When blue light (450 nm) is shone on a particular metal surface, electrons are ejected with a kinetic energy of 2.5 x 10-20 J. Calculate the work function for this metal.

Answers

Answer 1

Answer:

the work function of the metal is 4.167 x 10⁻¹⁹ J .

Explanation:

Given;

wavelength of the incident light, λ = 450 nm = 450 x 10⁻⁹ m

kinetic energy, K.E = 2.5 x 10⁻²⁰ J

The energy of the incident light is calculated as;

[tex]E = hf = \frac{h c}{\lambda} \\\\where;\\\\c \ is \ speed \ of \ light = 3 \times 10^8 \ m/s\\\\ h \ is \ Planck's constant = 6.626 \times 10^{-34} Js \\\\E = \frac{(6.626 \times 10^{-34})(3\times 10^8)}{450 \times 10^{-9}} \\\\E = 4.417 \times 10^{-19} \ J[/tex]

Apply Einstein photoelectric equation to determine the work function of the metal;

E = W + K.E

where;

W is the work function of the metal

W = E - K.E

W = 4.417 x 10⁻¹⁹ J - 2.5 x 10⁻²⁰ J

W = 44.17 x 10⁻²⁰ J -  2.5 x 10⁻²⁰ J

W = 41.67 x 10⁻²⁰ J

W = 4.167 x 10⁻¹⁹ J

Therefore, the work function of the metal is 4.167 x 10⁻¹⁹ J .

Answer 2

The work function of the photon is 4.167*10^19J

The energy of this photon can be calculated as

E = hc/λ

Data given;

λ = 450nm = 450*10^-9mh = 6.626*10^-34JSK.E = 2.5*10^-20Jc = 3.0*10^8m/sEnergy of the Photon

substituting the values into the equation;

[tex]E = hc / y\\E = \frac{6.626*10^-^3^4*3.0*10^8}{450*10^-^9} \\E = 4.42*10^-^1^9J[/tex]

Work Function

The work function of the photon can be calculated as;

E = K.E + Ф

4.42*10^-19 = 2.5*10^-20 + Ф

Ф = [tex]4.42*10^-^1^9 - 2.5*10^-^2^0=4.167*10^-^1^9J[/tex]

The work function of the photon is 4.167*10^-19 J

Learn more on work function  of a photon here;

https://brainly.com/question/11683155


Related Questions

Have you ever noticed that how much electrical energy is consumed by electrical appliances in your home. Make a chart of all of these appliances with their power in kW and an average use on daily, weekly, and monthly basis. Usually the electrical power is written on most of the appliances or on their packing. Calculate the total consumption of electrical energy in kWh in your home for December, 2020. Find the expected electricity bill for this month, if 1 kWh energy costs Rs 10. Which item consumed most energy during the month

Answers

Answer:

A. The expected electricity bill for this month is Rs 18,896.2

B. The item which consumed the most energy during the month is the electric cooker with a total consumption of 1,110Kw/Month

Explanation:

Step 1 - Identify electrical appliances

I only have 8 electrical appliances in my home.

Electric Cooker. Its power rating 3000 Watts (that is 3Kw/h)Refrigerator. Its power rating is 150 Watts (that is 0.15Kw/h)Waterheater. Its power rating is 4000 Watts (that is 4Kw/h)Electric Iron. Its power rating is 1000 Watts (that is 1Kw/h)Led TV. Its power rating is 235 watts (that is 0.235Kw/h)13 Energy-saving Light bulbs at 60 watts which is a total  of 780 watts (which is 0.78Kw)Electric Standing Fan. Its power rating is 55 watts (that is 0.055Kw)Washing machine. Its power rating 255 watts (that is 0.255Kw)

Step 2 - Assign usage per hour and calculate wattage used /month

The Electric Cooker is used an average of 9 hours/day. This is 270hours/month. Total Kw used per month 3Kw * 270hours = 1,110Kw/MonthThe refrigerator is used 24 hours. That is 0.15Kw *24*30days= 108Kw/MonthThe water heater is used 1 hour every day. That is 4Kw  *30days = 120Kw/MonthThe electric Iron is used for 20 Minutes every day.That is  1Kw * 0.34hr *30= 10Kw/MonthThe Led Tv is used for 12hours/day.  That is 0.235Kw*12*30=84.6Kw/monthThe bulbs are used for about 18hours/day. That is 0.78kw*18*30= 421.2Kw/monthThe electric standing fan is used for about 18 hours/day. That is 0.055kw*18*30=29.7Kw/monthThe washing machine is used for about 6 hours/week. That is 0.255Kw*4*6=6.12Kw/month

Step 3 - Add up all the Kw used per month and multiply by the cost of 1 Kw

Total Kilowatt Consumed/Month = 1110 +108+120+10+84.6+421.2+29.7+6.12

= 1,889.62Kw/Month

Total cost of energy consumed per month = 1889.62 * Rs 10

= Rs 18,896.2

Cheers!

