What type of organism is most likely to be oxidase positive?
A. Aerobic
B. Anaerobic
C. Gram negative
D. Enteric

Answer:

the work done on the ball is 0

Explanation:

Given the data in the question;

Katie swings a ball around her head at constant speed in a horizontal circle with circumference 2.1 m.

circle circumference = 2πr = 2.1 m

radius r will be; r = 2.1 m / 2π = 0.33 m

Tension force = 34.4 N

one half revolution means, displacement of the ball is;

d = 2r = 2 × 0.33 = 0.66 m

Now, Work done = force × displacement × cosθ

we know that, the angle between the tension force on string and displacement of object is always 90.

so we substitute

Work done = 34.4 N × 0.66 m × cos(90)

Work done = 34.4 N × 0.66 m × 0

Work done = 0 J

Therefore,  the work done on the ball is 0

Answer:

In a column of fluid, pressure increases with depth as a result of the weight of the overlying fluid. Thus a column of fluid, or an object submerged in the fluid, experiences greater pressure at the bottom of the column than at the top. This difference in pressure results in a net force that tends to accelerate an object upwards.

The pressure at a depth in a fluid of constant density is equal to the pressure of the atmosphere plus the pressure due to the weight of the fluid, or p = p 0 + ρ h g , p = p 0 + ρ h g , 14.4

Granite: 2.70 × 10 32.70 × 10 3

Lead: 1.13 × 10 41.13 × 10 4

Iron: 7.86 × 10 37.86 × 10 3

Oak: 7.10 × 10 27.10 × 10 2

Explanation:

a) D_t = 500m*10laps

D_t = 5000m or 5km

b)

I) v = d/t

v = 500m/50s

v = 10m/s

ii) 10m/s = 5000m/t

t = 5000m/10m/s

t = (500s)*(1min/60s)

t = 8'20" or 8 mins and 20 sec

c) v_f = v_0 + a*t

v_f-v_0 = a*t

a = (v_f-v_0)/t

a = (12m/s-8m/s)/2s

a = (4m/s)/2s

a = 2m/s²

Part(a),

The distance travelled by the cyclist is 5 km.

Part(b),

(i) The average speed is 10 m/s

(ii) The time taken to cover 10 laps is 8 minutes and 20 seconds.

Part(c),

The acceleration is 2 m/s²

Speed is defined as the ratio of the time distance travelled by the body to the time taken by the body to cover the distance. Speed is the ratio of the distance travelled by time. The unit of speed in miles per hour.

a) The distance will be calculated as

D = 500m*10laps

D = 5000m or 5km

b) The average speed is calculated as,

I) v = d/t

v = 500m/the 50s

v = 10m/s

The time will be calculated as,

ii) 10m/s = 5000m/t

t = 5000m/10m/s

t = (500s)*(1min/60s)

t = 8'20" or 8 mins and 20 sec

The acceleration is calculated as,

c) vf = v0 + at

vf-v0 = at

a = (vf-v0)/t

a = (12m/s-8m/s)/2s

a = (4m/s)/2s

a = 2m/s²

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Answer

Irma

Explanation:

You should invite Irma to the meeting because she is in Charlotte and she also visited after 10/24/20

Answer:

Explanation:

In the first moments after the Big Bang, the universe was extremely hot and dense. As the universe cooled, conditions became just right to give rise to the building blocks of matter – the quarks and electrons of which we are all made. A few millionths of a second later, quarks aggregated to produce protons and neutrons. Within minutes, these protons and neutrons combined into nuclei. As the universe continued to expand and cool, things began to happen more slowly. It took 380,000 years for electrons to be trapped in orbits around nuclei, forming the first atoms. These were mainly helium and hydrogen, which are still by far the most abundant elements in the universe. Present observations suggest that the first stars formed from clouds of gas around 150–200 million years after the Big Bang. Heavier atoms such as carbon, oxygen and iron, have since been continuously produced in the hearts of stars and catapulted throughout the universe in spectacular stellar explosions called supernovae.

But stars and galaxies do not tell the whole story. Astronomical and physical calculations suggest that the visible universe is only a tiny amount (4%) of what the universe is actually made of. A very large fraction of the universe, in fact 26%, is made of an unknown type of matter called "dark matter". Unlike stars and galaxies, dark matter does not emit any light or electromagnetic radiation of any kind, so that we can detect it only through its gravitational effects.  

