When a rope is wrapped around a wheel (or pulley) and pulled, the lever arm is the ________ Blank 1 of the wheel and the angle between this and the force is ALWAYS ________ degrees. Blank 2

Answers

Answer 1

Answer:

the DISTANCE between the lever arm and the force is always 90º

Explanation:

In this exercise, you are asked to complete the missing words so that the phrase makes sense.

note that the torque is

              τ = F x r

where bold indicates vectors

When the rope is pulled, the DISTANCE between the lever arm and the force is always 90º


Related Questions

When the spacecraft is at the halfway point, how does the strength of the gravitional force on the spaceprobe by Earth compre with the strength

Answers

Solution :

When the spacecraft is at halfway point, the distance from the Earth as well as Mars are same. We have to account the masses of the planets. The gravitational force that is exerted by the Earth is greater because of its combined mass with the space probe.

The mass of Earth is greater than the mass of Mars. Therefore, the force of Earth is more than Mars.

No me sale este problema :c, plano inclinado

Answers

Answer:

i didn't understand,

Explanation:

sorry

Which of the following quantity is unit-less? 1 Specific gravity 2 Mass density 3 Acceleration due to gravity 4 All of the above​

Answers

Answer:

1

Explanation:

Specific gravity is a ratio (of 2 densities) so it has no unit.

En la figura, la tensión desarrollada en cada
cuerda está dada por los dinamómetros:
T1=8 N y T2=6 N, y el ángulo de inclinación
de la primera cuerda es de 45°. Determine la
masa de la caja que debe sostener y el
ángulo con respecto a la horizontal.

Answers

Answer:

Parte A

El ángulo con respecto al horizonte, de la segunda cuerda es de aproximadamente 19,47°

Parte B

La masa de la caja que se va a sostener es de aproximadamente 0,7808 kg.

Explanation:

Parte A

Los parámetros dados son;

La tensión en la cuerda, T₁ = 8 N

La tensión en la cuerda, T₂ = 6 N

El ángulo de inclinación de la primera cuerda con la horizontal, θ₁ = 45°

Sea θ₂ el ángulo de inclinación de la segunda cuerda, obtenemos;

T₁·cos (θ₁) = T₂·cos (θ₂)

∴ 8 N × cos (45°) = 6 N × cos (θ₂)

cos (θ₂) = 8 N × cos (45°) / (6 N) = (√2)/2 × (4/3) = (2·√2)/3

θ₂ = arcos ((2·√2) / 3) ≈ 19,47°

El ángulo con respecto al horizonte, de la segunda cuerda, θ₂ ≈ 19,47°

Parte B

El peso de la caja, W = T₁·sin (θ₁) + T₂·sin (θ₂)

∴ W = 8 N × sen (45 °) + 6 N × sen (19,47 °) ≈ 7,66 N

El peso de la caja que se va a sostener, W ≈ 7,66 N

La masa de la caja que se va a sostener, m ≈ 7,66 N / (9,81 m/s²) ≈ 0,7808 kg

three condensers are connected in series across a 150 volt supply, the voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10^-8 c.calculate (a) the capacitance of each condenser (b)the effective capacitance of the combination

Answers

Answer:

(a) 1.5 nF, 1.2 nF, 1 nF

(b) 0.4 nF

Explanation:

V = 150 V

V' = 40 V, V'' = 50 V, V''' = 60 V, q = 6 x 10^-8 C

(a) C' = q/V' = 6 x 10^-8 / 40  = 1.5 x 10^-9  F

C'' = q/V'' = 6 x 10^-8 / 50 = 1.2 x 10^-9 F

C''' = q/V''' = 6 x 10^-8 / 60 = 1 x 10^-9 F

(b) The effective capacitance is

[tex]\frac{1}{C}=\frac{1}{C'}+\frac{1}{C''}+\frac{1}{C'''}\\\\\frac{1}{C}=\frac{10^9}{1.5}+\frac{10^9}{1.2}+\frac{10^9}{1}\\\\C = 0.4\times 10^{-9} F[/tex]  

what force to be required to accelerate a car of mass 120 kg from 5 m/s to 25m/s in 2s​

Answers

Answer:

[tex]f = m \frac{v1 - v2}{t} \\ = 120 \times \frac{25 - 5}{2} \\ = 120 \times \frac{20}{2} \\ = 120 \times 10 \\ = 1200N \\ thank \: you[/tex]

