What is the solution of the linear equation? LaTeX: 5k\:+\:3.8\:=\:3k\:+\:95 k + 3.8 = 3 k + 9 Group of answer choices 26 6.4 .065 2.6

The answer is 1/2 because there are total 10 questions. So, the probability of getting 5 correct answers is 5/10 that is 1/2.

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Answer:

mass = 9a^5

center of mass = [tex]\frac{7a}{12}, \frac{7a}{12}, \frac{7a}{12}[/tex]

Step-by-step explanation:

Finding the mass of the solid E

given density function : p ( x,y,z ) = [tex]9x^2 + 9y^2 + 9z^2[/tex]

Mass =   [tex]\int\limits^a_0 \int\limits^a_0 \int\limits^a_0 {9(x^2+y^2+z^2)} \, dx dydz[/tex]   [tex]= \int\limits^a_0 \int\limits^a_0 {9(\frac{a^3}{3}+ay^2+az^2 )} \, dydz[/tex]

         [tex]= \int\limits^a_0 {9(\frac{a^4}{3}+\frac{a^4}{3} +a^2z^2 )} \, dz[/tex]  [tex]= \int\limits^a_0 {9(\frac{2a^4}{3}+a^2z^2 )} \, dz[/tex]  [tex]= 9 ( \frac{2a^5}{3} + \frac{a^5}{3} )[/tex]  

( taking limits as a and 0 )

hence Mass = 9 [tex](a^5)[/tex]

finding the center of mass

attached below is solution

Answer:the one area < with line underneath then -4

St-by-step explanation: I’m pretty sure this is correct

Answer:

Step-by-step explanation:

[tex] \mathrm{16x - 7 \leqslant - 71}[/tex]

Move constant to Right hand side and change its sign

[tex] \mathrm{16x \leqslant - 71 + 7}[/tex]

Calculate

[tex] \mathrm{16x \leqslant - 64}[/tex]

Divide both sides of the equation by 16

[tex] \mathrm{ \frac{16x}{16} \leqslant \frac{ - 64}{16} }[/tex]

Calculate

[tex] \mathrm{x \leqslant - 4}[/tex]

Hope I helped!

Best regards!

Answer:

x=3

Step-by-step explanation:

(segment piece) x (segment piece) =   (segment piece) x (segment piece)

3x(x+1) = 4x(x)

Divide each side by x

3x(x+1)/x = 4x(x)/x

3(x+1) = 4x

Distribute

3x+3 = 4x

Subtract 3x

3x+3-3x= 4x-3x

3 =x

Answer:

x = 3

Step-by-step explanation:

0 is a rediculas answer 9 and 12 are to big.

The lines are supposed to have a simular length:

3(3) + 4 = 13

4(3) + 3 = 15

These are the best answers that fit.

Step-by-step explanation:

Let minimum score on the final exam to earn an A be X

[tex]mean \: = \frac{sum \: of \: observation}{number \: of \: observation} [/tex]

[tex]90 = \frac{83 + 97 + 89 + 82 + x}{5} [/tex]

Further solving :

X = 99 marks

Answer:

13

Step-by-step explanation:

let the number be x

how Cindy worked it out :

(x -6) ÷ 3 = 25

x -6 = 75

x = 81

How she should have worked it out:

(x - 3) ÷ 6

(81 - 3) ÷ 6

78 ÷ 6 = 13

Answer:

The answer is "[tex]\bold{\frac{2}{n}}[/tex]".

Step-by-step explanation:

considering [tex]Y_1, Y_2,........, Y_n[/tex] signify a random Poisson distribution of the sample size of n which means is λ.