An even more mysterious form of energy called “dark energy” accounts for about 70% of the mass-energy content of the universe. Even less is known about it than dark matter. This idea stems from the observation that all galaxies seems to be receding from each other at an accelerating pace, implying that some invisible extra energy is at work.

Protons and neutrons formed from quarks in the early universe, a process driven by extremely high temperatures and energies.

In the early cosmos, quarks generated protons and neutrons, which form atomic nuclei, according to the Big Bang hypothesis. Quarks and gluons, which bond quarks, existed freely in a quark-gluon plasma state in the early cosmos due to extreme heat and energy.

Hadronization formed protons and neutrons from quarks as the cosmos cooled and expanded. Eventually, protons and neutrons formed atomic nuclei as the cosmos evolved. This key stage in the early universe's existence formed the basic particles that make up matter today.

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1. Based on Scenario A, multiple frames will minimize re-transmission overhead and should be preferred in the encapsulation of packets.

2. Based on Scenario B, the encapsulation of packets should be in a single frame because of the high level of network reliability and accuracy.

Justification:

There will not be further need to re-transmit the packets in a highly reliable and accurate network environment, unlike in an environment that is very prone to errors.  The reliable and accurate network environment makes a single frame economically better.

Encapsulation involves the process of wrapping code and data together within a class so that data is protected and access to code is restricted.

With encapsulation, each layer:

Thus, in a reliable and accurate network environment, single frames should be used to enhance transmission and minimize re-transmission overhead.  This is unlike in an environment that is very prone to errors, where multiple frames should rather be used to minimize re-transmission overhead.

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Answer:

the cubic meter (m3)

Explanation:

Volume is the measure of the 3-dimensional space occupied by matter, or enclosed by a surface, measured in cubic units. The SI unit of volume is the cubic meter (m3),

Answer:

please answer all  component's

Explanation:

please answer all  component's

Answer: TRACK

Explanation:

We have that the power of the compressor is

[tex]H_p=24.242hp[/tex]

From the question we are told that:

Flow rate [tex]W=1kg/s[/tex]

inlet Pressure [tex]P_1=1 bar[/tex]

inlet Temperature [tex]T_1= 288k[/tex]

Outlet Temperature [tex]T_2= 370k[/tex]

Outlet Pressure [tex]P_2=200 kN/m^2=2bars[/tex]

[tex]Cp = 1.103 kJ[/tex]

[tex]R = 287 kJ (kg.k)​[/tex]

Generally, the equation for Adiabatic head  is mathematically given by

[tex]H=\frac{ZRT_1}{Cp-1/K}[\frac{P_2}{P_1}^{(Cp-1)/Cp}-1][/tex]

Where

[tex]Z=Compressibility\ factor[/tex]

[tex]Z=0.99[/tex]

Therefore

[tex]H=\frac{(0.99)(287)(288)}{(1.103)-1/(1.103)}[\frac{(200)}{(1)}^{((1.103)-1)/(1.103)}-1][/tex]

[tex]H=560925.5958 J/kg[/tex]

[tex]H=5.6*10^5J/kg[/tex]

Generally, the equation for centrifugal compressor power  is mathematically given by

[tex]H_p=\frac{WH}{E*33000}[/tex]

Where

E is efficiency (adiabatic)

[tex]E=70\%=0.7[/tex]

Therefore

[tex]H_p=\frac{(1)(5.6*10^5)}{0.7*33000}[/tex]

[tex]H_p=24.242hp[/tex]

In conclusion

The power of the compressor is

[tex]H_p=24.242hp[/tex]

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Answer:

a) 70,560 J

b) 88.2 N/m

Explanation:

The spring potential will equal the change in gravity potential

PS = PE = mgh = 80(9.8)(100 - 10) = 70,560 J

PS = ½kx²

k = 2PS/x² = 2(70560)/(100 - 50 - 10)² = 88.2 N/m

Answer:

39200 joules

the potential energy will be zero

Explanation:

we know that potential energy is found by multiplying mass, acceleration due to gravity and height from the Earth's surface

so it will be

potential energy= mgh

80x9.8x15

= 39200 joules

the potential energy of the mental ball will be zero when kept on the Earth's surface because the height from the Earth's surface will be zero and zero multiplied to any number is zero only

