Answer:
3
Explanation:
The three things that can affect a condition to enforce a slide is friction, weight, and slope of an area. Solutions that can make flow easily are those that can create less friction depending on the condition of an environment where it is present.
Which compound has the greatest molecular mass?
CO2
H2O
Pb2
NH4
A student working in the laboratory produces 6.81 grams of calcium oxide, CaO, from 20.7 grams of calcium
carbonate, CaCO3, according to the reaction CaCO3 → CaO + CO2. Calculate the theoretical yield and
the percent yield for the reaction. Show and/or explain your work.
Answer:
A. Theoretical yield of CaO is 11.59 g
B. Percentage yield of CaO = 58.76%
Explanation:
The following data were obtained from the question:
Mass of CaCO₃ = 20.7 g
Actual yield of CaO = 6.81 g
Theoretical yield of CaO =?
Percentage yield of CaO =?
The equation for the reaction is given below:
CaCO₃ —> CaO + CO₂
Next, we shall determine the mass of CaCO₃ that decomposed and the mass of CaO produced from the balanced equation. This can be obtained as follow:
Molar mass of CaCO₃ = 40 + 12 + (3×16)
= 40 + 12 + 48
= 100 g/mol
Mass of CaCO₃ from the balanced equation = 1 × 100 = 100 g
Molar mass of CaO = 40 + 16 = 56 g/mol
Mass of CaO from the balanced equation = 1 × 56 = 56 g
SUMMARY:
From the balanced equation above,
100 g of CaCO₃ decomposed to produce 56 g of CaO.
A. Determination of the theoretical yield of CaO.
From the balanced equation above,
100 g of CaCO₃ decomposed to produce 56 g of CaO.
Therefore, 20.7 g of CaCO₃ will decompose to produce =
(20.7 × 56)/100 = 11.59 g of CaO.
Thus, the theoretical yield of CaO is 11.59 g
B. Determination of the percentage yield.
Actual yield of CaO = 6.81 g
Theoretical yield of CaO = 11.59 g
Percentage yield of CaO =?
Percentage yield = Actual yield /Theoretical yield × 100
Percentage yield = 6.81/11.59 × 100
Percentage yield of CaO = 58.76%
Assuming that only the listed gases are present, what would be the mole fraction of oxygen gas be for each of the following situations?
A gas sample of 2.31 atm of oxygen gas and 3.75 atm of hydrogen gas that react to form water vapor. Assume the volume of the container and the temperature inside the container does not change.
The mole fraction of oxygen gas : 0.381
Further explanationGiven
2.31 atm Oxygen
3.75 atm Hydrogen
Required
The mole fraction of Oxygen
Solution
Dalton Law's of partial pressure
P tot = P₁ + P₂ + ..Pₙ
Input the value :
P tot = P O₂ + P H₂
P tot = 2.31 atm + 3.75 atm
P tot = 6.06 atm
The mole fraction of O₂ (X O₂):
P O₂ = X O₂ x P tot
X O₂ = P O₂ / P tot
X O₂ = 2.31 /6.06
X O₂ = 0.381
The mole fraction of oxygen gas in the given mixture of oxygen and hydrogen gas is 0.381.
How do we calculate mole fraction?If the details is present in terms of partial pressure then by using the below equation, we can calculate the mole fraction as:
p = (x)(P), where
p = partial pressure
P = total pressure
x = mole fraction
Total pressure of the mixture will be calculated by adding the partial pressure of oxygen and hydrogen gases as:
P = 2.31 + 3.75 = 6.06 atm
Now mole fraction of oxygen will be calculated as:
x = 2.31 / 6.06 = 0.381
Hence mole fraction of oxygen is 0.381.
To know more about mole fraction, visit the below link:
https://brainly.com/question/1553736
Express 4,935,000 using standard scientific notation
Answer:
4.935×10-1
Explanation:
Take away the 0
