What is the solution for this inequality? -10x ≤ 40 A. x ≤ -4 B. x ≤ 4 C. x ≥ -4 D. x ≥ 4

Answers

Answer 1

Answer:

C. x ≥ -4

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify

-10x ≤ 40

Step 2: Solve for x

[Division Property of Equality] Divide -10 on both sides:                               x ≥ -4
Answer 2

Answer:

C. x ≥ -4

Step-by-step explanation:

To solve this inequality isolate the variable. Do this by using the properties of equality, specifically the division property. So, divide both sides by -10. This equals, x ≤ -4. However, whenever an inequality is divided or multiplied by a negative number the sign must be flipped. Therefore, the final answer is x ≥ -4.


Related Questions

(Algebra ll) Given the function below

Answers

Answer: B

Step-by-step explanation:

To find the values of x, we first need to write the function into an equation. We can derive 2 equations from the problem.

Equation 1: y=2|x+6|-4

Equation 2: y=6

Now, we can substitute.

2|x+6|-4=6

Let's solve for x.

2|x+6|-4=6        [add both sides by 4]

2|x+6|=10          [divide both sides by 2]

|x+6|=5              [subtract both sides by 6]

x=-1

Now that we know x=-1 is one of the solutions, we can eliminate C and D.

We know that the absolute value makes the number inside positive always. Therefore, let's solve for x with -5 instead.

|x+6|=-5              [subtract both sides by 6]

x=-11

Therefore, we know that B is the correct answer.

Explain what you would do first to simplify the expression below. Justify why, and then state the result of performing this step.

Answers

Remember PEMDAS, you have to simplify the exponent first.

why can two prime numbers only have one common factor?

Answers

A prime number has exactly two factors, 1 and itself. For example, 13 is a prime number because the only factors of 13 are 1 and 13. The number 8 is not prime because it has four factors: 1, 2, 4 and 8. The number 1 is not a prime number because it only has one factor (itself).

3x + y = 10 x - y = 2 2​

Answers

Answer: in the picture

4x+9/y+11=0 and 6/y -3x=8​

Answers

9514 1404 393

Answer:

  (x, y) = (-2 12/17, -51)

Step-by-step explanation:

Here is the answer to ...

  [tex]4x+\dfrac{9}{y}+11=0\\\\\dfrac{6}{y}-3x=8[/tex]

If you mean something else, then parentheses are needed.

__

Let z = 1/y. Then the equations in general form are ...

  [tex]4x+9z+11=0\\3x-6z+8=0[/tex]

The solution (cross multiplication method) is ...

  x = (9·8 -(-6)·11)/(4(-6)-3·9) = 138/-51 = -2 12/17

  z = (11·3 -8·4)/-51 = -1/51

  y = 1/z = -51

The solution is (x, y) = (-2 12/17, -51).

Complete the similarity statement for the two triangles shown
40 m
15 m
30 m
25 m
>H
Enter your answer in the box
20 m
50 m
S
F
ACHS ~A

Answers

Answer:

TFY

Step-by-step explanation:

let's start with the 90 degrees angle.

this is C in the first, and T in the second triangle.

so, C and T must be aligned.

and the we go around.

F ~ H

and then

Y ~ S

Chang knows one side of a triangle is 13 cm. Which set of two sides is possible for the lengths of the other two
sides of this triangle?
5 cm and 8 cm
6 cm and 7 cm
7 cm and 2 cm
8 cm and 9 cm

Answers

Answer:

8 cm and 9 cm

Step-by-step explanation:

Hi there!

The sum of the lengths of two sides of a triangle must always be greater than the length of the third side.

5 cm and 8 cm ⇒ 5+8=13; not greater than 13

6 cm and 7 cm ⇒ 6+7=13; not greater than 13

7 cm and 2 cm ⇒ 7+2=9; not greater than 13

8 cm and 9 cm ⇒ 8+9=17; greater than 13

Therefore, the last set of two sides is possible for the lengths of the the other two sides of this triangle.

I hope this helps!

8cm and 9 cm because the sum of the two sides must be greater than 13.

