What is the mass of phosphorus that contains twice the number of atoms found in 14
g of iron?
[Relative atomic mass : P = 31; Fe = 56]

Answers

Answer 1

Answer:

15.5 gm

Explanation:

What is the mass of phosphorus that contains twice the number of atoms found in 14 g of iron?

[Relative atomic mass : P = 31; Fe = 56]

14 gm Fe = 14gm/ 56 gm/mole = 14 mole gm/56gm = 14/56 mole

0.25 moles

2 X 0.25 = 0.5 moles

1 mole P = 31 gm

so

0.5 moles P =31/2 =15.5 gm


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One container has a volume of 3.00 L and contains O₂ at 4.00 atm. The other container has a volume of 2.00 L and contains Ne at 2.00 atm.

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[tex]P_1 \times V_1 = P_2 \times V_2\\\\P_2 = \frac{P_1 \times V_1}{V_2} = \frac{4.00atm \times 3.00L}{5.00L} = 2.40atm[/tex]

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