The percent of the number 2160 which is 270 is 12.5%.
Given a number 2160.
It is required to find the percent of this number which is 270.
Let x be the percent of 2160 which is 270.
Then, this can be written as:
2160 × (x/100) = 270
2160 × x = 270 × 100
2160 × x = 27000
x = 27000 / 2160
= 12.5
Hence the required percentage is 12.5%.
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12. Reason A data set is represented by the box plot shown. Between which two values would the middle 50% of the data be found? Explain.
The middle 50% data of the boxplot will be calculated between the value of 7 to 14.
Explain about the box plot?The variation in information is shown using a boxplot, which is a standardized method based on a five-number summary ("minimum," first quartile ("Q1"), median ("Q3"), and "maximum"). It can reveal information about your outliers' values. Boxplots can also show you exactly securely your data is grouped, whether or not your data is skewed, and whether or not your data is symmetrical.The data set ranges are:
4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17
Divide the given data in 4 quartiles Qs;
Q1 = 4 - 6
Q2 = 7 - 10
Q3 = 11 - 14
Q4 = 15 - 17
Thus, 50% data will be lying in Q2 and Q3.
Range - 7 - 14
Thus, the middle 50% data of the box plot will be calculated between the value of 7 to 14.
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to calculate the workload of a resource that serves different flow unit types, one must know which of the following?
The workload of the resource is 20.5 units.
To calculate the workload of a resource that serves different flow unit types, one must know the amount of flow units, the processing time for each flow unit, and the number of resources available. This is best calculated using Little's Law, which states that the average number of flow units in a system is equal to the average rate of flow units multiplied by the average time they spend in the system.
For example, if a resource is serving 3 flow unit types, A, B and C, with 10, 8 and 5 units respectively, and a processing time of 2 minutes, 1 minute and 3 minutes respectively, with 2 resources available, the workload can be calculated as follows:
Workload = (10*2 + 8*1 + 5*3) / 2
= 41 / 2
= 20.5 units
Therefore, the workload of the resource is 20.5 units.
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Complete question
What are the flow unit types that the resource is serving?
For the functions f(x)=−7x+3 and g(x)=3x2−4x−1, find (f⋅g)(x) and (f⋅g)(1).
Answer: (f⋅g)(1) = 10.
Step-by-step explanation:
To find (f⋅g)(x), we need to multiply the two functions f(x) and g(x) together. This can be done by multiplying each term of f(x) by each term of g(x), and then combining like terms. We get:
(f⋅g)(x) = f(x) * g(x)
= (-7x+3) * (3x^2 - 4x - 1)
= -21x^3 + 28x^2 + x - 3x^2 + 4x + 1
= -21x^3 + 25x^2 + 5x + 1
To find (f⋅g)(1), we can substitute x=1 into the expression for (f⋅g)(x):
(f⋅g)(1) = -21(1)^3 + 25(1)^2 + 5(1) + 1
= -21 + 25 + 5 + 1
= 10
Therefore, (f⋅g)(1) = 10.
which of the following numeric measures would be most likely to produce invalid statistical analysis?
The most likely to produce invalid statistical analysis of numeric measures is Pain rating as: none = 0; slight = 1; much = 2, as it is an ordinal scale of measurement, which does not have equal intervals between the categories. So, the correct answer is B).
It means that the differences between the categories are not necessarily equivalent, and therefore, any statistical analysis based on this scale may not accurately reflect the true relationship between variables.
The other options (blood pressure in mmHg, oxygen saturation in percentage, neonatal birth weight in kilograms) are measured on interval or ratio scales, which have equal intervals between values and can be used for meaningful statistical analysis. so, the correct option is B).
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____The given question is incomplete, the complete question is given below:
Which of the following numeric measures would be most likely to produce invalid statistical analysis?A)Analysis of patients' blood pressures in mmHgB)Pain rating as: none = 0; slight = 1; much = 2C)Assessment of oxygen saturation in percentageD)Analysis of neonatal birthweight in kilogr
Question 2
State the probability that a randomly selected, normally
distributed value lies between
a) o below the mean and o above the mean (round to
the nearest hundredths)
b) 20 below the mean and 20 above the mean (round
to the nearest hundredths)
The probability of a randomly selected, normally distributed value lying between 20 below the mean and 20 above the mean is 0.9545 (rounded to the nearest hundredth).
