What is the volume of the triangular prism shown below?
10
A. 100 cu. units
B. 200 cu. units
C. 400 cu. units
D. 300 cu. units

Answer:

B. -21.012÷ -3.4

its yr correct ans.

hope it helps

Answer:

three

P A R

A R A D

A D I S E 

P Q R

A B C D

A B C D E

There are three such pairs of letters. 

Answer:

Hello friend kya in snap and p to Trisha

Answer:

4/3

Step-by-step explanation:

In slope-intercept form [tex]y=mx+b[/tex], [tex]m[/tex] represents the slope of the line.

Let's write [tex]3x+4y=-2[/tex] in slope-intercept form by isolating [tex]y[/tex]:

[tex]3x+4y=-2,\\4y=-3x-2,\\y=-\frac{3}{4}x-\frac{1}{2}[/tex]

Therefore, the slope of this line is [tex]\frac{-3}{4}[/tex]. To find the slope of a line perpendicular to it, multiply the reciprocal of the slope by -1 (take the negative reciprocal).

Therefore, the slope of a line perpendicular to [tex]3x+4y=-2[/tex] is:

[tex]m_{perp}=-(-\frac{4}{3})=\boxed{\frac{4}{3}}[/tex]

Answer:

4/3

Given equation :-

Slope :-

Slope of perpendicular line :-

Answer:

[tex]\frac{x+6}{2x^2-9x+5}=-\sum_{n=0}^{\infty} [(-2)^{n}x^{n} + \frac{x^{n}}{5^{n+1}}][/tex]

when:

[tex]|x|<\frac{1}{2}[/tex]

Step-by-step explanation:

In order to solve this problem, we must begin by splitting the function into its partial fractions, so we must first factor the denominator.

[tex]\frac{x+6}{2x^2-9x+5}=\frac{x+6}{(2x+1)(x-5)}[/tex]

Next, we can build our partial fractions, like this:

[tex]\frac{x+6}{(2x+1)(x-5)}=\frac{A}{2x+1}+\frac{B}{x-5}[/tex]

we can then add the two fraction on the right to get:

[tex]\frac{x+6}{(2x+1)(x-5)}=\frac{A(x-5)+B(2x+1)}{(2x+1)(x-5)}[/tex]

Since we need this equation to be equivalent, we can get rid of the denominators and set the numerators equal to each other, so we get:

[tex]x+6=A(x-5)+B(2x+1)[/tex]

and expand:

[tex]x+6=Ax-5A+2Bx+B[/tex]

we can now group the terms so we get:

[tex]x+6=Ax+2Bx-5A+B[/tex]

[tex]x+6=(Ax+2Bx)+(-5A+B)[/tex]

and factor:

[tex]x+6=(A+2B)x+(-5A+B)[/tex]

so we can now build a system of equations:

A+2B=1

-5A+B=6

and solve simultaneously, this one can be solved by substitution, so we get>

A=1-2B

-5(1-2B)+B=6

-5+10B+B=6

11B=11

B=1

A=1-2(1)

A=-1

So we can use these values to build our partial fractions:

[tex]\frac{x+6}{(2x+1)(x-5)}=\frac{A}{2x+1}+\frac{B}{x-5}[/tex]

[tex]\frac{x+6}{(2x+1)(x-5)}=-\frac{1}{2x+1}+\frac{1}{x-5}[/tex]

and we can now use the partial fractions to build our series. Let's start with the first fraction:

[tex]-\frac{1}{2x+1}[/tex]

We can rewrite this fraction as:

[tex]-\frac{1}{1-(-2x)}[/tex]

We can now use the following rule to build our power fraction:

[tex]\sum_{n=0}^{\infty} ar^{n} = \frac{a}{1-r}[/tex]

when |r|<1

in this case a=1 and r=-2x so:

[tex]-\frac{1}{1-(-2x)}=-\sum_{n=0}^{\infty} (-2x)^n[/tex]

or

[tex]-\frac{1}{1-(-2x)}=-\sum_{n=0}^{\infty} (-2)^{n} x^{n}[/tex]

for: |-2x|<1

or: [tex] |x|<\frac{1}{2} [/tex]