[tex]E(Y_i)= \lambda \ \ \ \ \ and \ \ \ \ \ Var(Y_i)= \lambda[/tex]

Let assume that,  

[tex]\hat \lambda_i = \frac{Y_1+Y_2}{2}[/tex]

multiply the above value by Var on both sides:

[tex]Var (\hat \lambda_1 )= Var(\frac{Y_1+Y_2}{2} )[/tex]

            [tex]=\frac{1}{4}(Var (Y_1)+Var (Y_2))\\\\=\frac{1}{4}(\lambda+\lambda)\\\\=\frac{1}{4}( 2\lambda)\\\\=\frac{\lambda}{2}\\[/tex]

now consider [tex]\hat \lambda_2[/tex] = [tex]\bar Y[/tex]

[tex]Var (\hat \lambda_2 )= Var(\bar Y )[/tex]

             [tex]=Var \{ \frac{\sum Y_i}{n}\}[/tex]

             [tex]=\frac{1}{n^2}\{\sum_{i}^{}Var(Y_i)\}\\\\=\frac{1}{n^2}\{ n \lambda \}\\\\=\frac{\lambda }{n}\\[/tex]

For calculating the efficiency divides the [tex]\hat \lambda_1 \ \ \ and \ \ \ \hat \lambda_2[/tex] value:

Formula:

[tex]\bold{Efficiency = \frac{Var(\lambda_2)}{Var(\lambda_1)}}[/tex]

                  [tex]=\frac{\frac{\lambda}{n}}{\frac{\lambda}{2}}\\\\= \frac{\lambda}{n} \times \frac {2} {\lambda}\\\\ \boxed{= \frac{2}{n}}[/tex]

Answer:

[tex]$\mathbf{\frac{1}{19} }[/tex]

Step-by-step explanation:

[tex]$$\bullet \Nth \ Term;\\$$$\frac{n+2}{2n^{2} +3n-2}[/tex]

[tex]$$\bullet U_{10} \ Term;\\\\$$\boxed{\frac{(10+2) }{2*10^{2} +3*10-2}= \frac{1}{19} }[/tex]

Answer:

[tex]\boxed{\displaystyle \frac{1}{19}}[/tex]

Step-by-step explanation:

[tex]\displaystyle \frac{n+2}{2n^2 +3n-2}[/tex]

Replace n with 10 to find the 10th term.

[tex]\displaystyle \frac{10+2}{2(10)^2 +3(10)-2}[/tex]

Evaluate.

[tex]\displaystyle \frac{12}{2(100) +30-2}[/tex]

[tex]\displaystyle \frac{12}{200 +30-2}[/tex]

[tex]\displaystyle \frac{12}{228}[/tex]

Simplify.

[tex]\displaystyle \frac{1}{19}[/tex]

Answer:

Option (D) : (3.5, 8.75)

Answer:

a number, r, added to 6

Step-by-step explanation:

a number, r, added to 6

Answer:

a number, r, added to 6

Step-by-step explanation:

a number, r, added to 6

Answer:

Y=2(1)+4

Y=2+4

Y=6

Step-by-step explanation:

Please follow me

Answer:

a

Step-by-step explanation:

its a

The answer is m = 3000 - 40h

m = 1200 + 50h.

The answer is option A.

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Answer:

[tex]-1 \frac{3}{4}[/tex]

Step-by-step explanation:

Using this number line, we can plot our original number - [tex]\frac{3}{4}[/tex] (see picture attached)

Adding a negative is the same thing as subtracting - so we are subtracting [tex]2\frac{1}{2}[/tex] from  [tex]\frac{3}{4}[/tex].

To subtract this, we can break up [tex]2\frac{1}{2}[/tex]  into 3 parts: 1, 1, and [tex]\frac{1}{2}[/tex]. We can subtract each of these from the current number and see where we land up. (again see picture)

We land up at [tex]-1 \frac{3}{4}[/tex].

Hope this helped!

