Answer:
Orange
Step-by-step explanation:
As the chance of choosing orange is 18% which is the least.
it is known that the population proton of utha residnet that are members of the church of jesus christ 0l6 suppose a random sample of 46 selceted and prioon of the sample that belongs to the churh is calcutated what is the problaity of obtaining a sample priton less than 0;50 g
Answer:
0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Proportion of 0.6
This means that [tex]p = 0.6[/tex]
Sample of 46
This means that [tex]n = 46[/tex]
Mean and standard deviation:
[tex]\mu = p = 0.6[/tex]
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.6*0.4}{46}} = 0.0722[/tex]
Probability of obtaining a sample proportion less than 0.5.
p-value of Z when X = 0.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.5 - 0.6}{0.0722}[/tex]
[tex]Z = -1.38[/tex]
[tex]Z = -1.38[/tex] has a p-value of 0.0838
0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.
Use the P (A + B) = P (A) x P (B) rule to find the probability of system failure. Let A and B be the events that the first alarm and second alarm, respectively, fail. Do you get the same answer you did in the earlier question?
Answer:
answer is in the pic Mark me brainliest plz
Step-by-step explanation:
Answer:
The probability of the first alarm failing is (1 - 0.8) = 0.2
The probability of the second alarm failing is (1−0.9)=0.1.
Using the multiplication rule (since A and B are independent), the probability of failure is 0.2 * 0.1 = 0.02
Step-by-step explanation:
A manufacturer inspects a sample of 500 smart phones and finds that 496 of them have no defects. The manufacturer sent a shipment of 2000 smartphones to a distributor. Predict the number of smartphones in the shipment that are likely to have no dects.
Answer:
1984
Step-by-step explanation:
4 pts
>
Question 2
The total number of students enrolled in MATH 123 this semester is 5,780.
If it increases by 0.28% for the next semester, what will be the enrollment
next semester? Round to a whole person.
4 pts
Question 3
Answer:
17
Step-by-step explanation:
So, this is a percentage problem.
Start off by finding how many students 0.28% is:
If 100% = 5780
0.01% = 0.578
Now:
0.01% = 0.578
0.28% = 16.184
The exercise tells you to round for a whole person, so 16.184 turns 17
And that's the answer!
-5y-9=-(y-1) equation
a -1/2
b -2 1/2
c -2
d -2/5
Compute the mean deviation of the following set of data; 9,6, 3, 9, 7, 2, 1, 5, 6, 8.
Answer:
5.6
Step-by-step explanation:
( 9 + 6 + 3 + 9 + 7 + 2 + 1 + 5 + 6 + 8 ) / 10
= 56 / 10
= 5.6
haydenkyletoddhaydenkyletodd
A full glass of water can hold 1/6 of a bottle.
How many glasses of water can be filled with 3 bottles of water
Find the value of the variable y, where the sum of the fractions 6/(y+1) and y/(y-2) is equal to their product.
PLEASE HELP NEED ASAPPPPPP WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWERRRRR
Answer:
The answer is
[tex]y = 3[/tex]
[tex]y = - 4[/tex]
Step-by-step explanation:
We must find a solution where
[tex] \frac{6}{y + 1} + \frac{y}{y - 2} = \frac{6}{y + 1} \times \frac{y}{y - 2} [/tex]
Consider the Left Side:
First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get
[tex] \frac{6}{y + 1} \times \frac{y - 2}{y - 2} + \frac{y}{y - 2} \times \frac{y + 1}{y + 1} [/tex]
Which equals
[tex] \frac{6y - 12}{(y -2) (y + 1)} + \frac{ {y}^{2} + y }{(y - 2)(y + 1)} [/tex]
Add the fractions
[tex] \frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)} = \frac{6}{y + 1} \times \frac{y}{y - 2} [/tex]
Simplify the right side by multiplying the fraction
[tex] \frac{6y}{(y + 1)(y + 2)} [/tex]
Set both fractions equal to each other
[tex] \frac{6y}{(y + 1)(y - 2)} = \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)} [/tex]
Since the denomiator are equal, we must set the numerator equal to each other
[tex]6y = {y}^{2} + 7y - 12[/tex]
[tex] = {y}^{2} + y - 12[/tex]
[tex](y + 4)(y - 3)[/tex]
[tex]y = - 4[/tex]
[tex]y = 3[/tex]
Answer:
Step-by-step explanation:
[tex]\frac{6}{y+1}+\frac{y}{y-2}=\frac{6}{y+1} \times \frac{y}{y-2} \\multiply ~by~(y+1)(y-2)\\6(y-2)+y(y+1)=6y\\6y-12+y^2+y=6y\\y^2+y-12=0\\y^2+4y-3y-12=0\\y(y+4)-3(y+4)=0\\(y+4)(y-3)=0\\y=-4,3[/tex]
how much water consumed by Aguilar family as shown in the meter reading
Answer:
?????????????????
