What is the value of the following function when x = 0?
у = -5
y = -2
y = -1
y = 0

Answer:

AB=44.98298

Step-by-step explanation:

Since this is  a right triangle, we can use trig functions

cos theta = adj / hyp

cos 12 = 44/AB

AB cos 12 = 44

AB = 44/ cos 12

AB=44.98298

the answer is

A. 28, 25, 22

Answer:

1≤f(x)≤5

Step-by-step explanation:

-1≤x≤1

-2≤2x≤2 (Multiplied by 2 both side)

-2+3≤2x+3≤2+3 (Adding three both sides)

1≤f(x)≤5

It's bottom left

It says let C represent the cost of a one-year membership.

C is 80 in order to represent the day you must divide it by 10.

which gives one box for day and 10 boxes for year

Answer:

16 inches³

Step-by-step explanation:

Volume of prism = base area * height

Base is square, so area of base = side * side = 2 * 2 = 4 in²

Volume of prism = 4 * 4

Volume of prism = 16 in³

Answer:

Step-by-step explanation:

2 * 10^7   You are to use a single digit. That's the 2 on the left. Then count what it takes to get the decimal between the 2 and the 3. It's 7

0.000136

Count the number of zeros. Add a minus 1. You want the number to be counted until you get minus 1 which is the number of powers after the 1.

1 * 10^-4

26837 becomes 2 * 10^4. 4 is the number of digits you have before you get to a number between 1 and 10.

0.0302 becomes 3 * 10^-(1 + 1) = 3 * 10^-2

Answer:

The period of y = sin(x) is 2π

The period of y = sin x would be equal to  2π.

The period of the function y = sin x refers to the length of one complete cycle of the graph of the sine function.

In this case, the period is calculated by the coefficient of x, which is 1.

For the function y = sin x, the period is 2π which means that the graph of y = sin x repeats itself every 2π units along the x-axis.

If the graph of y = sin x. Starting from the point (0,0), as x increases by 2π, then the y-values will repeat the same pattern. This repetition continues indefinitely as x increases or decreases.

Therefore, we can conclude that the period of y = sin x is 2π.

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Answer:

AB

Step-by-step explanation:

The segments that are parallel need to be in the same direction ( up and down)

The segments that are parallel are FH, AB, GC

Answer:

AB

Step-by-step explanation:

since is a cube all of the angles are 90 degees and this only possibel whn the line That a vertical a parrelllt to each other

Answer:

56

Step-by-step explanation:

f(x)=6*x^2+2 =6*3^2+2=56

Answer:

56

Step-by-step explanation:

9514 1404 393

Answer:

  2. (only)

Step-by-step explanation:

The Pythagorean theorem tells you the sum of the squares of the two legs of a right triangle is equal to the square of the hypotenuse. To determine if these are right triangles, determine if that condition is met.

  1. 3^2 +5^2 = 9 + 25 = 34 ≠ (√35)^2 . . . . not a right triangle

  2. 5^2 +4^2 = 25 +16 = 41 = (√41)^2 . . . a right triangle

  3. 6^2 +8^2 = 36 +64 = 100 ≠ (√10)^2 . . . . not a right triangle

  4. 3^2 +3^2 = 9 +9 = 18 ≠ (3√3)^2 = 27 . . . . not a right triangle

Answer:

C. -2(-2)

Step-by-step explanation:

A. -2(-1/5) = 1

B. -2(1/2)=1

C. -2(-2)=4

D. -2(2)=-4

Answer:

Theta = 37.9 degrees

AC = 11.4

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp/ adj

tan theta = 7/9

tan ^ -1 tan theta = tan ^-1 (7/9)

theta =37.87498

To 1 decimal place

Theta = 37.9 degrees

We use the Pythagorean theorem to find AC

a^2 + b^2 = c^2

7^2 + 9^2 = AC^2

49+81 = AC^2

130 = AC^2

Taking the square root of each side

sqrt(130) = sqrt(AC^2)

AC = 11.40175

Rounding to 1 decimal place

AC = 11.4

Answer:

The area of the circle is 100 square units.

Step-by-step explanation:

We are given that the circumference of a circle is 20π, and we want to determine its area.

Recall that the circumference of a circle is given by the formula:

[tex]\displaystyle C = 2\pi r[/tex]

Substitute:

[tex]20 \pi = 2 \pi r[/tex]

Solve for the radius:

[tex]\displaystyle r = \frac{20\pi}{2\pi} = 10[/tex]

The area of a circle is given by:

[tex]\displaystyle A = \pi r^2[/tex]

Since the radius is 10 units:

[tex]\displaystyle A = \pi (10)^2[/tex]

Evaluate:

[tex]\displaystyle A = 100\pi\text{ units}^2[/tex]

In conclusion, the area of the circle is 100 square units.

Answer:

(4, 1)

Step-by-step explanation:

See attachment courtesy of Desmos.

Answer:

A " (1,-2)

B " (4,0)

C " (6,-3)

Step-by-step explanation:

Hope it helped.