What is the fundamental concept of probability?A number between zero and one represents the probability that an occurrence will take place. An event is a predefined set of random variable outcomes. Only one mutually exclusive event can occur at a time. Exhaustive events encompass or include all possible outcomes.
We can calculate the probabilities of a randomly chosen value falling between different z-scores using the provided standard normal distribution table.
a) The probability of a value being 0 below or above the mean is the same as the probability of a value being -1 to 1 standard deviations from the mean. According to the standard normal distribution table, the probability of a z-score between -1 and 1 is 0.6827. As a result, the probability of a randomly chosen, normally distributed value falling between 0 below and 0 above the mean is 0.6827. (rounded to the nearest hundredth).
b) The probability of a value falling between 20 and 20 standard deviations from the mean is the same as the probability of a value falling between -20/10 and 20/10 standard deviations from the mean (since the standard deviation is 10). According to the standard normal distribution table, the probability of a z-score between -2 and 2 is 0.9545. As a result, the probability of a randomly chosen, normally distributed value falling between 20 below and 20 above the mean is 0.9545. (rounded to the nearest hundredth).
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can someone please help me asap!!! ill mark brainlistt...
Answer:
Step-by-step explanation:
To solve this problem, we can use the formula for the Pythagorean theorem, which states that for any right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In this case, we are given the length of two sides of the triangle (the legs) and we need to find the length of the hypotenuse.
Let's label the sides of the triangle:
The shorter leg is the vertical side opposite the angle marked 55 degrees, so let's call it "a".
The longer leg is the horizontal side adjacent to the angle marked 55 degrees, so let's call it "b".
The hypotenuse is the side opposite the right angle, so let's call it "c".
Using trigonometry, we can determine the value of "a" and "b":
a = b * tan(55°) (since tangent = opposite/adjacent, we solve for opposite which is "a" in this case)
a = 100 * tan(55°) = 100 * 1.428 = 142.8
b = 100
Now, we can use the Pythagorean theorem to find the length of the hypotenuse:
c^2 = a^2 + b^2
c^2 = 142.8^2 + 100^2
c^2 = 20484.84 + 10000
c^2 = 30484.84
c = sqrt(30484.84)
c ≈ 174.6
Therefore, the length of the hypotenuse is approximately 174.6 units (the units are not given in the problem, but we can assume they are consistent with the units used for the given values of "a" and "b").
The problem does not specify the orientation or scale of the graph, but we can assume that it is a right triangle with the angle marked 55 degrees in the upper left corner.
The vertical side (the shorter leg) of the triangle should be labeled with a length of approximately 142.8 units (assuming the units used for the problem are consistent with the values given for "a" and "b"). The horizontal side (the longer leg) should be labeled with a length of 100 units.
The hypotenuse (the side opposite the right angle) should be drawn as a diagonal line connecting the endpoints of the vertical and horizontal sides. The hypotenuse should be labeled with a length of approximately 174.6 units.
The angle marked 55 degrees should be labeled as such, and the other two angles of the triangle (the right angle and the angle opposite the longer leg) should be labeled accordingly.
A triangular prism has height 20 cm.
Its triangular face has base 7 cm and height 10 cm.
A. what is the volume of the prism?
B. suppose you triple the height of the prism.what happen to the volume?
C. suppose you triple the base of the triangular face.what happen to the volume?
D. suppose you triple the height of the triangular face.what happen to the volume?
E. suppose you triple all 3 dimensions.what happen to the volume?
Answer:
A. The volume of the triangular prism can be calculated using the formula V = (1/2)bh × h, where b is the base of the triangular face and h is the height of the prism. Thus, V = (1/2)(7 cm)(10 cm) × 20 cm = 700 cubic centimeters.
B. If the height of the prism is tripled to 60 cm, then the new volume would be V' = (1/2)(7 cm)(10 cm) × 60 cm = 2100 cubic centimeters. Thus, the volume is tripled.
C. If the base of the triangular face is tripled to 21 cm, then the new volume would be V' = (1/2)(21 cm)(10 cm) × 20 cm = 2100 cubic centimeters. Thus, the volume is tripled.