Next, we can work with the second fraction:

[tex]\frac{1}{x-5}[/tex]

On which we can factor a -5 out so we get:

[tex]-\frac{1}{5(1-\frac{x}{5})}[/tex]

In this case: a=-1/5 and r=x/5

so our series will look like this:

[tex]-\frac{1}{5(1-\frac{x}{5})}=-\frac{1}{5}\sum_{n=0}^{\infty} (\frac{x}{5})^n[/tex]

Which can be simplified to:

[tex]-\frac{1}{5(1-\frac{x}{5})}=-\sum_{n=0}^{\infty} \frac{x^n}{5^(n+1)}[/tex]

when:

[tex]|\frac{x}{5}|<1[/tex]

or

|x|<5

So we can now put all the series together to get:

[tex]\frac{x+6}{2x^2-9x+5}=-\sum_{n=0}^{\infty} [(-2)^{n}x^{n} + \frac{x^{n}}{5^{n+1}}}[/tex]

when:

[tex]|x|<\frac{1}{2}[/tex]

We use the smallest interval of convergence for x since that's the one the whole series will be defined for.

Answer:

w = 5

y = 4

Step-by-step explanation:

w + y = 9

3w - y = 11 ( + )

________

4w + 0 = 20

4w = 20

w = 20 / 4

w = 5

Substitute w = 5 in eq. w + y = 9,

w + y = 9

5 + y = 9

y = 9 - 5

y = 4

Answer:

Just A and C

Step-by-step explanation:

B doesn't count because you would not be looking at the 9. Only the 4.

You only look at one number to the right.

Answer:

A and C are correct, but not B

Step-by-step explanation:

When you round, you only look at the number behind the place you are rounding.

6.04 doesn't round to 6.1, so that is not correct

9514 1404 393

Answer:

  a) yes

  b) see attached

  c) see discussion

  d) neither

  e) increasing (2,5); decreasing (-2, 2)

Step-by-step explanation:

a) The graph passes the vertical line test, so is the graph of a function.

__

b) A table of values is attached

__

c) Generally, this sort of function would be defined piecewise:

  [tex]\displaystyle f(x)=\begin{cases}-\dfrac{1}{2}x+1&\text{for }-2\le x<2\\2x-4&\text{for }2\le x \le5\end{cases}[/tex]

In the attachment, we have shown the use of the "maximum" function to define it. The effect is the same.

__

d) The function has no symmetry about the origin or the y-axis, so is neither odd nor even.

__

e) The function is increasing where the line has positive slope, on the interval (2, 5). The function is decreasing where the line has negative slope, on the interval (-2, 2).

Answer:

0.33

Step-by-step explanation:

See comment for complete question

Given

[tex]H = 60\%[/tex]

[tex]W=25\%[/tex]

[tex]HW = 20\%[/tex] --- at-home wins

Required

The proportion of at-home games that were wins

This proportion is represented as:

[tex]Pr = HW : H[/tex]

Substitute values for HW and H

[tex]Pr = 20\% : 60\%[/tex]

Divide by 20%

[tex]Pr = 1 : 3[/tex]

Express as fraction

[tex]Pr = 1 /3[/tex]

[tex]Pr = 0.33[/tex]

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Answer:

  maybe

Step-by-step explanation:

It can be. It depends on the problem.

__

The rules of exponents are ...

  (a^b)/(a^c) = a^(b-c)

  a^-b = 1/a^b

Clearly, for division problems if the denominator exponent is larger, the difference 'b-c' will be negative.

__

You recall that an exponent is the way we show repeated multiplication.

 x·x·x = x³

In division, like factors cancel, so ...

  [tex]\dfrac{x\cdot x\cdot x}{x\cdot x}=\dfrac{x^3}{x^2}=\dfrac{x}{1}\cdot\dfrac{x\cdot x}{x\cdot x}=x^{3-2}=x^1=x[/tex]

Now, consider the same problem "upside down."

