what is the friction​

This is convex lens .

hence It's a converging lens .

The picture shown is a type of converging lens. The correct option is A.

A converging lens, also known as a convex lens, is a type of optical lens that is thicker in the middle than at the edges. It is shaped like a curved-outward disc and is commonly used in optical systems such as cameras, telescopes, and microscopes. When light passes through a converging lens, it bends inward and converges at a focal point located on the other side of the lens.

This focal point is determined by the curvature of the lens and its refractive index, which affects how much the light is bent. The distance between the lens and the focal point is called the focal length, and it determines the magnification and the image size produced by the lens. Converging lenses are used in many applications that require focusing and magnifying light, such as correcting vision problems and creating images in photography and microscopy.

Therefore, The correct answer is converging lens.

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Answer:

becaude of electricity

Answer:

The correct answer is "22.27 hours".

Explanation:

Given that:

Radioactive isotope activity,

= 490,000 Bq

Activity,

= 110,000 Bq

Time,

= 48 hours

As we know,

⇒ [tex]A = A_0 e^{- \lambda t}[/tex]

or,

⇒ [tex]\frac{A}{A_0}=e^{-\lambda t}[/tex]

By taking "ln", we get

⇒ [tex]ln \frac{A}{A_0}=- \lambda t[/tex]

By substituting the values, we get

⇒ [tex]-ln \frac{110000}{490000} = -48 \lambda[/tex]

⇒    [tex]-1.4939=-48 \lambda[/tex]

                 [tex]\lambda = 0.031122[/tex]

As,

⇒ [tex]\lambda = \frac{ln_2}{\frac{T}{2} }[/tex]

then,

⇒ [tex]\frac{ln_2}{T_ \frac{1}{2} } =0.031122[/tex]

⇒ [tex]T_\frac{1}{2}=\frac{ln_2}{0.031122}[/tex]

         [tex]=22.27 \ hours[/tex]  

Answer:

HOPE IT HELPS YOU!!!

Explanation:

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Answer:

A complete third electron shell holds 8 electrons

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hope it helps...

have a great day!!

Answer:

8

Explanation:

Answer:

   v = 4.1 m / s

Explanation:

Velocity is defined by the relation

          v =[tex]\frac{dx}{dt}[/tex]

 we perform the derivative

         v = 4.1 m / s

Another way to find this magnitude is to see that the velocity on the slope of a graph of h vs t

        v = [tex]\frac{\Delta x}{\Delta t}[/tex]

        Δx = v Δdt + x₀

        h=   4.1 t + 5.5

         v = 4.1 m / s

         x₀ = 5.5 m

Answer:

The coefficient of friction between the cars and the road is 0.859.

Explanation:

The two cars collide each other inelastically, then we can determine the resulting velocity by the Principle of Momentum Conservation:

[tex]m_{A}\cdot v_{A} + m_{B}\cdot v_{B} = (m_{A} + m_{B})\cdot v[/tex] (1)

Where:

[tex]m_{A}[/tex], [tex]m_{B}[/tex] - Masses of the cars, in kilograms.

[tex]v_{A}[/tex], [tex]v_{B}[/tex] - Initial velocities of the cars, in meters per second.

[tex]v[/tex] - Velocity of the resulting system, in meters per second.

If we know that [tex]m_{A} = 2120\,kg[/tex], [tex]v_{A} = 13.4\,\frac{m}{s }[/tex], [tex]m_{B} = 2810\,kg[/tex] and [tex]v_{B} = 0\,\frac{m}{s}[/tex], then the  velocity of the resulting system:

[tex]v = \frac{m_{A}\cdot v_{A}+m_{B}\cdot v_{B}}{m_{A}+m_{B}}[/tex]

[tex]v = \frac{(2120\,kg)\cdot \left(13.4\,\frac{m}{s} \right)+(2810\,kg)\cdot \left(0\,\frac{m}{s} \right)}{2120\,kg + 2810\,kg}[/tex]

[tex]v = 5.762\,\frac{m}{s}[/tex]

By Principle of Energy Conservation and Work-Energy Theorem, we understand that the initial translational kinetic energy ([tex]K[/tex]), in joules, is dissipated due to work done by friction ([tex]W_{f}[/tex]), in joules, that is to say:

[tex]K = W_{f}[/tex] (2)

[tex]\frac{1}{2}\cdot (m_{A}+m_{B})\cdot v^{2} = \mu\cdot (m_{A}+m_{B})\cdot g \cdot s[/tex]

[tex]\frac{1}{2}\cdot v^{2} = \mu \cdot g\cdot s[/tex] (2b)

Where:

[tex]\mu[/tex] - Coefficient of friction, no unit.

[tex]g[/tex] - Gravitational acceleration, in meters per square second.

[tex]s[/tex]- Travelled distance, in meters.