Un alambre de plástico, aislante y recto mide 10 cm de longitud y tiene una densidad de carga de +150 nC/m, distribuidos de manera uniforme por toda su longitud. Se encuentra sobre una mesa horizontal. A) Encuentre la magnitud y la dirección del campo eléctrico que produce este alambre en un punto que está 8 cm directamente arriba de su punto medio. B) Si el alambre ahora se dobla para formar un círculo que se coloca aplanado sobre la mesa, calcule la magnitud y la dirección del campo eléctrico que produce en un punto que se encuentra 6 cm directamente arriba de su centro.

Answers

Answer:

English only

Explanation:

When solving problems related to Electric Fields, care must be taken about symmetries. In our particular case when we take a look to at the drawings of the attached file, we realize:

1.-By symmetry each dx associated at a, has an opposite dx with point b as reference. The respective dE ( the charge is uniform ) is the same, as the charge of the wire is positive the force and the Field on a test charge (+) located at h will be upward, therefore the components dEx will cancel each other and the Electric Field becomes E = Ey = ∫ 2×dE× cosθ

The solutions:

A) Ey = 4623 N/C

B) Ey = 19.34 N/C

E = Ey = ∫ 2×dE× cosθ

Here     cosθ   = h/ d   ⇒  cosθ = h/√h² + x²      dE = K× dQ / d²

d² = h² + x²

k = 8.9 ×10⁹ Nm²C⁻²  ;   dQ = λ×dx     λ = 150×10⁻⁹ C    h = 0.08 m

Then by substitution

Ey =  2 ∫[K× λ×dx/ (h² + x²) ] × h / √h² + x²

reordering that equation:

Ey = 2×K×λ×h ∫ dx / [√ ( h² + x² ) ]³          (2)

To solve the integral we make use of a change of variables

x = h × tanα     then   x² = h² ×tan²α   and  dx = h× sec²α dα

plugging that values in equation (2)

Ey  =  2×K×λ×h ∫  h× sec²α× dα / [√ ( h² + h²tan²α)]³

Ey  = 2×K×λ×h² ∫ sec²α× dα / [ h × √ (1 + tan²α)]³            1 + tan²α = sec²α

Ey = 2×K×λ×h²× ∫ (sec²α / h³× sec³α )×dα

Ey = 2×K×λ/h × ∫ ( 1 / secα dα

Ey = 2×K×λ/h × sinα             now we αneed to come back to our original variables:

as   x = h × tanα         tanα = x/h   then x is the opposite leg in a right triangle  and h the adjacent one then the hypothenuse is √ (h² + x²)         then    sin α = x/ √ (h² + x²)      

Ey = 2×K×λ/h × x/ √ (h² + x²) |₀⁰°⁰⁵

Ey  = 2×8.9×10⁹× 150×10⁻⁹× 5×10⁻²/8× 10⁻²× √ 10⁻² ( 8 + 5 )   N/C

Ey = 4623 N/C

To answer the second question again we will make use of symmetries if you look at drawing ( Figure 2 ) you see that again the components in direction of x-axis cancel each other and the components in y-axis direction will add. Then

Ey = ∫ dE× cosθ

following the same procedure  we will find:

Ey = ∫ [K×λ × dl/d²] × h/ d

The importan point here is that the radius of the circle is

2×π×r = 0.01      ( the length of the wire)  ⇒  r = 0.16×10⁻² m

And we need to take into account that the integration is over the circle and the length of the circle is 0.01 m or ××2×π×r. All other factors are constant. Then by substitution

Ey = [K×λ ×h×  / ( √ r² + h²)³ ] × 10⁻²    N/C

Ey = 8.9 × 10⁹ × 150× 10⁻⁹ × 6× 10⁻² × 10⁻² / √ 10⁻² ( 0.16 + 6)

Ey = 0.8 × 10² / 6

Ey = 19.34 N/C

The work function for silver is 4.73 eV. (a) Convert the value of the work function from electron volts to joules.

Answers

Answer:

[tex]W=7.56\times 10^{-19}\ J[/tex]

Explanation:

Given that,

The work function for silver is 4.73 eV.

We need to find the value of the work function from electron volts to joules.