Step-by-step explanation:
????????
write seven million six hundred twenty thousand six hundred fifty in standard form?
Answer:
7,620,650
Step-by-step explanation:
___________
Answer:
7,620,650
Step-by-step explanation:
To write in standard form, you just write the entire number out.
A car took 6 minutes to travel between two stations that are 3 miles apart find the average speed of the car in mph
Answer: 30 mph is the answer.
Step-by-step explanation:
s = 3 miles
t = 6 minutes
so,
60 minute = 1 hour
1 minute = 1/60 hour
6 minutes = 1/60 * 6 = 0.1 hour
so
average speed = s/t
= 3/0.1 = 30 mph
3х + 2 +(-5)? I need help pls
Answer:
3x + 2 - 5
3x - 3
x = 3 ÷ 3
x = 1
I hope this helped!
Tan^2t /sin t = tan t sec t
Answer:
Step-by-step explanation:
[tex]\frac{tan^2t}{sint}=\frac{tan t\times tant}{sin t} =\frac{tan t}{sint} \times \frac{sin t}{cos t} =\frac{tan t}{cos t} =tan t ~sec t[/tex]
2+8+5+9+90=
3+45+111=
Answer:
1) 114
2) 159
Step-by-step explanation:
2+8+5+9+90 = 114
3+45+111 = 159
Hope this helps.
Answer:
1)144
2)159
..........
Help me pls
I put the picture in the attach file below
(Sorry i'm in secondary school but i have a problem with my settings)
Answer:
1,2,4,8
Step-by-step explanation:
1
2
1,2
4
4,1
4,2
4,2,1
8
8,1
8,2
8,2,1
8,4
8,4,1
8,4,2
8,4,2,1
The table shows the proof of the relationship between the slopes of two perpendicular lines. What is the missing statement in step 2?
Answer:
[tex]\frac{AB}{BC} = \frac{CE}{ED}[/tex]
Step-by-step explanation:
Given
The attached proof
Required
Complete the missing piece
In (a), we have:
[tex]\triangle ABC \to \triangle CED[/tex]
This implies that, the following sides are similar:
[tex]AB \to CE[/tex]
[tex]AC \to CD[/tex]
[tex]BC \to ED[/tex]
An equation that compares the triangle can be any of:
[tex]\frac{AB}{BC} = \frac{CE}{ED}[/tex]
[tex]\frac{AB}{AC} = \frac{CE}{CD}[/tex]
.....
From the options;
[tex]\frac{AB}{BC} = \frac{CE}{ED}[/tex] is true
pls how can u convert 9ml to cm cube
Answer:
There is no conversion necessary. It's a 1 to 1 ratio.
ml = [tex]cm^{3}[/tex]
so, 9ml is 9[tex]cm^{3}[/tex]
Answer:
9ml = 9cm³
Step-by-step explanation:
1ml = 1cm³
Therefore,
9ml = 9cm³
Can you please help me with this ☺️
Answer:
a=27.807
Step-by-step explanation:
Its simple, set it up for law of sine which is sinA/a = sinB/b
Sin108/a = Sin20/10
PLEASE HELP I DONT NEED EXPLANATION JUST THE EQUATION IM IN A TEST RN HELP ASAP THANK YOU SO MUCH :)))
Answer:
[tex]-x^{2}[/tex]
Step-by-step explanation:
It simple really its just a reflection over the x-axis making it a negative towards the parent function
Answer:
The answer is -x²
Step-by-step explanation:
Hope this helps :)
Joe works as a salesman at the baby retail store. He receives a 5% commission on the first $ 10 000,9% on the next $ 7000, and 13% on any additional sales. Calculate how much Joe must sell to make $ 2082.9 in commission
Answer:
Joe must sell $ 24,330 to make $ 2,082.9 in commission.