What must happen to an object in order to accelerate it?

Answers

Answer:

For an object to accelerate, appropriate force must be applied to the object to cause it to change it’s velocity if it’s already in motion. However, to cause it to overcome static friction if it is at rest, and cause it to change it’s velocity

Explanation:

you have boasted to your friends that you can ride your bicycle at 30 KPH (KM per Hour) over a 30KM race track comprising of two 15km laps. However, when you finish the first lap, your coach tells you that your average is only 15 KPH. How fast must you ride to bring your average speed to 30 kph.

Answers

Answer:

faster than 100 kph

Explanation:

Time taken to complete the first lap is

[tex]\dfrac{15\ \text{km}}{15\ \text{kph}}=1\ \text{hour}[/tex]

If the person's average speed is to be 30 kph then the complete race would be over in [tex]\dfrac{30}{30}=1\ \text{hour}[/tex]

But 1 hour has passed in the first lap already so, the next 15 km must be covered in 0 time.

So, the speed of the bike must be more than 100 kph.

PLEASE ANSWER ILL GIVE BRAIN!!!

Answers

what’s the question?

Answer:

what's the question?........

Why does a concave lense always form a virtual image?

Answers

Answer:

Concave lens spreads out light rays that are then refracted through it.: A concave mirror or a converging lens will only produce a virtual image at a point if the image is located beyond the focal point. By the focal point, we define the point that is more than one focal length away.

You slide a 15 kg box down a ramp with friction set to an angle of 38°. If the height of the ramp is 1.2 m, what's the frictional force on the box as it gets to the bottom of the ramp if the applied force down the ramp is 52 N?

Answers

Answer:

38.75N

Explanation:

According to Newton's second law

\sum Fx = ma

Fm-Ff = ma

Fm is the moving force

Fm = mgsin theta

Fm = 15(9.8)sin38

Fm = 90.5N

Ff is the frictional force

m is the mass = 15kg

a is two acceleration

Get the acceleration

a= F/m

a = 52/15

a ,= 3.45m/s²

Substitute the given values into the formula

90.5-Ff = 15(3.45)

90.5-Ff = 51.75

Ff = 90.5-51.75

Ff = 38.75N

Hence the frictional force on the box is 38.75N

Velocities of two bodies A and B are given in vectors notation as va =i+2j-3k and Vb=3i+2j-k what will be the relative velocity of b with respect to a?

Answers

Answer:

[tex]V_{B/A}=2i+2k[/tex]

Explanation:

The relative velocity can be calculated by means of the difference between vector B minus vector A.

[tex]V_{A}=i+2j-3k\\V_{B}=3i+2j-k\\V_{B}-V_{A}=(3-1)i + (2-2)j+(-1-(-3))k\\V_{B/A}=2i+2k[/tex]

The difference between temperature and thermal energy is that___________.

Answers

Answer:

Heat vs temperature - Energy Education The core difference is that heat deals with thermal energy, whereas temperature is more concerned with molecular kinetic energy. Heat is the transfer of thermal energy, whereas temperature is a property the object exhibits.

10 POINTS QUESTION: Why both are models for monomers, polymers, and cross-linked polymers

Answers

Answer:

Because both monomers and polymers and cross linked polymers are mers with physically properties which is good for applycations

Explanation:

because they are good for using and not using

also, this is a 5 point question, you are not  fooling anyone. thx for 5 points tho

Intensitatea curentului electric a unui circuit este de 123A iar sarcina electrica este de 1,7C sa se afle intervalul de timp in care este transportata sarcina electrica

Answers

The intensity of the electric current of a circuit is 123A and the electric charge is 1.7C to find the time interval in which the electric charge is transported.

Given that,

Current, I = 123 A

Electric charge, q = 1.7 C

To find,

The time interval in which the charge is transported.

Solution,

The electric current is given by electric charge per unit time. So,

[tex]I=\dfrac{q}{t}\\\\t=\dfrac{q}{I}\\\\t=\dfrac{1.7}{123}\\\\t=0.0138\ s[/tex]

So, the required time is 0.0138 seconds.

