Answer:
f(x) = 4x² + 48x + 149
Step-by-step explanation:
f(x) = 4(x + 6)² + 5
The above expression can be written as: f(x) = ax² + bx + c, by doing the following:
1. Expand (x + 6)²
(x + 6)² = (x + 6)(x + 6)
(x + 6)(x + 6)
x(x + 6) + 6(x +6)
x² + 6x + 6x + 36
x² + 12x + 36
(x + 6)² = x² + 12x + 36
2. Substitute x² + 12x + 36 for (x + 6)² in
f(x) = 4(x + 6)² + 5
This is illustrated below:
f(x) = 4(x + 6)² + 5
(x + 6)² = x² + 12x + 36
f(x) = 4(x² + 12x + 36) + 5
Clear bracket
f(x) = 4x² + 48x + 144 + 5
f(x) = 4x² + 48x + 149
Therefore, the standard of the function:
f(x) = 4(x + 6)² + 5
is
f(x) = 4x² + 48x + 149
How many significant figures does each value contain? 5.6803 kg has significant figures. 0.00047 seconds has significant figures. 0.240 miles has significant figures.
Answer:
5.6803 has five significant figures.
0.00047 has two significant figures.
0.240 has three significant figures.
What are Significant Figures?Significant figures are numbers that are necessary to express a true value.
Place the values in scientific notation.
[tex]5.6803 * 10^{0} = 5.6803\\\\4.7 * 10^{-4} = 0.00047\\\\2.4 * 10^{-1}=0.240[/tex]
Explanation5.6803
The zero that is within 5.6803 is "trapped," meaning it is in between two nonzero digits. Therefore, all five digits are significant figures.
This answer is also already in scientific notation because 5.6803 satisfies the inequality [tex]1 < x < 10[/tex], which decides if a number is correctly written in scientific notation or not.
0.00047
The zeroes that precede the 4 and the 7 are not significant because they are dropped in scientific notation and are not trapped by other nonzero digits. Therefore, only two digits of this value are significant.
0.240
Since the zero at the end of 0.240 is a trailing zero, it is significant along with the 2 and the 4. The zero that precedes these digits and the decimal point is not significant. Therefore, only three digits of this value are significant.
Therefore:
5.6803 has five significant figures.
0.00047 has two significant figures.
0.240 has three significant figures.
add 2 hours 40 minutes to 11 hours 40 minutes
Answer:
14 hours and 20 minutes
Step-by-step explanation:
11 hours + 2 hours = 13 hours
40 minutes + 40 minutes = 1 hour and 20 minutes
Then you add the answers together
13 hours + 1 hour 20 minutes = 14 hours and 20 minutes
Hope this helps
Answer:
860min or 13:80=14:20=2:20
Step-by-step explanation:
1 hour=60min
2 hours=120min
So, we will add 120min to 40 min
120min+40min=160min
1hour=60min
11hour=660min
So we will add 660min to 40min
660min+40min=700min
160min+700min=860min
2:40
+11:40
13:80
Hope this helps ;) ❤❤❤
According to the number line, which statement MUST be true? A) A > 1 B) B > 4 C) C < 4 D) D < 0
Answer:
The anwser is C) C < 4
......... .
Rita got three colors of beads, half of them are pink. She used all her pink beads to make some bracelets. If the number of pink beads she used for each bracelet is one eighths of the total number of beads, how many bracelets did she make?
Answer: she made 4 bracelets.
Step-by-step explanation:
Let x, y, z are the number of three kinds of beads, where x= number of pink beads.
As per given, number of pink beads= half of total beads
[tex]\Rightarrow\ x=\dfrac{1}{2}(x+y+z)\\\\\Rightarrow 2x= x+y+z\\\\\Rightarrow\ x= y+z\ \ \ ...(i)[/tex]
Also, She used all pink beads, Number of pink beads she used for each bracelet= one eighths of the total number of beads
[tex]\dfrac{1}{8}(x+y+z)\\\\=\dfrac{1}{8}(x+x)\ \ \ [ {\text{From (i)}}][/tex]
[tex]=\dfrac{1}{8}(2x)\\\\=\dfrac{x}{4}[/tex]bracelets =
Number of bracelets = (Number of pink beads) ÷ (Number of pink beads used for each bracelet)
[tex]=\dfrac{x}{\dfrac{x}{4}}=4[/tex]
Hence, she made 4 bracelets.
