What is the formula for finding an obtuse angle?

Answer:

Answer:

[tex]8\sqrt{11}[/tex]

Step-by-step explanation:

Given:

[tex]x+\dfrac{1}{x}=\sqrt{11}[/tex]

Sum of two squares

[tex]\boxed{a^2+b^2=(a+b)^2-2ab}[/tex]

[tex]\textsf{Let}\; a = x[/tex]

[tex]\textsf{Let}\; b = \dfrac{1}{x}[/tex]

Therefore:

[tex]\begin{aligned}x^2+\dfrac{1}{x^2}&=\left(x+\dfrac{1}{x}\right)^2-2x\left(\dfrac{1}{x}\right)\\\\&=\left(\sqrt{11}\right)^2-2\\\\&=11-2\\\\&=9\end{aligned}[/tex]

Sum of two cubes

[tex]\boxed{a^3+b^3=(a+b)(a^2-ab+b^2)}[/tex]

[tex]\textsf{Let}\; a = x[/tex]

[tex]\textsf{Let}\; b = \dfrac{1}{x}[/tex]

Therefore:

[tex]\begin{aligned}x^3+\dfrac{1}{x^3}&=\left(x+\dfrac{1}{x}\right)\left(x^2-x\left(\dfrac{1}{x}\right)+\left(\dfrac{1}{x}\right)^2\right)\\\\ &=\left(x+\dfrac{1}{x}\right)\left(x^2-1+\dfrac{1}{x^2}\right)\\\\&=\left(x+\dfrac{1}{x}\right)\left(x^2+\dfrac{1}{x^2}-1\right)\\\\&=\sqrt{11}\left(9-1\right)\\\\&=8\sqrt{11}\end{aligned}[/tex]

Charmaine sends 34 message, Jose send 75 texts and Shen send 25 messages.

What is linear equation?

An equation is a mathematical statement, which has an equal sign (=) between the algebraic expression. Linear equations are the equations of degree 1. It is the equation for the straight line.

Let C be charmaine text, S be shen text, J be jose text.

C +J+ S=134

Shen send 9 messages fewer than charmine .

S = C -9

C = S+9

And Jose sent 3 times more then shen

J =3S

We get,

S+9+3S+S=134

5S +9 = 134

5S = 134 -9

5S = 125

S = 25

C = 25 +9

= 34

J= 75

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Answer:

A

Step-by-step explanation:

Fill in X and Y for each of the equations until you find one that fits

The equation of the line y=2x+3 passes through the (1,4) point only.
The line gave y=2x+3.

In order to check whether the line passes through the points the following steps are:

A) (1,4)

Here x=1 , y=4.

We will put these values in the line y=2x+3.

4= 2(1)+3

4=4
As L.H.S=R.H.S, therefore this point (1,4) passes through the line.

B) (-1,4)

Here x=-1 , y=4.

We will put these values in the line y=2x+3.

4= 2(-1)+3

4= -2+3
4 [tex]\neq[/tex] 1
As L.H.S  [tex]\neq[/tex]R.H.S, therefore this point (1,4) does not pass through the line.

C) (2,3)

Here x=2 , y=3.

We will put these values in the line y=2x+3.

3= 2(2)+3

3= 4+3
3 [tex]\neq[/tex] 7
As L.H.S  [tex]\neq[/tex]R.H.S, therefore this point (2,3) does not pass through the line.

D) (3,2)

Here x=3 , y=2.

We will put these values in the line y=2x+3.

2= 2(3)+3

2= 6+3
2 [tex]\neq[/tex] 9
As L.H.S  [tex]\neq[/tex]R.H.S, therefore this point (3,2) does not pass through the line.

Only (1,4) point passes through the line.

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The area of this rectangular walk is 390[tex]ft^{2}[/tex]

A rectangle is a closed two-dimensional figure with four sides. The opposite sides of a rectangle are equal and parallel to each other and all the angles of a rectangle are equal to 90°.

The width of the walk is constant and is 2ft, length of the walk is determined by the part of the rectangular yard.

Area of walk = 3 x 27 +3x27 + 3 x 38 + 3 x 38 which is 390[tex]ft^{2}[/tex]

In conclusion the area of the walk is 390[tex]ft^{2}[/tex]

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Answer:

4

Step-by-step explanation:

3(-5x-5) + 19x = _x - 15

-15x-15+19x = _x - 15

4x - 15 = _x - 15

It has to be the same on both sides so 4 would go in that blank.