What is common between transverse waves and longitudinal waves?

Both include an amplitude, crest, and rarefactions
Both move faster at higher temperatures
Both move slower through densely packed molecules
Both include a wavelength from compression to compression

Answers

Answer:

b

Explanation:

i took the quiz

Both the transverse and longitudinal waves move faster at higher temperatures.

What is meant by transverse wave?

A wave in which the motion of the particles is perpendicular to the direction of the wave propagation is referred to as a transverse wave.

Here,

As a result of the shear stress that is produced, transverse waves are frequently observed in elastic materials.

In this situation, the oscillations are caused by the displacement of the solid particles from their relaxed state in directions perpendicular to the wave's propagation.

The wave in which the particles of the medium oscillate parallel to the direction of propagation of the wave is called a longitudinal wave.

Sound waves similarly oscillate parallel to the direction of propagation, forming the compressions and rarefactions. Hence sound waves are called longitudinal waves.

Hence,

Both the transverse and longitudinal waves move faster at higher temperatures.

To learn more about transverse waves, click:

https://brainly.com/question/13863548

#SPJ5

Look at the atoms below
a. Atom W: 9 protons and 9 neutrons
b. Atom X: 8 protons and 9 neutrons
c. Atom Y: 9 protons and 9 neutrons
d. Atom Z: 9 protons and 10 neutrons
Which ones below are isotopes of each other and why?

Answers

element z are isotopes because number of netron are different and number of protons are same

I think this is physics?
A student wants to calculate the density of the two objects shown below:
A Metal Cube and a Small Statue.
Describe the methods that the student should use to calculate the densities of the two objects.
ASAP please this piece of work is already late XD

Answers

Answer:

Okay

Explanation:

First we should quickly remind ourselves of the equation for density:density= mass/ volumeTo calculate the density we need a method of measuring the mass of each object and another method for measuring the volume of each object. To measure the mass in both cases we can simply use a measuring balance. To measure the volume we will need to use 2 separate methods. For the cube we can simply measure the length, height and depth with a ruler, multiply our measurements and we obtain the volume. The statue is a little more tricky because it has an irregular shape so we can't use the ruler anymore. Instead we should use graduated tank/trough of water. First of all measure the amount of water in the tank before putting in the statue. Then submerge the statue in the water and take another measurement of the volume of water in the tank. The statue will displace the water in the tank giving a higher value. We finally subtract the initial volume from the final volume and we should obtain the volume of the statue.We now have all the measurements necessary to calculate the density of both objects!

find the cp of an article which is sold for rupees 4048 , thereby , making a profit of 15 percent​

Answers

Answer:

4048 = 115x/100.

Explanation:

Profit P = (15/100) X x.

P= 15x/100.

15x/100 = 4048- x.

4048 = 15x/100 + x.

4048 = 115x/100.

If a 1.3 kg ball is dropped from the top of a 33.7 meter building what is its potential energy before it is dropped?
B) What is the maximum velocity of the ball in problem 1 just before it hits the ground?
C) How much kinetic energy does the ball in problem 1 have after it has fallen 10 m down the building?

Answers

Answer:429.338 J; 25.7 m/s; 127.4 J

Explanation:

Given

mass of ball m=1.3 kg

Height of building H=33.7 m

(a)Potential Energy before dropping [tex]=mgH=1.3\times 9.8\times 33.7=429.338\ J[/tex]

(b)Velocity Just before hitting the ground

[tex]v=\sqrt{2gH}=\sqrt{2\times 9.8\times 33.7}=25.7\ m/s[/tex]

(c)After falling 10 m

Here initial velocity is zero

using [tex]v^2-u^2=2as[/tex]

Here,

[tex]v=\text{final veloity}[/tex]

[tex]u=\text{Initial velocity}[/tex]

[tex]a=\text{acceleration due to gravity}[/tex]

[tex]s=\text{displacement}[/tex]

Putting values

[tex]v^2-0=2\times 9.8\times 10\\v=14\ m/s[/tex]

So, kinetic energy  [tex]\dfrac{mv^2}{2}=\dfrac{1.3\times 196}{2}=127.4\ J[/tex]

A softball and a baseball are launched from 2 different pitching machines at the same time.
th
Softball
182 g
165 m/sec
Baseball
143 g
112 m/sec
Which of these BEST explains what factors give the baseball and softball different velocities?
O mass and speed
O mass and direction
O speed and direction
O size and mass

Answers

The answer is Mass and speed

The two blocks shown below have masses m1 = 400 g and m2 = 600 g. They are connected by a string and lie on a frictionless tabletop. A 3.5 N force is applied to block m2, pulling it to the right. Find the acceleration then find the tension force in the string between two objects

Answers

Answer is X^\12+13/2

The answer to a multiplication problem is called the?

Answers

Answer:

product

Explanation:

Answer:

product

Explanation:

You find the product when you multiply two or any number of factors.

Which of these statements is FALSE?*
If you find someone's DNA at a crime scene, they are guilty without a doubt
Even identical Twins have different DNA Fingerprints
DNA is individual evidence
When DNA is found, it will not always lead to usable DNA Fingerprint evidence

Answers

answer: the first one
hope this helped

Can someone please help me?

Answers

Answer:

acceleration...............

Answer:

speed

Explanation:

wanna see some real speed betch

A 445-N force is used to hold up a Papa Johns sign in place. What is the mass of the sign?

Answers

Answer:

The mass of the sign is 44.5 kg.

Explanation:

Given that,

Force acting on the sign, F = 445 N

We need to find the mass of the sign.

Net force acting on it is given by :

F = mg

Where g is the acceleration due to gravity

[tex]m=\dfrac{F}{g}\\\\m=\dfrac{445\ N}{10\ m/s^2}\\\\m=44.5\ kg[/tex]

So, the mass of the sign is 44.5 kg.

define specific heat capacity

Answers

the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).

Q. IF THE SPEED LIMIT IS 22M/S, IS THE CAR TRAVELLING TOO FAST.

Answers

Answer:

yes its travelling at 79.2 km/h (49.2m/h)

How much potassium nitrate (KNO3) would dissolve in 50 milliliters of water at 45ºC given that 55g of KNO3 is dissolved in 150mL of water at 45°C.

A. 19.7g
B. 15.1g
C. 18.3g
D. 23.3g

Answers

The answer is C. 18.3g

Putting the ball back into play by the offense is called a ____ ____

Answers

Answer:

Hand ball ?

Explanation:

A cart has a momentum of 42 kg m/s to the right. Its mass is 6 kg.
→ What is its velocity?
show your work

Answers

Answer:

v = 7 m/s

Explanation:

p = m × v

42 = 6 × v

6v = 42

v = 42/6

v = 7 m/s

A 5 kg ball of clay is moving with a speed of 25 m/s directly toward a 10 kg ball of clay which is at rest. The two clay balls collide and stick together. What is their velocity immediately after the collision?​

Answers

Answer:

8.3m/s

Explanation:

Given parameters:

mass of clay ball  = 5kg

Speed of clay ball  = 25m/s

mass of clay ball at rest  = 10kg

speed of clay ball at rest  = 0m/s

Unknown:

Velocity after collision  = ?

Solution:

 Since the balls stick together, this is an inelastic collision:

   m1v1 + m2v2  = v(m1 + m2)

  5(25) + 10(0)  =  v (5 + 10)

         125 = 15v

           v  = 8.3m/s

1. An airplane flies with a constant speed of 720 km/h. How long will it take to travel a distance of 1500
kilometers?

Answers

Answer:

[tex]125\:\mathrm{minutes\: or\: }2.08\bar{3}\: \mathrm{hours}[/tex]

Explanation:

Speed is given by [tex]s=\frac{d}{t}[/tex], where [tex]d[/tex] is distance travelled and [tex]t[/tex] is time. Rearranging this equation, we have [tex]t=\frac{d}{s}[/tex].

Plugging in our given information:

[tex]t=\frac{d}{s}=\frac{1500\:\mathrm{km}}{720\:\mathrm{km/h}}=2.08\bar{3}\: \mathrm{hours}[/tex]

Thus, our answer is:

[tex]2.08\bar{3}\: \mathrm{hours}\cdot \frac{60\:\mathrm{minutes}}{1\:\mathrm{hour}}=\fbox{$125\:\mathrm{minutes}$}[/tex]

Help me I got this photo please

Answers

Answer:

Carbon Sink- photosythesis, ocean absorption, fossilization

Carbon Source- combustion, respiration

Explanation:

If an oceanic plate and a continent plate converge, or push towards each other, which plate will sink under the other one?​

Answers

Answer:

The oceanic plate will sink under

Explanation:

Due to erosion over time and the sudden shift, the continental plate will rise causing earthquakes, tsunami’s, etc..

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