What is the length of the hypotenuse of the right angle triangle, keep your answer to 1 decimal place a is 9cm and b is 13cm

Given:

The area of rectangular garden is [tex]x^2-4x-21[/tex] square units.

To find:

The length and width of the cucumber field.

Solution:

The area of a rectangle is:

[tex]A=l\times w[/tex]

Where l is length and w is width of the rectangle.

The area of rectangular garden is [tex]x^2-4x-21[/tex] square units.

We need to find the factors of [tex]x^2-4x-21[/tex] to get the length and width.

[tex]A=x^2-4x-21[/tex]

Splitting the middle term, we get

[tex]A=x^2-7x+3x-21[/tex]

[tex]A=x(x-7)+3(x-7)[/tex]

[tex]A=(x-7)(x+3)[/tex]

Area of a rectangle is the product of length and width.

Therefore, the length and width of the rectangle are [tex](x-7)[/tex] units and [tex](x+3)[/tex] units.

Answer:

Step-by-step explanation:

The first line has slope of a/b and the second one has slope of m/n.

As an ≠ bm ⇒ a.b ≠ m/n, the slopes are different.

Since the slopes are different the lines are not parallel, hence they intersect at one point.

This means there is one solution only.

ax + by = c and mx + ny = d and an # bm then these simultaneous equations have Only one common solution.

[tex]\sf{ }[/tex] [tex]\sf{ }[/tex]

Step-by-step explanation:

[tex]here \: is \: your \: solution : - \\ \\ GIVEN \: \: -:- \\ \\ = > \: area \: of \: circle \: = 616 \: m {}^{2} \\ \\ \ = > pi = 22 \div 7 \\ \\ = > we \: need \: to \: find \: radius \: \\ \\ = > area \: of \: circle \: = \pi \: r {}^{2} \\ \\ = > \: \pi \: r {}^{2} = 616 \: m {}^{2} \\ \\ = > \: r {}^{2} \times (22 \div 7) = 616 \\ \\ = > \: r {}^{2} =( 616 \times 7) \div 22 \\ \\ = > \: r { }^{2} = 4312 \div 22 \\ \\ = > r {}^{2} = 196 \\ \\ = > \: r = \sqrt{196} \\ \\ = > \: r = 14 \: \: \: (ANSWER✓✓✓) \\ \\ HOPE \: IT \: HELPS \: YOU \: (◕ᴗ◕✿)[/tex]

Answer:

12

Step-by-step explanation:

First substitute the equation with the variable replacements given:

-r/9 + 5x <--- Before

-27/9 + 5(3) <--- After

Next Solve the parts of the Equation

-27/9 + 5(3)

-3 + 15 <--- -27 divided by 9 is -3, 5 times 3 is 15.

= 12 <--- 15 - 3 = 12.

I hope this helps!

Answer:

12

Step-by-step explanation:

[tex]-\frac{27}{9}+5(3)[/tex]

- 3 + 15

15 - 3

12

Answer:

5

Step-by-step explanation:

You divide the change in the output value by the change in the input value.

  Input: 0 |  4

Output: 1  |  21

20/4= 5

[tex]\displaystyle\bf 2^{2x+1}-9\cdot 2^x+4=0 \quad ; \qquad \boxed{ 2^x=t \; ; \; 2^{2x}=t^2} \\\\2t^2-9t+4=0 \\\\D=81-32 =49 \\\\ t_1=\frac{9+7}{4} =4 \\\\ t_2=\frac{9-7}{4} =\frac{1}{2} \\\\1) \ 2^x=4 \Longrightarrow x_1=2 \qquad 2) \ 2^x=2^{-1}\Longrightarrow x_2=-1 \\\\Answer: \boxed{x_1=2 \quad ; \quad x_2=-1}[/tex]

Answer:

The length of the lights is 2088 inches

Step-by-step explanation:

The question is mixed up with another (See comment for correct question)

Given

[tex]Length = 799in[/tex]

[tex]Width = 245in[/tex]

Required

The perimeter of the deck (this is what the question implies)

The perimeter (P) is:

[tex]P = 2 * (Length + Width)[/tex]

[tex]P = 2 * (799 + 245)[/tex]

[tex]P = 2 * 1044[/tex]

[tex]P = 2088[/tex]

Answer:

3.5

Step-by-step explanation:

Tn=a(n-1)d

Tn=3.5+(101-1)0

Tn=3.5+0

Tn=3.5

Answer:

The picture of file

Step-by-step explanation:

Your'e welcome

f ( - 2 ) = 5 × 3^( - 2 )

f ( - 2 ) = 5 × 1/9

f ( - 2 ) = 5/9

=====================================================

Explanation:

x = original amount of caster oil (in quarts)

Since 15% remains, this means you used 85% of the original amount x.

Note how 15% + 85% = 100%

So,

85% of x = 34 quarts

0.85x = 34

x = 34/0.85

x = 40

You started with 40 quarts of oil.

15% of that remains, meaning 0.15*40 = 6 quarts of oil are left over.

-----------

We could also solve like this

(amount used)/(amount total) = (percent)/(100)

34/x = 85/100

34*100 = x*85

3400 = 85x

85x = 3400

x = 3400/85

x = 40

So we end up with the same x value as before, and we follow the same set of steps at the end of the first section to end up with the answer of 6 quarts.

Translate How is mathematical thinking established? How can we have mathematical thinking? in to Chinese.

数学思维是如何建立的？ 怎样才能有数学思维？

Answer:

a. 18

Step-by-step explanation:

AB+BC = AC

x + x = 36

2x = 36

x = 36/2

x = 18

Answer:

None of both

Step-by-step explanation:

It say y = lxl

so it mean if y = 3 so x = 3 or -3

Answer:

the answer is 2035.75 cm³

Step-by-step explanation:

comment if you want explanation

Answer:

Maximum at (-5, 3)

Step-by-step explanation:

The quadratic equation is in vertex form, which specifically shows the vertex.