ALGEBRAIC EXPRESSION 11. Subtract the sum of 13x – 4y + 7z and – 6z + 6x + 3y from the sum of 6x – 4y – 4z and 2x + 4y – 7. 12. From the sum of x 2+ 3y 2 − 6xy, 2x 2 − y 2 + 8xy, y 2 + 8 and x 2 − 3xy subtract −3x 2 + 4y 2 – xy + x – y + 3. 13. What should be subtracted from x 2 – xy + y 2 – x + y + 3 to obtain −x 2+ 3y 2− 4xy + 1? 14. What should be added to xy – 3yz + 4zx to get 4xy – 3zx + 4yz + 7? 15. How much is x 2 − 2xy + 3y 2 less than 2x 2 − 3y 2 + xy?
Answer:
Explained below.
Step-by-step explanation:
(11)
Subtract the sum of (13x - 4y + 7z) and (- 6z + 6x + 3y) from the sum of (6x - 4y - 4z) and (2x + 4y - 7z).
[tex][(6x - 4y - 4z) +(2x + 4y - 7z)]-[(13x - 4y + 7z) + (- 6z + 6x + 3y) ]\\=[6x-4y-4z+2x+4y-7z]-[13x-4y+7z-6z+6x+3y]\\=6x-4y-4z+2x+4y-7z-13x+4y-7z+6z-6x-3y\\=(6x+2x-13x-6x)+(4y-4y+4y-3y)-(4z+7z+7z-6z)\\=-11x+y-12z[/tex]
Thus, the final expression is (-11x + y - 12z).
(12)
From the sum of (x² + 3y² - 6xy), (2x² - y² + 8xy), (y² + 8) and (x² - 3xy) subtract (-3x² + 4y² - xy + x - y + 3).
[tex][(x^{2} + 3y^{2} - 6xy)+(2x^{2} - y^{2} + 8xy)+(y^{2} + 8)+(x^{2} - 3xy)] - [-3x^{2} + 4y^{2} - xy + x - y + 3]\\=[x^{2} + 3y^{2} - 6xy+2x^{2} - y^{2} + 8xy+y^{2} + 8+x^{2} - 3xy]- [-3x^{2} + 4y^{2} - xy + x - y + 3]\\=[4x^{2}+3y^{2}-xy+8]-[-3x^{2} + 4y^{2} - xy + x - y + 3]\\=4x^{2}+3y^{2}-xy+8+3x^{2}-4y^{2}+xy-x+y-3\\=7x^{2}-y^{2}-x+y+5[/tex]
Thus, the final expression is (7x² - y² - x + y + 5).
(13)
What should be subtracted from (x² – xy + y² – x + y + 3) to obtain (-x²+ 3y²- 4xy + 1)?
[tex]A=(x^{2} - xy + y^{2} - x + y + 3) - (-x^{2}+ 3y^{2}- 4xy + 1)\\=x^{2} - xy + y^{2} - x + y + 3 +x^{2}- 3y^{2}+ 4xy -1\\=2x^{2}-2y^{2}+3xy-x+y+2[/tex]
Thus, the expression is (2x² - 2y² + 3xy - x + y + 2).
(14)
What should be added to (xy – 3yz + 4zx) to get (4xy – 3zx + 4yz + 7)?
[tex]A=(4xy-3zx + 4yz + 7)-(xy - 3yz + 4zx) \\=4xy-3zx + 4yz + 7 -xy + 3yz - 4zx\\=3xy-7zx+7yz+7[/tex]
Thus, the expression is (3xy - 7zx + 7yz + 7).
(15)
How much is (x² − 2xy + 3y²) less than (2x² − 3y² + xy)?