5+8=13
6+7=13
7+2=9
8+9=17

Plss answer the bottom question

Answers

Answer:

200

Step-by-step explanation:

250/100=2.5

2.5*80=200

So the answer is 200

X =54
This is a banging answer

A bag contains 6 apples and 4 oranges. If you select 5 pieces of fruit without
looking, how many ways can you get 5 apples?

Answers

Answer:

6 I think

Step-by-step explanation:

Between 20 to 35 degrees north latitude, and also between 20 to 35 degrees south latitude are found:

Answers

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Its area includes all Sahara's locations in North Africa, South Arabia, Iran's and Iraq's larger parts, North-Western India, California throughout the United States, South Africa but most of Australia.

Half-arid temperatures include places like the Utah, Montana, and Gulf Coastal regions of sagebrush. Also, it comprises regions in Iceland, Russia, Scandinavia, Greenland, and Northeast India. Semi-arid thankless than tube called per year of rain and up to 20 inches per year at much more than arid deserts.

Regions from of the latitude of 25° to 35° usually develop desert, because air sinks and is heated under pressures in this area. The world's dry and semi-arid desert regions are between 20°C and 35°C north latitude and between 20°C and 35°C South latitude.

a)if A×B ={(1,2),(2,3),(1,3),(2,2),(3,2),(3,3)} find i) set A ii) set B.​i need for exam

Answers

Answer:

soln,

set A ={ 1,2,3}

set B ={2,3}

La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?

Answers

Answer:

Falso.

Step-by-step explanation:

Sea [tex]d = \frac{a}{b}[/tex] un número racional, donde [tex]a, b \in \mathbb{R}[/tex] y [tex]b \neq 0[/tex], su opuesto es un número real [tex]c = -\left(\frac{a}{b} \right)[/tex]. En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) El exponente es cero.

(b) El exponente es un negativo impar.

(c) El exponente es un negativo par.

(d) El exponente es un positivo impar.

(e) El exponente es un positivo par.

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, [tex]c = d = 1[/tex]. La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

[tex]d' = d^{-n}[/tex] y [tex]c' = c^{-n}[/tex]

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

[tex]d' = \left(\frac{a}{b} \right)^{-n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}[/tex]

[tex]d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]y [tex]c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{b}{a} \right)\right]^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = - \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' \neq c'[/tex], la proposición es falsa.

(c) El exponente es un negativo par.

Si [tex]n[/tex] es par, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' = c'[/tex], la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

[tex]d' = d^{n}[/tex] y [tex]c' = c^{n}[/tex]

[tex]d' = \left(\frac{a}{b}\right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = - \left(\frac{a}{b} \right)^{n}[/tex]

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es par, entonces [tex]d' = c'[/tex] y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

What number should be subtracted from -3/4 to get 5/6?

Answers

Answer:

Let that rational number to be subtracted be x.Given,-5/​6 - x = 4/9= - x = 4/9+5/6= - x = 23/18x = - 23/18.

Step-by-step explanation:

I need help with my math!!!

Answers

Answer:

[tex]y = |x+2|+1[/tex]

Step-by-step explanation:

Find the area of circle Q in terms of x

Answers

Answer:

The answer is C 100πcm^3

A man runs at the speed of 10 km/hr. How much time will he take to cover 2000 meters?

Answers

200 hours.

It’s 10km for every one hour
Divide 2000 by 10 and you will be left with the number of km for every one hour.

Factor -1.8 out of 3.6b-9

Answers

Answer:   -1.8(-2b+5)

=================================================

Explanation:

Consider something like 2b+6 factoring to 2(b+3). When we distribute that outer 2 back inside the parenthesis, we're multiplying that 2 by everything inside. Factoring goes in reverse of this and we divide each term of 2b+6 by the GCF 2.

The same thing applies to this current problem as well.

Divide each term by the -1.8 we want to factor out.

(3.6b)/(-1.8) = -2b(-9)/(-1.8) = 5

The results -2b and 5 will go inside the parenthesis. That's how we end up with -1.8(-2b+5)

You can use distribution to verify this

-1.8(-2b+5)

-1.8*(-2b) - 1.8*(5)

3.6b - 9

What is the value of tan 0 in the unit circle below?