We know that,

[tex]1\ eV=1.6\times 10^{-19}\ J[/tex]

For 4.73 eV,

[tex]4.73\ eV=1.6\times 10^{-19}\times 4.73\\\\=7.56\times 10^{-19}\ J[/tex]

So, the work function for silver is [tex]7.56\times 10^{-19}\ J[/tex].

a ball is launched upward at an angle from the ground. which way does its acceleration point at the top?

Answers

For a ball that is launched upward at an angle from the ground, the direction of its acceleration at the top of the projectile curve is downwards.

Acceleration of the ball at the top

As the ball is projected upward its acceleration points upwards until the ball reaches the maximum height or top of the projectile path.

At the top of the projectile path, its acceleration start pointing downwards.

Thus, for a ball that is launched upward at an angle from the ground, the direction of its acceleration at the top of the projectile curve is downwards.

Learn more about downward acceleration here: https://brainly.com/question/22048837

#SPJ1

Answer:

vertical

Explanation:

Which of the following statements describes how tectonic plates move?
A. They move from the crust to the core.
B. They move from the mantle to the inner core.
C. They move from the inner core to the outer core.
D. They move slowly on top of the mantle.

Answers

Answer:

D

Explanation:

The tectonic plates move on the mantle, sort of floating on it as they are part of the crust. When they collide things like mountain ranges form, and big earthquakes happen.

why does a desert cooler cool better than a hot dry day​

Answers

On a hot dry day, the amount of water vapour present in atmosphere is less. Thus, water present inside the desert cooler evaporates more, thereby cooling the surroundings more. Hence, a desert cooler cools better on a hot dry day.

what is the relationship between Hectare and cubic meter

Answers

Answer;

1 hectare meter is equal to 10000 cubic meter.

(a) What is the escape speed on a spherical asteroid whose radius is 301 km and whose gravitational acceleration at the surface is 0.412 m/s2

Answers

Answer:

[tex]V.E=498.02m/s^2[/tex]

Explanation:

From the question we are told that:

Radius [tex]r=301Km[/tex]

Gravitational acceleration [tex]g=0.412 m/s^2[/tex]

Generally the equation for Escape velocity is mathematically given by

 [tex]V.E^2=2gr[/tex]

 [tex]V.E^2=2*0.412m/s^2*301000[/tex]

 [tex]V.E^2=248024[/tex]

 [tex]V.E=\sqrt{248024}[/tex]

 [tex]V.E=498.02m/s^2[/tex]

Two drums of the same size and same height are taken.
i)what will be the difference in liquid pressure on their bases if A of them is completely filled and B is half filled and kept at the same place.
ii) what will be the difference in liquid pressure on their bases if both A and B are filled with water completely but one of them is kept at nepal and another in india?why?
iii) what will be the difference in liquid pressure on their bases if A is filled with water and B is filled with salty water and kept at delhi in the same position?why?​

Answers

Answer:

i) The pressure acting on the base of B will be half the pressure acting on the base of A

ii) The pressure acting on the base of B will be the same as the pressure acting on the base of A

iii) The pressure on the base of drum A will be slightly less than the pressure on the base of drum B

Explanation:

The pressure acting on the base of the drum, P = h·ρ·g

Where;

h = The level of the liquid in the drum

[tex]h_{max}[/tex] = The height of the drums

ρ = The density of the liquid in the drum

g = The acceleration due to gravity ≈ 9.81 m/s²

i) If A is completely filled, we have [tex]h_A[/tex] = [tex]h_{max}[/tex]

Therefore, [tex]P_A[/tex] = [tex]h_{max}[/tex]×[tex]\rho_{liquid}[/tex]×g

If B is half filled, we have, [tex]h_B[/tex] =  (1/2)·[tex]h_{max}[/tex]

[tex]P_B[/tex] = (1/2) × [tex]h_{max}[/tex]×[tex]\rho_{liquid}[/tex]×g

Therefore, [tex]P_B[/tex] = (1/2) × [tex]P_A[/tex]

The pressure acting on the base of B will be half the pressure acting on the base of A

ii) If both A and B are each filled with water (the same liquid), then the pressure on their bases will be [tex]P_A[/tex] = [tex]h_{max}[/tex]×[tex]\rho_{water}[/tex]×g = [tex]P_B[/tex], the same, given that the acceleration due to gravity, g, is constant and the same in Nepal and India

iii) If A is filled with water, and B is filled with salty water, we have that, the density of salty water is slightly higher than water, therefore, we get;

[tex]P_A[/tex] = [tex]h_{max}[/tex]×[tex]\rho_{water}[/tex]×g <  [tex]P_B[/tex] =

The pressure on the base of drum A will be less than the pressure on the base of drum B.