[tex]A=(2x^{2} - 3y^{2} + xy)-(x^{2} - 2xy + 3y^{2})\\=2x^{2} - 3y^{2} + xy-x^{2} + 2xy - 3y^{2}\\=x^{2}-6y^{2}+3xy[/tex]
Thus, the expression is (x² - 6y² + 3xy).
Find an equation of the line: Through the point (2, −4) with a y-intercept of −2 Through the points (4,2) and (3,1) Through the point (3,2) with a slope of −2
Answer and Step-by-step explanation: Equations of line through points and slope can be determined by:
[tex]y-y_{0}=m(x-x_{0})[/tex]
m is slope
Point (2,-4) and y-intercept = -2Y-intercept is point (0,-2)
m = [tex]\frac{y_{a}-y_{b}}{x_{a}-x_{b}}[/tex]
m = [tex]\frac{-4-(-2)}{2-0}[/tex]
m = - 1
Equation:
[tex]y+2=-1(x-0)[/tex]
[tex]y=-x-2[/tex]
Points (4,2) and (3,1)m = [tex]\frac{2-1}{4-3}[/tex]
m = 1
Equation:
[tex]y-2=(x-4)[/tex]
[tex]y=x-2[/tex]
Point (3,2) and slope = -2m = -2
Equation:
[tex]y-2=-2(x-3)[/tex]
[tex]y=-2x+6+2[/tex]
[tex]y=-2x+8[/tex]
A rectangular prism has a volume of 864 cubic units. How many cubic unit will fill the volume of the solid if they were packed without any gaps or overlaps
Answer: 864.
Step-by-step explanation:
The volume of a rectangular prism has a volume equal to:
V = W*L*H
W = width
L = length
H = height
We know that the volume is equal to 864 cubic units.
This means that if we want to fill the prism such that there is no gap or overlap, we should use exactly 864 unit cubes.
Find the greatest common factor for each of the following expressions, then factor each expression. a. 4p – 4 = ? b. x4 + x3 + x2 = ? c. 8p2 + 9p2q = ? d. x2y2 + 3xy – 4x – 2x4y3 = ? Factor each of the following expressions. a. 4a3 + 28a2 + 4a + 28 = ? b. x3 + 3x2− 2x − 6 = ? c. 8x2− 4xy + 2x − y = ? Factor each of the following, using the difference of perfect squares where possible. a. u2 – 100 = ? b. 4a2 − 49 = ? c. 81 − y2= ? d. 16q4− 16 = ? e. 9c3− 9c = ? f. 48a2b − 12b = ?
Answer:
1. a. Greatest common factor: 4
b. Greatest common factor: x2
c. Greatest common factor: p2
d. Greatest common factor: x
2. a. (a2 + 1)(4a + 28)
b. (x + 3)(x2− 2)
c. (4x+ 1)(2x−y)
3. a. u2 – 100 = (u + 10)(u − 10)
b. 4a2 − 49 = (2a + 7)(2a − 7)
c. 81 − y2= (9 + y)(9 − y)
d. 16q4− 16 = 16(q4 − 1) 16 (q4 −1) = 16(q2 + 1) (q2− 1) = 16(q2 + 1) (q + 1) (q − 1)
e. 9c3− 9c = 9c (c2− 1) = 9c(c + 1)(c − 1)
f. 48a2b − 12b = 12b (4a2− 1) = 12b(2a + 1)(2a − 1)
Step-by-step explanation:
I got it at PennFoster
wyatt uses 3.15 cups of flour in a recipe that makes 9 shortcakes. Cora uses 2.4 cups of flour in a recipe that makes 8 shortcakes. How much more flower per shortcake is needed for Cora's recipe?
Answer:
0.3
Step-by-step explanation:
You have to divide 2.4 ➗ 8
what is the cost of paving a driveway that is 18m long and 4 m wide, if the paving costs $35 per square metre?
Answer:
$2520
Step-by-step explanation:
→ Work out the area of the drive way
18 m × 4 m= 72 m²
→ Multiply the area by the cost per square metre
72 m² × $35 = $2520
The cost of paving a driveway that is 18m long and 4 m wide, if the paving costs $35 per square metre is $2520.
To calculate the cost of paving the driveway, you need to find the total area of the driveway and then multiply it by the cost per square meter.