° ° °

Answer:

10/3 days  or 3 1/3 days

Step-by-step explanation:

Let d = number of days total

75% of the days is 10

.75 d = 10

d = 10/.75

d = 40/3 days

We want to know how man is 25% of d

d * 25%

(40/3) *.25

10/3 days

Answer:

1/25

Step-by-step explanation:

f(x) = 5^x

Let x = -2

f(-2) = 5^-2

We know a^-b = 1/a^b

f(-2) = 1/5^2

      = 1/25

Answer:

[tex]\frac{1}{25} [/tex]

Step-by-step explanation:

[tex]f(x) = {5}^{x} \\ f( - 2) \\ f( - 2) = {5}^{ - 2} \\ = \frac{1}{ {5}^{2} } \\ = \frac{1}{25} [/tex]

Answer:

Step-by-step explanation:

Tan 22 = [tex]\frac{opposite \ side}{adjacent \ side}[/tex]

[tex]tan \ 22 = \frac{30}{x}\\\\0.4040 = \frac{30}{x}\\\\0.4040*x = 30\\\\x = \frac{30}{0.4040}\\\\x = 74.25\\\\x = 74.3[/tex]

Answer:

Sin= opp/hyp

Sin22= 30/x

0.3746=30/x

cross multiply

0.3746x=30

make x the subject of the formula

x= 30/0.3746

x=80

Answer:

O D. 3x2 + 2x-3

Answer:

A.7x2-5x questions 2of 20

Step-by-step explanation:

Hi there!

Please see the answer in the picture.

Hope it helps!

1. Approach

One is given a trigonometric equation with and one is asked to prove that it is true. Using the attached image, combined with the knowledge of trigonometry, one can evaluate each trigonometric function. Then one can simplify each ratio to solve. To yield the most accurate result, one has to each of the ratios in a fractional form, rather than simplifying it into a decimal form. Remember the right angle trigonometric ratios, these ratios describe the relationship between the sides and angles in a right triangle. Such ratios are as follows,

[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}\\\\csc(\theta)=\frac{hypotenuse}{opposite}\\\\sec(\theta)=\frac{hypotenuse}{adjacent}\\\\cot(\theta)=\frac{adjacent}{opposite}[/tex]

Please note that the terms (opposite) and (adjacent) are relative to the angle uses in the ratio, however the term (hypotenuse) refers to the side opposite the right angle, this side never changes its name. Use these ratios to evaluate the trigonometric functions. Then simplify to prove the identity.

2. Problem (9)

[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]

As per the attached image, the following statements regarding the value of each ratio can be made:

[tex]sin(60)=\frac{\sqrt{3}}{2}\\\\cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cos(60)=\frac{1}{2}[/tex]

Substitute,

[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]

[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

Simplify,

[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\frac{2\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\frac{2\sqrt{3}}{2}}{1+1}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\sqrt{3}}{1+1}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\sqrt{3}}{2}=\frac{\sqrt{3}}{2}[/tex]

Thus, this equation is true.

2. Problem (10)

Use a similar strategy to evaluate this equation,

[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]

Use the attached image to evaluate the ratios.

[tex]cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cot(60)=\frac{1}{\sqrt{3}}[/tex]

Substitute,

[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]

[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

Simplify,

[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]

[tex]2-\sqrt{3}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}+1}}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]

Rationalize the denominator,

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}*\frac{\sqrt{3}-1}{\sqrt{3}-1}[/tex]

[tex]2-\sqrt{3}=\frac{(\sqrt{3}-1)^2}{3-1}[/tex]

[tex]2-\sqrt{3}=\frac{3-2\sqrt{3}+1}{2}[/tex]

[tex]2-\sqrt{3}=\frac{4-2\sqrt{3}}{2}[/tex]

[tex]2-\sqrt{3}=2-\sqrt{3}[/tex]

Therefore, this equation is also true.

Answer:

11/12

Step-by-step explanation:

2/3 + 1/4

Get a common denominator of 12

2/3 *4/4   + 1/4 *3/3

8/12 + 3/12

11/12

Answer:

5 km would be the answer

Step-by-step explanation:

For 45-45-90 triangles, the values are x, x, for the less long sides, then for the hypotenuse it's x sqrt2, because that is the rule for 45-45-90 triangles. So since in this problem, the value for the hypotenuse is 5sqrt2 km, the c value would be 5 km. Hope this helps!

Answer:

Option A is correct

Step-by-step explanation:

Hope it is helpful....

The graph to the inequality is Graph A.

Mathematical expressions with inequalities are those in which the two sides are not equal. Unlike to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.

We have the Inequality y +2 ≤ 1/4x -1

Now, simplifying the inequality

y ≤  1/4x -3.

As, The equation of a line in Slope-Intercept form is:

y= mx+ b

where m is the slope and b is intercept.

Here we have m = 1/4 and b= -3.

Now, we have the sign of inequality is ≤ then line is solid and the shaded region is below the line.

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