D. If the height of the triangular face is tripled to 30 cm, then the new volume would be V' = (1/2)(7 cm)(30 cm) × 20 cm = 2100 cubic centimeters. Thus, the volume is tripled.
E. If all three dimensions (base, height of triangular face, and height of prism) are tripled, then the new volume would be V' = (1/2)(21 cm)(30 cm) × 60 cm = 18900 cubic centimeters. Thus, the volume is multiplied by a factor of 27.
My little cousin needs help with this can anyone help please.
I’m busy with my tests and I don’t have the time to explain.
Answer:
I don't knowI am sorry I will let someone else answer
Step-by-step explanation:
What the values of angles B and C?
The value of b is 73° as opposite angles of congruent sides are equal in an isosceles triangle.
What dοes a math angle mean?An angle is created by cοmbining twο rays (half-lines) that have a cοmmοn terminal. The angle's vertex is the latter, while the rays are alternately referred tο as the angle's legs and its arms.
What is fundamental angle?An angle within a shape that has the shape's base as οne οf its sides is knοwn as the base angle οf a shape in geοmetry. Cοnsider the triangle in the image as an example. We can οbserve that the triangle's base side is made up οf an angle B side and an angle C side. As a result, the triangle's base angles are angles B and C.
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construct shear and bending diagrams for the following beams. show your equations used to create the plots. p p p p l/2 l/4 l/4 p p p l/3 l/3 l/3
The shear force and bending moment diagrams for the given beam will have multiple segments of different shapes and slopes, reflecting the variation of loads along the length of the beam.
To construct the shear and bending diagrams for the given beam, we need to analyze the beam for the different sections where the load is applied. We can break down the beam into five sections:
Leftmost section (0 ≤ x ≤ L/4)
Second section (L/4 < x ≤ L/2)
Third section (L/2 < x ≤ 5L/12)
Fourth section (5L/12 < x ≤ 7L/12)
Rightmost section (7L/12 < x ≤ L)
We can use the equations for shear and bending moments to create the plots:
For section 1: 0 ≤ x ≤ L/4
The shear force diagram will be constant since there is no load applied in this section. The bending moment diagram will be a sloping line, which will be zero at x = 0 and will increase linearly with x as we move toward the right end of the section.
For section 2: L/4 < x ≤ L/2
The shear force diagram will start from the value of P at x = L/4 and remain constant up to x = L/2. The bending moment diagram will be a parabolic curve, which will be zero at x = L/4 and L/2 and will reach a maximum value at the midpoint of the section.
For section 3: L/2 < x ≤ 5L/12
The shear force diagram will start from the value of P at x = L/4 and remain constant up to x = L/2. At x = 5L/12, a load of P/3 is added, causing the shear force to increase suddenly. The bending moment diagram will be a cubic curve, which will be zero at x = L/4 and L/2, and will have a local minimum at x = 5L/12.
For section 4: 5L/12 < x ≤ 7L/12
The shear force diagram will start from the value of P + P/3 at x = 5L/12 and remain constant up to x = 7L/12. The bending moment diagram will be a cubic curve, which will be zero at x = L/4 and L/2, and will have a local maximum at x = 7L/12.
For section 5: 7L/12 < x ≤ L
The shear force diagram will start from the value of P + P/3 at x = 5L/12 and remain constant up to x = 7L/12. At x = L/3, a load of P/3 is added, causing the shear force to decrease suddenly. The bending moment diagram will be a parabolic curve, which will be zero at x = L/4 and L/2 and will reach a minimum value at the midpoint of the section.
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-0.1x^2+10=0
find the x
Answer:
x = ±10
Step-by-step explanation:
1) Subtract 10 from both sides.
[tex]-0.1 \times x^2=-10[/tex]
2) Divide both sides by -0.1.
[tex]x^2=\frac{-10}{-0.1}[/tex]
3) Simplify [tex]\frac{-10}{-0.1}[/tex] to 100.
[tex]x^2=100[/tex]
4) Take the square root of both sides.
[tex]x=\pm \sqrt{100}[/tex]
5) Since 10 * 10 is 100, the square root of 100 is 10.
[tex]x=\pm10[/tex]
I will mark you brainiest!