I have a doubt with the second one, this is what I think it is. Consult your teacher if you think my answer for the second one is wrong

Answer:

392000 joules

Explanation:

hope it helpsss

Answer:

it's electron attraction

The answer is Electron Attraction

Answer:

[tex]y=\frac{1}{2}x-2[/tex]

Explanation:

Slope-intercept form means we want the y to be by itself in the equation. Every thing we do will be about getting the y alone on the left side of the equation

To start we should move x to the left hand side. We can do this by subtracting x from both sides. That way, there is an x on the right, but not the left.

x-x-2y=4-x

this gives us

-2y=4-x

Great! So now what? Well, the y isn't by itself yet because it still is being multiplied by negative two (-2). In order to move it from the left side to the right side, we have to do the opposite of multiply; divide. So, we will divide both sides by -2

[tex]\frac{-2y}{-2} =\frac{4}{-2} -\frac{x}{-2}[/tex]

-2 divided by -2 is 1, 4 divided by -2 is -2, and -x divided by -2 is [tex]\frac{1}{2}x[/tex]

This gives us the answer:  [tex]y=\frac{1}{2}x-2[/tex]

Tips:

A negative divided by a negative is a positive ex: -4 divided by -2 is positive 2

If you are subtracting by a negative number, you are actually adding by a positive ex: 2-(-2) is actually 2+2

Don't be afraid to have fractions in your equations

Whatever you do to the one side of the equation, you must do it to the other side as well. Multiply the left side by 2? You HAVE TO multiply the right side by two as well. Add 3 to the right side? You HAVE TO add 3 to the left.

For problems like this (and when you have access to the internet), where you need to rewrite an equation, double check your work on desmos, which is an online graphing calculator. Input both the original equation and the equation you rewrote, and if they don't create the same line, you did something wrong.

Answer:

Resistance is 1.75 ohms

Explanation:

Magnetic flux:

[tex]{ \phi{ = NBA}}[/tex]

N is number of turns, N = 8

B is magnetic flux

A is area of projection.

From faradays law:

[tex]E = - \frac{ \triangle \phi}{t} [/tex]

where E is the Electro motive force.

But E = IR

where I is current and R is resistance:

[tex]IR = \frac{( \phi_{1} - \phi _{2}) }{t} \\ \\ 140 \times R = \frac{8 \times (8 - 5)}{0.098} \\ \\ R = \frac{24}{0.098 \times 140} \\ \\ resistance = 1.75 \: ohms[/tex]

Answer:

 N = 107.94 N

Explanation:

For this exercise we must use Newton's second law.

Let's set a reference system with the x-axis parallel to the ground and the y-axis vertical

X axis

        Fₓ = ma

ej and

       N -F_y - W = 0

let's use trigonometry to decompose the applied force

     cos -35 = Fₓ / F

     sin -35 = F_y / F

     Fₓ = F cos -35

     F_y = F sin -35

     Fₓ = 40.0 cos -35 = 32.766 N

     F_y = 40.0 sin -35 = -22.94 N

we substitute

     N = Fy + W

     N = 22.94 + 85

     N = 107.94 N

Answer:

c

Explanation:

Liquid plastic is frozen in a physical change that increases its volume,it can be known about the plastic that Its mass will remain the same, therefore the correct answer is option C.

Anything which has mass and occupies space is known as matter ,mainly there are four states of matter solid liquid gases, and plasma.

These different states of matter have different characteristics according to which they vary their volume and shape.

It is known about plastic that its mass will remain the same when liquid plastic is frozen, by increasing its volume.

Liquid plastic is frozen in a physical change that increases its volume,it can be known about the plastic that Its mass will remain the same,  therefore the correct answer is C.

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A single force acts on a particle situated on the positive x axis. The torque about the origin is in the negative z direction. The force might be in the negative y direction. Thus, option B is correct.

To determine the force that could generate a torque in the negative z direction, we need to consider the right-hand rule for cross products. The torque vector, denoted by τ, is given by the cross product of the position vector, r, and the force vector, F:

[tex]τ = r × F[/tex]

In this case, the position vector, r, points along the positive x-axis. The negative z-direction torque indicates that the force vector must be perpendicular to both the position vector and the negative z-axis.

