what is the mass of 2.31 x 10^23 formula units of SrF2?

Answer:

144.12873

Explanation:

Hope this helps you

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回答：

144.12873

説明：

これがお役に立てば幸いです

Answer:

96gm/mole

Explanation:

(NH 4)2CO 3 =2×18+12+3×16=96gm/mole

Answer:

1st Diagram (at the left) → Mid-Atlantic Ridge

2nd Diagram (at the right) → Andes Mountains

3rd Diagram (below) → San Andreas Fault

Explanation:

I have been able to label the diagram with the correct information.

The 1st diagram at the left is the Mid-Atlantic Ridge. This is a divergent plate boundary that is found at the floor of the Atlantic Ocean. It is also seen as part of the mountain range in the world. The Mid-Atlantic Ridge also includes a deep rift valley. This rift valley runs along the axis of the ridge. This is along nearly its entire length.

The Andes Mountains is found along the Pacific Ring of Fire. It is seen in a Mesozoic–Tertiary orogenic belt of mountains. The Andes rises due to the compression of the western rim of the South American Plate. It is a result of tectonic plate processes.

San Andreas Fault is known to form the tectonic boundary which exists between the Pacific Plate and the North American Plate. The motion of the fault is right-lateral strike-slip. It divides into three segments.

Answer:

1.83 atm

Explanation:

Total pressure is the sum of partial pressures, so the pressure of hydrogen and pressure of oxygen add to equal 4.53 atm

4.53 = 2.7 + Po

Po = 4.53 - 2.7 = 1.83 atm

Solution :

For the real gas following Vander Waals equation, reversible isothermal work done is given by :

[tex]$W= \int P \ dV$[/tex]

[tex]$W= \int \left(\frac{nR}{V-nb}-\frac{an^2}{V^2}\right) dV$[/tex]

[tex]$W_{real}=-nRT \ln \left[\frac{V_2-b}{V_1-b}\right]-an^2\left[\frac{1}{V_2}-\frac{1}{V_1}\right]$[/tex]

Given : [tex]$V_1=0.1 \ dm^3$[/tex], [tex]$$V_2 =100 \ dm^3[/tex]  

[tex]$a=359 \ atm \ L^2/ mol^2, \ \ b = 0.0427 \ L/mol$[/tex]

As T is not given, assuming T = 290 K

[tex]$W_{real} = 0.0823 \times 240 \left[ \ln \left(\frac{100-0.042}{0.1-0.0427}\right)\right]-3.59\left[\frac{1}{100}-\frac{1}{0.1}\right]$[/tex]

[tex]$W_{real}= -183.06+35.864$[/tex]

[tex]$W_{real}=-147.196$[/tex]

For the perfect gas,

[tex]$W=nRT \ln\left[\frac{V_2}{V_1}\right] =(1)(0.0823)(290) \ln \left[\frac{100}{0.1}\right]$[/tex]

[tex]$W_{ideal}=169.415$[/tex] kJ

Answer:

4665.97

Explanation:

Answer:

312.731

Explanation:

it had a long answer but im sure ur teacher wanted u to round it

hope this helps!

~goldfishareswag/brianna

:)

Answer:

Students have investigated what's going on in the fictional town of Westfield, they learned that the mysterious reddish-brown substance in the water is actually rust, which formed because of a chemical reaction between the iron pipes and the fertilizer substance in the water.

Explanation:

Answer:

see explanation and punch in the numbers yourself ( will be better for your test)

Explanation:

If you are given atoms you need to divide by Avogadro's number 6.022x10^23

then you will have moles of sulfur-- once you have moles multiply by the molar mass of sulfur to go from moles to grams

mm of sulfur is 32 g/mol

Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, the grams of sulfur in  1.9x10²³ atoms of sulfur is 9.92g.

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance.