Step-by-step explanation:
Since Joe works as a salesman at the baby retail store, and he receives a 5% commission on the first $10,000, 9% on the next $7,000, and 13% on any additional sales, to calculate how much Joe must sell to make $2082.9 in commission the following calculation must be performed:
10,000 x 0.05 = 500
7,000 x 0.09 = 630
2,082.90 - 500 - 630 = X
952.90 = X
0.13X = 952.90
X = 952.90 / 0.13
X = 7.330
10,000 + 7,000 + 7,330 = X
24,330 = X
Therefore, Joe must sell $ 24,330 to make $ 2,082.9 in commission.
Question 1a) Suppose you sample 100 times at random with replacement from a population in which 26% of the individuals are successes. Write a Python expression that evaluates to the chance that the sample has 20 successes.
Answer:
from math import comb
n = 100
x = 20
p = 0.26
q = 0.76
print(comb(n, x)*(p**x)*(q**(n-x)))
Step-by-step explanation:
Given that :
Number of trials, n = 100
P(success), p = 26% = 0.26
P(success)' = 1 - p = 1 - 0.26 = 0.74
Chance that sample has 20 successes = x
This problem meets the condition for a binomial probability distribution :
p(x = 20)
Recall :
P(x = x) = nCx * p^x * q^(n-x)
Using python :
comb is an built in function which calculate the combination of two arguments it takes ; and returns the combination value.
** mean raised to the power and
* is used for multiplication
The Python code as per the given question is provided below.
Program explanation:
The number of trials,
100Probability of success,
20% or 0.26Size of array generated,
2000The output that shows chances of 20 success,
SProgram code:
import numpy as np
S=sum(np.random.binomial(100,0.26,2000)==20)/2000
S
Learn more about Python expression here:
https://brainly.com/question/21645017
Hannah ran 12 laps for 8 days. How many laps did she run in total if she take a break of 1 complete day and 1 half day.
Answer:
The correct answer would be - 9.75 laps (if runs 12 laps in 8 days) or 78 laps (if 12 laps each day for 8 days)
Step-by-step explanation:
Given:
a) Laps covered in 8 days = 12
interval = 1 and half day
total laps = ?
Solution:
To know the total laps with intervals we need to calculate the laps run each day :
= 12/8 laps per day
= 3/2 laps per day
Now multiply the daily run with days
= (3/2)*6.5 (due to 8 - 1.5 = 6,5 days)
= 9.75 laps
B) Given:
Laps covered in 8 days = 12*8 =96
interval = 1 and half day
total laps = ?
Solution:
To know the total laps with intervals we need to calculate the laps run each day :
= 96/8 laps per day
= 12laps per day
Now multiply the daily run with days
= 12*6.5 (due to 8 - 1.5 = 6,5 days)
= 78 laps
Please help asap!!! :(
Answer:
Our maximum is 19 when x=3 and y=7 and our minimum is -21 when x=3 and y = -3
Step-by-step explanation:
First, we can graph these inequalities out. As you can see in the picture, the three vertices where the inequalities all connect form a triangle. We can check each of these vertices to find our minimum and maximum.
First, we have (3,7). 4y-3x = 4(7)-3(3)=28-9=19
Next, for (3, -3), we have 4y-3x = 4(-3)-3(3) = -12-9=-21
Finally, for (0.5, 2), we have 4y-3x=4(2)-3(0.5)=8-1.5 = 6.5
Our maximum is 19 when x=3 and y=7 and our minimum is -21 when x=3 and y = -3
There are two points of the form (x,-4) that have a distance of 10 units from the point (3,2). Give the x value for one of those points.
Answer:
x = - 5
Step-by-step explanation:
[tex]Let \ (x _ 1 , y _ 1 ) \ and \ (x _ 2 , y _ 2 ) \ be \ the \ points. \\\\The \ distance \ between \ the \ points \ be ,\ d = \sqrt{(x_2 - x_1)^2 + ( y _ 2 - y_1)^2}[/tex]
Given : d = 10 units
And the points are ( x , - 4) and ( 3 , 2 ).