Answer: 4

Step-by-step explanation:

Assuming [tex]\overline{BC}[/tex] is a diameter, minor arc [tex]AB[/tex] has a measure of [tex]180^{\circ}-108^{\circ}=72^{\circ}[/tex].

Using the inscribed angle theorem, [tex]36=x+3 \implies x=\boxed{33}[/tex].

Answer:

43x+3x+17y

Step-by-step explanation:

because 43x+17y+3x=43x+17y+3x

Answer:

$23.55

Step-by-step explanation:

First we will need to determine the total amount of sales Ryan and Carlos made. To do that we will multiply the amount of products sold by the product cost.

$2.75 x 12 = $33

Now we need to deduct the cost of supplies they need to pay back from their profits.

$33- $9.45= $23.55

Now we are left with Ryan and Carlos' total profit, which is $23.55

Question 1

Since the x-coordinates are the same, the line is vertical. Therefore, the slope is undefined.

Question 2

Since the y-coordinates are the same, the line is horizontal. Therefore, the slope is zero.

The linear equation with a slope of 1/2 and that passes through the point (1, -2) is written in point-slope form as:

y = (1/2)*(x - 1) - 2

For a linear equation with a slope m and a known point (h, k), the slope-point form is written as:

y = m*(x - h) + k

Where y and x are the two variables.

Here we know that the slope is 1/2, and the known point is (1, -2), then the values on the equation above are:

m = 1/2

h = 1

k = -2

Replacing that in the general formula for the linear equation in the slope-point form that is written above, we will get:

y = (1/2)*(x - 1) - 2

That is what we wanted to find.

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The value of the expression 1+1+q+q++1+1+1 is 5 + 2q.

Expression simply refers to the mathematical statements which have at least two terms which are related by an operator and contain either numbers, variables, or both. Addition, subtraction, multiplication, and division are all possible mathematical operations.

As an illustration, the expression x + y has the terms x and y with an addition operator between them.

The expression will be:

= 1+1+q+q++1+1+1

= 5 + 2q

The value is 5 + 2q.

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Answer:

5+2q

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

7/2 / 1/4

7/2 * 4/1

7/1 * 2/1

7*2 = 14

Answer: 14

Step-by-step explanation:

   To answer this question, we will divide.

(3 ½) / (¼)

   "Keep, change, and flip:"

(3 ½) * (4)

   Multiply the two values together:

14

Answer:

Step-by-step explanation:

x = 32

x - 10 = 22

add 10 to both sides of the equation

-10 + 10 = 0

22+ 10 = 32

x = 32

Answer:

5, 4, 7

Step-by-step explanation:

Answer: false

Step-by-step explanation:

if the expected grade was 100 but passing was 80 then she couldn't have passes with a 48

The graph of the inequality is plotted using the below points.

Graph:

In math, graph show you information as a visual image or picture.

Given,

Here we need to find the graph of the given inequality.

To graph an inequality:

To graph the related boundary line. We have to replace the <, >, ≤ or ≥ sign in the inequality with = to find the equation of the boundary line.

Now, we have to identify at least one ordered pair on either side of the boundary line and substitute those (x, y) values into the inequality.

Then shade the region that contains the ordered pairs that make the inequality a true statement.

Here if points on the boundary line are solutions, then use a solid line for drawing the boundary line. This will happen for ≤ or ≥ inequalities.

Where as if points on the boundary line are not solutions, then use a dotted line for the boundary line. This will happen for < or > inequalities.

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The total number of pounds of avocados Jenna bought is B. 2

A linear equation is an algebraic equation of degree one. In general, the variable or the variables(in the case of a linear equation in two variables) the variables are x and y.

Assuming Jenna bought x pounds of apples and y pounds of avocados.

Altogether she bought 7 pounds of apples and avocados.

∴ x + y = 7...(i)

Altogether, she spent $14. 25.

∴ 1.25x + 4y = 14.25...(ii)

Now multiplying eqn(i) by 1.25 and subtracting from eqn(ii) to cancel out the variable x, we get

2.75y = 5.5.

y = 2 pounds of avocados and hence 5 pounds of apples.

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Using the rate, the number of book Mason reads per month is 2 books.

Mason read 4 books in 2 months. Mason reads at a constant rate. The number of books he reads each month can be calculated as follows;

The number of books he reads is at a constant rate. The rate formula can be used to find the number of book Mason read each month.

rate = number of books read / number of month

Therefore,

number of books read = 4 books

number of month = 2 month

Hence,

rate  = 4 / 2

rate = 2 books per month

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Using the par value method, the journal entry to record the treasury stock transaction is as follows:

Debit Treasury Stock $2,350

Debit Paid-in Capital in Excess of Par Value $1,880

Credit Cash $4,230

Treasury stock transactions can be recorded using the cost or the par value methods.

