What is the domain of D(t) as it applies in this situation?

Answer:

2, 5, 8, 11

Step-by-step explanation:

The domian is the x axis points thingy

Answer:

19.14

Step-by-step explanation:

You have a half circle and a square, look at them separate then add for the area.

Circle

Your radius is half the diameter, so 4/2

Radius  = 2

[tex]A = 3.14 * radius\\A = 3.14 * 2\\A = 6.28[/tex]

This is for the entire circle, half of that would be 3.14

Square

[tex]A = 4^{2} \\A = 16[/tex]

Add them both together for a total area of 19.14 square miles

Step-by-step explanation:

90*8.25=742 rounds to 675 because its the closest. 85-95=10 divided by 2=5+85=90. 9-7.5=1.5 divided by 2=0.75+7.5=8.25. thats how i got those numbers. THE ANSWER IS C

Answer:

0.7246 radians

Step-by-step explanation:

According to the Question,

Given that, a rectangle box has length 12 inches, width 15 inches, and a height of 17 inches

d = √{ (12)² +(15)² }  = √(144+225) = √369inches

 Tan∅ = 17/√369

Taking the [tex]Tan^{-1}[/tex] , we have

∅ = [tex]Tan^{-1}[/tex](17/√369) ≈ 0.7246 radians

Answer:

Find the definitions and points below.

Step-by-step explanation:

1. Food Handling refers to any of the stages in the preparation, storage, transportation, packaging, and delivery of food.

2. Utensils are those vessels and tools that are used to carry, cut, stir, and store items and ingredients required in food preparation.

3.  Three quality points for dairy and eggs which indicate quality and freshness are;

a. Smell: A decaying and pungent smell indicates a lack of quality.

b. Color: An abnormal color with physical signs of rottenness shows a lack of quality.

c. The sinking test is used to check for the freshness of eggs. If an egg sinks when put in a glass of water, it is a sign of freshness. If it floats, it is an indication of decay.

4. Three quality points for dry goods that indicate quality and freshness:

Moisture: The presence of moisture in dry food shows a lack of quality.

Weight: Heaviness might be an indication that one coconut is better than another.

Texture: A dry food that is sticky might indicate a lack of freshness. Smoothness, crunchiness, hardness, and toughness are other qualities to look out for.

5. Five ways I could increase the nutritional value of pastries include

1. Using fresh ingredients: Fresh ingredients free from contamination will guarantee that foods with good nutritional values are produced.

2. Preparing them in a hygienic environment: A hygienic environment will prevent food poisoning by bacteria and other contaminants.

3. Using proper measurements: When the right measurements are used in the preparation of pastries a balanced snack is produced.

4. Good preservation techniques: The right preservation techniques will prevent food spoilage.

5. Good packaging and wrapping: These will prevent exposure of the food to moisture, rodents, and other unwanted factors. Thus, the nutritional value is preserved.

Answer:

Problem 17)

[tex]\displaystyle y=-\frac{5}{2}x+\frac{7}{2}[/tex]

Problem 18)

[tex]\displaystyle y=\frac{3}{2}x-\frac{3}{2}+\frac{\pi}{4}[/tex]

Step-by-step explanation:

Problem 17)

We have the curve represented by the equation:

[tex]\displaystyle 4x^2+2xy+y^2=7[/tex]

And we want to find the equation of the tangent line to the point (1, 1).

First, let's find the derivative dy/dx. Take the derivative of both sides with respect to x:

[tex]\displaystyle \frac{d}{dx}\left[4x^2+2xy+y^2\right]=\frac{d}{dx}[7][/tex]

Simplify. Recall that the derivative of a constant is zero.

[tex]\displaystyle \frac{d}{dx}[4x^2]+\frac{d}{dx}[2xy]+\frac{d}{dx}[y^2]=0[/tex]

Differentiate. We can differentiate the first term normally. The second term will require the product rule. Hence:

[tex]\displaystyle 8x+\left(2y+2x\frac{dy}{dx}\right)+2y\frac{dy}{dx}=0[/tex]

Rewrite:

[tex]\displaystyle \frac{dy}{dx}\left(2x+2y\right)=-8x-2y[/tex]

Therefore:

[tex]\displaystyle \frac{dy}{dx}=\frac{-8x-2y}{2x+2y}=-\frac{4x+y}{x+y}[/tex]

So, the slope of the tangent line at the point (1, 1) is:

[tex]\displaystyle \frac{dy}{dx}\Big|_{(1, 1)}=-\frac{4(1)+(1)}{(1)+(1)}=-\frac{5}{2}[/tex]

And since we know that it passes through the point (1, 1), by the point-slope form:

[tex]\displaystyle y-1=-\frac{5}{2}(x-1)[/tex]

If desired, we can simplify this into slope-intercept form. Therefore, our equation is:

[tex]\displaystyle y=-\frac{5}{2}x+\frac{7}{2}[/tex]

Problem 18)

We have the equation:

[tex]\displaystyle y=\tan^{-1}\left(x^3\right)[/tex]

And we want to find the equation of the tangent line to the graph at the point (1, π/4).