Find x
[tex]d = \sqrt{( 3 - x)^2 + ( -4 - 2)^2} \\\\10 = \sqrt{( 3 - x)^2 + ( -6)^2} \\\\10^2 = [ \ \sqrt{( 3 - x)^2 + 36} \ ]^2 \ \ \ \ \ \ \ \ \ [ \ squaring \ both \ sides \ ] \\\\100 = ( 3 - x )^2 + 36\\\\100 - 36 = ( 3 - x )^ 2\\\\( 3 - x ) = \sqrt{64}\\\\3 - x = \pm 8\\\\3 - x = 8 \ and \ 3 - x = - 8\\\\-x = 8 - 3 \ and \ -x = - 8 - 3\\\\-x = 5 \ and \ -x = - 11\\\\x = - 5 \ and \ x = 11\\\\[/tex]
Check which value of x satisfies the distance between the points.
x = 11
[tex]d = \sqrt{(3-11)^2 + (-2--4)^2} = \sqrt{(-8)^2 + (-2+4)^2}= \sqrt{64+4} = \sqrt {68} \ units[/tex]
does not satisfy.
x = - 5:
[tex]d = \sqrt{ (3 -- 5)^2 + ( - 4 - 2)^2} = \sqrt{8^2 + 6^2} = \sqrt{100} =10 \ units[/tex]
Therefore , x = - 5
At one point in history, the NBA finals required that one of the two teams win at least three of five games in order to win the Championship. If one team wins the first two games, what is the probability that the same team wins the Championship, assuming that the two teams are well matched and each team is equally likely to win each game
Answer:
50% i believe
Step-by-step explanation:
because in every scenario theres 2 teams and if they are well matched it be half and half on every game assuming they're the same level of comp
kxndjdkdkdkkdkskskdkdjdjdjskskskdjdjddjd
Answer:
Not a functionFunctionFunctionNot a functionNot a functionHope this helps!
Can someone do 1-15 odds
Answer:
1: -80
3: 21.7
5: inf many solutions? (i cant do that one without a problem)
7: 21
9: - 2/3
11: 6 and 3/8
13: 0.4
15: inf many? (cant solve again)
Step-by-step explanation:
help help HELP!! will give brainliest
If f(x) = x², g(x) = 5x, and h(x) = x + 4, find each value.
Find h[f(4)].
Answer:
[tex]h(f(4))=20[/tex]
Step-by-step explanation:
We are given the functions:
[tex]f(x)=x^2,\, g(x)=5x\text{, and } h(x)=x+4[/tex]
And we want to find
[tex]h(f(4))[/tex]
Find f(4) first:
[tex]f(4)=(4)^2=16[/tex]
Thus:
[tex]h(f(4))=h(16)[/tex]
Now, evaluate h(16):
[tex]h(16)=(16)+4=20[/tex]
Hence:
[tex]h(f(4))=20[/tex]
Quality control. As part of a quality control process for computer chips, an engineer at a factory randomly samples 212 chips during a week of production to test the current rate of chips with severe defects. She finds that 27 of the chips are defective.
(a) What population is under consideration in the data set?
(b) What parameter is being estimated?
(c) What is the point estimate for the parameter?
(d) What is the name of the statistic can we use to measure the uncertainty of the point estimate?
(e) Compute the value from part (d) for this context.
(f) The historical rate of defects is 10%. Should the engineer be surprised by the observed rate of defects
during the current week?
(g) Suppose the true population value was found to be 10%. If we use this proportion to recompute the value in part (e) using p = 0.1 instead of pˆ, does the resulting value change much?
Answer:
See Explanation
Step-by-step explanation:
According to the Question,
Given That, As part of a quality control process for computer chips, an engineer at a factory randomly samples 212 chips during a week of production to test the current rate of chips with severe defects. She finds that 27 of the chips are defective.(a) The sample is from all computer chips manufactured at the factory during the week of production. We might be tempted to generalize the population to represent all weeks, but we should exercise caution here since the rate of defects may change over time.
(b) The fraction of computer chips manufactured at the factory during the week of production that had defects.
(c) Estimate the parameter using the data: phat = 27/212 = 0.127.
(d) Standard error (or SE).
(e) Compute the SE using phat = 0.127 in place of p:
SE ≈ √(phat(1−phat)/n) = 0.023.
(f) The standard error is the standard deviation of phat. A value of 0.10 would be about one standard error away from the observed value, which would not represent a very uncommon deviation. (Usually beyond about 2 standard errors is a good rule of thumb.) The engineer should not be surprised.
(g) Recomputed standard error using p = 0.1: SE = 0.021. This value isn't very different, which is typical when the standard error is computed using relatively similar proportions (and even sometimes when those proportions are quite different!).