 [tex]\dfrac{x\cdot x}{x\cdot x\cdot x}=\dfrac{x^2}{x^3}=\dfrac{1}{x}\cdot\dfrac{x\cdot x}{x\cdot x}=x^{2-3}=x^{-1}=\dfrac{1}{x}[/tex]

Answer:

this is the answer I got! i don't know if it helps, but I hope it does

Answer:

T = 2.215

df = 7

Critical value = 2.364

Fail to reject the null

Step-by-step explanation:

Swimmer __Spandex __Speedo Fastskin__ d

1 __________31.1 _______29.1 __ 2

2_________ 28.9 ______30.4 __ -1.5

3_________ 31.4 ______ 32.0 __ - 0.6

4_________ 34.9 ______31.7 __ 3.2

5 _________27.7 ______28.2 __ - 0.5

6_________ 36.7 _____ 32.9 ___ 3.8

7 _________ 33.3 _____28.6 ___ 4.7

8_________ 30.8 _____26.2 ___ 4.6

The mean difference = Σd / n

2, - 1.5, - 0.6, 3.2, - 0.5, 3.8, 4.7, 4.6

μd = Σd / n = 15.7 / 8 = 1.9625

Sd = standard deviation of difference = 2.5065 (using calculator)

H0 : μd = 0

H1 : μd ≠ 0

The test statistic:

T = μd / (Sd/√n)

T = 1.9625 / (2.5065/√8)

T = 2.2145574

The degree of freedom, df = n - 1 = 8 - 1 = 7

Using a Pvalue calculator :

α = 0.05

Critical value, Tcritical = 2.364 (T distribution table)

Since Test statistic < Critical value

we fail to reject H0 ;

Answer:

x = 2

Step-by-step explanation:

4x-3 + 3 =  5 + 3

4x = 8

4x ÷ 4 = 8 ÷ 4

x = 2

Hi there!  

»»————-　★　————-««

I believe your answer is:  

"When solving 4x-3=5 the property used in the first step is the addition property of equality."

[tex]\boxed{x = 2}[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'x'....}}\\\\4x-3=5\\----------\\\text{\textbf{Addition Property of Equality:} Add three on both sides.}}\\\\\rightarrow 4x - 3 = 5 \\\rightarrow 4x -3 + 3 = 5 + 3\\\\\rightarrow \boxed{4x = 8}\\\\\text{\textbf{Division Property of Equality:} Divide both sides by 4.}}\\\\\rightarrow {4x=8}\\\rightarrow \frac{4x=8}{4}\\\\\rightarrow \boxed{x = 2}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

I don't know the answer to ur question. LOL

Answer:

stop being desperate

nobody is gonna fall in love with some desperate weirdo

Answer:

1200

Explanation:

Order does not matter, if we said xyz order, it would still not make a difference if it was zyx or yzx hence we use the combination formula:

nCr = n! / r! * (n - r)!

where n= total number of items

r= number of items chosen at a time

Combinations are used when the order of events do not matter in calculating the outcome.

We calculate using the formula:

(30×20×12)÷3!=1200

There are therefore 1200 ways for the three distinct items to not be in same row or column

Answer:

There are 2 x intercepts

Answer:

52nd percentile

Step-by-step explanation:

The sorted data :

36.0, 37.0, 39.5, 40.0, 40.5, 43.0, 44.0, 45.5, 45.5, 46.5, 48.0, 48.00, 49.0, 50.0, 51.5, 52.5, 53.0, 53.5, 54.0, 57.3, 57.5, 58.0, 58.5, 59.0, 59.5, 60.0, 61.0, 61.0, 61.0, 61.5, 62.0, 62.5, 63.0, 63.0, 63.5, 64.0, 64.0, 64.0, 64.5, 65.0, 66.0, 67.5, 67.5, 68.5, 70.0, 70.5, 71.5, 72.0, 72.5, 72.5, 72.5, 73.5, 74.5, 77.5

The total size of the data = 54

The value 61.0 occurs in position ; 27th, 28th and 29th

Taking the position average :

(27+28+29)/3 = 84/3 = 28th position

This means the percentile score of 61 is :

(Position average / total size) * 100%

(28/54) * 100%

0.5185185 * 100%

= 51.85%

This means that 61 inch length falls in the 52nd percentile

Answer:

C

Step-by-step explanation:

[tex] ({8}^{ { - 9})^{ \frac{ - x}{9} } } [/tex]

when putting a power to another power, then these two powers are multiplied.

so, -9 × (-x/9) = (-9 × -x) / 9 = 9x/9 = x

so, this reduces to the original

[tex] {8}^{x} [/tex]

and therefore C is the right answer.