Take the derivative of both sides with respect to x:

[tex]\displaystyle \frac{dy}{dx}=\frac{d}{dx}\left[\tan^{-1}(x^3)][/tex]

We can use the chain rule:

[tex]\displaystyle \frac{d}{dx}[u(v(x))]=u'(v(x))\cdot v(x)[/tex]

Let u(x) = tan⁻¹(x) and let v(x) = x³. Thus:

(Recall that d/dx [arctan(x)] = 1 / (1 + x²).)

[tex]\displaystyle \frac{d}{dx}\left[\tan^{-1}(x^3)\right]=\frac{1}{1+v^2(x)}\cdot 3x^2[/tex]

Substitute and simplify. Hence:

[tex]\displaystyle \frac{d}{dx}\left[\tan^{-1}(x^3)\right]=\frac{1}{1+v^2(x)}\cdot 3x^2=\frac{3x^2}{1+x^6}[/tex]

Then the slope of the tangent line at the point (1, π/4) is:

[tex]\displaystyle \frac{dy}{dx}\Big|_{x=1}=\frac{3(1)^2}{1+(1)^6}=\frac{3}{2}[/tex]

Then by the point-slope form:

[tex]\displaystyle y-\frac{\pi}{4}=\frac{3}{2}(x-1)[/tex]

Or in slope-intercept form:

[tex]\displaystyle y=\frac{3}{2}x-\frac{3}{2}+\frac{\pi}{4}[/tex]

Answer:

Here's your answer .

hope it helps you

Answer:

11,494.0³

Step-by-step explanation:

Volume of a sphere= (4/3) × pi × radius³

4÷3 × 3.14 ×14³

= 11,494.0³

Answer:

(-7, -1) =(x1,y1)

(8, 5)=(x2,y2)

now

[tex]slope (m) = \frac{y2 - y1}{x2 - x1} [/tex]

[tex]or = \frac{5 - ( - 1)}{8 - ( - 7)} [/tex]

[tex]or = \frac{5 + 1} {8 + 7} [/tex]

[tex]or = \frac{6}{15} [/tex]

[tex]or = \frac{2}{5} [/tex]

Step-by-step explanation:

hope it is helpful to you ☺️

Answer:

C

Step-by-step explanation:

Since all the graphs have the same line, you’re just looking for the correct shaded region. Since for both equations you want the shaded region to be less than the line, answer c solves the inequality.

Consider that choice B is the same as saying 2x^2+1x^0.

The exponents 2 and 0 are both even, which is sufficient to say that the entire polynomial function itself is also even.

Something like choice A expands out and simplifies to x^2-2x+2, and that's equivalent to saying x^2+2x^1+2x^0. The presence of the x^1 term, with its odd exponent, is what makes choice A not even (it's not odd either).

Similarly, choices C and D also have exponents of 1, so they aren't even either.

Answer:

G(x)=2x2+1

Step-by-step explanation:

Answer:

Step-by-step explanation:

X P(X=x)

0 0.39*0.39*0.39 = 0.059319

1 3*0.61*0.39*0.39 = 0.278343

2 3*0.61*0.61*0.39 = 0.435357

3 0.61*0.61*0.61 = 0.226981

Answer:

Test statistic = - 2.71

Step-by-step explanation:

Table of the sample data is attached below :

Using a dependent sample t test :

H0 : μd = 0

H0 : μd ≠ 0

The difference in the 6th and 13th date data is :

Difference, d = -4, -6, -3, -1, 1, -7

The sample size, n = 6

The mean of d ; μd = Σd/ n = - 3.667

Standard deviation of difference, Sd = 3.011

The test statistic : μd/(Sd/√n)

Test statistic = - 3.33 / (3.011/√6)

Test statistic = - 3.33 / 1.2292356

Test statistic = - 2.709

Test statistic = - 2.71

Answer:

60 miles

Step-by-step explanation:

Create an equation where y is the total cost and x is the number of miles traveled.

0.8x will represent the cost from the miles traveled. 8.5 will be added to this to represent the taxi cost and additional charge from tolls:

y = 0.8x + 8.5

Plug in 56.50 as y and solve for x, the number of miles:

y = 0.8x + 8.5

56.5 = 0.8x + 8.5

48 = 0.8x

60 = x

So, you can travel 60 miles

Given: The series ∑cₙ[tex]9^n[/tex] is convergent

To find: The series ∑cₙ[tex](-3)^n[/tex] is convergent or not.

Solution: If the radius of convergence R the we can conclude that R≥4

So, the series will converge as -3<9.

Answer:

B. 0.82

C. 077

Step-by-step explanation:

Given

[tex]Number = 0.8[/tex] -- approximated

Required

The possible value of Number

Since [tex]Number = 0.8[/tex] is approximated, then the possible values of Number that  can be gotten from the preparation

The approximated value 0.8 has the following range: 0.75 to 0.84

Options B and C are in this category.

