Answer:
vmax = 51.4 m/s
Explanation:
If the turn is flat, this means that the car is not accelerated in the vertical direction, so the normal force and the force of gravity are equal each other in magnitude, as follows:[tex]F_{n} = F_{g} = m*g (1)[/tex]
At the same time there exists a single force that keeps the car turning, which is the centripetal force, aiming to the center of the turn.This force is not a different force, is just the net force acting on the car in the horizontal direction, which is the friction force.This friction reaches to a maximum value, when the friction force is equal to the static friction force.This force can be expressed as follows:[tex]F_{fs} = \mu_{s} *F_{n} = \mu_{s} * m*g (2)[/tex]
This force must be equal to the maximum centripetal force, which can be written as follows:[tex]F_{c} = m*\frac{v^{2}}{r} (3)[/tex]
Since the left sides of (2) and (3) are equal each other, right sides must be equal too:[tex]\mu_{s} * m*g = m*\frac{v^{2}}{r} (4)[/tex]
Rearranging, and solving for v, we get the maximum speed that the car can go around the turn without sliding:[tex]v_{max} =\sqrt{\mu_{s} *g*r} =\sqrt{0.9*9.8m/s2*300m} = 51.4 m/s (5)[/tex]
During a hockey game, a puck is given an initial speed of 10 m/s. It slides 50 m on the horizontal ice before it stops due to friction. What is the coefficient of kinetic friction between the pick and the ice.A) 0.12B) 0.10C) 0.11D) 0.090
Answer:
The value is [tex]\mu_k = 0.102[/tex]
Explanation:
From the question we are told that
The initial speed of the pluck is [tex]u = 10 \ m/s[/tex]
The distance it slides on the horizontal ice is [tex]s = 50 \ m[/tex]
Generally from kinematic equation we have that
[tex]v^2 = u^2 + 2as[/tex]
Here v is is the final velocity and the value is 0 m/s given that the pluck came to rest, so
[tex]0^2 = 10 ^2 + 2* a * 50[/tex]
=> [tex]a = - 1 \ m/s^2[/tex]
Here the negative sign show that the pluck is decelerating
Generally the force applied on the pluck is equal to the frictional force experienced by the pluck
So
[tex]F = F_f[/tex]
=> [tex]m * a = m* g * \mu_k[/tex]
=> [tex]1 = 9.8 * \mu_k[/tex]
=> [tex]\mu_k = 0.102[/tex]
Which factor listed below has the greatest effect on the period of a pendulum?
a
Mass of the pendulum
b
Angle of the pendulum
c
Length of the string
d
Amplitude of the oscillations
Answer:
C
Explanation:
equation for pendulum period is
[tex]\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}}}[/tex]
and it depends only on its length (and gravity which is not on the list of answers)
A horizontal spring has a spring constant of 2.00 N/m. One end of the spring is attached to a fixed wall. A mass of 0.200 kilograms is attached to the free end of the spring and the spring is compressed by 0.500 meters from its natural length. The mass is released. What is the speed of the mass when the spring returns to its natural length?
a. 2.24 m/s
b. 2.50 m/s
c. 5.00 m/s
d. 1.58 m/s
Answer:
(D) the speed of the mass when the spring returns to its natural length is 1.58 m/s.
Explanation:
Given;
spring constant of the spring, k = 2 N/m
mass attached to the spring, m = 0.2 kg
compression of the spring, x = 0.5 m
Apply the principle of conservation of mechanical energy;
K.E = P.E
¹/₂m(v² - u²) = ¹/₂kx²
where;
u is the initial speed of the mass = 0
¹/₂mv² = ¹/₂kx²
mv² = kx²
[tex]v^2= \frac{kx^2}{m} \\\\v= \sqrt{\frac{kx^2}{m}} \\\\v = \sqrt{\frac{(2)(0.5)^2}{0.2}} \\\\v = 1.58 \ m/s[/tex]
Therefore, the speed of the mass when the spring returns to its natural length is 1.58 m/s.
why do feet smell and noses run?