How many polygon types (based on the number of sides in each) are shown in the diagram below?
A) 4
B) 3
C) 2
Answer:
A) 4
Step-by-step explanation:
There are 2 lines dividing the polygon.
The first two on the top are triangles.
The two on the bottom are irregular polygons.
Added up, that's 4 polygons according to the line distribution.
. If h> 3 and h - 2g= 0, which of
the following must be true?
A. g> 2.5
B. g> 1.5
C. g <0.5
D. g <1.5
E. g>2
By linear equality , g >1.5 is must be true.
What are equality and inequality along a line?
Equal (=) is the symbol used in linear equations. Example. Using the inequality symbols (>,, is greater than or equal to, and is less than or equal to), linear inequalities are expressed.
x - 5 > 3x - 10 is an illustration of a linear inequality. As the larger than symbol is employed in this inequality, the LHS is strictly greater than the RHS. After being solved, the inequality appears as 2x 5 x (5/2).
If h> 3 and h - 2g= 0
H=2g
2g>3
g >1.5
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do you mind helping me with this?
Answer:
125
Step-by-step explanation:
We Take
625 / 5 = 125
So, the answer is 125
A fair coin is tossed five times. What is the theoretical probability that the coin lands on the same side every time??
A) 0.1
B) 0.5
C) 0.03125
D) 0.0625
Answer:
The answer is C
Step-by-step explanation:
Assuming this is a fair coin, the theoretical probability of the coin going on one side, let's say heads, is 50%, or 0.5. So what's the chance the coin lands head 5 times? To do this we do 0.5^5 OR 0.5*0.5*0.5*0.5*0.5. Both of these answers equal 0.03125. So C is the Answer. Hope this helps :D
Math
rade> Y.9 Solve two-step equations: complete the solution GK7
2(p+ 4) = 12
P + 4 =
Social studies
Complete the process of solving the equation.
Fill in the missing term on each line. Simplify any fractions.
Р
Submit
Recommendations
Divide both sides by 2
Subtract 4 from both sides
P = 2 is the answer to the equation 2(p + 4) = 12.
Is it an equation or an expression?An expression is made up of a number, a variable, or a combination of a number, a variable, and operation symbols. Two expressions are combined into one equation by using the equal symbol. For illustration: When you add 8 and 3, you get 11.
Divide the two among the terms between the parenthesis:
2p + 8 = 12
Add 8 to both sides of the equation, then subtract 8:
2p + 8 - 8 = 12 - 8
2p = 4
multiply both sides by two:
2p/2 = 4/2 \sp = 2
p = 2 is the answer to the equation 2(p + 4) = 12 as a result.
Simply put p = 2 back into the equation and simplify to obtain p + 4:
[tex]p + 4 = 2 + 4 = 6[/tex]
Hence, p + 4 = 6.
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Jamie is going to run for
1
2
2
1
start fraction, 1, divided by, 2, end fraction of an hour at a constant rate, and they want to plan what that rate will be.
1. Write an equation that represents the distance Jamie will run in kilometers (
�
dd) at a rate of
�
rr kilometers per hour.
The distance Jamie will run is equal to half of the rate in kilometers per hour, the equation is d = r (1/2)
What is speed and velocity?Speed is a scalar number that represents the rate of movement of an item. It is described as the distance covered in a certain amount of time, regardless of direction. In contrast, velocity is a vector quantity that accounts for both speed and direction. It is characterised as the pace at which an item shifts in a certain direction. In physics, the idea of velocity is crucial since it aids in explaining how an object's location varies over time and is used to compute other crucial variables like acceleration and momentum.
The distance is calculated using the given formula:
Distance = rate (time)
Given that, the time is 1/2 hour thus:
d = r (1/2)
Thus, the distance Jamie will run is equal to half of the rate in kilometers per hour, and the equation is d = r (1/2).