Given number of atoms= 1.9x10²³atoms

we know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number

mole =given number of atoms ÷ 6.022×10²³(Avogadro number)

Substituting the values

mole=1.9x10²³÷ 6.022×10²³

mole = 0.31 mole of sulfur

Mole = given mass÷ Molar mass

Molar mass of sulfur=32g/mol

mass of sulfur =0.31 mole ×32g/mol

mass of sulfur=9.92g

Therefore, the grams of sulfur in  1.9x10²³ atoms of sulfur is 9.92g.

To know more about mole, here:

https://brainly.com/question/15209553

#SPJ2

Answer:  Boron

Explanation: lol

Answer:

Boron. (What kind of name is that?????????????)

Explanation:

Answer:

1) 4.21 x 10^24 molecules of Fe2O3

2) 36.416g of O2

Explanation:

1) First, find moles of Fe2O3 by using the mole ratio of 3:2. Fe2O3 has a coefficient of 2, and O2 has a coefficient of 3 thus making their mole ratio 2:3. Then, multiply 10.5 moles of O2 by 2/3 which equals 7 moles of Fe2O3. Finally, convert moles of Fe2O3 to molecules by multiplying it by Avogadro's number.

10.5 mol x 2/3= 7 mol Fe2O3

7 mol multiplied by 6.02 x 10^23 = 4.21 x 10^24 molecules

2) First, convert grams of KClO3 to moles by dividing it by its molar mass(approximately 122.5 g), which equals .759 mol. Then find moles of O2 by multiplying .759 mol KClO3 by the mole ratio of O2 to KClO3, which is 3:2. That equals 1.138 moles of O2. Finally, convert moles to grams by  multiplying 1.138 mol by the molar mass of O2 (approximately 32g). 36.416g of O2 is your final answer.

93g KClO3/ 122.5g = .759 mol KClO3

.759 mol x 3/2= 1.138 mol O2

1.138 mol x 32g= 36.416g O2

Answer:

See Explanations ...  I'll have to deliver my explanation in two posts. One is beyond the limits allowed.    

Explanation:

Stoichiometry is very easy if you understand the relationship between the 'mole' and the balanced chemical equation. Let's start by defining the 'mole'

The 'mole' of substance is the mass of substance (element or compounds) that contains 1 Avogadro's Number ( = 6.02 x 10²³ ) of particles. The mass of substance that does contain 1 Avogadro's Number of particles is 1 formula weight of substance (also, molecular weight of substance). That is,

1 mole = 1 formula wt. = 1 mole weight = 1 Avogadro's Number = 6.02 x 10²³ particles of substance.

So, assuming you can determine formula weight then that value expressed in terms of grams is a 'Gram Formula Weight'; that is, 1 GFW = 1 mole wt.

At this point it is assumed that you understand how to balance simple chemical equations by inspection. That is, by the Law of Mass Balance ...

total mass of reactants = total mass of products

In problem 1 you are given iron (Fe) + molecular oxygen (O₂) => iron(III) oxide (Fe₂O₃)  ...   4Fe + 3O₂ => 2Fe₂O₃   ... ∑mass R = ∑mass P.

Now, focus on the coefficients of each substance, that is, 4 for Fe, 3 for O₂ and 2 for Fe₂O₃. These values (coefficients) are moles of each substance in a special type of equation called the 'Standard Equation'. The Standard Equation is one which when balanced its coefficients are in the smallest whole number mole ratio of substance. That is the equation above is showing 4 moles of Fe, 3 moles of O₂ and 2 moles of Fe₂O₃.  This is  important in that most balanced equations that will be given in textbook problems will be in Standard Form.

From the Standard Form, the coefficients can be doubled, or divided in half, or whatever multiple or fraction one desires. The reaction would still perform in correct proportions. However, the multiples or fractions would not be in Standard Form. Most, if not all, stoichiometry problems will provide only the Standard Form.

Example, let's take the given equation above (from problem 1)

4Fe + 3O₂ => 2Fe₂O₃.

