What is the volume of the rectangular prism in cubic centimeters?

Answer:

i am unsure

Step-by-step explanation:

I HEART POINTS

Answer:

B is the correct answer

Step-by-step explanation:

Answer: (4+1)*5=25; (25+1)*5=130; (130+1)*5=655.

Step-by-step explanation:

Answer:

−1+1.732051i

Step-by-step explanation:

Answer:

circle area = 50.24 units²

Step-by-step explanation:

circle area = πr² = 3.14(4²) = 3.14(16) = 50.24 units²

Answer:

It’s a: The area of the floor would be a rational number

Step-by-step explanation:

Answer:

m∠R = 123°

m∠S = 91°

Step-by-step explanation:

The measure of an inscribed angle is 1/2 the measure of the intercepted arc

m of arc QRS = 2 m∠P = 2(57) = 114

Now m of arc SPQ = 360 - 114 = 246

So, m∠R = 1/2(246) = 123

m of arc RSP = 2 m∠Q = 2(89) = 178

m of arc PQR = 360 - 178 = 182

m∠S = 1/2(182) = 91

Answer without Explanation:

B

50. 150 divided by 3

Answer:

√89

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√(9 - 1)² + [-6 - (-1)]²

√(8)² + (-5)²

√64 + 25

√89

Answer:

hi

Step-by-step explanation:

Answer:

c = [tex]\sqrt{58}[/tex]

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

c² = 7² + 3² = 49 + 9 = 58 ( take the square root of both sides )

c = [tex]\sqrt{58}[/tex]

Answer:

Step-by-step explanation:

According to Pythagoras Theorem:

[tex] {7}^{2} + {3}^{2} = {c}^{2} [/tex]

Hence,

[tex] = > {c}^{2} = {7}^{2} + {3}^{2} [/tex]

[tex] = > {c}^{2} = 49 + 9[/tex]

[tex] = > {c}^{2} = 58[/tex]

[tex] = > c = \sqrt{58} [/tex]

So,

[tex]c = \sqrt{58} [/tex]

Is the answer.

Answer: b

Step-by-step : not needed

Answer:

The circumference would be 25.12 mm

Step-by-step explanation:

[tex]c = 2\pi r[/tex]

[tex]c = 6.28 \times 4[/tex]

[tex]c = 25.12[/tex]

Answer:

C

Step-by-step explanation:

The probability is 1/3

Answer:

375

Step-by-step explanation:

500-125(25% of 500)=375

Answer:

It's 3[tex]x^{2}[/tex]/86

hope this helps:)

8 x 7s = 56s

8 x (-2) = -16

so 8(7s - 2) = 56s - 16

Answer:

Step-by-step explanation:

1 pound = 16 ounces

35 pounds = 560 ounces + 24 ounce = 584ounces

35 pounds,24ounces = 16 ounces

Answer:

The theoretical probabilty of the coin landing on tails is 50/50 so their is a 50% chance of it landing on tails so theoretically it would land on tails 15 out of 30 times

Step-by-step explanation:

Answer:

(a) His speed when he runs from C to A is [tex]4.\overline {285714}[/tex] m/s

(i) The bearing of B from A is approximately 127.18°

(ii) The bearing of A from B is approximately 307.18°

Step-by-step explanation:

(a) The given parameters are;

The distance from A to B = 120 m

The speed with which Olay runs from A to B, v₁ = 4 m/s

The distance from B to C = 180 m

The speed with which Olay runs from B to C, v₂ = 3 m/s

The distance from C to A = 150 m

His average speed for the whole journey = 3.6 m/s

We find

The total distance of running from A back to A, d = 120 m + 180 m + 150 m = 450 m

The time it takes to run from A to B, t₁ = 120 m/(4m/s) = 30 seconds

The time it takes to run from B to C, t₂ = 180 m/(3m/s) = 60 seconds

Let t₃ represent the time it takes Olay to run from C to A

We have;

The total time it takes to run from A back to A = t₁ + t₂ + t₃

Therefore;

[tex]Average \ velocity = \dfrac{Total \ distance }{Total \ time} = \dfrac{d}{t_1 + t_2 + t_3}[/tex]

Substituting the known values for the average velocity, 'd', 't₁' and 't₂'  gives;

[tex]Average \ velocity = 3.6 \, m/s = \dfrac{450 \, m}{30 \, s + 60 \, s + t_3}[/tex]

3.6 m/s × (30 s + 60 s + t₃) = 450 m

3.6 m/s × 30 s + 3.6 m/s × 60 s + 3.6 m/s × t₃ = 450 m

108 m + 216 m + 3.6 m/s × t₃ = 450 m

∴ 3.6 m/s × t₃ = 450 m - (108 m + 216 m) = 126 m

t₃ = 126 m/(3.6 m/s) = 35 s

The speed with which Olay runs from C to A, v₃ = Distance from C to A/t₃

The speed with which he runs from C to A = 150 m/(35 s) = 30/7 m/s =[tex]4.\overline {285714}[/tex] m/s

(i) The given bearing of C from A = 210°

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

∴ cos(A) = (b² + c² - a²)/(2·b·c)

Where;

a = The distance from B to C = 180 m

b = The distance from C to A = 150 m

c = The distance from A to B = 120 m

We find;

cos(A) = (150² + 120² - 180²)/(2 × 150 × 120) = 0.125

A = arccos(0.125) ≈ 82.82°

The bearing of B from A ≈ 210° - 82.82° ≈ 127.18°

The bearing of B from A ≈ 127.18°

(ii) The angle, θ, formed by the path of the bearing of A from B is an alternate to the supplementary angle of the bearing of B from A

Therefore, we have;

θ ≈ 180°- 127.18° ≈ 52.82°

The bearing of A from B = The sum of angle at a point less θ

∴ The bearing of A from B = 360° - 52.82° ≈ 307.18°

The bearing of A from B ≈ 307.18°.

Answer:

A vertical line

Answer:

35°

Step-by-step explanation:

Due to the parallelism, angle2=angle4

Answer:

-3 + 8 = 5

Step-by-step explanation:

When we have a "minus a negative", it's a positive. So the - -8 is the same as + 8.

LMK if you have questions.

-3 + -8 = -11

is that a nice one or something