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[tex]y = ( \sqrt{47 + \sqrt{9 - \sqrt{25} } } )[/tex]
find the value of y ~
The simplification of the given expression
[tex]y = ( \sqrt{47 + \sqrt{9 - \sqrt{25)} } } [/tex]
is y = 7
How to simplify expressions?[tex]y = ( \sqrt{47 + \sqrt{9 - \sqrt{25)} } } [/tex]
find the square root of 25
[tex]y =( \sqrt{47 + \sqrt{9 - 5} } [/tex]
simplify root 9 - 5
[tex]y = ( \sqrt{47 + \sqrt{4} } [/tex]
find the square root of 4
[tex]y = ( \sqrt{47 + 2)} [/tex]
Add root 47 and 2
[tex]y = ( \sqrt{49} )[/tex]
Find the square root of 49
y = 7
Therefore, the solution to the given expression is y = 7
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Change the following equation of a line into slope-intercept form.
y + 4 = 2x
Answer:
Step-by-step explanation:
[tex]y=2x-4[/tex] (slope-intercept form is [tex]y=mx+b[/tex] where m=gradient
and b is where line intercepts y-axis)
Find the average rate of change of the area of a circle withrespect to its radius r as r changes from2 to each of the following.(i) 2 to 3 (ii) 2 to 2.5 (iii) 2 to 2.1
The average rate of change is 5π; for r changing from 2 to 2.5, it is 2.5π, and for r changing from 2 to 2.1, it is 4.1π.
The area of a circle is given by the formula A = πr². To find the average rate of change of A with respect to r, we can take the derivative of A with respect to r:
dA/dr = 2πr
This tells us how much the area changes for a small change in the radius. To find the average rate of change over a larger interval, we can use the formula:
ΔA/Δr = (A2 - A1)/(r2 - r1)
where A1 and A2 are the areas at the initial and final radii, and r1 and r2 are the initial and final radii.
(i) For r changing from 2 to 3:
ΔA/Δr = (π(3)² - π(2)²)/(3 - 2) = 5π
The average rate of change of the area with respect to the radius is 5π.
(ii) For r changing from 2 to 2.5:
ΔA/Δr = (π(2.5)² - π(2)²/(2.5 - 2) = 2.5π
The average rate of change of the area with respect to the radius is 2.5π.
(iii) For r changing from 2 to 2.1:
ΔA/Δr = (π(2.1)² - π(2)²)/(2.1 - 2) = 4.1π
The average rate of change of the area with respect to the radius is 4.1π.
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Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the y-axis. (Round your answer to three decimal places.)
Answer:
1.066 (3 d.p.)
Step-by-step explanation:
The volume of the solid formed by revolving a region, R, around a vertical axis, bounded by x = a and x = b, is given by:
[tex]\displaystyle 2\pi \int^b_ar(x)h(x)\;\text{d}x[/tex]
where:
r(x) is the distance from the axis of rotation to x.h(x) is the height of the solid at x (the height of the shell).[tex]\hrulefill[/tex]
We want to find the volume of the solid formed by revolving a region, R, around the y-axis, where R is bounded by:
[tex]y=\dfrac{1}{\sqrt{2\pi}}e^{-\frac{x^2}{3}}[/tex]
[tex]y=0[/tex]
[tex]x=0[/tex]
[tex]x=1[/tex]
As the axis of rotation is the y-axis, r(x) = x.
Therefore, in this case:
[tex]r(x)=x[/tex]
[tex]h(x)=\dfrac{1}{\sqrt{2\pi}}e^{-\frac{x^2}{3}}[/tex]
[tex]a=0[/tex]
[tex]b=1[/tex]
Set up the integral:
[tex]\displaystyle 2\pi \int^{1}_0x \cdot\dfrac{1}{\sqrt{2\pi}}e^{-\frac{x^2}{3}}\;\text{d}x[/tex]
Take out the constant:
[tex]\displaystyle 2\pi \cdot \dfrac{1}{\sqrt{2\pi}}\int^{1}_0x \cdot e^{-\frac{x^2}{3}}\;\text{d}x[/tex]
[tex]\displaystyle \sqrt{2\pi}\int^{1}_0x \cdot e^{-\frac{x^2}{3}}\;\text{d}x[/tex]
Integrate using the method of substitution.