Both of the following are in correct proportions and will react with respect to the proportions YOU choose ...

(multiply by 2) => 8Fe + 6O₂ => 4Fe₂O₃.

(dividing by 2) => 2Fe + 3/2O₂ => Fe₂O₃.

Both are balanced and conform to the Law of Mass Balance but are not in Standard Form. Oh, and the Standard Form equations are assumed to be at 0°C and 1 atm, even if not specified in the problem. You may not need that now, but will become important in Gas Laws.

Let's move on to stoichiometry calculations. There are several methods being taught within the chemed. community, but I'm going to focus only on using mole ratios.  

My approach begins with this rule => convert reaction data to moles, solve using mole ratios and convert to needed dimension at the end of the problem. This will simplify a lot of problems once you understand what it's about.

OK, for problem 1 ...

How many molecules of Fe₂O₃ can be produced from 10.5 moles of O₂?

Given the Standard Form equation 4Fe + 3O₂ => 2Fe₂O₃.

Now, write (neatly) the equation and list the givens under the specific substances ...

             4Fe +       3O₂         =>     2Fe₂O₃.

              ex*     10.5 moles       ? molecules       note: ex* = excess (not used)

In this problem, since O₂ is already in terms of moles no conversion needed.

What you need to focus on is the relationship between the coefficients of O₂ and Fe₂O₃. Note that the coefficient of Fe₂O₃ is SMALLER than the coefficient of O₂. This means that the number of moles of Fe₂O₃ formed will be smaller than moles of O₂ given, that is 10.5 moles. How much smaller? Easy Calculation => Take the coefficient of O₂ and the coefficient of Fe₂O₃ and make a ratio of the numbers that will make 10.5 SMALLER. That is, you should use 2/3(10.5) to get a smaller number, not 3/2(10.5) because that would give a larger number and inconsistent with the ratio given in the balanced equation.      

So, moles of Fe₂O₃ produced = 2/3(10.5) moles Fe₂O₃ = 7 moles Fe₂O₃. Note that 7 moles is smaller than 10.5 moles.

Now, the number of molecules of Fe₂O₃ is also an easy calculation.

Remember that 1 mole contains 6.02 x 10²³ particles, then 7 moles would contain ...

= 7 moles Fe₂O₃  x  6.02 x 10²³ molecules Fe₂O₃/mole Fe₂O₃

= 4.21 x 10²⁴ molecules Fe₂O₃.  

Go to 2nd post for problem 2 solution.

Answer:

1.4 L.

Explanation:

Applying Charles law,

V/T = V'/T'....................... Equation 1

Where V = Initial volume, V' = Final volume, T = Initial Temperature in Kelvin, T' = Final Temperature in Kelvin.

Make V' the subject of the equation

V' = (V/T)T'..................... Euqation 2

Given: V = 1.5 L, T = 295 K, T' = 2 °C = (2+273) K = 275 K

Substitute these values into equation 2

V' = (1.5/295)275

V' = 1.398

V' ≈ 1.4 L

Answer:

75% will have long legs and 25% will have short legs

Explanation:

Answer:

I do not know the Answer I'm just trying to get my point

Explanation:

Thank you

Answer:

i am quite unsure what you want me to answer but if you explain it to me w ould live to help

Explanation:

Answer: should be 28 degrees

Explanation:

Answer:

because it has more space

Explanation:

density have many pressure

Answer:

The process or result of oxidizing or being oxidized.(Rust)

Explanation:

Pluto

Answer:

24.5 g of NaCl

Explanation:

We begin from the balanced reaction:

3MgCl₂ +   2Na₃PO₄  →    6NaCl   +  Mg₃(PO₄)₂

If the sodium phosphate is in excess, then the limting reagent is the magnessium chloride.

We convert mass to moles:

20 g . 1mol / 95.2g = 0.210 moles.