Since the a is negative, you get a maximum y value of 3.

Vertex form: y=a(x-h)^2+k

Answer:

50

Step-by-step explanation:

Arc AT the center = angle at the center = 50

Answer:

M= 6, -1

Step-by-step explanation:

Factoring these numbers, it will result in (m-6)(m+1). So, m= 6,-1

Answer:

cant download send ss

Step-by-step explanation:

Answer:

hundredth

Step-by-step explanation:

numbers after the decimal point start counting from

tenth

hundredth

Answer:

0.07 or 7 hundredths

Step-by-step explanation:

(12.3456)- I'll use this as my example

1-tens place

2-ones place

3- tenths place

4= hundredths place

5-thousandths place

6- im pretty sure its the 10 thousandths place

Answer:

I dont think i dont know this but its 10?

Answer:

X would be 63.9

Hope it helps

Step-by-step explanation:

The value of the variable 'x' using the cosine formula will be 63.9 units.

It's a form of a triangle with one 90-degree angle that follows Pythagoras' theorem and can be solved using the trigonometry function.

Trigonometric functions examine the interaction between the dimensions and angles of a triangular form.

The value of 'x' is given by the cosine of the angle ∠QSR. And the cosine of an angle is the ratio of the base and hypotenuse of the right-angle triangle. Then we have

cos 35° = x / 78

x = 63.9

The value of the variable 'x' using the cosine formula will be 63.9 units.

More about the right-angle triangle link is given below.

https://brainly.com/question/3770177

#SPJ7

Answer:

(12, 2 )

Step-by-step explanation:

Given (x, y ) on the graph of f(x) , then on the inverse function

(x, y ) → (y, x ), then

(2, 12 ) → (12, 2 ) ← point on g(x) the inverse function

Answer:

Step-by-step explanation:

recall that the inside angles of a triangle add up to 180°

and also that the angle 115° is the other part of a 180° total

180=115+y

180-115 =65

then the inside angle at Y  is 65°

add the three inside (interior of the triangle) angles up

180= 65 + (4k+5) + (6k+10)

180 = 65 + 10k + 15

180 = 80 + 10k

100  = 10k

10 = k

see how I did that?  

Answer:

1. 3rd option

2. 4th option

3. 1st option

4. 2nd option

5. 2nd option

Step-by-step explanation:

1.

on changing the signs of an equality the sign gets reveresd

-6 < -2x

6 > 2x

3 > x

2.

2x - 3 > 11 - 5x

(2x + 5x) + (-3 + 3) > (11 + 3) + (-5x + 5x)

7x > 14

x > 2

put of all the options x = 4 is a value greater than 2 thus satisfying the condition.

3.

6k + 10. 5 = 3k + 12

(6k - 3k) + (10.5 - 10.5) = (3k - 3k) + (12 - 10.5)

3k = 1.5

k = 0.5

4.

y + 3 = -y + 9

(y + y) + (3 - 3) = (-y + y) + (9 - 3)

2y = 6

y = 3

5.

-9x + 1 = -x + 17

adding x and subtracting 1 from both sides

(-9x + x) + (1 -1) = (-x +x) + (17 -1)

-8x = 16

multiplying the equation by -1

8x = -16

diving both sides by 8

x = -2

Answer:

[tex]1. \: \: x < 3[/tex]

[tex]2. \: \: 2[/tex]

[tex]3. \: \: k = 0.5[/tex]

[tex]4. \: \: y = 3[/tex]

[tex]5. \: \: x = 12[/tex]

Step-by-step explanation:

[tex]1. \: \: - 2(5 - 4x) < 6x - 4 \\ - 10 + 8x < 6x - 4 \\ - 10 + 2x < - 4 \\ 2x < 6 \\ x < 3[/tex]

[tex]2. \: \: 2x - 3 > 11 - 5x \\ 7x - 3 > 11 \\ 7x > 14 \\ x = 2[/tex]

[tex]3. \: \: 6k + 10.5 = 3k + 12 \\ 3k + 10.5 = 12 \\ 3k = 1.5 \\ k = 0.5[/tex]

[tex]4. \: \: y + 3 = - y + 9 \\ 2y + 3 = 9 \\ 2y = 6 \\ y = 3[/tex]

[tex]5. \: \: - 9x + 1 = - x + 17 \\ - 8x + 1 = 17 \\ - 8x = 16 \\ x = - 2[/tex]

Answer:

[tex]2y^2-7y+6=0[/tex]

Step-by-step explanation:

We are given that [tex]\alpha[/tex] and [tex]\beta[/tex] are the zeroes of the polynomial [tex]6y^2-7y+2[/tex]

[tex]y^2-\frac{7}{6}y+\frac{1}{3}[/tex]

We have to find a quadratic polynomial whose zeroes are [tex]1/\alpha[/tex] and [tex]1/\beta[/tex].

General quadratic equation

[tex]x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes[/tex]

We get

[tex]\alpha+\beta=\frac{7}{6}[/tex]

[tex]\alpha \beta=\frac{1}{3}[/tex]

[tex]\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}[/tex]

[tex]\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}[/tex]

[tex]\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2[/tex]

[tex]\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}[/tex]

[tex]\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3[/tex]

Substitute the values

[tex]y^2-(7/2)y+3=0[/tex]

[tex]2y^2-7y+6=0[/tex]

Hence, the quadratic polynomial whose zeroes are [tex]1/\alpha[/tex] and [tex]1/\beta[/tex] is given by

[tex]2y^2-7y+6=0[/tex]