Answer:

Second term of this sequence: [tex]10[/tex].

Third term of this sequence: [tex]20[/tex].

Step-by-step explanation:

The first step is to find the common ratio of this sequence.

In a geometric sequence, multiply one term by the common ratio to find an expression for the next term. Let [tex]r[/tex] denote the common ratio of this sequence. For this sequence:

However, the question states that the value of the fourth term is [tex]40[/tex]. In other words, [tex]5\, r^{3} = 40[/tex].

Solve this equation for [tex]r[/tex]:

[tex]r^{3} = 8[/tex].

[tex]r = 2[/tex].

(Since the power of [tex]r[/tex] is non-even in the equation, there's no need to consider the sign of [tex]r\![/tex] when taking the cube root.)

Substitute [tex]r = 2[/tex] into the expression for the second term and the third term to find their values:

Answer:

(-6,-12)

Step-by-step explanation:

A dilation makes a figure gets bigger so just multiply 3 to point N to find N prime.

[tex] - 2 \times 3 = - 6[/tex]

[tex] - 4 \times 3 = - 12[/tex]

So our new coordinates is

(-6,-12)

Answer:

(-6,-12)

Step-by-step explanation:

A dilation makes a figure gets bigger so just multiply 3 to point N to find N prime.

So our new coordinates is

(-6,-12)

Step-by-step explanation:

Answer:

hey what's

Step-by-step explanation:

a question wow okay the answer is

Answer:

a

Step-by-step explanation:

square root distribute to numerator and denominator so both get square rooted [tex]\sqrt{5}[/tex]/8

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Answer:

  -1/3x

Step-by-step explanation:

We want to find the term 'a' such that ...

  (5/6x -4) + a = (1/2x -4)

Add 4-1/2x to both sides.

  (5/6 -1/2)x -4 +4 +a = 0

  (5/6 -3/6)x + a = 0 . . . . . . express the fractions using a common denominator

  1/3x + a = 0 . . . . . . . . . . simplify the difference

  a = -1/3x . . . . . . . . . . .subtract 1/3x

The term you can add to make the desired equivalent is -1/3x.

Answer:

10

Step-by-step explanation:

As it could be inferred from the name, repeated measure design may be explained as experimental measures involving multiple (more than one) measures of a variable on the same observation, subject or participants which are taken at either various times or periodic intervals, different levels, different conditions. Hence, a repeated measurement taken with the same sample but under different treatment conditions. Therefore, since the measurement will be performed on a the same subjects(paired) , then the number of subjects needed will be 10. As it is this same samples that will be used for the other levels or conditions.

Answer: Tis 0

Step-by-step explanation:

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Answer:

  A.  yes

Step-by-step explanation:

The diagonals of a rectangle are congruent and bisect each other.

The diagonals of a parallelogram bisect each other. If they are also congruent, then the parallelogram is a rectangle.

Answer:

Yes.

Step-by-step explanation:

Press option yes

Answer:

The answer is below

Step-by-step explanation:

The bar chart to the question is attached below.

The distance traveled by Paolo = 210 m, The distance traveled by Lucas = 150 m, The distance traveled by Jashua = 175 m, The distance traveled by Topher = 190 m

1) The farther distance walk by Paolo = The distance traveled by Paolo - The distance traveled by Topher = 210 m - 190 m = 20 m

2) The farther distance walk by Jasha = The distance traveled by Jashua - The distance traveled by Lucas = 175 m - 150 m = 25 m

3) The farther distance walk by Topher = The distance traveled by Topher - The distance traveled by Lucas = 190 m - 150 m = 40 m

4) Combined distance of Paolo's and Lucas = 210 m + 150 m = 360 m

Combined distance of Jashua and Topher = 175 m + 190 m = 365 m

Therefore the Combined distance of Jashua and Topher is more

5) Average distance = (210 + 150 + 175 + 190)/4 = 181.25 m