3 moles of MgCl₂ can produce 6 moles of NaCl

0.210 moles of salt, may produce (0.210 . 6) /3 = 0.420 moles

Ratio of reactant is twice the product

We convert the moles to mass:

0.420 mol .  58.45 g/mol = 24.5 g

Answer: you can find out information about Wheatstone bridge.

Explanation: maybe resistors are adjusted such a way that current through

Galvanometer is zero. There is no picture.

Answer:

mmh maybe the connections arent right

Explanation:

coz when u mess up even a bit current wont flow

When a drought occurs, their food supply can shrink and their habitat can be damaged. Lack of food and drinking water for wild animals. Increase in disease in wild animals, because of reduced food and water supplies. Migration of wildlife.

the north pole of the magnet will repel the north pole of another magnet

Answer:

The correct answer to that question is glaciers, waves, wind.

Answer:

I think it is D but I could be wrong.

Explanation:

Answer:

B.

Explanation:

Answer:

pOH = 1.3, pH = 12.7

Explanation:

Since NaOH is a strong base, it will completely ionize; further, since it completely ionizes, our hydroxide concentration (a product of the ionization) will be the same as the given concentration of NaOH.

NaOH -> Na⁺ + OH⁻, [OH⁻] = 5.0 x 10^-2 M

pOH is the negative log of the hydroxide concentration, so plug our hydroxide concentration in:

pOH = -log[OH⁻] = -log[5.0 x 10^-2 M] = 1.3

Since pH + pOH = 14, we can plug in pOH and solve for pH:

pH + 1.3 = 14

pH = 14 - 1.3 = 12.7

Thus, our pOH = 1.3 and pH = 12.7.

Answer:

2.7 mL

Explanation:

The equation of the reaction is;

2AlBr3 + 3Cl2 -----> 2AlCl3 + 3Br2

Number of moles in 2.12 x 1022 formula units of aluminum bromide

1 mole of AlBr3 = 6.02 * 10^23 formula units

x moles = 2.12 x 1022 formula units

x = 2.12 x 1022 formula units  * 1 mole/ 6.02 * 10^23 formula units

x = 0.0352 moles of AlBr3

According to the reaction equation;

2 moles of AlBr3 produces 3 moles of Br2

0.0352 moles of AlBr3 produces 0.0352 moles  *  3 moles /2 moles

= 0.0528 moles of Br2

Mass of Br2 produced = 0.0528 moles of Br2 * 159.808 g/mol

Mass of Br2 produced = 8.44g

But density = mass/volume

volume = mass/density

volume of Br2 = 8.44 g/ 3.12 g/mL

volume of Br2 =  2.7 mL

Answer: The empirical formula is [tex]P_2O_5[/tex]

Explanation:

Mass of O = 5.717 g

Mass of P= (10.150-5.717) g = 4.433 g  

Step 1 : convert given masses into moles.

Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{5.717g}{16g/mole}=0.357moles[/tex]

Moles of P=[tex]\frac{\text{ given mass of P}}{\text{ molar mass of P}}= \frac{4.433g}{31g/mole}=0.143moles[/tex]  

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For O = [tex]\frac{0.357}{0.143}=2.5[/tex]  

For P =[tex]\frac{0.143}{0.143}=1[/tex]

The ratio is to be converted to whole number

Thus whole number ratio of O : P = [tex]2.5\times 2:1\times 2=5: 2[/tex]

Hence the empirical formula is [tex]P_2O_5[/tex]

Answer:

Metabolism

Explanation:

This is called Metabolism.

Metabolism is a combination of spontaneous chemical reactions which release non-spontaneous energy and chemical reactions requiring energy to proceed. In order to perform cellular processes, living organisms can take energy from food, nutrients or sunlight.

Answer:

kidneys takes the waste out of the blood. It is then stored in the bladder, until the urinary tract takes the urine out of the body.

Answer:

C

Explanation:

Same reason as the answer before mine, but the answer to your questionaire is C.