The total area of the driveway can be calculated using the formula:
Area = length × width.
Given that the driveway is 18 meters long and 4 meters wide, the area would be:
Area = 18m × 4m
Area = 72 square meters.
Now, find the cost of paving the driveway by multiplying the area by the cost per square meter:
Cost = Area × Cost per square meter
Cost = 72 square meters × $35/square meter
Cost = $2520.
So, the cost of paying the driveway would be $2520.
To learn more on Area click:
https://brainly.com/question/20693059
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Help please and explain
Answer:
30 ft
Step-by-step explanation:
We can use ratios
3 6
------ = ------------
15 x
Using cross products
3x = 6*15
Divide each side by 3
3x/3 = 6*15/3
x = 30
Answer:
30 ft
Step-by-step explanation:
6/3 = x/15
2 = x/15
2×15 = x
30 = x
Write 1.4888.. in form of p/q
Let x = 1.4888... .
Then 10x = 14.888... and 100x = 148.888..., so that
100x - 10x = 148.888... - 14.888...
90x = 147
x = 147/90 = 49/30
Find x. A. 22 B. 113–√ C. 222–√ D. 113√3
Answer:
x = 31.12
Step-by-step explanation:
First find the base (hypotenuse) of the smaller triangle (the isosceles triangle): Its three sides are 11, 11 and b. b can be found using the Pythagorean Theorem: b^2 = 11^2 + 11^2 = 242. Then b = √242, or b = approximately 15.56.
b (which is approximately 15.56) is the shorter leg of the large (right) triangle. The trig function needed to solve for x is the cosine:
adjacent side
cos 60 degrees = ----------------------
hypotenuse,
15.56
which becomes (1/2) = ------------
x
Solving this for x, we get: x = 2(15.56) = 31.12
Trevor thought there would only be 8 teams in the soccer tournament, but there were 17. What was his percent error?
Answer:
Around 52.94%
Step-by-step explanation:
We can use the percentage error formula, which is
[tex]\frac{|approx-exact|}{exact}\cdot100[/tex].
The approximated value was 8, however the exact value was 17, so we can substitute inside the equation.
[tex]\frac{|8-17|}{17}\cdot100 \\\\\frac{|-9|}{17}\cdot100 \\\\\frac{9}{17}\cdot100 \\\\0.5294...\cdot100 \\\\52.94[/tex]
Hope this helped!
Christine, Dale, and Michael sent a total of 71 messages during the weekend. Dale sent 9 fewer messages than Christine. Michael sent 2 times as many messages as Christine. How many messages did they each send?
Answer:
Micheal sent 40 messages, Christine sent 20, and Dave sent 11.
Step-by-step explanation:
Christine, Dale, and Michael sent a total of 71 messages
C + D + M = 71
Dale sent 9 fewer messages than Christine
D = C - 9
Michael sent 2 times as many messages as Christine
M = 2C
Plug-in the numbers.
C + C - 9 + 2C = 71
4C - 9 = 71
4C = 80
C = 20
Now, plug in to other equations for other results.
D = (20) - 9
D = 11
M = 2(20)
M = 40
Micheal sent 40 messages, Christine sent 20, and Dave sent 11.
Verify?
40 + 20 + 11 = 71.
Simplify 27^(-2/3) x 25^(1/2) x 5^0 9 5 9/5 5/9
Answer:
[tex]\frac{5}{9}[/tex]
Step-by-step explanation:
Using the rules of exponents/ radicals
[tex]a^{\frac{m}{n} }[/tex] ⇔ [tex]\sqrt[n]{a^{m} }[/tex] , [tex]a^{0}[/tex] = 1
[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex]
Given
[tex]27^{-\frac{2}{3} }[/tex] × [tex]25^{\frac{1}{2} }[/tex] × [tex]5^{0}[/tex]
= [tex]\frac{1}{27^{\frac{2}{3} } }[/tex] × [tex]\sqrt{25}[/tex] × 1
= [tex]\frac{1}{9}[/tex] × 5 × 1
=[tex]\frac{5}{9}[/tex]
The weight of a box varies directly as the volume of the box. If a 138-pound box has a volume of 23 gallons, what is the weight of a box that has a volume of 25 gallons? A. 31 pounds B. 150 pounds C. 138 pounds D. 29 pounds
Answer:
150 pounds
the weight is directly proportional to the volume. hence:
138/23 = 6
now, 25*6 = 150
Answer:
B. 150 pounds
Step-by-step explanation:
Which ppint is the center of the circle?