Answers

Answer:

1 / sqrt(3)

Step-by-step explanation:

tan(o) = sin(o) / cos(o)

sin(o) is the vertical distance from the x-axis. and that is in this basic circle the y-coordinate of the point.

cos(o) is the horizontal distance from the y-axis. that is the x-coordinate of the point.

so,

tan(o) = (1/2) / (sqrt(3)/2) = (2×1) / (2×sqrt(3)) = 1/sqrt(3)

Write each as a percent. Use proportions.
7/25
2/3
3/8

Answers

28%
66%
37.5%
thats the answer

Through any two points there is exactly one _____

space.

plane.

line.

point.

Answers

Answer:

C. Line

Is the correct answer

7x-3=5x+9 solve for x​

Answers

Given :-

7x - 3 = 5x + 9

To Find :-

The value of x.

Solution :-

Taking the given equation ,

=> 7x -3 = 5x + 9

=> 7x - 5x = 9 + 3

=> 2x = 12

=> x = 12 ÷ 2

=> x = 6

Hence the required answer is 2 .

pls help, i have class rn :(

in how many ways can alice distribute 12 apples to 3 children (a child can have no apples)

Answers

if the children could have the apples it would be 4 per each child but since u said no child can have apples don’t distribute them so 0?

what is the ratio of Sin 45°?​

Answers

Answer:

1/√2

Step-by-step explanation:

The value of sin 45 is 1/√2

Find the perimeter of ΔJKL. Round your answer to the nearest tenth if necessary

Answers

x = 42.5, so the perimeter is 117.5, hope this helps- if you could mark brainliest that’d be awesome thanks

Answer:

Step-by-step explanation:

as angles of two triangles are equal, so they are similar.

x/17 =35/14=40/16

x/17=35/14

x=35/14×17=85/2=42.5

perimeter of ΔJKL=40+35+42.5=117.5

At the beginning of year 1, Matilda invests $450 at an annual simple interest rate of 5%. She makes no deposits to or withdrawals from the account. Which explicit formula can be used to find the account's balance at the beginning of year 15? What is the balance?

Answers

Answer:

$765

Step-by-step explanation:

[tex]interest \: = \frac{prt}{100} \\ = \frac{(450)(5)(14)}{100} \\ = 315 \\ total \: money \: = 315 + 450 \\ = 765[/tex]

A(n) = 450 + (n – 1)(0.05 • 450); $765.00

What is the product?

Answers

21x^7y^11 ur welcome cuh

URGENTT!!!! help quick please

Answers

The answer is going to be
X=20

What is the equation of the following line written in general form? (The y-intercept is -1.)

Answers

Answer:

2x-y-1=0

Step-by-step explanation:

.

At the beginning of the chemistry experiment, Lisa measured the temperature of a liquid to be -5°C. During the experiment, she measured the liquid 3 times and the results showed, its dropped 9°C, rose 25°C, and drop 15°C. What was the liquid temperature at the end of the experiment?

Answers

Answer:

-4°C

Step-by-step explanation:

At the beginning of the chemistry experiment the temperature of the liquid was -5°C and it dropped 9°C so you do:

-5°C - 9°C = -14°C

The answer is -14°C for the first part of the question because when you are subtracting a positive number from a negative number you have to add the two numbers together but your answer will always be a negative number.

Then you add 25°C to -14°C:

-14°C + 25°C = 11

Because when adding a negative number to a positive number that is bigger than the negative number you have to subtract but your answer will always be a positive number, however if the positive number is smaller than the negative number your answer will be a negative number.

Then you subtract 11°C from 15°C:

11°C - 15°C = -4°C

Because when you subtract a number that is bigger than the first number you get a negative number.

The height of a cone is two times its base diameter. What is the volume of the cone in terms of its base radius r?

options are on the picture:)

Answers

Answer:-

The option B is the right answer.

Solution:-

[tex] \sf h = 2d = 2 \: • \: 2r = 4r[/tex]

[tex] \sf = \frac{1}{3} \pi {r}^{2} h[/tex]

[tex] \sf = \frac{1}{3} \pi {r}^{2} \: • \: 4r[/tex]

[tex] \sf = \frac{4}{3} \pi {r}^{3} \: \green✓ [/tex]

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