What is the name of a number that can be written in the form a+bi where a and b are nonzero real numbers?

Answer:

k=-6

Step-by-step explanation:

Answer:

[tex]\Large \boxed{k=-6}}[/tex]

Step-by-step explanation:

35 = -5(2k+5)

Expand brackets.

35 = -10k - 25

Add 25 on both sides.

60 = -10k

Divide both sides by -10.

-6 = k

Answer:

a 0,1 and b 1,0

Step-by-step explanation:

exam took

Answer:

The other answer is incorrect the answer is

D) The locations of A' and B' are A' (0, 6) and B' (6, 0); lines f and f' are parallel.

Basically the first three items are true, with the rest false.

=========================================================

Explanation:

Let's go through each answer choice one by one to see if it is true or false.

---------------------

A. The quadratic equation is in standard form.  

This is true. Standard form for quadratics is y = ax^2+bx+c. In this case, a = 2, b = 0, c = 3. It might help to write the equation as y = 2x^2+0x+3.

---------------------

B. Using substitution, the system of equations can be rewritten as 2x2 – x – 3 = 0.  

This is true. Start with y-x = 6. Replace y with 2x^2+3 and we get

2x^2+3-x = 6

From here we subtract 6 from both sides

2x^2+3-x-6 = 6-6

2x^2-x-3 = 0

---------------------

C. There are two real number solutions.  

This is true. When you graph the two equations (I recommend GeoGebra but Desmos is another good tool), you'll see they intersect at two different locations. Each location is a solution in the form (x,y).

---------------------

D. There are no real number solutions.  

This is false. It contradicts choice C.

---------------------

E. A solution of the system of equations is (–1, 1.5).

This is false. The two solutions are (-1, 5) and (1.5, 7.5) which is where the two graphs intersect.

Another way to check is to plug x = -1 into either equation. You'll find the result to both is y = 5 instead of y = 1.5

Answer:

its ABC

Step-by-step explanation:

Since ∠COA and ∠BOD are vertical angles, they are congruent.

You are also given that ∠ACO ≅ ∠DBO and BO ≅ CO.

By ASA (Angle-Side-Angle) congruency, you know that △ACO ≅ △DBO

The proof is shown below:

If the three angles and the three sides of a triangle are equal to the corresponding angles and the corresponding sides of another triangle, then both the triangles are said to be congruent.

In Δ PQR and ΔXYZ, as shown below, we can identify that PQ = XY, PR = XZ, and QR = YZ and ∠P = ∠X, ∠Q = ∠Y and ∠R = ∠Z. Then we can say that Δ PQR ≅ ΔXYZ.

ASA criterion stands for Angle-Side-Angle criterion. Under the ASA criterion, two triangles are congruent if any two angles and the side included between them of one triangle are equal to the corresponding angles and the included side of the other triangle.

Given:

∠ACO ≅ ∠DBO, and BO ≅ CO

as, ∠COA =∠BOD (vertically opposite angles)

∠ACO ≅ ∠DBO ( given)

BO ≅ CO ( given)

So, By ASA (Angle-Side-Angle) congruency,  △ACO ≅ △DBO

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Answer:

7/6

Step-by-step explanation:

We can find the slope by using the slope formula

m = (y2-y1)/(x2-x1)

    = ( -3 -4)/(5 -11)

  -7/-6

  =7/6

Answer:

7/6

Step-by-step explanation:

m = (y2 - y1)/(x2 - x1)

m = (-3 - 4)/(5 - 11)

m = -7/(-6)

m = 7/6

Answer:

2. it stays the same even if the angles in the triangle change

a. the angles must add up to 180º. a straight line is equal to 180º, so as long as the angles add up to 180º, it will be a straight line.

5. it represents the sum of the measures of the interior angles of the triangle

a. Kellianne lined up the interior angles of the triangle. if added they equal 180º which is the measure of the straight line.

7. it combines the three interior angles of the triangle to form a straight line

a. same answers as previous

8. it is a straight line with a measure of 180º

a. refer to above

hope this helps :)

Answer:

B E H

Step-by-step explanation:

Answer:

1. b.  2. a.  3. a.

Step-by-step explanation:

1. (f + g)x = f(x) + g(x)

= x^2 + 2x + 4

(f + g)(-1) =  (f + g)(x)  where x = 1 so it is

(-1)^2 + 2(-1) + 4

=  1 - 2 + 4

= 3.

2.  We find (f o g)(x) by replacing the x in f(x) by g(x):

= √(x + 1) and

(f o g)(3) =  √(3 + 1)

= √4

= 2.