O point w
O point X
O point Y
O point z
Answer:
??????????????????????????????????????????????????????????????
Step-by-step explanation:
Answer:
where is Point or picture
HELP ASAP
[tex]Given that $33^{-1} \equiv 77 \pmod{508}$, find $11^{-1} \pmod{508}$ as a residue modulo 508. (Give an answer between 0 and 507, inclusive.)[/tex]
===================================================
Work Shown:
[tex]33^{-1} \equiv 77 \text{ (mod 508)}\\\\(3*11)^{-1} \equiv 77 \text{ (mod 508)}\\\\3^{-1}*11^{-1} \equiv 77 \text{ (mod 508)}\\\\3*3^{-1}*11^{-1} \equiv 3*77 \text{ (mod 508)}\\\\11^{-1} \equiv 231 \text{ (mod 508)}\\\\[/tex]
Notice how 33*77 = 2541 and 11*231 = 2541
[tex]2541 \equiv 1 \text{ (mod 508)}[/tex] since 2541/508 has a remainder of 1.
So effectively [tex]33*77 \equiv 1 \text{ (mod 508)}[/tex] and [tex]11*231 \equiv 1 \text{ (mod 508)}[/tex]
Every time Liliana bakes a batch of brownies, she uses 34 cup of chocolate. If she has 128 cup(s) of chocolate remaining, how many batches of brownies can Liliana make? Input your answer as a whole number.
Answer:
3
MARK BRAINLIEST IF THIS HELPED!
i hope u have a great day.
Plz HELP !!!!! I would appreciate it!!!
Answer/Step-by-step explanation:
a. The sides of ∆ABC can be labelled as follows, taking θ as the reference point.
Adjacent = side AB
Opposite = side BC
Hypotenuse = side AC
b. I. "<B is an acute angle" => FALSE. It is a right angle (90°)
II. "The side opposite to <C is BC" => FALSE. The side opposite to <C is AB.
III. The side adjacent to <A is AB => TRUE
IV. The side opposite to <B is not the longest. => FALSE. It is the hypotenuse and the longest side.
c. Cos θ = [tex] \frac{adjacent}{hypotenuse} = \frac{AB}{AC} [/tex]
Tan θ = [tex] \frac{opposite}{adjacent} = \frac{BC}{AB} [/tex]
d. Sin C = [tex] \frac{opp}{hypo} = \frac{AB}{AC} [/tex]
Cos C = [tex] \frac{adjacent}{hypotenuse} = \frac{BC}{AC} [/tex]
Tan C = [tex] \frac{opp}{adjacent} = \frac{AB}{BC} [/tex]
3 Question
Select the correct answer.
What is the value of this expression when a = 2 and b = -3?
a3 - 63
5
Hola
O
O
3
Answer:
The qs is not clear.
Simply put values of a and b and you will get the ans.
Step-by-step explanation:
The same amount of trash is dumped into a landfill every day. The function below shows the total number of tons of trash n in the landfill after x days:
n = 2000x + 1000
What does the number 2,000 represent?
Answer:
Amount of trash added to the landfill everyday
Step-by-step explanation:
If 2000 represents the amount of trash added to the landfill everyday then 1000 is the starting amount.
I got it right on the test. Hope this helped!
Let f (x) = x – 4 and g(x) = 6 - x
Evaluate g(f(10)).
G(f(10))
First solve f(x) by replacing x with 10:
F(x) = x-4 = 10-4 = 6
Now replace x in g(x) with 6
G(x) = 6-x = 6-6 = 0
So g(f(10)) = 0
The graph of function f is shown. Function g is represented by the table. Which statement correctly compares the two functions?