If we know that [tex]v = 5.762\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]s = 1.97\,m[/tex], then the coefficient of friction is:

[tex]\mu = \frac{v^{2}}{2\cdot g\cdot s}[/tex]

[tex]\mu = \frac{\left(5.762\,\frac{m}{s} \right)^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (1.97\,m)}[/tex]

[tex]\mu = 0.859[/tex]

The coefficient of friction between the cars and the road is 0.859.

Answer:

id

Explanation:

i don't know

The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.

Initial speed of the rock, u = 40m/s

Final position of the rock s = 0m taking the release point as reference. The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.

Nuclear energy is a useful source of power but has disadvantages. The disadvantage of nuclear energy is it produces dangerous waste.

Initial speed of the rock, u = 40m/s

Final position of the rock s = 0m taking the release point as reference

From the second equation of motion:

solving above we get:

t = 0s or t = 8.16s,  t =0  seconds is neglected since it represents the initial position which is the same as the final position at t = 8.16s

So, the rock takes 8.16 seconds to return to the release point.

Therefore, The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.

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Answer:

(4) 50 ohms (5) 11.76 ohms

Explanation:

In the parallel combination, the equivalent resistance is given by :

[tex]\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+....[/tex]

4. When three 150 ohms resistors are connected in parallel, the equivalent is given by :

[tex]\dfrac{1}{R}=\dfrac{1}{150}+\dfrac{1}{150}+\dfrac{1}{150}\\\\R=50\ \Omega[/tex]

5. Three resistors of 20 ohms, 40 ohms and 100 ohms are connected in parallel, So,

[tex]\dfrac{1}{R}=\dfrac{1}{20}+\dfrac{1}{40}+\dfrac{1}{100}\\\\=11.76\ \Omega[/tex]

Hence, this is the required solution.

Answer:

. You want your product to be as strong and as long lasting as possible. There are also the safety implications to consider. You see, dangerous failures arising from poor material selection are still an all too common occurrence in many industries. yep that the answer have a Great day

Explanation:

(◕ᴗ◕✿)

Answer:If an object's speed changes, or if it changes the direction it's moving in,

then there must be forces acting on it. There is no other way for any of

these things to happen.

Once in a while, there may be a group of forces (two or more) acting on

an object, and the group of forces may turn out to be "balanced".  When

that happens, the object's speed will remain constant, and ... if the speed

is not zero ... it will continue moving in a straight line.  In that case, it's not

possible to tell by looking at it whether there are any forces acting on it

Answer:

Explanation:

Use the equation

[tex]v^2=v_0^2+2a[/tex]Δx

In this dimension (the y dimension...the only one we have to care about for this problem), here's what we know:

a = -32 ft/s/s

v₀ = 0 m/s (since someone was holding the stone still before it was dropped)

v = 136 ft/s

Δx = ??

Filling in:

[tex]136^2=0^2+2(-32)[/tex]Δx so

Δx = [tex]\frac{136^2}{2(-32)}[/tex] so

Δx = -289 feet (negative because the stone dropped that many feet below the point from which it was dropped, but you would answer a height question with the positive of this number. If you were asked how far the stone dropped, it would be negative; if you're asked how tall the cliff is, that would be positive)

Answer:

Since resistance is proportional to length   R = K L / A

the resistance of each piece would be R / 10 = 10 ohms

A copper wire is the conductor wire. If the wire is cut into 10 equal lengths,  the resistance of each piece will be 10 ohms.

Resistance is the opposition to the flow of electrons in the conductor wire.

Given is the total resistance of the wire is 100 ohms.

Resistance is directly proportional to the length of the wire.  When the wire is cut into 10 pieces, the new resistance will be

[tex]\dfrac{R}{10} =\dfrac{100}{10} =10 \:\rm ohms[/tex]

Hence, the resistance of each piece will be 10 ohms.

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Answer:

2.8 seconds

Explanation: Given that a simple pendulum that consists of a massless 2.00-meter length of rope attached to a 5.00-kg mass at one end. What is the period of oscillation for this simple pendulum

The parameters given are :

Length = 2 m

Mass = 5kg

Using the formula below

T = 2 pi × sqrt ( L / g )

Substitute all the parameters into the formula.

T = 2 × 3.143 × sqrt ( 2 / 9.8 )

T = 2 × 3.143 × 0.4517

T = 2.838 s

Therefore, the period of oscillation for this simple pendulum is 2.8 s approximately.

Answer:

44.72m/s

Explanation:

use th formula:vf²=vi²at

and then substitute the values

remember the units

If there is no air resistance, the speed of the free falling object from the same height will be the same. Therefore, the ratio of speed of the stone to that of rock for 2 seconds falling will be 1 : 1.

An object freely falling under the force of gravitation is called the free falling body. Here, the acceleration of the object is the acceleration due to gravity.