The most successful types of plants on Earth are

Answers

angiosperm! make up around 90%of all plants species

Answer:

The angiosperms dominate Earth's surface and vegetation in more environments, particularly terrestrial habitats, than any other group of plants. As a result, angiosperms are the most important ultimate source of food for birds and mammals, including humans.

Explanation:

plz mark brainlest

What process forms the Mid-Atlantic Ridge?
A. Radioactive decay
B. Seafloor spreading
C. Radiometric dating
D. Sediment formation

Answers

Answer:

B. seafloor spreading

Explanation:

divergent motion between the Eurasian and North American, and African and South American Plates. ... In this way, as the plates move further apart new ocean lithosphere is formed at the ridge and the ocean basin gets wider

geological society

If the particles that make up an object begin to move quickly, their average kinetic energy _____ and the object's temperature _____. Group of answer choices

Answers

Explanation:

If the particles that make up an object begin to move quickly, their average kinetic energy increases the object's temperature rises. Group of answer choices

A 5.0 kg box moving at 2.0 m/s on a horizontal, frictionless surface runs into a light horizontal spring of force constant 85 N/cm. Use the work-energy theorem to find the maximum compression of the spring.

Answers

Answer:

x = 4.85 cm

Explanation:

From work energy theorem when dealing with a spring in compression, we know that total work done is;

W_t = ½kx²

Where;

k is Force constant

x is max compression

Now, we know that this is also equal to the kinetic energy.

K.E = ½mv²

Thus;

½kx² = ½mv²

Making x the subject;

x = √(mv²/k)

We are given;

m = 5 kg

v = 2 m/s

k = 85 N/cm = 8500 N/m

Thus;

x = √(mv²/k)

x = √(5 × 2²/8500)

x = 0.0485 m

x = 4.85 cm

In both the camera and the __________, light enters a narrow opening and is projected onto a photosensitive surface. Group of answer choices

Answers

Answer: The HUMAN EYE

Explanation:

The human eye is made up of different parts which ranges from controlling the amount of light that enters the eye to the focusing of the image that is formed. The camera is a device which is both mechanically and electronically operated which shares a number of similarities with the eye.

In the human eye, the IRIS helps to regulate the amount of rays passing through the pupil to the lens by either contracting or dilating in light or dark environment respectively. While in the camera, the DIAPHRAGM controls the amount of light entering the camera.

The PUPIL serves as the passage for light into the eye while in the camera, the APERTURE does the same.

The photosensitive surface in the eye is the YELLOW SPOT while in the camera, the photosensitive surface is the PHOTOGRAPHIC FILM.

When cars travel around a banked (curved) road at the optimum angle,the normal reaction force (n) can provide the necessary centripetal force without the need for a friction force. (a)Describe whar would happen to Optimum banking angle when radius doubles? (b)Describe what would happen to optimum angle when speed doubles? (c)A car negotiate a turn of radius 80cm.What is the optimum banking angle for this curve if the speed is to be equal to 12m/s?​

Answers

Answer:

(a) The optimum banking Decreases

(b) The optimum banking Increases

(c) The optimum banking is approximately 86.88°

Explanation:

(a) The equation of motion on a banked road is given as follows;

[tex]v = \sqrt{R \cdot g \times \left(\dfrac{tan (\theta) + \mu}{1 - \mu \cdot tan (\theta) }\right) }[/tex]

For no friction, we have;

v = √(R·g·tan(θ))

Where;

R₁ = The radius of the road

g = The acceleration due to gravity ≈ 9.81 m/s² = Constant

θ₁ = The bank angle

μ = The coefficient pf friction = Constant

v = The vehicle's speed

If the radius doubles, for no friction, we have;

v² = R·g·(tan(θ))

tan(θ) = v²/(R·g)

Therefore, when the radius doubles, tan(θ) becomes smaller and therefore, the optimum banking angle θ decreases (becomes smaller)

