1 - 3(n - 1)

and so a(21) = -1 - 3(20) = -61 (Answer D)

Answer:

  40 cm

Step-by-step explanation:

Each point of the final 6-pointed star has 2/3 of the perimeter of the equilateral triangle. So, the 6 points have a total perimeter of ...

  6(2/3)(10 cm) = 40 cm

The perimeter of the final star is 40 cm.

Answer:

40

Step-by-step explanation:

The star has $12$ sides. Each side is one-third of the perimeter of a triangular tile, or $\frac{10}3$ cm. So the perimeter of the star is

$$12\cdot\frac {10}3 = 4\cdot 10 = \boxed{40\text{ cm}}.$$

Alternatively, consider that the original tiles are composed of $12$ triangles with $3$ sides each, which have $12\cdot 3 = 36$ sides in all. Only $12$ of those $36$ sides make up the perimeter of the star. $12$ is one-third of $36,$ so the perimeter of the star is one-third of the total perimeter of the tiles. The tiles have a total perimeter of $10 \cdot 12=120\text{ cm},$ so the perimeter of the star is $\frac{120}3 = 40$ cm.

Answer:

a=-3

Step-by-step explanation:

Answer:

Proof in the explanation.

Step-by-step explanation:

I expanded both sides as a first step. (You may use foil here if you wish and if you use that term.)

This means we want to show the following:

[tex]3-9\tan^2(\theta)-4\sin^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]

[tex]=12\cos^2(\theta)-9-4\cos^2(\theta)\tan^2(\theta)+3\tan^2(\theta)[/tex].

After this I played with only the left hand side to get it to match the right hand side.

One of the first things I notice we had sine squared's on left side and no sine squared's on the other. I wanted this out. I see there were cosine squared's on the right. Thus, I began with Pythagorean Theorem here.

[tex]3-9\tan^2(\theta)-4\sin^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]

[tex]3-9\tan^2(\theta)-4(1-\cos^2(\theta))+12\sin^2(\theta)\tan^2(\theta)[tex]

Distribute:

[tex]3-9\tan^2(\theta)-4+4\cos^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]

Combine like terms and reorder left side to organize it based on right side:

[tex]4\cos^2(\theta)-1+12\sin^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

After doing this, I since that on the left we had products of sine squared and tangent squared but on the right we had products of cosine squared and tangent squared. This problem could easily be fixed with Pythagorean Theorem again.

[tex]4\cos^2(\theta)-1+12\sin^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

[tex]4\cos^2(\theta)-1+12(1-\cos^2(\theta))\tan^2(\theta)-9\tan^2(\theta)[/tex]

Distribute:

[tex]4\cos^2(\theta)-1+12\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

Combined like terms while keeping the same organization as the right:

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

We do not have the same amount of the mentioned products in the previous step on both sides. So I rewrote this term as a sum. I did this as follows:

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

Here, I decide to use the following identity [tex]\cos\theta)\tan(\theta)=\sin(\theta)[/tex]. The reason for this is because I certainly didn't need those extra products of cosine squared and tangent squared as I didn't have them on the right side.

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\sin^2(\theta)-9\tan^2(\theta)[/tex]

We are again back at having sine squared's on this side and only cosine squared's on the other. We will use Pythagorean Theorem again here.

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\sin^2(\theta)-9\tan^2(\theta)[/tex]

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8(1-\cos^2(\theta))-9\tan^2(\theta)[/tex]

Distribute:

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8+8\cos^2(\theta)-9\tan^2(\theta)[/tex]

Combine like terms:

[tex]12\cos^2(\theta)-9+3tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)[/tex]

Reorder again to fit right side:

[tex]12\cos^2(\theta)-9+4\cos^2(\theta)\tan(\theta)+3\tan^2(\theta)[/tex]

This does match the other side.

The proof is done.

Note: Reordering was done by commutative property.