[tex]\textsf{Let}\;u=-\dfrac{x^2}{3}\implies \dfrac{\text{d}u}{\text{d}x}=-\dfrac{2x}{3}\implies \text{d}x=-\dfrac{3}{2x}\;\text{d}u[/tex]
[tex]\textsf{When}\;x=0 \implies u=0[/tex]
[tex]\textsf{When}\;x=1 \implies u=-\dfrac{1}{3}[/tex]
Rewrite the original integral in terms of u and du:
[tex]\displaystyle \sqrt{2\pi}\int^{-\frac{1}{3}}_0x \cdot e^{u}\cdot -\dfrac{3}{2x}\;\text{d}u[/tex]
[tex]\displaystyle \sqrt{2\pi}\int^{-\frac{1}{3}}_0 -\dfrac{3}{2}e^{u}\; \text{d}u[/tex]
[tex]-\dfrac{3\sqrt{2\pi}}{2}\displaystyle \int^{-\frac{1}{3}}_0 e^{u}\; \text{d}u[/tex]
Evaluate:
[tex]\begin{aligned}-\dfrac{3\sqrt{2\pi}}{2}\displaystyle \int^{-\frac{1}{3}}_0 e^{u}\; \text{d}u&=-\dfrac{3\sqrt{2\pi}}{2}\left[ \vphantom{\dfrac12}e^u\right]^{-\frac{1}{3}}_0\\\\&=-\dfrac{3\sqrt{2\pi}}{2}\left[ \vphantom{\dfrac12}e^{-\frac{1}{3}}-e^0\right]\\\\&=-\dfrac{3\sqrt{2\pi}}{2}\left[ \vphantom{\dfrac12}e^{-\frac{1}{3}}-1\right]\\\\&=1.06582594...\\\\&=1.066\; \sf (3\;d.p.)\end{aligned}[/tex]
Therefore, the volume of the solid is approximately 1.066 (3 d.p.).
[tex]\hrulefill[/tex]
[tex]\boxed{\begin{minipage}{3 cm}\underline{Integrating $e^x$}\\\\$\displaystyle \int e^x\:\text{d}x=e^x(+\;\text{C})$\end{minipage}}[/tex]
Find all the values of
arcsin −√3/2
Select all that apply:
a.π3
b.5π6
c.11π6
d.5π3
e.2π3
f.7π6
g.4π3
Answer:
g
Step-by-step explanation:
The given expression is arcsin (-√3/2), which represents the angle whose sine is equal to -√3/2. Recall that the range of the arcsin function is from -π/2 to π/2 radians, so we can narrow down the possible solutions to the second and third quadrants.
Since the sine function is negative in the third quadrant, we can start by considering the angle 4π/3, which is in the third quadrant and has a sine of -√3/2:sin(4π/3) = -√3/2
However, we need to check if there are any other angles in the second or third quadrants that satisfy the equation. Recall that sine is periodic with a period of 2π, so we can add or subtract any multiple of 2π to the angle and still obtain the same sine value.
In the second quadrant, we can use the reference angle π/3 to find the corresponding angle with a negative sine:
sin(π - π/3) = sin(2π/3) = √3/2
This angle does not satisfy the equation, so we can eliminate it as a possible solution.In the third quadrant, we can use the reference angle π/3 to find another possible solution:
sin(π + π/3) = sin(4π/3) = -√3/2
This confirms our initial solution of 4π/3, so the answer is (g) 4π/3.
Let me know if this helped by hitting brainliest! If you have a question, please comment and I"ll get back to you ASAP!
Answer:
We know that sin(π/3) = √3/2, so we can write:
arcsin(-√3/2) = -π/3 + 2nπ or π + π/3 + 2nπ
where n is an integer.
Therefore, the values of arcsin(-√3/2) are:
a. π/3 + 2nπ
c. 11π/6 + 2nπ
e. 2π/3 + 2nπ
f. 7π/6 + 2nπ
So, options a, c, e, and f are all correct.
PLEASE HELP ME!!! Type the correct answer in each box. Use T for true and F for false.
Complete the truth table for the contrapositive of a conditional statement.
р
T
T
LL
LL
q
T
F
T
LL
P→q
T
F
T
T
~9~p
The answer will of given mathematical logic will be T F T T F respectivelly.
What fundamental ideas underlie mathematical logic?A negation, conjunction, and disjunction are the fundamental mathematical logics. The symbols for negation, conjunction, and disjunction in mathematical logic are "," "," and "v," respectively.