Answer:
Nose has mucous glands with hairs which helps the body in trapping pollutants and infectants from entering inside the body. On the other hand,our feet is composed of millions of sweat pores when dirt and other things accumulate,it smells because of sweat mixed with the dirt and other dirty things of the ground.
Explanation:
Hope this helps
g A wave on a string has a speed of 13.3 m/s and a period of 0.3 s. What is the frequency of the wave
Answer:
3.33 Hz
Explanation:
The first step is to calculate the wavelength
= speed × period
= 13.3 × 0.3
= 3.99
Therefore the frequency of the wave can be calculated as follows
= speed/wavelength
= 13.3/3.99
= 3.33 Hz
20 pts.
Which of the following statements is true?
O Electromagnets use electrlcity and magnets.
O Magnetic fields are strongest around the poles of a magnet.
O The south pole of a magnet will repel the south pole of another magnet.
O all of the above
Answer:
all are true so d is right
Explanation:
Electromagnets use electrlcity and magnets is true.
Magnetic fields are strongest around the poles of a magnet is true.
The south pole of a magnet will repel the south pole of another magnet is true
and since all of them is true the answer is d all of the above
The average speed of a car that drives 140 kilometers in 2 hours
Answer:
240 kilometer
Explanation:
ur just mutipling the number by 2
Your average speed was 70.0 Kilometers per hour (km/h)
1. According to paragraph 3 in the text, MOST of the electromagnetic waves from
the sun that reach Earth are: *
O A. microwaves, x rays and visible light
O B. radio waves, infrared waves and visible light
O C. infrared waves, visible light and ultra-violet radiation
D. gamma rays, ultra-violet radiation and microwaves
Answer:
Most of the EM waves from the sun that reach Earth are infrared waves, visible light, and UV radiation.
Explanation:
I hope this helps! Have a good day!
PS Final Exam
What type of friction exists between a moving car's tires and the road?
O rolling friction
O static friction
O sliding friction
I
2800000 kg
Fig. 2.1
The total mass of the rocket and its full load of fuel is 2.8 106 kg. The constant force provided by
the rocket's motors is 3.2 x 107N.
32000000 N.
(a) Calculate
(i) the total weight of the rocket and the fuel.
weight =
Answer:
W = 27468000 [N] or 27.47 [kN]
Explanation:
The weight of a body is defined as the product of mass by gravitational acceleration.
[tex]W = m*g[/tex]
where:
W = weight of the rocket with fuel [kg]
m = mass = 2800000 [kg]
g = gravity acceleration = 9.81 [m/s²]
Now we can solve:
[tex]W = 2800000*9.81\\W = 27468000 [N][/tex]
A radioactive nuclide of atomic number Z emits an alpha particle and the daughter nucleus then emits a beta particle. What is the atomic number of resulting nuclide?
A) Z-1
B) Z+1
C) Z-2
D) Z-3
Answer:
A) Z-1
Explanation:
when a radioactive element of atomic number Z emits an alpha particle, the mass of the new nucleus decreases by 2, i.e the new atomic number of the element = ( Z- 2).
Also, when the daughter nucleus emits a beta particle, the new nucleus increases by 1, that is the new atomic number of the element = (Z + 1).
Thus, the atomic number of resulting nuclide = Z ( - 2) + ( + 1).
= Z - 2 + 1
= Z - 1
Therefore, the atomic number of resulting nuclide is Z - 1
What is the Potential Energy of a roller coaster if it has a velocity of 35 m/s and a mass of 2000 kg and is at a height of 200 m? Please answer fast
A.) 137,200,000 J
B.) 12,005,000 J
C.) 3,920,000 J
D.) 1,400,000 J
Answer:
C
Explanation:
It cant be A or D, meaning your left with B and C. there cant be an answer in the 1000's place eather
explain an experiment of the phenomenon of rainfall
Unclear/incomplete question. However, I inferred you need an explanation of the phenomenon of rainfall.
Explanation:
Basically, the phenomenon of rainfall follows a natural cycle called the water cycle. What we call 'rainfall' occurs when water condensed (in liquid form) in the atmosphere is made to fall down on the ground as tiny droplets as a result of the forces of gravity.