Answer:
Option (A)
Step-by-step explanation:
Graph of function 'f' represents,
x - intercept of the function 'f' → (1, 0)
y - intercept of the function → (0, 6)
As x-approaches ∞, value of the function approaches (-2)
Points in the given table is for the another function 'g'
x - intercept of the function 'g' → (1, 0) [For x - intercept, y = 0]
y - intercept of the function 'g' → (0, 3) [For y - intercept, x = 0]
As x approaches ∞, value of function 'g' approaches (-1).
Therefore, x - intercepts of both the functions are same but end behavior are different when x → ∞.
Option (A) will be the answer.
Figure a is a scale image of figure b. what is the value of x? please answer asap!
Answer:
[tex]\boxed{x = 20}[/tex]
Step-by-step explanation:
Hey there!
Well to find x we need to set up the following.
[tex]\frac{10}{12.5} = \frac{16}{x}[/tex]
Cross multiply
10x = 200
Divide both sides by 10
x = 20
Hope this helps :)
Find the AM and GM for the numbers 18 and 2
Answer:
Step-by-step explanation:
Solution:
AM =( X_1 + X_2 )/2
=( 18 + 2 )/2
=20/2
=10
Find Geometric mean for data 18,2
Solution:
GM =sqrt( X_1 × X_2 )
=sqrt( 18 × 2 )
=sqrt(36)
=6
1. The cost of buying some books is partly constant and partly varies with the number of books bought. The cost is #4800 when 20 books are bought and #8000 when 40 are bought. Find the cost when 1000 books are bought
Answer:
Step-by-step explanation:
let the cost based on number of book bought be x and the constant be c:
4800 = 20x + c
8000 = 40x + c
c is common in both equations:
c =4800-20x
c = 8000-40x
equate the two:
4800-20x = 8000 - 40x
20x = 3200
x = 160
and c = 4800-20*160
c = 1600
Cost of 1000 books:
160*1000 + 1600
= 161600
answer answer it it it
Answer:
May-June
Step-by-step explanation:
Notice that:
● during April-May period the Badminton memberships rate of increase is greather then Swimming's since the graph of Badminton is showing a faster increase.
● During June-July period, both functions are decreasing so this period does not satisfy our condition.
● During May-June The Swimming memberships growed faster than Badminton's so its rate of increase is greather than Badminton's.
● during August-September period, The swimming memeberships are increasing slower than Badminton's
So the answer is May-June
Answer:
May-June
Step-by-step explanation:
HELP ASAP
What is the distance, in units, between the points [tex](-3, -4)[/tex] and [tex](4, -5)[/tex]? Express your answer in simplest radical form.
Answer:
d=5√2 unit
Step-by-step explanation:
distance between two points d=√(x2-x1)²+(y2-y1)²
two pints (-3,-4) and (4,-5)
d=√(4-(-3)²+(-5-(-4)²
d=√(4+3)²+(-5+4)²
d=√49+1
d=√50
d=√25*2
d=5√2
Answer
[tex] \boxed{5 \sqrt{2} \: \: \:units}[/tex]
Step by step explanation
Let the points be A and B
A ( - 3 , - 4 ) ⇒( x₁ , y₁ )
B ( 4 , - 5 )⇒( x₂ , y₂ )
Now, let's find the distance between these points :
Distance = [tex] \mathsf{ \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }[/tex]
Plug the values
⇒[tex] \mathsf{ \sqrt{ {(4 - ( - 3))}^{2} + {( - 5 - ( - 4))}^{2} } }[/tex]
Calculate
⇒[tex] \mathsf{ \sqrt{ {(4 + 3)}^{2} + {( - 5 + 4)}^{2} } }[/tex]
⇒[tex] \mathsf{ \sqrt{ {(7)}^{2} + {( - 1)}^{2} } }[/tex]
Evaluate the power
⇒[tex] \mathsf{ \sqrt{49 + 1} }[/tex]
Add the numbers
⇒[tex] \mathsf{ \sqrt{50} }[/tex]
Simplify the radical expression
⇒[tex] \mathsf{5 \sqrt{2} \: \: units}[/tex]
Hope I helped!
Best regards!!