What is the purpose of mathematical logic?Logical proofs frequently employ mathematical logic. Proofs are legitimate arguments that establish the veracity of mathematical assertions. A series of statements make up an argument. The conclusion is the last assertion, and the premises are all the statements that came before it (or hypothesis).
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The complete truth table is shown in the below diagram.
≈ q → ≈ p: True False True True
Define the conditional statement for contrapositive?The contrapositive of a conditional statement is a new conditional statement that is formed by negating both the hypothesis (the "if" part) and the conclusion (the "then" part) of the original statement, and switching their positions. The truth table for the contrapositive of a conditional statement has the same number of rows as the truth table for the original statement.
For example, if the original statement is "If it is raining, then the ground is wet", then the contrapositive would be "If the ground is not wet, then it is not raining."
According to the given table the contrapositive of a conditional statement q and p is defines as;
True
False
True
True
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The population of a certain city was 3,846 in 1996. It is expected to decrease by about 0.27% per year. Write an exponential decay function, and use it to approximate the population in 2022.
Answer:
To write an exponential decay function for this situation, we can use the formula:
P(t) = P₀e^(rt)
where:
P(t) = the population at time t
P₀ = the initial population
r = the annual rate of decrease (as a decimal)
t = time in years
We are given P₀ = 3,846 and r = -0.0027 (since the population is decreasing).
To approximate the population in 2022, we need to find t, the number of years from 1996 to 2022. That is:
t = 2022 - 1996 = 26 years
Now we can plug in the values we have:
P(t) = 3,846 e^(-0.0027t)
To find P(2022), we plug in t = 26:
P(26) = 3,846 e^(-0.0027(26))
≈ 3,200.62
Therefore, we can approximate the population of the city in 2022 to be about 3,201 people.
Answer:
3,101
Step-by-step explanation:
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To write an exponential decay function for the population of the city, we can use the formula:
P(t) = P₀e^(-rt)
where P(t) is the population at time t, P₀ is the initial population, r is the decay rate, and e is the base of the natural logarithm.
In this problem, P₀ = 3,846 and r = 0.0027 (0.27% expressed as a decimal). We want to find the population in 2022, which is 26 years after 1996.To use the formula, we need to convert 26 years to the same time units as the decay rate. Since the decay rate is per year, we can use 26 years directly. Therefore, the exponential decay function for the population is:
P(t) = 3,846e^(-0.0027t)
To find the population in 2022 (t = 26), we substitute t = 26 into the function:
P(26) = 3,846e^(-0.0027*26) ≈ 3,101
Therefore, the population in 2022 is approximately 3,101.
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Find the derivative of f(x) = -2x^3 by the limit process…
Answer:
f'(x) = -6x^2
f'(-5) = -150
f'(0) = 0
f'(√17) = -102
2 PART QUESTION PLS HELP Harris has a spinner that is divided into three equal sections numbered 1 to 3, and a second spinner that is divided into five equal sections numbered 4 to 8. He spins each spinner and records the sum of the spins. Harris repeats this experiment 500 times.
Question 1
Part A
Which equation can be solved to predict the number of times Harris will spin a sum less than 10?
A) 3/500 = x/15
B) 12/500 = x/15
C) 12/15 = x/500
D) 3/15 = x/500
QUESTION 2
Part B
How many times should Harris expect to spin a sum that is 10
or greater?
_______
Accοrding tο the data, the answers tο Questiοns 1 and 2 are: Harris shοuld anticipate spinning a sum οr less 10 apprοximately 367 times and a tοtal that is 10 οr larger apprοximately 133 times.
What are a fοrmula and an equatiοn?Yοur example is an equatiοn since an equatiοn that's any statement with an equal's sign. The usage οf equatiοns in mathematical expressiοns is widespread because mathematicians adοre equal signs. An equatiοn is a cοllectiοn οf guidelines fοr prοducing a specific οutcοme.