3. (f/g) c  = f(x) / g(x)

= (x - 3)/(x + 1)

The domain is the values of x which give real values of (f/g).

x cannot be - 1 because the denominator x + 1 = -1+1 = 0 and dividing by zero is undefined. So x can be all real values of x except x = -1.

The domain is (-∞, -1) U (-1, ∞)

Answer:

Hey there!

What we know:

What we would like to know:

First, let's find AB.

Sine 58= AB/65

Solving for AB, we see that it is about 55.12 m.

Next, let's find BD.

Sine 42= BD/55.12

Solving for BD, we see that it is about 36.88 m.

Let me know if this helps :)

Answer:

254 million

Step-by-step explanation:

In a calculator it would to

210 x 1,0194^(10)

Answer:

5/8 of the game

Step-by-step explanation:

Half of a quarter is 1/2, and 1 quarter is already done, therefore 1/2, or to simplify it 1/8, plus 2/8, would be 3/8. Now, a quarter is 1/4th of something therefore there must be 4 quarters in a total.so that means that there are 8 halfves  in total , so 8-3=5, so the fractional parts of the game left is 5/8.

The part of the game i.e. left should be [tex]5\div 8[/tex]

Since the half of the quarter is one-half. And, the one quarter is done so one-half is remaining. That means

[tex]= 1\div 8 + 1\\\= 2\div 8[/tex]

Since one-fourth should be of something also there are total 4 quarters that means there are 8 halves.

So, remaining it should be

= 8 -3

= 5

Hence, The part of the game i.e. left should be [tex]5\div 8[/tex]

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      Hi my lil bunny!

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[tex]-364/9-(-102/9)-(182/9)​[/tex]

[tex]= \frac{148}{3}[/tex] (Decimal: -49.333333)

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If this helped you, could you maybe give brainliest..?

❀*May*❀

Answer:

1 state

Step-by-step explanation:

You can see this by the state increases by 1, from 14-15, in the graph above.

Also, can you please give me the brainliest answer thing. :)

Answer:

The solution set is therefore {-10, 2}

Step-by-step explanation:

The absolute value equation |3x + 12| = 18 has two distinct solutions.

|3x + 12| = 18 may be rewritten as

3x + 12 = 18 and

-(3x + 12) = 18

The first equation immediately above becomes 3x = 6 after we subtract 12 from both sides.  Therefore, x = 6/3, or x = 2.

Simplifying the second equation yields -3x - 12 = 18.  To solve this for x, we add 12 to both sides, obtaining -3x = 30.

Dividing both sides by -3 yields x = -10.

The solution set is therefore {-10, 2}

Answer:

Step-by-step explanation:

To find the side adjacent to the 50° angle we use tan

[tex] \tan( \alpha ) = \frac{opposite}{adjacent} [/tex]

From the question

The opposite is 6m

The adjacent is ?

So we have

[tex] \tan(50) = \frac{6}{?} [/tex]

[tex]? \tan(50) = 6[/tex]

[tex]? = 6 \times \frac{1}{ \tan(50) } [/tex]

But

[tex] \frac{1}{ \tan(x) } = \cot(x) [/tex]

So we have

[tex] \frac{1}{ \tan(50) } = \cot(50) [/tex]

Substitute it into the expression

That's

We have the final answer as

[tex]? = 6 \cot(50) [/tex]

Hope this helps you

=====================================================

Explanation:

We're given an opposite side and an adjacent side. The tangent rule ties these two sides together. "tangent" is nowhere to be found in any of the answer choices, but cotangent is. Recall that

cot = 1/tan

which means

tan = opposite/adjacent

cot = adjacent/opposite

one is the reciprocal of the other

-----------

This means

cot(angle) = adjacent/opposite

cot(50) = x/6

6*cot(50) = x

x = 6*cot(50)

Answer:

[tex] 2w^2(w + 2)(4w - 3) [/tex]

Step-by-step explanation:

[tex] 8w^4 + 10w^3 − 12w^2 = [/tex]

First, factor out the GCF of all terms, 2w^2:

[tex] = 2w^2(4w^2 + 5w - 6) [/tex]

Now we work on the trinomial.

Think of ax^2 + bx + c.

Multiply ac

ac = 4 * (-6) = -24

Now we need two numbers whose product is -24 and whose sum is 5.

They are -3 and 8.

We break up the middle term, 5w, into a sum using these two numbers.

5w = 8x - 3w

[tex] = 2w^2(4w^2 + 8w - 3w - 6) [/tex]

Now we factor by parts. We factor a common factor out of the first two terms, and we factor a common factor out of the last two terms.