For a freely falling body, the velocity v = g t

where g is the acceleration due to gravity and for earth g is 9.8 m/s².

Everybody falls with the same rate freely under the acceleration due to gravity if there is no air resistance at all.

Here, the time t = 2 s

then v = 9.8 m/s² × 2 s = 19.6 m/s.

the speed of both the rock and stone will be 19.6 m/s in the absence of air resistance. Hence, the ratio of their speed is 1 : 1.

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Answer:

Send a clear photo again

Explanation:

And tag me

Explanation:

the answer is in the image above

Answer:

the voltage will be the same across all resistors

Explanation:

the total voltage supplied to the circuit will remain the same across all resistors

Answer:

The linear mass density of rope is 0.16 kg/m.

Explanation:

mass, m = 0.52 kg

force, F = 47 N

length, L = 3.3 m

(a) The linear mass density of the rope is defined as the mass of the rope per unit length.

Linear mass density = m/L = 0.52/3.3 = 0.16 kg/m

Answer:

d. In dc steady state conditions, the voltages across the capacitors are constant and the currents through the capacitance are zero. The current through the inductors are constant and the voltage across the inductances are zero.

Explanation:

The current through a capacitor is given by i = CdV/dt where C = capacitance of capacitor and V = voltage across capacitor. At steady state dV/dt = 0 and V = constant. So, i = CdV/dt = C × 0 = 0.

So, in dc steady state, the voltage across a capacitor is constant and the current zero.

The voltage across an inductor is given by V = Ldi/dt where L = inductance of inductor and i = current through inductor. At steady state di/dt = 0 and V = constant. So, V = Ldi/dt = L × 0 = 0.

So, in dc steady state, the voltage across an inductor is zero and the current constant.

So, In dc steady state conditions, the voltages across the capacitors are constant and the currents through the capacitance are zero. The current through the inductors are constant and the voltage across the inductances are zero.

The answer is d.

Answer: the iris

Explanation: I looked it up

Answer:

Iris

Explanation:

Because (iris) has muscles that can expand/contract depends to the amount of light that pupil needs to process/figure out images.

Answer:

Ray A = Incidence ray

Ray B = Reflected ray

Explanation:

From the law of reflection,

Normal: This is the line that makes an angle of 90° with the reflecting surface.

Ray A is the incidence ray: This is the ray that srikes the surface of a reflecting surface. The angle formed between the normal and the incidence ray is called the incidence angle

Ray B is the reflected ray: This is the ray leaves the surface of a reflecting surface. The angle formed between the reflected ray and the normal is called reflected angle

Answer:

The rate of the dump truck is 650 [tex]\frac{lb}{s}[/tex]

Explanation:

A large dump truck can move 1,170 tons/h of gravel from one point to another on a work site.

To convert the units from tons/h to lb/s, you should know that:

To carry out the unit conversion you must perform the following steps:

[tex]1170 \frac{ton}{h}*\frac{2000 lb}{1 ton} *\frac{1 h}{3600 s}[/tex]

Solving:

[tex]1170 \frac{ton}{h}*=650 \frac{lb}{s}[/tex]

So, the rate of the dump truck is 650 [tex]\frac{lb}{s}[/tex]

Answer:

speed=to distance ÷time , thank me later

Answer:

33 mph

Explanation:

My best guess

Answer:

Hmmm...

This is a bit tricky

Ok...

Negative Velocity means you're Moving in the Opposite direction....

Negative Acceleration (deceleration) means you're slowing down.

Deceleration would mean slowing down if you were Moving with a Positive velocity.

But In this case...

You're Moving with negative velocity and Negative acceleration...

This simply means that the acceleration and velocity vector are in the same direction....

Its means that...

"YOU'RE SPEEDING UP"

Just that you're doing it in the opposite direction.

Hope this helps.

Answer:

to focus the link light

Explanation:

Because the lens is flexible and elastic, it can change its curved shape to focus on objects and people that are either nearby or at a distance. ... The ciliary muscles, which are part of the ciliary body, are attached to the lens and contract or release to change the lens shape and curvature.

Answer:

to focus the link light

Explanation:

vote brainliest I never got voted brainliest plssss

Answer: D

The force decreases inversely proportional to 1/r(squared)

Explanation:

I looked it up im sure this is correct

Answer:

option d

Explanation:

Two objects are attracted to each other by a gravitational force F. ... As the distance r from the center of the planet increases, what happens to the force of gravity on the rocket? The force decreases inversely proportional to 1/r(squared) A spacecraft is orbiting Earth with an orbital radius r.

the force of gravity is represented as

F = GM1M2/r²

now the mass of warth and rocket is considered to be constant and G is a universal constant so it can be said

F is inverse to r²

therefore as the value of r increases that is distance between earth and rocket increases the force decreases

(Follows inverse square law)