Part A: Tο calculate the likelihοοd that Harris will spinning a sum οr less 10, multiply the οverall number οf spins by the chance οf οbtaining a sum οr less 10. The οutcοmes οf the first spinner's spin are 1, 2, and 3, while the results οf the secοnd spinner's spin are 4, 5, 6, 7, and 8. Hence, the amοunts οr less 10 are:
1 + 4 = 5
1 + 5 = 6
1 + 6 = 7
1 + 7 = 8
1 + 8 = 9
2 + 4 = 6
2 + 5 = 7
2 + 6 = 8
2 + 7 = 9
3 + 4 = 7
3 + 5 = 8
3 + 6 = 9
There are 11 amοunts that cοuld be less than ten. The number οf successful results divided by the entire number οf pοssibilities, which is 11/15, represents the likelihοοd οf receiving a payοut οf less than 10 in a single spin. Harris will therefοre spin a tοtal less than 10 times, and the equatiοn tο estimate this is:
11/15 = x/500
After finding x, we οbtain:
x = (11/15) x 500
x = 366.67, which rοunds up tο 367
Sο, Harris shοuld expect tο spin a sum less than 10 abοut 367 times.
Part B: Tο determine hοw frequently Harris shοuld anticipate spinning a sum οf ten οr mοre, we can deduct the times that he shοuld anticipate spinning a sum lοwer than ten frοm the οverall number οf spins:
500 - 367 = 133
Therefοre, Harris shοuld expect tο spin a sum that is 10 οr greater abοut 133 times.
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The cost of manufacturing a molded part is related to the quantity produced during a production run. When 100 parts are produced, the cost is $300. When 104 parts are
produced, the cost is $324. What is the average cost per part?
OA $0.23 per part
B. $6 per part
OC. $0.17 per part
OD. $7 per part
Answer:
B. $6 per part
Step-by-step explanation:
The average cost per part can be computed as follows
Average Cost = (324-300)/(104-100)
= 24/4
=$6
Answer: B. $6 per part
What is the meaning of "the homotopy classes of paths from x to x in a space X"?
The homotopy classes of paths from x to x in a space X refer to a set of equivalence classes of continuous paths that start and end at the same point, x, in the space X, where equivalence is defined in terms of homotopy.
What is the homotopy about?In other words, for any two paths, there exists a continuous transformation (called a homotopy) between them such that the endpoints remain fixed. Two paths are said to be homotopic if they can be continuously deformed into each other while keeping their endpoints fixed. The set of all paths that are homotopic to each other forms an equivalence class.
The homotopy classes of paths from x to x are important in algebraic topology, as they provide a way to study the topological structure of a space by analyzing the properties of the paths within it. They can also be used to define higher algebraic structures such as the fundamental group and higher homotopy groups.
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Michelle and Robert constructed a wooden bridge for ATVs over a deep creek on the edge of their property. To recuperate the cost of the materials, they decided to charge an annual toll of $8 to each of the 120 members of a local club. A survey showed that for every $1 the toll is increased, 4 members wouldn't use the bridge anymore. What is the best toll charge to allow them to recuperate the cost of the materials the fastest?
Answer:
the answer is $10
Step-by-step explanation:
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Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading greater than 0.28°C. Round your answer to 4 decimal places
The probability of obtaining a reading greater than 0.28°C is 0.3897.
What is standard normal distribution ?
The standard normal distribution is a specific type of probability distribution that has a mean of 0 and a standard deviation of 1. It is also called the Z-distribution or the Gaussian distribution.
The standard normal distribution is commonly used in statistics and probability theory to make comparisons and calculations across different normal distributions. To use the standard normal distribution for calculations involving a normal distribution with a different mean and standard deviation, the data must be standardized by subtracting the mean and dividing by the standard deviation.
According to the question:
To solve this problem, we need to standardize the value of 0.28°C using the standard normal distribution formula:
z = (x - mu) / sigma
where:
x = 0.28°C
mu = 0°C
sigma = 1.00°C
Substituting the values, we get:
z = (0.28 - 0) / 1.00
z = 0.28
Now, we need to find the probability of obtaining a reading greater than 0.28°C, which is the same as finding the area to the right of z = 0.28 on the standard normal distribution curve. We can use a standard normal distribution table or calculator to find this area.
Using a calculator or software, we find that the probability of obtaining a reading greater than 0.28°C is 0.3897, rounded to 4 decimal places.
Therefore, the probability of obtaining a reading greater than 0.28°C is 0.3897.
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