When the cost method is used, the Treasury Stock account is debited or credited with the cost (cash price paid or received).

When the par value method is used, the difference between the cash price or cost and the par value is recorded in the Paid-in Capital in Excess of the Par Value account.

The Treasury Stock account is then credited or debited with the par value.

Treasury Stock $2,350 (470 x $5) Paid-in Capital in Excess of Par Value $1,880 (470 x $9 - $5) Cash $4,230 (470 x $9)

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Journalize the treasury stock transaction using the par value method.

Answer: 4/3

Step-by-step explanation:

The reciprocal of a/b is b/a.

Answer:

find p (A or ),given that A and B are independent

After division, 0.75 is 3/4 as a division problem.

In the given question we have to find what is 3/4 as a division problem.

The given division problem is 3/4.

With the help of the division formula Dividend = (Divisor Quotient) + Remainder, we can confirm the quotient and the remainder of the division. If the remaining is 0, we can multiply our quotient by the divisor to see if it is accurate. The quotient is accurate if the product equals the dividend.

To solve this division problem we divide 3 by 4. The answer should come in the decimal form because 3 is less than 4. So we take decimal to solve this.

Now the solution of the given division problem is:

3/4 = 0.75

Hence, 0.75 is 3/4 as a division problem.

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The linear equations that represent the relationships in the question order are;

A linear equation is an equation of the form; y = m·x + c

The slope of the line is found as follows;

(-5 - (-21))/(-1 - (-5)) = 4

The equation is y - (-5) = 4·(x - (-1)) = 4·x + 4

y = 4·x + 4 - 5 = 4·x - 1

The y-intercept is (0, 4), the x-intercept is (4, 0)

The slope is therefore; (0 - 4)/(4 - 0) = -1

The equation is therefore; y - 0 = -1 × (x - 4) = -x + 4

The y-intercept is (0, -1), the x-intercept is (4, 0)

The slope is therefore; (0 - (-1))/(4 - 0) = 1/4

The equation is therefore; y - 0 = (1/4) × (x - 4) = x/4 - 4/4 =

The slope of the line is; [tex]\dfrac{-3\frac{3}{4} - \left(-\frac{3}{4}\right) }{4-1} = -1[/tex]

y - (-3/4) = -1 × (x - 1) = -x + 1

y = -x + 1 - (3/4) = -x + 1/4

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Answer:

100 times square times Y 49 gives= 14000

The comparison of the terms are:

From the question, we have the following equation:

-4x + 11 = -10x + 17

The variable terms are terms that have the variable x represented

In this case, the variable terms are

Left-hand side = -4x

Right-hand side = -10x

When -4x and -10 are compared, we can conclude that

-4x is greater than -10x

From the question, we have the following equation:

-4x + 11 = -10x + 17

The constant terms are terms that do not have the variable x represented

In this case, the constant terms are

Left-hand side = 11

Right-hand side = 17

When 11 and 17 are compared, we can conclude that

11 is less than 17

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Answer:

undefined

Step-by-step explanation:

The square root of any negative number is undefined because there is no possible solution. - × - = + and + × + = +

The domain and range of this square root function are: D: [–4, ∞) and R: [0, ∞).

In Mathematics, a domain can be defined as the set of all real numbers for which a particular function or relation is defined. This ultimately implies that, a domain is the set of all possible input values (x-values) for a function while a range is the set of all possible output values (y-values) of a function.

Based on the information provided, the function is represented as follows:

g(x) = √(x + 4)

Since a square root function doesn't exist for all negative values, the domain of this function is given by:

x + 4 ≥ 0

x ≥ -4

Domain = [-4, ∞]

Since we do not have a vertical translation, the range of this square root function is given by:

x ≥ 0

Range = [0, ∞]

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Answer:

[–4, ∞) and R: [0, ∞)

Step-by-step explanation:

I got it right on the test.

Answer:

2 1/4 kg

Step-by-step explanation:

The test that Joan can use to determine if husbands earn more is the t test.

A t test is a statistical test used to compare two groups' means. It is frequently used in hypothesis testing to determine whether a process or treatment has an effect on the population of interest, or whether two groups differ. A t-test is an inferential statistic that is used to determine whether or not there is a significant difference in the means of two groups and how they are related.

The Independent Samples t Test compares the means of two independent groups to see if there is statistical evidence that the associated population means differ significantly. This can be utilized by Joan.

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