[tex] = 2w^2[4w(w + 2) - 3(w + 2)] [/tex]

[tex] = 2w^2(w + 2)(4w - 3) [/tex]

Answer:

(7, -5.5)

Step-by-step explanation:

is seen below on this graph (7, -5.5) shows x = 7 and y = -5.5

Answer:

2

Step-by-step explanation:

Use PEMDAS

First simplify the exponent (9)

Next multiply 5 and 3 (15)

Now add 15 and 15 (30)

Add 9 and 6 (15)

Lastly simply 30 by 15 (2)

Answer:

[tex]\boxed{A. 2}[/tex]

Step-by-step explanation:

Hey there!

Well we first need to solve the top part.

15 + 5 * 3

5*3 = 15

15 + 15 = 30

3^2 + 6

3*3 = 9

9+6 = 15

Now we have 30 ÷ 15 = 2.

Hope this helps :)

Answer:

6/8 of a mile,

Step-by-step explanation:

if one furlong is 1/8 of a mile, the 6 shall be 1/8 added to itself 6 times, therefore it shall be 6/8.

Answer:

3/4 of a mile

Step-by-step explanation:

1 furlong = 1/8 mile

========     ====

6 forlongs = x

cross multiply

1*x = 6 * (1/8)

x = 6/8

reduce 6/8. Divide top and bottom by 2

x = 3/4

The required ways of the combination to display the flowers on the dinner is  20.

There are 6 flowers in vases in your kitchen. You want to put 3 of them on the dining room table for dinner tonight. Order isn’t important. How many ways can you display the flowers for dinner to determiined.

In arithmetic, combination and permutation are two different ways of grouping elements of a set into subsets. In a combination, the components of the subset can be recorded in any order. In a permutation, the components of the subset are listed in a distinctive order.

Examples of permutation and combination, Managing people, numbers, numerals, alphabets, letters , and colors are examples of permutations. Choosing of menu, foodstuffs, dresses, matters, and the group are examples of combinations.

Since, the total number of flower in vases is 6
3 of them to be selected for the dinner table tonight.
The combination is given as.
= C( 6 , 3)
= 6!/3!(6 - 3)!
= 6!/3!3!
= 20

Thus, the required ways of combination to display the flowers on dinner is  20.

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The construction that you can use to prove the Pythagorean Theorem based on similarity of triangles is 2nd construction. Please see the attached file.

Two triangles are similar triangles of their corresponding angles are equal corresponding sides are in equal ratios.

The Pythagorean theorem, also known as Pythagoras's theorem, is a fundamental relation in Euclidean geometry among the three sides of a right triangle. It mentions that the sum of the squares of the other two sides is equal to the square of the hypotenuse (the side opposite the right angle).

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Answer:

1/18(x-2)^2+45/18=y

Step-by-step explanation:

(x-2)^2+(y-7)^2=(y+2)^2

(x-2)^2+y^2-14y+49=y^2+4y+4

(x-2)^2-14y+49=4y+4

(x-2)^2+45=18y

1/18(x-2)^2+45/18=y

Answer:

£9.50

Step-by-step explanation:

if the price was reduced 70%, then Dave is paying 30% of the original.

0.3 of £ = 2.85

£ = 2.85 / 0.3

£ = 9.5

£9.50

Answer:

$4.84

Step-by-step explanation:

2.85*.70=1.99

2.85+1.99=4.84

Answer:

i think it is the third one but dont know just an educational geuss

Step-by-step explanation:

The given steps from the derivation of the quadratic formula are:

Step 3:  [tex]-c+\frac{b^2}{4a}=a(x^2+\frac{b}{a}x+\frac{b^2}{4a^2})[/tex]

Step 4a: [tex]-c+\frac{b^2}{4a}=a(x+\frac{b}{2a})^2[/tex]

Step 4b: [tex]\frac{-4ac}{4a}+\frac{b^2}{4a}=a(x+\frac{b}{2a})^2[/tex]

The property "converting to a common denominator" justifies step 4b. So, option C: "converting to a common denominator" is correct.

The quadratic formula is as follows:

x = [-b ± (√b²+4ac)]/2a

This formula is derived from the quadratic equation [tex]ax^2+bx+c=0[/tex].