(b) When the speed doubles, we have;

v₁ = 2·v

∴ tan(θ₁) = (v₁)²/(R·g) = 4·(v)²/(R·g) = 4·tan(θ)

When the speed doubles, tan(θ) increases and therefore, the optimum banking angle θ increases increases

(c) The radius negotiated by the car, R = 80 cm = 0.8 m

The speed of the car, v = 12 m/s

From tan(θ) = v²/(R·g), we have;

tan(θ) = 12²/(0.8 × 9.81) ≈ 18.349

θ ≈ arctan(18.349°) ≈ 86.88°

An airplane with a ground speed of 550 km/hr travels along a heading of 30 degrees n of w at that high altitude there is a powerful 210 km/hr wind

Answers

Answer:

Determine the direction that the pilot is aiming the plane.

Explanation:

A particle is moving on a circular path of radius R. What will be its displacement and distance covered after 3 ½ round?


(please help fast)​

Answers

Answer:

2r or diameter

Explanation:

After 3 1/2 rounds it will end up on the other side of the circle and displacement will be 2 x the radius = d

Distance = 7 π R

Displacement = 2 R from the starting point directed through the center of the circle

In an experiment the mass of a calorimeter is 36.35 g . Express in micrometer ,millimetre and kg.

Answers

Answer:

1. 36.35 g = 36.35E15 micrometer.

II. 36.35 g = 363.5 millimetre.

III. 36.35 g = 0.03635 kilogram.

Explanation:

Given the following data;

Mass of calorimeter = 36.35 grams

To convert the mass in grams (g) to;

I. Micrometer

Conversion:

1 g = 1 exp 15 um

36.35 g = X um

Cross-multiplying, we have;

X = 36.35 * 1 exp 15 = 36.35 exp 15 um

36.35 g = 36.35E15 micrometer

II. Millimetre

Conversion:

1 g = 1 milliliter

36.35 g = X milliliter

Cross-multiplying, we have;

X = 36.35 * 1 = 36.35 milliliter

Next, we would convert milliliter to millimetre;

1 milliliter = 10 millimetre

36.35 milliliter = X millimetre

Cross-multiplying, we have;

X = 36.35 * 10 = 363.5 millimetre

36.35 g = 363.5 millimetre

III. Kilogram

Conversion:

1000 grams = 1 kilogram

36.35 g = X kilogram

Cross-multiplying, we have;

X * 1000 = 36.35 * 1

Dividing both sides by 1000, we have;

X = 36.35/1000 = 0.03635 kilogram

36.35 g = 0.03635 kilogram

Note:

g is the symbol for grams.Exp (E) means exponential = 10um is the symbol for micrometer.

A cannon sitting on level ground is aimed at 45.0 degrees relative to the horizontal. It fires a test shot at a target located 100.0 meters away from the cannon on the same level ground. The test overshoots the target by 20.0 meters. Which of the following angles can the cannon be adjusted to to hit the target. You may neglect air resistance and assume the cannon always delivers the same initial velocity to the cannonball .

A. 35.9 deg
B. 49.1 deg
C. 28.2 deg
D. 52.8 deg
E. 22.7 deg

Answers

Answer:

C. 28.2 deg

Explanation:

The horizontal range of a projectile is given as:

[tex]R = \frac{v^2Sin2\theta}{g}[/tex]

where,

R = Range

v = speed

θ = angle of launch

g = acceleration due to gravity = 9.81 m/s²

First, we will find the launch speed (v) by using the initial conditions:

R = 120 m

θ = 45°

Therefore,

[tex]120\ m = \frac{v^2Sin 90^o}{9.81\ m/s^2}\\\\v = \sqrt{(120\ m)(9.81\ m/s^2)}\\\\v = 34.31\ m/s[/tex]

Now, consider the second scenario to hit the target:

R = 100 m

Therefore,

[tex]100\ m = \frac{(34.31\ m/s)^2Sin2\theta}{9.81\ m/s^2}\\\\Sin2\theta = \frac{(100\ m)(9.81\ m/s^2)}{(34.31\ m/s)^2}\\\\2\theta = Sin^{-1}(0.833)\\\\\theta = \frac{56.44^o}{2}\\\theta = 28.22^o[/tex]

Hence, the correct option is:

C. 28.2 deg

What is this?
Picture

Answers

Answer:

may be upside down alphabet :"T"

Explanation:

The power of the kettle was 1.5 kW. The 0.2kg heating element took 5 seconds to heat from 20 °C to 100 °C. Calculate the specific heat capacity of water using this information.