Answer:

a

   The  90%  confidence interval is  [tex]52561.13 < \mu < 57540.8[/tex]

b

Confidence interval for the population men between $52561.13  up to $57540.8

Step-by-step explanation:

From the question we are told that

   The sample size is  [tex]n = 25[/tex]

     The  sample mean is  [tex]\= x = \$ 55,051[/tex]

     The standard deviation is  [tex]\sigma = \$ 7,568[/tex]

Given that the confidence level is  90% then the level of confidence is mathematically represented as

             [tex]\alpha = 100 -90[/tex]

              [tex]\alpha = 10\%[/tex]

             [tex]\alpha = 0.10[/tex]

Next we obtain the critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table the values is  

               [tex]Z_{\frac{\alpha }{2} } = 1.645[/tex]

Generally the margin of error is mathematically  represented as

               [tex]E = Z_{\frac{ \alpha }{2} } * \frac{ \sigma }{\sqrt{n} }[/tex]

substituting values

               [tex]E = 1.645 * \frac{ 7568}{ \sqrt{ 25} }[/tex]

             [tex]E = 2489.9[/tex]

The 90% confidence interval is mathematically evaluated as

       [tex]\= x -E < \mu < \= x +E[/tex]

substituting values

     [tex]55051 - 2489.8 < \mu < 55051 + 2489.8[/tex]

     [tex]52561.13 < \mu < 57540.8[/tex]

Answer:

d = s x t

Step-by-step explanation:

The formula for distance.

Answer:

B) 2

/////////////////

Answer:

Part a ) The degrees of freedom for the given two sample non-pooled t test is 24

Part b ) The degrees of freedom for the given two sample non-pooled t test is 30

Part c ) The degrees of freedom for the given two sample non-pooled t test is 30

Part d ) The degrees of freedom for the given two sample non-pooled t test is 25

Step-by-step explanation:

Degrees of freedom for a non-pooled two sample t-test is given by;

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Now given the information;

a) :- m = 12, n = 15, s₁ = 4.0, s₂ = 6.0

we substitute

Δf =  {[ 4²/12 + 6²/15 ]²} / {[( 4²/12)²/12-1] + [(6²/15)²/15-1]}

Δf  = 30184 / 1241

Δf  = 24.3223 ≈ 24 (down to the nearest whole number)

b) :- m = 12, n = 21, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/12 + 6²/21 ]²} / {[( 4²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 56320 / 1871

Δf = 30.1015 ≈ 30 (down to the nearest whole number)

c) :- m = 12, n = 21, s₁ = 3.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 3²/12 + 6²/21 ]²} / {[( 3²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 29095 / 949

Δf = 30.6585 ≈ 30 (down to the nearest whole number)

d) :- m = 10, n = 24, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/10 + 6²/24 ]²} / {[( 4²/10)²/10-1] + [(6²/24)²/24-1]}

Δf = 1044 / 41  

Δf = 25.4634 ≈ 25 (down to the nearest whole number).

Answer:

see explanation

Step-by-step explanation:

(f - g)(x) = f(x) - g(x) , that is

f(x) - g(x)

= - 5x³ - 4x² + 8x - (- 4x² + 8) ← distribute parenthesis by - 1

= - 5x³ - 4x² + 8x + 4x² - 8 ← collect like terms

= - 5x³ + 8x - 8

Substitute x = - 2 into this expression, thus

(f - g)(- 2)

= - 5(- 2)³ + 8(- 2) - 8

= - 5(- 8) - 16 - 8

= 40 - 16 - 8

= 16

Answer:

Segment LM Corresponds to RQ    

Segment R corresponds to angle M

Answer:

Step-by-step explanation:

six hundred men,six hundred men with big mouths to feed

Answer:

45

Step-by-step explanation:

multiply 9 by 5 to get 45

then, multiply 45 by 5 to get 225

The geometric sequence is 5(previous number)

[tex]f(f(3))=2\cdot3^2+1=19\\f(f(f(f(3))))=2\cdot19^2+1=723[/tex]

Answer:

= - 54

Step-by-step explanation:

- 99 + 3^2•5

- 99 + 9 × 5

- 99 + 45

= - 54

Answer:

Three fractions that are equivalent to [tex]\frac{3}{11}[/tex] are: [tex]\frac{6}{22}[/tex], [tex]\frac{24}{88}[/tex] and [tex]\frac{144}{528}[/tex].

Step-by-step explanation:

Equivalent fractions are set of fractions in which when simplified, they have the same answer.

Given: [tex]\frac{3}{11}[/tex]

i. multiply the numerator and denominator of [tex]\frac{3}{11}[/tex] by 2,

          = [tex]\frac{3*2}{11*2}[/tex] = [tex]\frac{6}{22}[/tex]

i. multiply both the numerator and denominator of [tex]\frac{6}{22}[/tex] by 4,

          = [tex]\frac{6*4}{22*4}[/tex]= [tex]\frac{24}{88}[/tex]

ii. multiply the numerator and denominator of [tex]\frac{24}{88}[/tex] by 6,

          = [tex]\frac{24*6}{88*6}[/tex] = [tex]\frac{144}{528}[/tex]

So that;

             [tex]\frac{3}{11}[/tex] = [tex]\frac{6}{22}[/tex] = [tex]\frac{24}{88}[/tex] = [tex]\frac{144}{528}[/tex].

Three fractions that are equivalent to [tex]\frac{3}{11}[/tex] are: [tex]\frac{6}{22}[/tex], [tex]\frac{24}{88}[/tex] and [tex]\frac{144}{528}[/tex].

Answer:

Multiply using the distributive property.

D is the best answer.

Step-by-step explanation:

The simplified form of expression 3x (4x - 3) is 12x² - 9x.

An algebraic expression is consists of variables, numbers with various mathematical operations,

The given expression is,

3x (4x - 3).

Simplify the expression by solving bracket term,

3x × (4x) - 3 x (3x)

12x² - 9x

The given expression can be simplified as 12x² - 9x.

Hence, option (D) is correct.

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Answer:

5^3  y^5

125 y^5

Step-by-step explanation:

5y^3/(5y)^-2​

Distribute the exponent in the denominator

5y^3/(5 ^-2 y^-2)

A negative exponent in the denominator brings it to the numerator

5y^3 5 ^2 y^2​​

Combine like terms

5 * 5^2  * y^3 5^2

We know that a^b * a^c = a^(b+c)

5^(1+2) * y^( 3+2)

5^3  y^5

125 y^5

Answer:

So first you do $0.50 x 3 = 1.5

then you add that to $12.00

$12.00 + 1.5 = 13.5

13.5 is the cost of one pizza.

Since they bought 12:

The total cost of the 12 pizza is $162 <== not important

13.5 divided by 8 is 1.687

round 1.56875 to the nearest cent 1.7 = $2

so each slice costs $2

Answer:

[tex]S = 3 h[/tex]

Step-by-step explanation:

Let M represent Michaela hair tier and S represents Michaela  sister's

Given

M = h

S = Triple of M

Required

Determine an expression for S

From the given parameters, we have that;

S = Triple of M

Mathematically, this implies;

[tex]S = 3 * M[/tex]

Substitute h for M

[tex]S = 3 * h[/tex]

[tex]S = 3 h[/tex]

Hence, the expression for Michaela  sister' is [tex]S = 3 h[/tex]

Answer:

300

Step-by-step explanation:

We need to find 12/37 of 444.

12/37 * 444 = 12/37 * 444/1 = (12 * 444)/(37 * 1) = 5328/37 = 144

She sat in the back seat 144 times out of 444.

444 - 144 = 300

She sat in the front seat 300 times.

Answer:

V = 523 in^3

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

V = 4/3 ( 3.14) * 5^3

V = 523.33333repeating

Rounding to the nearest inch^3

V = 523 in^3

Answer:

[tex] 523.6 {in}^{3} [/tex]

Step-by-step explanation:

[tex]v = \frac{4}{3} \pi {r}^{3} \\ = \frac{4}{3} \pi \times 5 \times 5 \times 5 \\ = 523.6 {in}^{3} [/tex]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27