Answer:

2TRN

Let me know if this is wrong!

233115555532224444432

Answer:

Range:

UCL = 4.73

LCL = 18.08

MEAN :

UCL = 27.115

LCL = 31.219

Step-by-step explanation:

Given the data:

The mean and range of each sample :

Sample __ Thread wear __ xbar __ R

1 ___31 __ 42 ___ 28 ____ 33.67 _14

2___ 26 _ 18 ____35____ 26.33 _17

3___25 __30 ___ 34____29.67 _ 9

4 __ 17 __ 25 ___ 21 _____ 21 ___ 8

5 __ 38 _ 29 ___ 35 _____ 34 __ 9

6 __ 41 __42 ___36 _____39.67_ 6

7 __ 21 __ 17 ___29 _____22.33 _12

8 __ 32 __26___28 ____ 28.67 _ 6

9 __ 41 __ 34 __ 33 ______ 36 __8

10__29___17___30 _____25.33_ 13

11 __26 __ 31 __ 40 _____32.33_ 14

12__23 __ 19 __ 45 _____12.33 __6

13 __17 __ 24 __ 32_____24.33__15

14 __43__ 35___17_____ 31.67 _ 26

15__18 ___25__ 29_____ 24 ___ 11

16__30___42___31 ____34.33__ 12

17__28___36 __ 32____ 32 ____8

18__40 __ 29 __ 31 ____33.33 __ 11

19__18 ___29__ 28____ 25 ____11

20_ 22 __ 34 __ 26 ___ 27.33 __12

Size per sample, sample size, n = 3

Number of samples, k = 20

We calculate the sample mean and range average :

Sample mean, x-- = Σxbar/n = 29.167

Range average, Rbar = ΣR/n = 11.4

The mean control limit :

x-- ± A2Rbar

From the x chart ;

A2 for n = 20 is A2 = 0.180

29.167 ± 0.180(11.40)

LCL = 29.167 - 0.180(11.40) = 27.115

UCL = 29.167 + 0.180(11.40) = 31.219

The Range control limit :

Rbar(1 ± 3(d3/d2))

From the R-chart :

d2 at n = 20 ; d2 = 3.735

d3 at n = 20 ; d3 = 0.729

LCL = 11.40(1 - 3(0.729/3.735)) = 4.725

UCL = 11.40(1 + 3(0.729/3.735)) = 18.075

Answer:

It should be a 2 sample t-test for the sample mean mu 1 - mu 2 at alpha = 0.05.

Step-by-step explanation:

To solve, you can just insert the data values into a graphing calculator and it should work. Remember to check the conditions and write out the null and alternate hypotheses.

Null: mu 1 - mu 2 = 0 There is no difference

Alternate: mu 1 - mu 2 =/= 0 There is a difference

Conditions:

-Random sample? Yes b/c assume that it is from a simple random sample.

-10%? Assume that there are more than 120 men and 80 women in the population"

-Normal Distribution? If the data for each respective sample is approx normal, assume they come from a normally distributed population. Large counts and the central limit theorem do not work here.

After this, insert ur data values into the graphing calculator n solve for p.

Once you get p, make a conclusion based on alpha = 0.05. If p is less than alpha, you can reject the null and conclude that you have significant evidence that the alternate is true. If p is greater than alpha, you cannot reject the null and conclude that you do not have significant evidence that the alternate is true.

Answer:

5670272728262728227627

Answer:

b.

Graph B

Step-by-step explanation:

We are given the following linear equation:

[tex]6x = y + 8[/tex]

When x = 0:

[tex]6(0) = y + 8[/tex]

[tex]y = -8[/tex]

Thus, the line goes through (0,-8).

When y = 4:

[tex]6x = y + 8[/tex]

[tex]6x = 4 + 8[/tex]

[tex]6x = 12[/tex]

[tex]x = \frac{12}{6} = 2[/tex]

So also through (2,4).

Thus means that the correct answer is given by Graph B.

Answer:

C

Step-by-step explanation:

Sara's speed is 10mph while Bob is 8mph

Using the areas of the sqaure and of the circle, it is found that the total area that is not reached by the sprinklers is of 343.36 ft².

The area of a square of side length l is given by:

A = l²

In this problem, we have that l = 40 ft, hence:

A = (40 ft)² = 1600 ft².

The area of a circle of radius r is given by:

[tex]A = \pi r^2[/tex]

In this problem, we have four circles of radius r = 10 ft, hence it's combined area, in square feet, is given by:

[tex]A_c = 4\pi (10)^2 = 400\pi = 1256.64 \text{ft}^2[/tex]

The area not reached by the sprinklers is the subtraction of the area of the square by the area of the circle, hence:

1600 - 1256.64 = 343.36 ft².

More can be learned about the area of a rectangle at https://brainly.com/question/10489198

Answer:

I guess the question is incomplete