The standard quadratic equation is [tex]ax^2+bx+c=0[/tex]

Step 1: [tex]ax^2+bx=-c[/tex]

Step 2: Taking 'a' as common

[tex]a(x^2+\frac{b}{a}x)=-c[/tex]

Step 3: Adding [tex]\frac{b^2}{4a}[/tex] on both sides

[tex]-c+\frac{b^2}{4a}=a(x^2+\frac{b}{a}x)+\frac{b^2}{4a}[/tex]

⇒ [tex]-c+\frac{b^2}{4a}=a(x^2+\frac{b}{a}x+\frac{b^2}{4a^2})[/tex]

Step 4a: Factoring the polynomial

[tex]-c+\frac{b^2}{4a}=a(x+\frac{b}{2a})^2[/tex]

Step 4b: Converting to a common denominator

[tex]\frac{-4ac}{4a}+\frac{b^2}{4a}=a(x+\frac{b}{2a})^2[/tex]

⇒ [tex]\frac{(-4ac+b^2)}{4a}=a(x+\frac{b}{2a})^2[/tex]

Step 5: Applying square root (on one side there is a square, so, on the other side it gets ±)

⇒ [tex]\frac{(-4ac+b^2)}{4a^2}=(x+\frac{b}{2a})^2[/tex]

⇒ ±[tex]\sqrt{\frac{(-4ac+b^2)}{4a^2}} =(x+\frac{b}{2a})[/tex]

⇒ [tex]x+\frac{b}{2a}[/tex] = ± [tex]\frac{\sqrt{b^2-4ac} }{2a}[/tex]

step 6: Subtacting [tex]\frac{b}{2a}[/tex] from both the sides

⇒ [tex]x=-\frac{b}{2a}[/tex] ± [tex]\frac{\sqrt{b^2-4ac} }{2a}[/tex]

⇒ x = [-b ± (√b²+4ac)]/2a

Thus, step 4b best explains or justifies the property "Converting to a common denominator".

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Explanation : If 66 is a factor of this unknown value, then 22 must be as well considering that 22 is a factor off 66. Let's say that this large value is 330. It is a multiple of 66, as 66 [tex]*[/tex] 5 = 330. At the same time 22 [tex]*[/tex] 15 = 330, so 330 is a multiple of 22 as well - or vice versa, 12 is a factor of 330.

We can also tell that 15, 22 fit into 330 through another approach. 22 [tex]*[/tex] 3 = 66, and 66 [tex]*[/tex] 5 = 330, so 5 [tex]*[/tex] 3 = 15 - the same value. This proves that 22 will always be a factor of a value that is the factor of 66.

Answer:

At company for less than 2 years:

College degree: 0.24

No college degree: 0.76

At company for more than 2 years:

College degree: 0.7

No college degree: 0.3

Step-by-step explanation:

To find the relative frequency for those at the company for less than 2 years with a degree:

5 + 16 = 21

5 / 21 = 0.23809523809

≈ 0.24

To find the relative frequency for those at the company for less than 2 years with a degree:

5 + 16 = 21

16 / 21 = 0.7619047619

≈ 0.76

Check:

0.24 + 0.76 = 1

To find the relative frequency for those at the company for more than 2 years with a degree:

14 + 7 = 21

14 / 21 = 0.666..

≈ 0.70

To find the relative frequency for those at the company for less than 2 years with a degree:

14 + 7 = 21

7 / 21 = 0.333..

≈ 0.30

Check:

0.70 + 0.30 = 1

I really hope this helps! Tell me if I'm wrong!

Answer:

27

Step-by-step explanation:

By the theorem of intersecting secant and tangent out side of a circle, we have:

[tex] {60}^{2} = 48 \times (48 + x) \\ 3600 = 48 \times (48 + x) \\ \frac{3600}{48} = 48 + x \\ 75 = 48 + x \\ 75 - 48 = x \\ x = 27 \\ [/tex]

260 units2 is the answer

Answer:

[tex]\boxed{x = 40}[/tex]

Step-by-step explanation:

Hey there!

Well angles like 142 and 2x + 22 equal each other because they are across from each other.

So we can set up the following,

142 = 3x + 22

Single out x

-22 to both sides

120 = 3x

Divide both sides by 3

x = 40

Hope this helps :)

Answer:

x=40

Step-by-step explanation:

142=3x+22

3x+22-22=142-22

3x=120

120/3=40

Answer:

(5,5) and (5,-11)

Step-by-step explanation:

You can find this out by plotting a circle with the diameter of 10 on the point "(-1,-3)". Then find all the times the circle is on the x axis of 5.

Answer:

so when the mughal emperor humayun had died akbar his son was put as kind of india he was 10 yearls old when his father died and then Bairam Khan was elected as a regent for Akbar.

Step-by-step explanation: