What is the solution to this inequality?
-16x>-80
A. x < 5
O B. x>-5
O c. x<-5
O D. x>5

Answer:

0 is the answer . The explanation is in the attachment .

Answer:

C.

Step-by-step explanation:

A concave polygon must have atleast an internal angle which is greater than other angles.

[tex]{ \underline{ \blue{ \sf{christ \: † \: alone}}}}[/tex]

Answer:

13/50

Step-by-step explanation:

Answer:

26/100

Method:

Fractions are much like percents, as they are both out of 100. The 26% is 26%/100% (26/100)

Answer:

100000 = 8 (4) ^t

Step-by-step explanation:

We are multiplying by 4 each time

y = a (4)^t

The initial amount is 8

y = 8 (4)^t

We want to get to 100000

100000 = 8 (4) ^t

Answer:

B

8 ⋅ 4^t  = 100,000

Step-by-step explanation:

Answer:

.71

Step-by-step explanation:

We only need to look at the brown eyes row

2+2+10 =14

Brown hair is 10

P(brown hair) = brown hair / total

                        =10/14 =5/7 = .714285714

Answer:

11341-5=11336

-122+42=-80, when you have different signs always keep in mind that you have to subtract and then get the sign of the big number.

for the third one you firstly have to work with the two negative signs,you have to multiply them, take note that when you multiply a negative by a negative you get a positive, a positive by a positive you get a positive and a negative by a positive you get a negative.

-0.35-(-0.25)

-0.35+0.25

=-0.1

I hope this helps

The steps to create attached screenshot of the inscribed circle of triangle ΔABC using GeoGebra tools includes;

1) Clicking on the Geometry link, under Powerful Math Apps group

2) On the opened Geometry page click on the Polygon icon and follow the instructions that come up, which is Select all vertices and then the first vertex (selected) again (a second time)

3) Once the triangle is created, select the Angle Bisector icon, under the Construct group; A message will appear, asking to Select three points or two lines, select three vertex, of the triangle created with a mouse click, with the vertex A in the center, such as BAC, or CAB a straight line representing the angle bisector of angle ∠A is created

4) Repeat the above to create the angle bisector of angle ∠B

5) Click on the Point button under the Basic Tools group, then click on the intersection of the two angle bisectors created above, the point will be automatically labelled point D

6) Click on the Perpendicular Line, icon under the Construct group, then click on point D, and then the line AB to draw the perpendicular from D to AB

7) Click on the point Point icon and then the intersection point of the perpendicular from D and AB to label the point E

8) Click on the Circle with Center basic tool and then points D and E above, to create the inscribed circle of triangle ΔABC

9) Select the Segment tool, then select the center of the circle and a point

on the circumference. Click on the label, from the pop up options, select

the label option AA then change the label of the segment created to Radius

and select Show Label and Show Value. The inscribed circle of ΔABC created with GeoGebra tools is attached

Learn more about GeoGebra hear;

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Answer:

Step-by-step explanation: from edmentum

Step-by-step explanation:

+ Both equations

You will get : 5x=13 ; x=13/5

and put x to the first equation

2*13/5-y=4

y=6/5

(13/5;6/5)

Answer is C

Answer:

(1, 3)

Step-by-step explanation:

Since up and down are opposites, the point didn't move at all.

I hope this helps!

pls ❤ and mark brainliest pls!

Answer:

jejejjejejr

Step-by-step explanation:

uejejjejejjsjs

Answer:

Option D, 52

Answered by GAUTHMATH

Step-by-step explanation:

The answer is mentioned above.

Hope it helps.

Answer:

1) a³b⁴/ ab³ = a²b

2)2 (x³ )² = 2x^6

3)3x*2x³ y² = 6x⁴y²

Answer:

13 and 17 units

Step-by-step explanation:

explaination is in pic.

The length of the diagonals of the quadrilateral AC and BD are 13 units and 17 units respectively, as per length between two points.

The length between two given points (x₁, y₁) and (x₂, y₂) will be:

√[(x₂ - x₁)² + (y₂ - y₁)²] units

Given, the vertices of a quadrilateral are A(4,-3),B(7,10),C(-8,2)and D(-1,-5).

Therefore, the diagonals of the quadrilateral will be AC and BD.

The coordinates of the diagonal AC are (4, - 3) and (- 8, 2).

Now, the length of the diagonal AC will be:

= √[(-8 - 4)² + (2 - (- 3))²] units

= √[(- 12)² + (5)²] units

= √[144 + 25] units

= √(169) units

= 13 units                                  (length can't be negative)

Similarly, the coordinates of the diagonal BD are (7, 10) and (- 1, - 5).

Now, the length of the diagonal BD will be:

= √[(-1 - 7)² + (- 5 - 10)²] units

= √[(- 8)² + (- 15)²] units

= √[64 + 225] units

= √(289) units

= 17 units                                  (length can't be negative)

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Answer:

m=4

Step-by-step explanation:

m = y2 - y1/x2 - x1

(y2=8, y1=0, x2= 2, x1=0)

m = y2 -y1/x2 - x1

= 8 - 0/2 - 0

= 8/2

=4

Answer: D

Step-by-step explanation:

To get rid of denominator in x, multiply everything by 3

3y=2x+21

Move the variables to the left

-2x+3y=21

Answer:

[tex]2^{\frac{1}{6} }[/tex]

Step-by-step explanation:

(2^1/3)^1/2 = 2^(1/3 x 1/2) =2^1/6

Answer:

48.5 and 34.5

Step-by-step explanation:

83 divided by 2 and then subtract 7

Answer:

45 and 38 equal 83 and 45 is 7 more than 38

[tex]\\ \sf\longmapsto 41sin\Theta=40[/tex]

[tex]\\ \sf\longmapsto sin\Theta=\dfrac{40}{41}[/tex]

Now

[tex]\boxed{\sf cos\Theta=\sqrt{1-sin^2\Theta}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{1-\left(\dfrac{40}{41}\right)^2}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{1-\dfrac{1600}{1682}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{1681-1600}{1681}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{81}{1681}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\dfrac{9}{41}[/tex]

We know

[tex]\boxed{\sf tan\Theta=\dfrac{Sin\theta}{Cos\Theta}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{tan\Theta}{1-tan^2\Theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{sin\Theta}{cos\Theta}}{1-\dfrac{sin^2\Theta}{cos^2\Theta}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{\left(\dfrac{40}{41}\right)}{\left(\dfrac{9}{41}\right)}}{1-\dfrac{\left(\dfrac{40}{41}\right)^2}{\left(\dfrac{9}{41}\right)^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{{40}}{{9}}}{1-\dfrac{{40}^2}{{9}^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{9^2-40^2}{9^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{81-1600}{81}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{-1519}{81}}[/tex]

[tex]\\ \sf\longmapsto {\dfrac{40}{\cancel{9}}}\times \dfrac{\cancel{81}}{(-1519)}[/tex]

[tex]\\ \sf\longmapsto \dfrac{40\times 9}{(-1519)}[/tex]

[tex]\\ \sf\longmapsto - \dfrac{360}{1519}[/tex]

Answer: x=-3

Step-by-step explanation:

2(x)-39=5(x+2x)

2x-39=5(3x)

2x-39=15x

-39=13x

-39/13=-3

Answer:

D. Range

Step-by-step explanation:

The definition of range is as the question says, and we can also use the process of elimination to make sure it's not the others.

A mean is the average of a data set.

A mode is the item that appears the most times.

And a median is the middle number.

As you can see, A, B, C all don't fit the given statement in the question, so it is D. Range.

I hope this helped! :D

Answer:

Step-by-step explanation:

25*-30= -$750

Second: He sells 22 of those calculators for $35 each, so he is making money.

22*35= $770

Third: With the remaining three calculators, he must pay $2 each for returned calculators, so he is losing money again.

3*-2= -6

Add all the costs and sales together, and you get 770-750-6= $14 profit

However, the problem does not say if he gets his money back for the 3 returned calculators. In that case if he did, you would add the cost of each of those calculators to his profit. 30*3= 90

$90+$14= $104 profit

here u go

Answer:

9/8 = n

Step-by-step explanation:

9 = 8n

Divide each side by 8

9/8 = 8n/8

9/8 = n

Answer:

[tex]x^{\frac{3}{2} } p^{6}[/tex]

Step-by-step explanation:

Answer:

Therefore 3/10 is closer to ½

Step-by-step explanation:

We've to get the difference:

» with 3/10 :

[tex] \frac{1}{2} - \frac{3}{10} = { \boxed{\frac{1}{5} }}[/tex]

» with 5/7

[tex] | \frac{1}{2} - \frac{5}{7} | = { \boxed{ \frac{3}{14} }}[/tex]

but:

[tex] \frac{3}{14} > \frac{1}{5} [/tex]

Among both the given fractions, the one that is closer to a ½ is 3/10.

A number that is stated as a quotient in mathematics, when the numerator and denominator are split in half. Both are integers in a straightforward fraction. In the numerator or denominator of a complex fraction is a fraction.

An element of a whole or, more broadly, any number of equal pieces, is represented by a fraction. When used in conversational English, a fraction indicates the number of components of a particular size, as in one-half, eight-fifths, and three-quarters.

A fraction is a number that represents a portion of a whole. In order to evaluate it, a whole is divided into a number of components.  A correct fraction has a numerator that is lower than its denominator.

Required calculations are done with both the fractions,

1/2 - 3/10 = 1/5

1/2 - 5/7 = 3/14

3/14 ≥ 1/5

Therefore, among both the given fractions, the one that is closer to a ½ is 3/10.

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Answer:

The Empty set............

Answer:

There is no solution for the intersection of these two sets, as they do not intersect! They don't have any numbers in common and thus form an empty set. The correct answer choice is option D. the empty set.

Step-by-step explanation:

The solution for { x | x <-5} is ---> x < -5

The solution for { x | x >5 } is ---> x > 5

If you placed the two sets on a number line close to each other, you would see that they do not intersect. Thus there is no solution for the intersection of set A and set B as defined in the given problem.

See the graph for better understanding. You see how there's an empty space or area between -5 and 5? Yeah, this is called the empty set which is option D from your answer choices.

A midpoint is a point that divides a given line into two equal halves.The answers to the questions are:

1. BC = 89

b. AB = 45

c. AC = 44

2. The coordinate of I is 2.5

3. J = 19

4. MQ = 32

5. NO = 13

6. NO = 23

b. MN = 25

A line segment can be divided into different fractions. Where the point that divides the line segment into equal parts is the midpoint. however, number line is a system that shows the location or positions of all directed numbers.

The given questions can be solved as follows:

1. Given that point A is between BC and AB = 4x -3, BC = 7x + 5, AC = 5x - 16

But,

BC = AB + AC

7x + 5 = (4x -3) + (5x - 16)

          = 9x - 19

7x + 5 = 9x - 19

19 + 5 = 9x - 7x

24 = 2x

x = [tex]\frac{24}{2}[/tex]

x = 12

So that;

a. BC = 7x + 5

         = 7(12) + 5

BC = 89

The value of BC is 89.

b. AB = 4x -3

         = 4(12) - 3

AB = 45

Thus AB has a value of 45.

c.  AC = 5x - 16

          = 5(12) -16

 AC = 44

The value of AC is 44.

2. Given that H is the mid point of GI, and G = 8, I = -3.

Then;

I = 2.5

The coordinate of I is 2.5

3. A midpoint is a point that divides a line segment in to two equal halves. Given that J is the midpoint of KL. KL = 38

J = [tex]\frac{KL}{2}[/tex]

  = [tex]\frac{38}{2}[/tex]

J = 19

The value of the midpoint J is 19.

4. It can be deduced from the conditions given in the question that:

  MQ = MN + NO + OP + PQ

          = 8 + 8 + 16      (NB: OP + PQ = 16)

MQ = 32

Thus, value of MQ is 32.

5. Since P is the mid point of NQ, and OP = 11, OQ = 35

 Then;

PQ  = OQ - OP

      = 35 - 11

PQ = 24

Since, PQ = NP =24

Then;

NO = NP - OP

      = 24 - 11

NO = 13

NO has a length of 13.

6. NO = 2y + 11, OP = 3y - 2, NP = 6y + 3 and MP = 64.

But,

NO + OP = NP

(2y + 11) + (3y - 2) = 6y + 3

5y + 9 = 6y + 3

9 - 3 = 6y - 5y

y = 6

So that;

a. NO = 2y + 11

          = 2(6) + 11

NO = 23

Here, the value of NO is 23.

b. MN = MP - NP

But,

NP = 6y + 3

     = 6(6) + 3

NP = 39

Then;

MN = 64 - 39

MN = 25

So that MN has a value of 25.

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Answer:

5*2 +2*2 = s*2

s = 5.38

s = 5.4