Answers

Answer:

Specific heat capacity, c = 468.75 J/Kg°C

Explanation:

Given the following data;

Power = 1.5 kW to Watts = 1.5 * 1000 = 1500 Watts

Time = 5 seconds

Mass = 0.2 kg

Initial temperature = 20°C

Final temperature = 100°C

To find specific heat capacity;

First of all, we would have to determine the energy consumption of the kettle;

Energy = power * time

Energy = 1500 * 5

Energy = 7500 Joules

Next, we would calculate the specific heat capacity of water.

Heat capacity is given by the formula;

[tex] Q = mcdt[/tex]

Where;

Q represents the heat capacity or quantity of heat. m represents the mass of an object. c represents the specific heat capacity of water. dt represents the change in temperature.

dt = T2 - T1

dt = 100 - 20

dt = 80°C

Making c the subject of formula, we have;

[tex] c = \frac {Q}{mdt} [/tex]

Substituting into the equation, we have;

[tex] c = \frac {7500}{0.2*80} [/tex]

[tex] c = \frac {7500}{16} [/tex]

Specific heat capacity, c = 468.75 J/Kg°C

How much energy does it take to boil water for pasta? For a one-pound box of pasta
you would need four quarts of water, which requires 15.8 kJ of energy for every degree Celsius (°C) of temperature increase. Your thermometer measures the starting
temperature as 48°F. Water boils at 212°F.


a. [1 pts] How many degrees Fahrenheit (°F) must you raise the temperature?
b. [2 pts] How many degrees Celsius (°C) must you raise the temperature?
c. [2 pts] How much energy is required to heat the four quarts of water from
48°F to 212°F (boiling)?

Answers

Answer:

a. 164°F

b. [tex]91.\overline 1 \ ^{\circ} C[/tex]

c. [tex]140.\overline 4[/tex] kJ

Explanation:

The starting temperature of the water, T₁ = 48F

The temperature at which the water boils, T₂ = 212°F

a. The difference between the initial and the boiling water temperature, ΔT = T₂ - T₁

Therefore;

ΔT = 212°F - 48°F = 164°F

The temperature by which he temperature must be raised, ΔT = 164°F

b. 48°F = ((48 - 32)×5/9)°C = (80/9)°C = [tex]8.\overline 8 \ ^{\circ} C[/tex]

212°F = ((212 - 32)×5/9)°C = 100°C

∴ ΔT = 100°C - [tex]8.\overline 8 \ ^{\circ} C[/tex] = [tex]9.\overline 1 \ ^{\circ} C[/tex]

c. The heat capacity of the water = The heat required to increase four quartz of water by 1 °C = 15.8 kJ

∴ The heat required to raise four quartz of water by [tex]9.\overline 1 \ ^{\circ} C[/tex], ΔQ = 15.8 kJ/°C × [tex]9.\overline 1 \ ^{\circ} C[/tex] = [tex]140.\overline 4[/tex] kJ.

A car starts from rest .If its acceleration is 1.5m/s^2 in 1.5 seconds. then calculate the distance traveled by it.​

Answers

Answer:1.6875 m

Explanation:

Formula= 1/2 x at^2

What is the relationship between Avogadro's number and a mole?
A. There are 6.02 x 1023 items in a mole, which equals Avogadro's
number
B. A mole is a smaller amount than Avogadro's number.
C. Avogadro's number is used to count particles, and a mole is used
to measure mass.
D. A mole applies to any item, but Avogadro's number is limited to
atoms.
SUBM

Answers

Answer:

A. There are 6.02 x 1023 items in a mole, which equals Avogadro's

number

Explanation:

The mole of a substance is

Why are the largest craters we find on the Moon and Mercury so much larger than the largest craters we find on the Earth

Answers

Answer:

Because Moon and Mars has no atmosphere.

Explanation:

Moon and Mars has no atmosphere, so there is no friction on the falling object due to the atmosphere. The speed of the falling object is more at Moon and Mars.

When a small object impact on the surface of moon or Mars with high speed, the size of crater is large than the earth as out earth has atmosphere.