Using the right-hand rule, we can determine that the force vector must be in the negative y-direction, which is option B.

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Answer:

  E_ {total} = [tex]\frac{Q }{L^2 \epsilon_o}[/tex]

Explanation:

In this exercise you are asked to calculate the electric field between two plates, the electric field is a vector

         E_ {total} = E₁ + E₂

         E_ {total} = 2 E

where E₁ and E₂ are the fields of each plate, we have used that for the positively charged plate the field is outgoing and for the negatively charged plate the field is incoming, therefore in the space between the plates for a test charge the two fields point in the same direction

to calculate the field created by a plate let's use Gauss's law

          Ф = ∫ E . dA = q_{int} /ε₀

As a Gaussian surface we use a cylinder with the base parallel to the plate, therefore the direction of the electric field and the normal to the surface are parallel, therefore the scalar product is reduced to the algebraic product.

           E 2A = q_{int} / ε₀

where the 2 is due to the surface has two faces

indicate that the surface has a uniform charge for which we can define a surface density

           σ = q_{int} / A

           q_{int} = σ A

we substitute

           E 2A = σ A /ε₀

           E = σ / 2ε₀  

therefore the total field is

           E_ {total} = σ /ε₀

let's substitute the density for the charge of the whole plate

           σ= Q / L²

            E_ {total} = [tex]\frac{Q }{L^2 \epsilon_o}[/tex]

Answer:

R = 0.0015Ω

Explanation:

The formula for calculating the resistivity of a material is expressed as;

ρ = RA/l

R is the resistance

ρ is the resistivity

A is the area of the wire

l is the length of the wire

Given

l = 85cm = 0.85m

A = πr²

A = 3.14*0.0018²

A = 0.0000101736m²

ρ = 1.75 × 10-8Ωm.

Substitute into the formula

1.75 × 10-8 = 0.0000101736R/0.85

1.4875× 10-8 = 0.0000101736R

R = 1.4875× 10-8/0.0000101736

R = 0.0015Ω

Answer:

okk

now what do I do with it

Answer:

26 km

Explanation:

Let's say our "cable" has a cross section of 1 m²

Then each meter of cable would weight 7900(9.8) = 77420 N

A Pascal is a Newton per square meter

2 x 10⁹ / 77420 = 25840 m or about 26 km or about 16 miles

Answer:

chk picture for eqn

Explanation:

Answer:

Biosphere is the part of the earth where life exists.

We know

[tex]\boxed{\large{\sf Velocity=\dfrac{Distance}{Time}}}[/tex]

[tex]\\ \Large\sf\longmapsto Velocity=\dfrac{6}{\dfrac{1}{2}}[/tex]

[tex]\\ \Large\sf\longmapsto Velocity=6\times 2[/tex]

[tex]\\ \Large\sf\longmapsto Velocity=12km/h[/tex]

Is this the right answer??

We should keep km and min in smallest SI unit

Answer:

[tex]\boxed {\boxed {\sf 100 \ J}}[/tex]

Explanation:

We are asked to calculate the work done to move a box.

Work is the product of force and distance or displacement.

[tex]W= F*d[/tex]

A 10 Newton force is applied horizontally on the box. Since the surface is frictionless, there is no force of friction, and the net force is 10 Newtons. The force moves the box 10 meters.

Substitute the values into the formula.

[tex]W= 10 \ N * 10 \ m[/tex]

Multiply.

[tex]W= 100 \ N*m[/tex]

Let's convert the units. 1 Newton meter is equal to 1 Joule, therefore our answer of 100 Newton meters is equal to 100 Joules.

[tex]W= 100 \ J[/tex]

100 Joules of work was done to move the box.

Answer:

The additional load is 20g

Answer:

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

Explanation:

Answer:

A.

Explanation:

Amplitude measures how much a wave rises or falls. This is illustrated by A.

In the diagram, the amplitude of the wave is shown by A.

There are various definitions of amplitude, which are all functions of the magnitude of the differences between the variable's extreme values.

The amplitude of a variable is simply a measure of change relative to its central position. In contrast, magnitude is a measure of the distance or quantity of a variable irrespective of its direction.

Amplitude is a property that is unique to waves and oscillations.

Therefore, in the diagram, the amplitude of a wave is shown by A.

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