The water cycle makes rainfall possible:
First, water on the earth's surface is evaporated (or is absorbed into) the atmosphere.Next, it then condensed into liquid form; which later falls to the surface to the ground again. And the process continues.Angelica inhaled deeply into a plastic cup. Why did the cup collapse?
Answer:
Air vacuum.
Explanation:
Air may seem like nothing, but there are tons of molecules in it. Air takes up space. When Angelica inhales, the air rushes into into and escapes the cup. Since theres no air anymore, the cup collapses because thereis no more space in it. She removes the air from the cup and it creates a vacuum inside, sucking the sides of the cup in.
James is planning on registering for a course in electrical engineering which of the following sub disciplines could he opt for instrumentation engineering prosthetics plant design or signal processing
Answer:
Instrmentation engineering
Explanation:
Hope this helps!
A force of 64 N gives an object an acceleration of 23.53 m/s^2. What is the mass of the object?
A-2.00 kg
B-1505 kg
C-2.72 kg
D-736 kg
Please help!!
A person is driving in a circle at 20m/s. Are they accelerating?
10. A boy weighs 475 N. What is his mass? (acceleration due to gravity on Earth is 9.8m/s2 = g)
Answer: mass = 48.47 kg.
Explanation:
Formula : Weight = mg , where m = mass of body , g= acceleration due to gravity .
Given: Weight = 475 N
[tex]g= 9.8\ m/s^2[/tex]
Substitute all values in formula , we get
[tex]475= m \times9.8\\\\\Rightarrow\ m = \dfrac{475}{9.8}\\\\\Rightarrow\ m \approx 48.47\ kg[/tex]
Hence, his mass = 48.47 kg.
Help me please..
Velocity is defined as a
and a?
A) speed, direction
B) change, direction
C) speed, acceleration
D) change, acceleration
Answer:
Speed and direction.....
What are conducting patterns?
Answer:
A conducting pattern is a pattern in which your dominant hand follows in order to establish beats and tempo to the choir. Conductors that are directing large orchestras and choirs will often times use a baton so that the entire group can clearly see the motions.
Explanation:
If the social distancing length between two students is doubled from two metered to four meters, does the gravitational force between the two students increase or decrease?
Explain your reasoning!
Answer:
the gravitational force decreases
Help me please..
When the slope of a velocity vs. time graph is negative and constant,
what type of motion is occurring?
A) No motion
B) Constant speed
C) Acceleration
D) Constant Velocity
E) Going in circles
Which substance may lower air temperatures after a volcanic eruption?
lava
sulfur dioxide
carbon dioxide
water vapor
The awnser is sulfur dioxide.
The gas that is responsible for lowering the temperature is sulfur dioxide gas.
A volcanic eruption refers to the sudden escape of lava and gases from the earth's core. It usually occurs at a very high temperature. The solidification of the volcano leads to rock formation.
During a volcanic eruption, the gas that is responsible for lowering the temperature is sulfur dioxide gas.
Learn more: https://brainly.com/question/1622004
Need ASAP!! An object lies motionless on a rough inclined surface .
Answer:
yes
Explanation:
yes
Answer:
that's true
Explanation:
if the rough inclined plane was rough enough than it would be true
Details
A 70 kg student rides the Gravitron at a carnival. The
Gravitron has a radius of 2.75 meters. The student feels
a centripetal force of 2100 N. How fast is the Gravitron
spinning?
Answer:
1400 math quiz
Explanation:
40s n shorty's
Bonnie and Clyde are trying to steal the world's largest diamond from a 10 story
building. Bonnie needs to make a landing spot for when Clyde jumps with the
diamond. She knows they will be jumping from 58 feet. Neglecting air resistance,
what is the speed Clyde will be falling at right before hitting the ground?
Answer:
The speed Clyde will be falling at is 33.72.
Given f(x)=2x+7, which of the following is the value of x when f(x)=13?
Answer:
The value of x is 3
Explanation:
Equation Solving
We are given the equation
f(x) = 2x + 7
Let's find the value of such that f(x) = 13.