Other Questions
please help me with this question. V= pi r2h rectangular prism cylinder cone sphere Labor and management at Leo Trucking cannot seem to agree upon a contract for the truck drivers. As each side contends that they are bargaining fairly, no agreement seems to be possible. The drivers are threatening to go on strike, and management knows that such a strike would prove to be costly. None of the parties involved in the dispute wants to reach a win-win agreement. They are each highly focused on their demands, which they would like to achieve, otherwise known as their ________ points. target tolerance focal distribution resistance answer f and g urgently it relates to the picture Muscle weakness is associated with Vit A/ Vit E/ Vit K/ Protein deficiency Professor Iron always gives two exams in his communications class. He only uses the lower of the two scores that a student gets on the exams when he calculates the course grade. Put the grade on the first exam on the horizontal axis and the grade on the second exam on the vertical axis. What kind of preference a student should have for these two grades. Group of answer choices Perfect Complements Perfect Substitutes Cobb-Douglas Preference Neutral Preference Trent Inc. needs an additional worker on a multiyear project. It could hire an employee for a $88,000 annual salary. Alternatively, it could engage an independent contractor for a $95,000 annual fee. Trent's income tax rate is 21 percent. Required: Compute the annual after-tax cost of each option and indicate which minimizes the after-tax cost of obtaining the worker Find the value of x. Which of the following is an autotroph?A. A consumerB. A preyC. A predatorD. A producer Which of the following excerpts is written in first-person point of view?Select all that apply.EXCERPT 1But all thisthe mysterious, far-reaching hairline trail, the absence of sun from the sky, the tremendous cold, and the strangeness and weirdness of it allmade no impression on the man. (Jack London, To Build a Fire)EXCERPT 2My teacher was a pilot in the Women Air Force Service Pilots; she flew a P-61, and one time she survived a terrible crash.EXCERPT 3A few moments later he was in our room, still puffing, still gesticulating, but with so fixed a look of grief and despair in his eyes that our smiles were turned in an instant to horror and pity. (Arthur Conan Doyle, The Adventures of Sherlock Holmes)EXCERPT 4I gazedand gazedbut little thoughtWhat wealth the show to me had brought (William Wordsworth, The Daffodils)EXCERPT 5I suppose all old soldiers are the same, said Mrs. White. The idea of our listening to such nonsense! How could wishes be granted in these days? And if they could, how could two hundred pounds hurt you, father? (W. W. Jacobs, The Monkeys Paw) Radison Enterprises sells a product for $114 per unit. The variable cost is $63 per unit, while fixed costs are $741,285. Determine (a) the break-even point in sales units and (b) the break-even point if the selling price were increased to $120 per unit. a. Break-even point in sales units fill in the blank 1 units b. Break-even point if the selling price were increased to $120 per unit Which is the most correct option regarding subnet masks? the ratio of corresponding side of similar triangles is 5:2, then find the ratio of their areas Write the sum using summation notation, assuming the suggested pattern continues.2, -10, 50, -250, +Is this sequence arithmetic or geometric? How do you know? a 82.6 L sample of gas exerts 350.8 mm hg pressure at 134.6 c. what valine does the gas have at 736.4 mm hg and 42.8 ca. 30.5b 4.13c. 12.5d. 134need help ASAP i need help asap!! thank you, your help is really appreciated At this intersection, how should you proceed? A. Stop and wait for the red lights to stop flashingB. Respond to the flashing red lights as if they are a stop sign. c. Respond to the flashing red lights as they are a yield sign 4. Change the following sentences to plural. Example: The boy is singing. The boys are singing. (a) The tiger jumped in the air. (b) The elephant is running. (c) They gave me an apple. (d) Raju put the apple in a box. (e) She opened the door. 10. What is the multiple zero and multiplicity of f(x) = (x - 3)(x - 3)(x + 5)?Multiple zero is -3; multiplicity is 2Multiple zero is 5; multiplicity is 1Multiple zero is -5; multiplicity is 1Multiple zero is 3; multiplicity is 2 Ngi ta tin hnh bi kim tra c thit k nh gi thi i vi bnh nhn anghp hi trn 60 sinh vin y nm nht, kt qu tnh c im trung bnh ca mu l 73,8 v lch chun mu l 8,3. Vi mc ngha 5%, s liu trn c mnh cho rng im trung bnhbi nh gi thi ca sinh vin y nm nht l trn 70 hay khng?