2x + 7 = 13
Subtracting 7:
2x = 13 - 7
2x = 6
Dividing by 2:
x = 6/2
x = 3
The value of x is 3
2 kg ball of clay moving at 40 m/s collides with a 5 kg ball of clay moving at 10 m/s directly toward the first ball. What is the final velocity if both balls stick together after the collision?
Answer:
vf = 4.3 m/s
Explanation:
Assuming no external forces acting during the collision, total momentum must be conserved:[tex]p_{o} = p_{f} (1)[/tex]
where p₀ = initial momentum, and pf = final momentum.
The initial momentum is just the sum (vector sum) of the initial momenta of both balls, as follows:[tex]p_{o} = m_{1} * v_{1o} + m_{2} * v_{2o} = 2 kg* 40 m/s - 5kg* 10m/s = 30 kg*m/s (2)[/tex]
The final momentum, assuming both balls stick together after the collision, can be expressed as follows:[tex]p_{f} = (m_{1} + m_{2} ) * v_{f} = 7 kg * v_{f} (3)[/tex]
From (2) and (3), solving for vf, we get:[tex]v_{f} =\frac{30 kg*m/s}{7 kg} = 4.3 m/s (4)[/tex]
A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion
[tex]{\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{First \: penetrating \: length\:(s_{1}) = 3 \: cm}[/tex]
[tex]\\[/tex]
[tex]{\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{Left \: Penetration \: length \: before \: it \: comes \: to \: rest \:( s_{2} )}[/tex]
[tex]\\[/tex]
[tex]{\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}} \\ \\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{Let \: Initial \: velocity = v\:m/s} \\\\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{Left \: velocity \: after \: s_{1} \: penetration = \dfrac{v}{2} \:m/s} \\\\ [/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{s_{1} = \dfrac{3}{100} = 0.03 \: m}[/tex]
[tex]\\[/tex]
☯ As we know that,
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ {v}^{2} = {u}^{2} + 2as }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ \bigg(\dfrac{v}{2} \bigg)^{2} = {v}^{2} + 2a s_{1}}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ \dfrac{ {v}^{2} }{4} = {v}^{2} + 2 \times a \times 0.03 }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ \dfrac{ {v}^{2} }{4} - {v}^{2} = 0.06 \times a }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{\dfrac{ - 3{v}^{2} }{4} = 0.06 \times a }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{a = \dfrac{ - 3 {v}^{2} }{4 \times 0.06} }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ a = \dfrac{ - 25 {v}^{2} }{2}\:m/s^{2} ......(1) }[/tex]
[tex]\\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{ Initial\:velocity=v\:m/s} \\\\ [/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{ Final \: velocity = 0 \: m/s }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ {v}^{2} = {u}^{2} + 2as}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{{0}^{2} = {v}^{2} + 2 \times \dfrac{ - 25 {v}^{2} }{2} \times s }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ - {v}^{2} = - 25 {v}^{2} \times s }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ s = \dfrac{ - {v}^{2} }{ - 25 {v}^{2} }}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ s = \dfrac{1}{25} }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ s = 0.04 \: m }[/tex]
[tex]\\[/tex]
☯ For left penetration (s₂)
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{s = s_{1} + s_{2} }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ 0.04 = 0.03 + s_{2}}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ s_{2} = 0.04 - 0.03 }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{s_{2} = 0.01 \: m = {\boxed{\sf{\purple{1 \: cm }}} }}[/tex]
[tex]\\[/tex]
[tex]\star\:\sf{Left \: penetration \: before \: it \: come \: to \: rest \: is \:{\bf{ 1 \: cm}}} \\ [/tex]
(6.9 * 10-6)(770 * 102)
Answer:
4948020
Explanation:
(6.9*10-6)(770*102)
Multiply 6.9 by 10 .
( 69 − 6 ) ( 770 ⋅ 102 )
Subtract 6 from 69 .
63 ( 770 ⋅ 102 )
Multiply 770 by 102 .
63 ⋅ 78540
Multiply 63 by 78540 .
4948020
